1Which of the following is the primary function of enzymes as proteins?
Protein Function
Easy
A.Catalyzing biochemical reactions
B.Storing genetic information
C.Serving as an energy currency molecule
D.Forming the lipid bilayer
Correct Answer: Catalyzing biochemical reactions
Explanation:
Enzymes are proteins that act as biological catalysts, speeding up biochemical reactions by lowering activation energy.
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2Hemoglobin is an example of a protein that primarily functions in:
Protein Function
Easy
A.Muscle contraction
B.Membrane synthesis
C.DNA replication
D.Oxygen transport
Correct Answer: Oxygen transport
Explanation:
Hemoglobin is a transport protein in red blood cells that carries oxygen from the lungs to tissues throughout the body.
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3Which type of protein provides structural support in tissues such as skin, tendons, and bone?
Protein Function
Easy
A.Insulin
B.Collagen
C.Amylase
D.Myoglobin
Correct Answer: Collagen
Explanation:
Collagen is the most abundant structural protein in animals, giving strength and support to connective tissues.
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4Antibodies are proteins that function mainly in:
Protein Function
Easy
A.Oxygen storage
B.Immune defense
C.Hormone signaling
D.Energy production
Correct Answer: Immune defense
Explanation:
Antibodies (immunoglobulins) are defensive proteins that recognize and bind to foreign antigens as part of the immune response.
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5The primary structure of a protein refers to:
Hierarchical Structure of Proteins
Easy
A.The assembly of multiple polypeptide subunits
B.The linear sequence of amino acids
C.The folding into an alpha helix
D.The overall 3D shape of a single chain
Correct Answer: The linear sequence of amino acids
Explanation:
Primary structure is the specific order of amino acids linked by peptide bonds in a polypeptide chain.
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6Which level of protein structure describes local folding patterns such as -helices and -sheets?
Hierarchical Structure of Proteins
Easy
A.Primary structure
B.Tertiary structure
C.Secondary structure
D.Quaternary structure
Correct Answer: Secondary structure
Explanation:
Secondary structure refers to regular local folding patterns like -helices and -sheets, stabilized by hydrogen bonds.
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7The quaternary structure of a protein is defined by:
Hierarchical Structure of Proteins
Easy
A.The arrangement of multiple polypeptide subunits
B.The sequence of amino acids
C.The peptide bond geometry
D.The presence of a single alpha helix
Correct Answer: The arrangement of multiple polypeptide subunits
Explanation:
Quaternary structure describes how two or more folded polypeptide chains (subunits) associate to form a functional protein complex.
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8Which type of bond primarily stabilizes the secondary structure of proteins?
Hierarchical Structure of Proteins
Easy
A.Hydrogen bonds
B.Disulfide bonds
C.Peptide bonds
D.Ionic bonds
Correct Answer: Hydrogen bonds
Explanation:
Secondary structures such as -helices and -sheets are stabilized by hydrogen bonds between backbone atoms.
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9The complete three-dimensional shape of a single folded polypeptide chain is called its:
Hierarchical Structure of Proteins
Easy
A.Secondary structure
B.Quaternary structure
C.Tertiary structure
D.Primary structure
Correct Answer: Tertiary structure
Explanation:
Tertiary structure is the overall 3D conformation of a single polypeptide chain, stabilized by various interactions among side chains.
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10The torsional angle around the bond in a protein backbone is denoted by:
Torsional angles in proteins and nucleic acids
Easy
A. (chi)
B. (omega)
C. (phi)
D. (psi)
Correct Answer: (phi)
Explanation:
The dihedral angle (phi) describes rotation about the bond in the polypeptide backbone.
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11A Ramachandran plot is used to display allowed combinations of which two angles?
Torsional angles in proteins and nucleic acids
Easy
A. and
B. and
C. and
D. and
Correct Answer: and
Explanation:
A Ramachandran plot maps the sterically allowed values of the backbone dihedral angles and .
