Unit 2: Differential calculus and its applications - Subjective Questions
MTH165 — Mathematics For Engineers • Practice Questions with Detailed Answers
20 questions
State the derivatives of the standard algebraic, exponential, logarithmic, trigonometric, and inverse trigonometric functions.
Standard derivatives:
- Algebraic function:
- Exponential functions:
- Logarithmic functions:
- Trigonometric functions:
- Inverse trigonometric functions:
State and explain the sum, product, quotient, and chain rules of differentiation.
Let and be differentiable functions.
- Sum rule:
- Difference rule:
- Product rule:
- Quotient rule:
- Chain rule: If and , then
For example, if , the chain rule gives
Differentiate with respect to using the general rules of differentiation.
The function is a product of , , and .
Using the product rule for three functions,
Therefore,
Taking as a common factor,
Equivalently,
For the parametric curve and , find and .
For a curve defined parametrically,
Here,
Hence,
The second derivative is
Since
we obtain
Thus,
Explain implicit differentiation and find for the curve .
Implicit differentiation is used when is not explicitly expressed as a function of . Both sides of the relation are differentiated with respect to , treating as a function of .
Given
differentiate with respect to :
Using the product rule,
Therefore,
Collecting terms containing ,
Hence,
Using logarithmic differentiation, find the derivative of for .
Logarithmic differentiation is useful when the variable appears in both the base and the exponent.
Given
take the natural logarithm on both sides:
Differentiate implicitly with respect to :
Multiplying by and substituting gives
The condition ensures that is defined in the real number system.
Use logarithmic differentiation to differentiate .
Take the natural logarithm of both sides:
Differentiate with respect to :
Thus,
Substituting the original expression for ,
Logarithmic differentiation converts products, quotients, and powers into sums and constant multiples, simplifying the calculation.
Find the th derivative of and .
For , successive differentiation gives
Therefore, the pattern is
For , successive derivatives are
The derivatives repeat after every four differentiations. A compact expression is
State Rolle's theorem and verify it for on the interval .
Rolle's theorem: If a function satisfies the following conditions:
- is continuous on ,
- is differentiable on ,
- ,
then there exists at least one such that .
For on :
- Since is a polynomial, it is continuous on and differentiable on .
- The endpoint values are
- Thus, .
Now,
Setting ,
Since , Rolle's theorem is verified, with
State Lagrange's mean value theorem and verify it for on .
Lagrange's mean value theorem: If is continuous on and differentiable on , then there exists at least one such that
For on , the function is continuous and differentiable because it is a polynomial.
The average rate of change is
Also,
By the theorem,
so
Since , the theorem is verified, and
State Cauchy's mean value theorem and explain how it generalizes Lagrange's mean value theorem.
Cauchy's mean value theorem: Let and be continuous on and differentiable on . If for every , then there exists at least one such that
Equivalently,
To obtain Lagrange's mean value theorem, choose
Then and . Cauchy's theorem becomes
which is exactly Lagrange's mean value theorem.
Thus, Lagrange's theorem is a special case of Cauchy's theorem.
State Taylor's theorem with the Lagrange form of the remainder and explain the meaning of each term.
Suppose possesses derivatives up to order in an interval containing and . Taylor's theorem states that
The Lagrange form of the remainder is
where lies between and .
- is the point about which the function is expanded.
- The finite sum is the Taylor polynomial of degree .
- is the error made by replacing with that polynomial.
- The value determines the coefficient of .
If as , the corresponding infinite Taylor series represents in the interval under consideration.
Derive the Maclaurin expansion of and use it to approximate up to terms containing .
Maclaurin's theorem is Taylor's theorem with :
For , every derivative is . Hence,
Therefore,
Using terms up to and substituting ,
Thus,
Hence,
Derive the Maclaurin series for and .
For , the derivatives repeat as
At , their values are
Therefore,
For , the derivatives repeat as
At , their values are
Therefore,
The sine series contains only odd powers, whereas the cosine series contains only even powers.
What is an indeterminate form? List the common indeterminate forms and explain why direct substitution does not determine their limits.
An indeterminate form is an expression obtained during limit evaluation whose appearance alone is insufficient to determine the value of the limit.
The common indeterminate forms are
For example, the form may produce different limits:
while
Both expressions have the form under direct substitution, but their limits differ. Therefore, an indeterminate form is not the final value of the limit. The expression must first be transformed using factorization, rationalization, standard limits, series expansions, logarithms, or L'Hospital's rule.
State L'Hospital's rule and evaluate .
L'Hospital's rule: If and are differentiable near a point and the quotient has the indeterminate form or , then, under the required regularity conditions,
provided the limit on the right exists.
Consider
Direct substitution gives . Applying L'Hospital's rule once,
This is again , so apply the rule a second time:
Thus,
Evaluate by converting the indeterminate form into a form suitable for L'Hospital's rule.
The expression has the indeterminate form . Let
Taking natural logarithms,
As , this quotient has the form . Applying L'Hospital's rule,
Simplifying,
Therefore,
Hence,
Taking logarithms converts a power-type indeterminate form into a product or quotient form to which L'Hospital's rule can be applied.
Explain the first derivative test and the second derivative test for determining local maxima and minima.
A point is a critical point if or if does not exist while is defined.
First derivative test:
- If changes from positive to negative as passes through , then is a local maximum.
- If changes from negative to positive, then is a local minimum.
- If does not change sign, then is neither a local maximum nor a local minimum.
Second derivative test: If , then
- implies that is a local minimum.
- implies that is a local maximum.
- makes the test inconclusive; the first derivative test or higher derivatives must then be used.
The first derivative test examines monotonicity, while the second derivative test examines the concavity of the graph at a stationary point.
Find the local maximum and local minimum values of .
Differentiate the function:
The stationary points satisfy :
The second derivative is
At ,
so gives a local maximum. Its value is
At ,
so gives a local minimum. Its value is
Therefore,
and
An open rectangular tank with a square base must hold a volume of . Determine the dimensions that minimize the material used.
Let the side of the square base be metres and the height be metres.
The volume condition is
so
Since the tank is open at the top, its surface area is
Substituting for ,
Differentiate:
For a stationary point,
Thus,
Then
Also,
and
Therefore, the surface area is minimized when
The required tank has a square base and a height of .
State the derivatives of the standard algebraic, exponential, logarithmic, trigonometric, and inverse trigonometric functions.
Standard derivatives:
- Algebraic function:
- Exponential functions:
- Logarithmic functions:
- Trigonometric functions:
- Inverse trigonometric functions:
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