1A shift register is primarily used to perform which of the following operations?
Shift Register
Easy
A.Storage and movement of binary data
B.Voltage amplification
C.Arithmetic division only
D.Signal rectification
Correct Answer: Storage and movement of binary data
Explanation:
A shift register is a group of flip-flops used to store binary data and shift it from one position to another on each clock pulse.
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2How many basic types of shift registers are there based on data entry and exit modes?
Registers: Operation of all basic Shift Registers
Easy
A.3
B.5
C.2
D.4
Correct Answer: 4
Explanation:
The four basic types are SISO, SIPO, PISO, and PIPO, based on serial or parallel input and output.
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3In a SISO shift register, data is entered and taken out in which form?
Registers: Operation of all basic Shift Registers
Easy
A.Parallel in, serial out
B.Serial in, serial out
C.Serial in, parallel out
D.Parallel in, parallel out
Correct Answer: Serial in, serial out
Explanation:
SISO stands for Serial In Serial Out, meaning data is entered one bit at a time and read out one bit at a time.
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4A 4-bit SISO shift register requires how many clock pulses to shift in 4 bits of data?
Registers: Operation of all basic Shift Registers
Easy
A.4
B.2
C.1
D.8
Correct Answer: 4
Explanation:
In a serial-in register, each clock pulse shifts in one bit, so 4 clock pulses are needed to load 4 bits.
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5Which shift register type loads all bits simultaneously and outputs them one bit at a time?
Registers: Operation of all basic Shift Registers
Easy
A.SIPO
B.PISO
C.SISO
D.PIPO
Correct Answer: PISO
Explanation:
PISO (Parallel In Serial Out) loads all bits at once in parallel and shifts them out serially.
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6The basic building block of a shift register is a:
Shift Register
Easy
A.Resistor
B.Multiplexer
C.Comparator
D.Flip-flop
Correct Answer: Flip-flop
Explanation:
Each stage of a shift register is made of a flip-flop, which stores one bit of data.
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7A bidirectional shift register can shift data in which direction(s)?
Bidirectional Shift Register
Easy
A.Right only
B.Both left and right
C.Neither direction
D.Left only
Correct Answer: Both left and right
Explanation:
A bidirectional shift register can shift data both to the left and to the right depending on a control signal.
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8What controls the direction of shifting in a bidirectional shift register?
Bidirectional Shift Register
Easy
A.A mode/direction control input
B.The output frequency
C.The number of flip-flops
D.The power supply voltage
Correct Answer: A mode/direction control input
Explanation:
A control input selects whether data shifts left or right in a bidirectional shift register.
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9A universal shift register can perform which of the following operations?
Universal Shift Register
Easy
A.Only parallel load
B.Shift left, shift right, and parallel load
C.Only serial output
D.Only shift left
Correct Answer: Shift left, shift right, and parallel load
Explanation:
A universal shift register supports left shift, right shift, parallel load, and hold operations, making it very flexible.
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10Which component is typically used at the input of each stage of a universal shift register to select the operation?
Universal Shift Register
Easy
A.Multiplexer
B.Rectifier
C.Transformer
D.Oscillator
Correct Answer: Multiplexer
Explanation:
Multiplexers at each flip-flop input select among shift left, shift right, parallel load, and hold operations.
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11In a synchronous counter, all flip-flops are clocked by:
Counters: Design of Asynchronous and Synchronous counters
Easy
A.The same clock signal
B.A random clock source
C.The output of the previous flip-flop
D.Different clock signals
Correct Answer: The same clock signal
Explanation:
In a synchronous counter, all flip-flops receive the same common clock pulse simultaneously.
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12An asynchronous counter is also commonly known as a:
Counters: Design of Asynchronous and Synchronous counters
Easy
A.Decade counter
B.Ring counter
C.Ripple counter
D.Johnson counter
Correct Answer: Ripple counter
Explanation:
Asynchronous counters are called ripple counters because the clock ripples through each flip-flop in sequence.