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12The torsional angle (psi) describes rotation about which backbone bond?
Torsional angles in proteins and nucleic acids
Easy
A. bond
B.The peptide bond
C. bond
D.The side chain bond
Correct Answer: bond
Explanation:
The dihedral angle (psi) corresponds to rotation about the bond in the protein backbone.
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13The peptide bond ( angle) is usually found to be:
Torsional angles in proteins and nucleic acids
Easy
A.Freely rotating
B.Always cis in configuration
C.Planar and mostly trans
D.Randomly oriented in space
Correct Answer: Planar and mostly trans
Explanation:
Due to partial double-bond character, the peptide bond is planar and adopts predominantly the trans configuration ().
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14The rigidity of the peptide bond is due to its:
Torsional angles in proteins and nucleic acids
Easy
A.Hydrophobic packing
B.Ionic interactions
C.Hydrogen bonding only
D.Partial double-bond character
Correct Answer: Partial double-bond character
Explanation:
Resonance gives the peptide bond partial double-bond character, restricting rotation and keeping the peptide unit planar.
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15Circular Dichroism (CD) spectroscopy measures the differential absorption of:
Characterization of secondary structure using CD
Easy
A.Ultraviolet and visible light
B.Left- and right-handed circularly polarized light
C.X-rays and gamma rays
D.Infrared and microwave radiation
Correct Answer: Left- and right-handed circularly polarized light
Explanation:
CD spectroscopy measures the difference in absorption of left- and right-circularly polarized light by chiral molecules like proteins.
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16In the far-UV region, CD spectroscopy is mainly used to determine the:
Characterization of secondary structure using CD
Easy
A.Molecular weight of proteins
B.Secondary structure content of proteins
C.Number of subunits in a protein
D.Amino acid sequence of proteins
Correct Answer: Secondary structure content of proteins
Explanation:
Far-UV CD (approximately 190-250 nm) reflects the peptide backbone and is used to estimate secondary structure content such as -helix and -sheet.
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17An -helical protein typically shows a characteristic CD spectrum with:
Characterization of secondary structure using CD
Easy
A.A strong maximum at 280 nm from aromatic residues
B.A flat baseline across all wavelengths
C.Two negative minima near 208 nm and 222 nm
D.A single positive peak at 260 nm
Correct Answer: Two negative minima near 208 nm and 222 nm
Explanation:
-helical proteins produce a CD signature with two negative bands at about 208 nm and 222 nm.
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18CD spectroscopy can detect protein secondary structure because proteins are:
Characterization of secondary structure using CD
Easy
A.Insoluble in water
B.Made only of nonpolar residues
C.Electrically neutral
D.Chiral (optically active)
Correct Answer: Chiral (optically active)
Explanation:
Proteins contain chiral centers and asymmetric folds, making them optically active and giving rise to distinct CD signals.
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19The process by which a protein loses its native structure due to heat or chemicals is called:
Protein stability and folding
Easy
A.Denaturation
B.Replication
C.Translation
D.Phosphorylation
Correct Answer: Denaturation
Explanation:
Denaturation is the disruption of a protein's native folded structure by agents such as heat, pH extremes, or chemical denaturants.
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20Which interaction is considered a major driving force for protein folding in aqueous solution?
Protein stability and folding
Easy
A.Gravitational attraction
B.Covalent peptide bonding
C.Metallic bonding
D.The hydrophobic effect
Correct Answer: The hydrophobic effect
Explanation:
The hydrophobic effect drives nonpolar side chains to cluster in the protein interior, away from water, providing the main force for folding.
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21In a Ramachandran plot, the fully allowed region for right-handed -helices corresponds approximately to which combination of backbone dihedral angles?
Torsional angles in proteins and nucleic acids
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The right-handed -helix clusters around and . The region corresponds to -sheets, while positive values are generally disallowed except for glycine.
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22Why does glycine occupy a uniquely broad region of allowed space in the Ramachandran plot compared to other amino acids?
Torsional angles in proteins and nucleic acids
Medium
A.Its side chain is a single hydrogen atom, reducing steric hindrance
B.Its peptide bond adopts a cis configuration more readily
C.Its side chain forms an extra hydrogen bond stabilizing rotation
D.It carries a positive charge that repels the backbone carbonyl
Correct Answer: Its side chain is a single hydrogen atom, reducing steric hindrance
Explanation:
Glycine's side chain is just an H atom, so it experiences minimal steric clash with backbone atoms. This allows a much wider range of and values, including regions forbidden for other residues.
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23The peptide bond dihedral angle is usually restricted to approximately . What is the primary reason for this restriction?
Torsional angles in proteins and nucleic acids
Medium
A.Partial double-bond character from resonance keeps the bond planar
B.Hydrogen bonding between amide protons of neighboring residues
C.Steric clash between successive side chains forcing planarity
D.Electrostatic repulsion between adjacent -carbons
Correct Answer: Partial double-bond character from resonance keeps the bond planar
Explanation:
Resonance delocalization of the amide lone pair gives the C–N peptide bond partial double-bond character. This restricts rotation and holds near (trans), keeping the peptide unit planar.
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24A protein CD spectrum in the far-UV region shows two negative minima at nm and nm and a positive maximum near nm. Which secondary structure dominates?
Characterization of secondary structure using CD
Medium
A.-helix
B.Random coil
C.Polyproline II helix
D.Antiparallel -sheet
Correct Answer: -helix
Explanation:
The characteristic double minima at and nm with a strong positive band near nm is the signature of -helical content. -sheets typically show a single minimum near nm, and random coils show a strong minimum near nm.
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25Circular dichroism measures which physical quantity as a function of wavelength?
Characterization of secondary structure using CD
Medium
A.Fluorescence emission intensity after UV excitation
B.Rotation of the plane of linearly polarized light
C.Differential absorption of left- and right-circularly polarized light
D.Total absorption of unpolarized UV light by aromatic residues
Correct Answer: Differential absorption of left- and right-circularly polarized light
Explanation:
CD arises because chiral chromophores absorb left- and right-circularly polarized light to different extents. The measured signal () is sensitive to the asymmetric environment of peptide bonds in ordered structures.
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26Why is the far-UV region (– nm) most informative for determining protein secondary structure by CD?
Characterization of secondary structure using CD
Medium
A.Disulfide bonds give sharp bands revealing folding topology
B.Aromatic side chains absorb strongly and report tertiary contacts
C.The peptide backbone amide bonds are the dominant chromophores there
D.Water absorption dominates and cancels background noise
Correct Answer: The peptide backbone amide bonds are the dominant chromophores there
Explanation:
In the far-UV region, the peptide bond ( and transitions) is the principal chromophore. Its arrangement in helices, sheets, and coils produces distinct CD signatures, whereas near-UV CD reports on aromatic/tertiary environments.
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27Which level of protein structure is defined solely by the linear sequence of amino acids connected by peptide bonds?
Hierarchical Structure of Proteins
Medium
A.Secondary structure
B.Primary structure
C.Tertiary structure
D.Quaternary structure
Correct Answer: Primary structure
Explanation:
Primary structure is the covalent sequence of amino acid residues. Secondary structure refers to local backbone folding, tertiary to overall 3D shape, and quaternary to assembly of multiple polypeptide subunits.
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28The clustering of nonpolar side chains in the interior of a globular protein, away from water, is the primary organizing force for which structural level?
Hierarchical Structure of Proteins
Medium
A.Primary structure
B.Secondary structure
C.The peptide bond geometry
D.Tertiary structure
Correct Answer: Tertiary structure
Explanation:
The hydrophobic effect drives nonpolar residues to bury themselves in the protein core, which is a major determinant of overall tertiary fold. Secondary structure is stabilized mainly by backbone hydrogen bonds, not side-chain burial.