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13Which counter is generally faster in operation?
Counters: Design of Asynchronous and Synchronous counters
Easy
A.Both are equally fast
B.Asynchronous counter
C.Ripple counter
D.Synchronous counter
Correct Answer: Synchronous counter
Explanation:
Synchronous counters are faster because all flip-flops change state at the same time, avoiding cumulative propagation delay.
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14How many flip-flops are needed to build a MOD-8 counter?
Counters: Design of Asynchronous and Synchronous counters
Easy
A.8
B.2
C.3
D.4
Correct Answer: 3
Explanation:
A MOD-8 counter counts 8 states, and since , it requires 3 flip-flops.
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15The maximum count of an -flip-flop binary counter is:
Counters: Design of Asynchronous and Synchronous counters
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
An -bit counter has states, counting from 0 to .
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16A ring counter is formed by connecting the output of a shift register back to its:
Ring counter and Johnson ring counter
Easy
A.Reset
B.Input
C.Power supply
D.Clock
Correct Answer: Input
Explanation:
In a ring counter, the output of the last flip-flop is fed back to the input of the first, forming a ring.
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17A 4-bit ring counter has how many valid states?
Ring counter and Johnson ring counter
Easy
A.8
B.16
C.4
D.2
Correct Answer: 4
Explanation:
A ring counter with flip-flops has exactly valid states, so a 4-bit ring counter has 4 states.
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18A 4-bit Johnson counter (twisted ring counter) has how many valid states?
Ring counter and Johnson ring counter
Easy
A.16
B.8
C.2
D.4
Correct Answer: 8
Explanation:
A Johnson counter with flip-flops has states, so a 4-bit version has 8 states.
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19In a Johnson counter, the feedback to the input comes from the:
Ring counter and Johnson ring counter
Easy
A.First flip-flop output
B.Clock input
C.Complemented output of the last flip-flop
D.True output of the last flip-flop
Correct Answer: Complemented output of the last flip-flop
Explanation:
A Johnson counter feeds back the inverted (complemented) output of the last flip-flop, which is why it is called a twisted ring counter.
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20Which counter provides a decoded output without needing extra decoding logic?
Ring counter and Johnson ring counter
Easy
A.Ripple counter
B.Binary counter
C.Ring counter
D.Up-down counter
Correct Answer: Ring counter
Explanation:
A ring counter produces a single active bit at a time, so its outputs are self-decoding and need no additional decoder.
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21A 4-bit Serial-In Serial-Out (SISO) shift register is loaded with the data 1011 (MSB first). How many clock pulses are required to completely read out all 4 bits serially?
Registers: Operation of all basic Shift Registers
Medium
A.2
B.3
C.4
D.8
Correct Answer: 4
Explanation:
In a SISO register, one bit is shifted out per clock pulse. To read out all bits, exactly clock pulses are needed. For a 4-bit register, that is 4 clock pulses.
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22A Serial-In Parallel-Out (SIPO) shift register receives the serial input sequence 1, 0, 1, 1 on four successive clock pulses. If shifting is left-to-right, what parallel output () appears after the 4th pulse?
Registers: Operation of all basic Shift Registers
Medium
A.1101
B.1110
C.0111
D.1011
Correct Answer: 1011
Explanation:
The first bit entered (1) shifts through to the last position, so after 4 pulses the register holds the sequence in order of entry: .
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23How many clock pulses does a 4-bit Parallel-In Serial-Out (PISO) register need to load data and then shift out all bits serially?
Registers: Operation of all basic Shift Registers
Medium
A.1
B.8
C.5
D.4 (load is asynchronous/parallel, shift needs 4)
Correct Answer: 4 (load is asynchronous/parallel, shift needs 4)
Explanation:
Parallel loading places all bits simultaneously (effectively 1 load operation), then 4 clock pulses shift out the 4 bits serially. The dominant count for serial readout is 4 clock pulses.
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24A ripple (asynchronous) up-counter uses 4 JK flip-flops, each with a propagation delay of . What is the maximum total propagation delay before the counter output is stable?
Counters: Design of Asynchronous and Synchronous counters
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
In a ripple counter the delays add cumulatively because each flip-flop triggers the next. Total delay = .
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25What is the key difference between a synchronous and an asynchronous counter?
Counters: Design of Asynchronous and Synchronous counters
Medium
A.In a synchronous counter each flip-flop has its own clock; in an asynchronous counter all share one clock
B.Synchronous counters can only count up while asynchronous can only count down
C.Both use a common clock but differ in flip-flop type
D.In a synchronous counter all flip-flops share a common clock; in an asynchronous counter the clock ripples through stages
Correct Answer: In a synchronous counter all flip-flops share a common clock; in an asynchronous counter the clock ripples through stages
Explanation:
Synchronous counters clock every flip-flop simultaneously, eliminating cumulative delay. Asynchronous (ripple) counters clock the first stage and pass output to trigger subsequent stages.
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26A synchronous counter must count in the sequence (mod-10). What is the minimum number of flip-flops required?
Counters: Design of Asynchronous and Synchronous counters
Medium
A.4
B.3
C.5
D.10
Correct Answer: 4
Explanation:
To represent 10 distinct states we need , giving (since ). Three flip-flops give only states, which is insufficient.
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27A mod-6 asynchronous counter is built from a mod-8 (3 flip-flop) counter by resetting at a specific count. At which count should the RESET (via a NAND gate to CLEAR) be triggered?
Counters: Design of Asynchronous and Synchronous counters
Medium
A.When the count reaches (111)
B.When the count reaches (101)
C.When the count reaches (110)
D.When the count reaches (1000)
Correct Answer: When the count reaches (110)
Explanation:
A mod-6 counter counts 0 through 5. The moment the count becomes 6 (110), the NAND detects it and asynchronously clears the counter back to 0, so valid states are 0–5.
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28For a 4-bit synchronous binary up-counter using T flip-flops, what should the T input of the third flip-flop () be?
Counters: Design of Asynchronous and Synchronous counters
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
In a synchronous binary counter, a flip-flop toggles only when all lower-order bits are 1. So toggles when , giving .
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29A 4-bit ring counter is initialized to 1000. What is the maximum number of unique states (modulus) it cycles through?
Ring counter and Johnson ring counter
Medium
A.16
B.2
C.4
D.8
Correct Answer: 4
Explanation:
A ring counter circulates a single 1 (or a single loaded pattern) around flip-flops, producing exactly unique states. For 4 flip-flops that is 4 states.
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30A 4-bit Johnson (twisted-ring) counter produces how many unique states before repeating?
Ring counter and Johnson ring counter
Medium
A.8
B.16
C.4
D.6
Correct Answer: 8
Explanation:
A Johnson counter feeds the complement of the last output back to the first stage, giving unique states. For flip-flops, that is states.
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31A Johnson counter is initialized to 0000. What is the state sequence for the first three clock pulses?
Ring counter and Johnson ring counter
Medium
A.1000, 0100, 0010
B.1111, 0111, 0011
C.0001, 0011, 0111
D.1000, 1100, 1110
Correct Answer: 1000, 1100, 1110
Explanation:
The complemented output of the last stage feeds the first. Starting from 0000, a 1 enters and fills the register from one end: 1000 → 1100 → 1110, eventually reaching 1111 before emptying.
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32To design a mod-10 (decade) counter using the Johnson counter approach, how many flip-flops are needed?
Ring counter and Johnson ring counter
Medium
A.10
B.4
C.5
D.8
Correct Answer: 5
Explanation:
A Johnson counter gives states. For a mod-10 counter, flip-flops. This is a common efficient decade counter design.
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33Which statement correctly compares a ring counter and a Johnson counter with the same number () of flip-flops?