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29Hemoglobin consists of two and two subunits assembled into a functional tetramer. This arrangement is an example of which structural level?
Hierarchical Structure of Proteins
Medium
A.Quaternary structure
B.Supersecondary structure
C.Tertiary structure
D.Secondary structure
Correct Answer: Quaternary structure
Explanation:
Quaternary structure describes the spatial arrangement and interactions of multiple polypeptide chains (subunits). Hemoglobin's tetramer is a classic example; individual subunit folds are tertiary structure.
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30In an antiparallel -sheet, the hydrogen bonds between strands are best described as:
Hierarchical Structure of Proteins
Medium
A.Formed exclusively within a single strand's residues
B.Nearly linear and evenly spaced between opposing strands
C.Absent, with strands held only by hydrophobic contacts
D.Bent and unevenly spaced compared to parallel sheets
Correct Answer: Nearly linear and evenly spaced between opposing strands
Explanation:
Antiparallel -sheets form nearly straight, evenly spaced inter-strand hydrogen bonds, making them slightly more stable than parallel sheets, whose H-bonds are distorted and angled.
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31An enzyme's catalytic activity is abolished when a single active-site histidine is mutated to alanine, though the protein still folds normally. This best illustrates that:
Protein Function
Medium
A.The mutation destabilizes the entire tertiary structure
B.Histidine is required for peptide bond formation
D.Specific residues, not just overall fold, are essential for function
Correct Answer: Specific residues, not just overall fold, are essential for function
Explanation:
Because the protein folds normally but loses activity, the histidine must play a direct chemical role in catalysis. Function depends on precise positioning of key catalytic residues, not merely on the folded architecture.
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32The binding of oxygen to one subunit of hemoglobin increases the oxygen affinity of the remaining subunits. This behavior is termed:
Protein Function
Medium
A.Competitive inhibition
B.Allosteric inhibition
C.Non-cooperative binding
D.Positive cooperativity
Correct Answer: Positive cooperativity
Explanation:
Positive cooperativity describes how ligand binding at one site enhances binding at others, producing hemoglobin's sigmoidal O-binding curve. It arises from conformational coupling between subunits (T R transition).
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33A structural protein such as collagen relies on which feature to achieve high tensile strength?
Protein Function
Medium
A.A globular fold with a deep hydrophobic binding pocket
B.Rapid conformational switching between two states
C.A tightly wound triple-helical arrangement of polypeptide chains
D.A single -helix stabilized by disulfide bonds
Correct Answer: A tightly wound triple-helical arrangement of polypeptide chains
Explanation:
Collagen's mechanical strength comes from three left-handed polyproline-II-like chains wound into a right-handed triple helix, stabilized by interchain hydrogen bonds and the repeating Gly-X-Y motif.
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34Which statement best explains the specificity of an enzyme for its substrate under the induced-fit model?
Protein Function
Medium
A.The enzyme changes shape upon substrate binding to optimize contacts
B.Specificity arises only from covalent bonds to the substrate
C.The substrate must exactly match a completely rigid active site
D.The enzyme binds any molecule of similar molecular weight
Correct Answer: The enzyme changes shape upon substrate binding to optimize contacts
Explanation:
The induced-fit model proposes that substrate binding triggers a conformational change in the enzyme, molding the active site around the substrate. This contrasts with the rigid lock-and-key view and explains fine specificity.
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35The dominant thermodynamic driving force for the folding of a globular protein in aqueous solution is:
Protein stability and folding
Medium
A.Formation of covalent disulfide bonds
B.Van der Waals attractions between backbone atoms
C.The hydrophobic effect from burying nonpolar residues
D.Electrostatic repulsion between charged side chains
Correct Answer: The hydrophobic effect from burying nonpolar residues
Explanation:
Burying nonpolar groups releases ordered water molecules, increasing solvent entropy. This hydrophobic effect is the largest contributor to the free energy of folding, though hydrogen bonds and van der Waals forces also contribute.