Ring counter and Johnson ring counter
Medium
A.The Johnson counter gives twice as many states as the ring counter
B.Both give the same number of states
C.The ring counter gives states while Johnson gives
D.The ring counter gives twice as many states as the Johnson counter
Correct Answer: The Johnson counter gives twice as many states as the ring counter
Explanation:
A ring counter has states while a Johnson counter has states, because Johnson feeds back the complement, doubling the count for the same hardware.
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34A shift register is used as a serial-to-parallel converter. If serial data arrives at into an 8-bit register, how often does a complete parallel byte become available?
Shift Register
Medium
A.Every
B.Every
C.Every
D.Every
Correct Answer: Every
Explanation:
At each bit takes . Filling an 8-bit register requires 8 bits, so a parallel word is ready every .
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35Shifting a binary number left by one position in a shift register (with 0 fed in) is equivalent to what arithmetic operation?
Shift Register
Medium
A.Division by 2
B.Addition of 1
C.Multiplication by 4
D.Multiplication by 2
Correct Answer: Multiplication by 2
Explanation:
Each left shift moves every bit to a higher weight position, doubling the value. Shifting left by one (with a 0 in the LSB) multiplies the number by .
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36A register holds the binary value 0110 (). After a single logical right shift (0 shifted into MSB), what value does it hold?
Shift Register
Medium
A.1100 ()
B.1011 ()
C.0110 ()
D.0011 ()
Correct Answer: 0011 ()
Explanation:
A right shift divides an unsigned value by 2 (integer division). 0110 = 6 becomes 0011 = 3, which equals .
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37In a bidirectional shift register, what does the control (mode) input primarily determine?
Bidirectional Shift Register
Medium
A.Whether the data is inverted
B.The number of flip-flops that are active
C.The direction of the shift (left or right)
D.The clock frequency of the register
Correct Answer: The direction of the shift (left or right)
Explanation:
A bidirectional shift register uses a mode/direction control line, typically selecting between shift-left and shift-right operation via multiplexers on each flip-flop input.
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38A 4-bit bidirectional shift register holds 1001. With serial input 0 and the direction set to shift-right, what is the register content after one clock pulse?
Bidirectional Shift Register
Medium
A.0011
B.1000
C.0100
D.0010
Correct Answer: 0100
Explanation:
Shift-right moves each bit toward the LSB and inserts the serial input (0) at the MSB. 1001 becomes 0100, with the original LSB (1) shifted out.
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39A universal shift register (such as the 74194) typically uses two mode-select lines . Which operation corresponds to ?
Universal Shift Register
Medium
A.Hold (no change)
B.Shift left
C.Shift right
D.Parallel load
Correct Answer: Parallel load
Explanation:
In the standard universal shift register: = hold, = shift right, = shift left, and = parallel load. Thus selects parallel loading.
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40Which combination of capabilities makes a shift register 'universal'?
Universal Shift Register
Medium
A.Shift-right operation combined with a hold state only
B.Parallel input with parallel output only
C.Serial/parallel input and serial/parallel output with shift-left and shift-right
D.Only serial input and serial output in one direction
Correct Answer: Serial/parallel input and serial/parallel output with shift-left and shift-right
Explanation:
A universal shift register supports all data movement modes: serial and parallel loading, serial and parallel output, plus bidirectional (left and right) shifting selected by mode control lines.
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41A synchronous mod-6 counter is designed using T flip-flops. During the analysis, the designer finds that the unused states and must not lock the counter into an isolated loop. If the excitation for the MSB is , which additional design property guarantees a self-correcting counter?
Counters: Design of Asynchronous and Synchronous counters
Hard
A.Every unused state eventually transitions into the main counting sequence within a finite number of clock pulses
B.The unused states must map only to state
C.The unused states must be forced to remain constant to avoid glitches
D.The counter must use JK flip-flops instead of T flip-flops
Correct Answer: Every unused state eventually transitions into the main counting sequence within a finite number of clock pulses
Explanation:
A self-correcting counter ensures that any unused/invalid state (here and ) leads back into the valid counting cycle after a finite number of clocks, preventing a lock-up loop. It need not map directly to .
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42A Johnson counter using flip-flops is used to generate timing signals. To decode any one of its unique states, how many inputs does each decoding AND gate require, and why?
Ring counter and Johnson ring counter
Hard
A. inputs, because each Johnson state is uniquely identified by two adjacent bits
B. inputs, because all flip-flop outputs must be checked
C. inputs, because only half the bits change per cycle
D. input, because each state activates exactly one flip-flop
Correct Answer: inputs, because each Johnson state is uniquely identified by two adjacent bits
Explanation:
In a Johnson counter, adjacent bit pairs (a or boundary) uniquely define each of the states, so 2-input AND gates suffice for decoding regardless of .
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43A 4-bit SISO shift register is loaded serially with data (first bit entered = 1). After the fourth clock pulse, the register content (from MSB to LSB ) is:
Registers: Operation of all basic Shift Registers
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
With serial-in shifting right, the first entered bit ends up in the last position. Entering in order and shifting, the final content (the first bit 1 reaches ).
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44A universal shift register (e.g., 74194) has mode-control inputs . Which combination performs synchronous parallel load of the register?
Universal Shift Register
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
In the standard universal shift register, holds, shifts right, shifts left, and performs parallel (broadside) load.
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45In a 4-bit asynchronous (ripple) up-counter with each flip-flop having propagation delay ns, the maximum worst-case output settling delay after a clock edge is:
Counters: Design of Asynchronous and Synchronous counters
Hard
A. ns
B. ns
C. ns
D. ns
Correct Answer: ns
Explanation:
In a ripple counter, delays add cumulatively. With 4 flip-flops each contributing ns, the worst case (when all bits toggle, e.g., ) is ns.
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46A 4-bit bidirectional shift register shifts right when control and left when . If it currently holds and with serial left-input , what is the content after one clock?
Bidirectional Shift Register
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Shift left moves each bit toward MSB: , , , and serial input . From : shift into , new , giving .
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47A ring counter and a Johnson counter each use 5 flip-flops. What is the ratio of the number of distinct states (ring : Johnson)?
Ring counter and Johnson ring counter
Hard
A.
B. but non-reducible
C.
D.
Correct Answer:
Explanation:
A ring counter with FFs has states (); a Johnson counter with FFs has states (). The ratio .
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48A synchronous counter is to be designed with the irregular sequence using JK flip-flops. How many flip-flops are minimally required?
Counters: Design of Asynchronous and Synchronous counters
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The largest state value is , which needs 3 bits (). Hence 3 flip-flops are minimally required to represent all states in the sequence.
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49For an -bit serial-in serial-out shift register operated at clock frequency , the time delay between serial input and serial output is:
Registers: Operation of all basic Shift Registers
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Each bit takes one clock period to move one stage. To traverse all stages, total delay .
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50In designing a synchronous mod-10 counter, the number of invalid (unused) states that must be considered for the design (using minimum flip-flops) is:
Counters: Design of Asynchronous and Synchronous counters
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Mod-10 needs 4 flip-flops giving states. Valid states , so invalid states , which must be treated as don't-cares or handled for self-correction.
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51A 4-bit ring counter is initialized to . Due to a noise glitch, one extra 1 is injected, making the state . What is the resulting behavior of the (non-self-correcting) ring counter?
Ring counter and Johnson ring counter
Hard
A.It circulates the erroneous two-1 pattern indefinitely
B.It automatically corrects back to a single 1 after 4 clocks
C.It halts at state permanently
D.It resets to on the next clock
Correct Answer: It circulates the erroneous two-1 pattern indefinitely
Explanation:
A basic ring counter simply recirculates its pattern. An injected error creates a new invalid loop that persists; without self-correcting logic, the two-1 pattern keeps circulating.