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36The net free energy of stabilization () for a typical folded protein is only about – kcal/mol. What does this small value imply?
Protein stability and folding
Medium
A.The folded and unfolded states have identical free energies
B.Proteins are extremely rigid and never unfold spontaneously
C.Folding is driven entirely by enthalpy with no entropic cost
D.Folded proteins are only marginally stable relative to unfolded states
Correct Answer: Folded proteins are only marginally stable relative to unfolded states
Explanation:
The small net reflects a delicate balance between large stabilizing and destabilizing contributions. This marginal stability allows proteins to be flexible enough for function yet stable enough to maintain structure.
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37Levinthal's paradox highlights that proteins cannot fold by randomly sampling all conformations. The resolution most widely accepted is that:
Protein stability and folding
Medium
A.Proteins fold instantaneously with no intermediate states
B.Folding follows directed pathways down an energy funnel
C.Chaperones covalently lock the final fold in place
D.The native state is chosen by pure thermodynamic chance
Correct Answer: Folding follows directed pathways down an energy funnel
Explanation:
Random sampling would take astronomically long. The energy-landscape (funnel) model resolves this: folding proceeds through biased pathways and intermediates that progressively lower free energy toward the native state.
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38A protein is heated and its CD signal at nm gradually disappears with a sharp sigmoidal transition. This observation indicates:
Protein stability and folding
Medium
A.Formation of additional -sheet upon heating
B.Cooperative loss of -helical structure during denaturation
C.Reversible aggregation without secondary structure loss
D.An increase in disulfide bond content at high temperature
Correct Answer: Cooperative loss of -helical structure during denaturation
Explanation:
The nm CD signal reports -helix content. Its sigmoidal disappearance with temperature reflects cooperative, two-state unfolding, where the helical secondary structure is lost over a narrow temperature range near the melting point.
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39Adding a high concentration of urea to a protein solution typically causes unfolding because urea:
Protein stability and folding
Medium
A.Forms strong covalent bonds with backbone carbonyls
B.Weakens the hydrophobic effect and solvates exposed groups
C.Cross-links side chains to lock in a misfolded state
D.Increases the entropy of the folded native state
Correct Answer: Weakens the hydrophobic effect and solvates exposed groups
Explanation:
Denaturants like urea improve the solubility of nonpolar groups and interact favorably with the peptide backbone, reducing the hydrophobic driving force for folding and shifting equilibrium toward the unfolded state.
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40A CD spectrum showing a single broad negative minimum near nm and a positive band near nm is most consistent with which secondary structure?
Characterization of secondary structure using CD
Medium
A.-helix
B.Random coil
C.-helix
D.-sheet
Correct Answer: -sheet
Explanation:
-sheet-rich proteins characteristically show a single negative minimum around – nm and a positive maximum near nm, distinct from the double minima (, nm) of -helices.
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41In a Ramachandran plot, glycine occupies regions forbidden to other residues. Which combination of values would be sterically allowed for glycine but strongly disfavored for L-alanine?
Torsional angles in proteins and nucleic acids
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Glycine lacks a side chain (only an H), removing steric clashes that restrict other residues. Positive regions (right side of the plot) are accessible to glycine but sterically forbidden for L-amino acids because their would clash with backbone atoms. The other values correspond to standard -helix or -sheet regions accessible to all residues.
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42A protein shows a far-UV CD spectrum with double minima at 208 nm and 222 nm and a maximum near 190 nm. Upon heating, the 222 nm signal approaches zero and a single deep minimum near 200 nm appears. What is the correct interpretation?
Characterization of secondary structure using CD
Hard
A.Transition from random coil to -sheet
B.Transition from -helix to random coil
C.Conversion of aromatic residues to disordered state
D.Transition from -sheet to -helix
Correct Answer: Transition from -helix to random coil
Explanation:
The 208/222 nm double minima with a 190 nm maximum are diagnostic of -helix. A single minimum near 200 nm (198–200 nm) is characteristic of random coil. Loss of the 222 nm band on heating indicates thermal unfolding of helix to disordered coil.
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43For a two-state folding equilibrium, the fraction folded is 0.90 at 25°C. If where , what is the approximate of unfolding at this temperature ( kJ/mol)?
Protein stability and folding
Hard
A. kJ/mol
B. kJ/mol
C. kJ/mol
D. kJ/mol
Correct Answer: kJ/mol
Explanation:
. kJ/mol. The positive value confirms the folded state is more stable.
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44The Anfinsen ribonuclease refolding experiment demonstrated a key principle, but reoxidation in the presence of a scrambling agent (urea + trace mercaptoethanol) initially gave only ~1% activity. What does this observation establish?
Hierarchical Structure of Proteins
Hard
A.Native structure is the thermodynamically most stable state under physiological conditions
B.The primary sequence does not determine tertiary structure
C.Folding requires chaperones even in vitro
D.Disulfide bonds form randomly and are kinetically trapped permanently
Correct Answer: Native structure is the thermodynamically most stable state under physiological conditions
Explanation:
Scrambled ribonuclease had incorrect disulfides (1 of 105 possible pairings is native). Adding trace thiol allows disulfide reshuffling, and full activity is recovered as the protein reaches the thermodynamic minimum. This confirms the native fold is determined by sequence and is the global free energy minimum.
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45The peptide bond torsion angle is typically restricted to ~180° (trans). For which residue is the cis conformation () most frequently observed, and why?
Torsional angles in proteins and nucleic acids
Hard
A.Glycine, because it has no side chain to cause steric hindrance
B.Proline, because cis and trans X–Pro bonds have comparable steric energy
C.Alanine, because its methyl group stabilizes the cis form
D.Cysteine, because disulfide constraints favor cis peptide bonds
Correct Answer: Proline, because cis and trans X–Pro bonds have comparable steric energy
Explanation:
In X–Pro peptide bonds, the pyrrolidine ring makes the cis and trans forms nearly equal in steric energy (unlike other residues where trans is strongly favored). Consequently cis peptide bonds occur most often preceding proline, and cis-trans proline isomerization is often the rate-limiting step in folding.
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46The hydrophobic effect is the dominant driving force in protein folding. At room temperature, its favorable contribution is primarily driven by:
Protein stability and folding
Hard
A.A favorable entropy change of the polypeptide backbone
B.An unfavorable enthalpy compensated by hydrogen bonding
C.A favorable entropy change from releasing ordered water around nonpolar groups
D.A favorable enthalpy change from van der Waals contacts in the core
Correct Answer: A favorable entropy change from releasing ordered water around nonpolar groups
Explanation:
At room temperature the hydrophobic effect is entropically driven: burying nonpolar surfaces releases the ordered 'clathrate' water shells surrounding them, increasing solvent entropy. This positive makes favorable, outweighing the loss of backbone conformational entropy.
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47Near-UV CD (250–320 nm) of a protein probes tertiary structure through aromatic and disulfide chromophores. A protein retains full far-UV CD signal but loses all near-UV CD signal upon mild denaturation. This is the signature of:
Characterization of secondary structure using CD
Hard
A.An amyloid fibril
B.Complete random coil formation
C.A domain-swapped dimer
D.A molten globule state
Correct Answer: A molten globule state
Explanation:
The molten globule retains native-like secondary structure (intact far-UV CD) but lacks fixed tertiary packing, so aromatic side chains become mobile and their near-UV CD vanishes. Full unfolding would abolish both signals; the selective loss of near-UV signal is the classic molten globule signature.
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48Hemoglobin's cooperative binding is described by the Hill equation. If a Hill plot yields a slope for a tetramer, what is the correct interpretation?