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52In a bidirectional shift register built from D flip-flops using 2-to-1 multiplexers at each stage, the total number of multiplexers required for an -bit register (supporting only left/right shift) is:
Bidirectional Shift Register
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Each flip-flop stage requires one 2-to-1 MUX to select between the left-neighbor and right-neighbor input for its D input, giving multiplexers for an -bit register.
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53A synchronous counter uses the JK excitation , for its MSB. This effectively makes flip-flop behave as:
Counters: Design of Asynchronous and Synchronous counters
Hard
A.A D flip-flop holding the value of
B.A T flip-flop that toggles when
C.An SR latch set by and reset by
D.A flip-flop that never changes state
Correct Answer: A T flip-flop that toggles when
Explanation:
When , a JK flip-flop behaves as a T flip-flop with . Here , so toggles only when both and are 1.
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54A universal shift register is used to implement a serial adder by recirculating data. To multiply an unsigned binary number by 2, the register should perform:
Universal Shift Register
Hard
A.A parallel load of the complemented value
B.A right shift with inserted at the MSB
C.A right shift with sign extension
D.A left shift with inserted at the LSB
Correct Answer: A left shift with inserted at the LSB
Explanation:
Shifting left by one position multiplies a binary number by 2, with a entering the LSB (assuming no overflow). Right shifting divides by 2.
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55A self-decoding Johnson counter with 3 flip-flops produces how many uniquely decodable output states, and what is the maximum count frequency benefit over a binary counter of same size regarding decoding glitches?
A 3-FF Johnson counter has states. Because only one bit changes per transition, 2-input AND-gate decoding is glitch-free, unlike binary counters where multiple bits change simultaneously.
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56A PIPO (parallel-in parallel-out) register differs from a PISO register primarily in that PIPO:
Registers: Operation of all basic Shift Registers
Hard
A.Outputs all bits simultaneously without shifting through stages
B.Shifts data one bit per clock at its outputs
C.Requires more clock pulses to read the data out
D.Can only load data serially
Correct Answer: Outputs all bits simultaneously without shifting through stages
Explanation:
A PIPO register loads and presents all bits in parallel in a single clock, offering the fastest data transfer. A PISO must shift bits out serially, needing multiple clocks.
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57Consider a 4-bit synchronous up-counter using T flip-flops. The excitation input for the third flip-flop should be:
Counters: Design of Asynchronous and Synchronous counters
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
In a synchronous binary counter, each bit toggles when all lower bits are 1. So toggles when , giving .
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58A bidirectional shift register is clocked at MHz. To rotate a 4-bit pattern completely around (end-around) and return to the original state in shift-left mode, the minimum time required is:
Bidirectional Shift Register
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
A complete rotation of a 4-bit register requires 4 shift operations (4 clocks). At MHz, each clock is , so total .
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59For a ripple counter to be converted to a mod-12 counter, a NAND gate resets all flip-flops when the count reaches 12. The NAND gate inputs must be connected to the outputs representing:
Counters: Design of Asynchronous and Synchronous counters
Hard
A. and
B. and
C. and (bits set at count )
D., , and
Correct Answer: and (bits set at count )
Explanation:
Count 12 in binary is , where and . Feeding these two outputs to the NAND gate generates the reset pulse to clear the counter back to zero.
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60Two 4-bit universal shift registers are cascaded to form an 8-bit register. To shift the combined register right, the serial output of the higher-order register must feed:
Universal Shift Register
Hard
A.The parallel-load input of both registers
B.The serial-right input of the lower-order register
C.The clock input of the lower-order register
D.The mode-control input of the higher-order register
Correct Answer: The serial-right input of the lower-order register
Explanation:
When cascading for right shift, data flows from the high-order register out into the serial input of the next (low-order) register, maintaining the continuous shift path across both.
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