Protein Function
Hard
A.Exactly three oxygen molecules bind before saturation
B.Non-cooperative binding identical to myoglobin
C.Positive cooperativity that is less than the theoretical maximum for four sites
D.Negative cooperativity among the four binding sites
Correct Answer: Positive cooperativity that is less than the theoretical maximum for four sites
Explanation:
indicates positive cooperativity. For a tetramer the theoretical maximum is ; a value of 2.8 reflects real, strong-but-incomplete cooperativity. The Hill coefficient is not the number of sites but a measure of interaction strength.
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49In a parallel -sheet versus an antiparallel -sheet, the hydrogen bonding geometry differs. Which statement correctly distinguishes them?
Hierarchical Structure of Proteins
Hard
A.Antiparallel sheets have narrowly spaced, nearly linear H-bonds; parallel sheets have evenly spaced but distorted H-bonds
B.Both have identical H-bond geometry but differ only in side-chain orientation
C.Antiparallel sheets lack inter-strand H-bonds and rely on disulfides
D.Parallel sheets have narrowly spaced linear H-bonds; antiparallel sheets have no inter-strand H-bonds
Correct Answer: Antiparallel sheets have narrowly spaced, nearly linear H-bonds; parallel sheets have evenly spaced but distorted H-bonds
Explanation:
In antiparallel sheets, paired strands align so H-bonds are nearly linear and come in narrow/wide alternating pairs, making them slightly more stable. In parallel sheets the strands are offset, producing evenly spaced but bent (distorted, non-linear) H-bonds.
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50In nucleic acids, the glycosidic torsion angle distinguishes syn and anti conformations. Which statement about B-DNA and Z-DNA is correct?
Torsional angles in proteins and nucleic acids
Hard
A.Z-DNA has purines anti and pyrimidines syn, opposite of B-DNA
B.B-DNA has all bases anti; Z-DNA has purines syn and pyrimidines anti
C.Both B-DNA and Z-DNA have all bases in the syn conformation
D.B-DNA has all bases syn; Z-DNA has all bases anti
Correct Answer: B-DNA has all bases anti; Z-DNA has purines syn and pyrimidines anti
Explanation:
In right-handed B-DNA all nucleotides adopt the anti glycosidic conformation. In left-handed Z-DNA, the alternating purine–pyrimidine backbone requires purines (e.g., guanine) to flip to syn while pyrimidines remain anti, producing the characteristic zig-zag backbone.
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51Cold denaturation of proteins occurs at low temperatures where becomes negative. This counterintuitive phenomenon arises because:
Protein stability and folding
Hard
A.Disulfide bonds spontaneously break at low temperature
B.Backbone entropy increases sharply as temperature drops
C.Hydrogen bonds become stronger at low temperature, destabilizing the core
D.The temperature dependence of is parabolic due to a large positive of unfolding
Correct Answer: The temperature dependence of is parabolic due to a large positive of unfolding
Explanation:
The large positive heat capacity change on unfolding (from exposing hydrophobic surface) makes a downward-opening parabola via the Gibbs–Helmholtz relation. Stability is maximal near room temperature and drops at both high and low T, so can cross zero at low temperature, causing cold denaturation.
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52The mean residue ellipticity at 222 nm can estimate helix content. If a fully helical reference gives deg·cm²·dmol⁻¹ and a sample gives , what is the approximate helical fraction (ignoring coil baseline)?
Characterization of secondary structure using CD
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Helix fraction , i.e. about 50% helical content. (Rigorous analysis includes a coil baseline and chain-length correction, but the ratio gives the first-order estimate.)
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53An enzyme follows Michaelis–Menten kinetics with and M. A competing enzyme has and M. At very low substrate concentration (), which enzyme is catalytically more efficient?
Protein Function
Hard
A.The second enzyme, because is higher
B.The first enzyme, because is higher
C.The first enzyme, because is higher
D.Both are equally efficient at low
Correct Answer: The second enzyme, because is higher
Explanation:
At , rate , so the specificity constant governs efficiency. Enzyme 1: ; Enzyme 2: . The second enzyme has a tenfold higher and is more efficient at low substrate.
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54Levinthal's paradox argues that random conformational search cannot explain folding times. The modern resolution invokes a folding funnel. Which statement best captures this concept?
Protein stability and folding
Hard
A.Chaperones physically thread the chain into its native fold
B.Folding is purely diffusion-limited with no thermodynamic bias
C.A single unique pathway with defined intermediates is followed by every molecule
D.A biased energy landscape guides the chain downhill through many parallel pathways to the native state
Correct Answer: A biased energy landscape guides the chain downhill through many parallel pathways to the native state
Explanation:
The funnel model replaces random search with an energy landscape sloped toward the native state. As native-like contacts form, free energy and conformational entropy both decrease, funneling many parallel trajectories to the folded state rapidly—resolving Levinthal's paradox without requiring a single defined path.
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55A helix differs from an -helix. Which pair of features correctly characterizes the helix relative to the -helix?
Hierarchical Structure of Proteins
Hard
A. hydrogen bonding and 3 residues per turn
B. hydrogen bonding and 3.6 residues per turn
C. hydrogen bonding and 3.6 residues per turn
D. hydrogen bonding and 4.4 residues per turn
Correct Answer: hydrogen bonding and 3 residues per turn
Explanation:
The helix has H-bonds between residue and with exactly 3 residues per turn (the subscript 10 is the number of atoms in the H-bonded ring). The -helix uses bonds with 3.6 residues per turn; the -helix uses .
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56The dihedral angles (about N–C) and (about C–C) define backbone conformation. For an idealized right-handed -helix, which approximate values apply?
Torsional angles in proteins and nucleic acids
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The canonical right-handed -helix has and . Values near correspond to antiparallel -sheet, and the positive pair would give a (rare) left-handed helix.
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57Allosteric regulation is often described by the MWC (concerted) model. A key prediction of the MWC model that distinguishes it from the KNF (sequential) model is that:
Protein Function
Hard
A.All subunits switch conformation simultaneously; the model cannot produce negative cooperativity
B.Negative cooperativity is the primary predicted behavior
C.Ligand binding induces conformational change only in the bound subunit
D.Subunits change conformation one at a time as ligand binds
Correct Answer: All subunits switch conformation simultaneously; the model cannot produce negative cooperativity
Explanation:
In the MWC model the oligomer exists in T and R states in equilibrium, and all subunits switch concertedly (symmetry is preserved), so it predicts only positive cooperativity. The KNF sequential model allows ligand-induced changes in individual subunits and can therefore account for negative cooperativity.
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58A protein has kJ/mol and kJ·mol⁻¹·K⁻¹ for unfolding (assumed T-independent). Estimate its melting temperature (where ).
Protein stability and folding
Hard
A. K
B. K
C. K
D. K
Correct Answer: K
Explanation:
At , , so K (), a typical melting temperature for a mesophilic protein.
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59CD signals arise from differential absorption of left- and right-circularly polarized light by chiral chromophores. In far-UV protein CD, the dominant chromophore giving secondary-structure information is:
Characterization of secondary structure using CD
Hard
A.The -carbon chiral centers directly
B.Disulfide bonds between cysteine residues
C.Aromatic side chains of tryptophan and tyrosine
D.The peptide (amide) bond and transitions
Correct Answer: The peptide (amide) bond and transitions
Explanation:
Far-UV CD (190–250 nm) is dominated by amide backbone transitions: the (~222 nm) and (~190–208 nm). Their exciton coupling in ordered structures produces the characteristic helix/sheet spectra. Aromatic and disulfide chromophores dominate the near-UV region (250–320 nm) reporting tertiary structure.
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60Quaternary structure stabilization frequently relies on buried interface area. In a domain-swapped dimer, the mechanism of oligomerization is best described as:
Hierarchical Structure of Proteins
Hard
A.Covalent crosslinking of subunits via engineered disulfides only
B.Random aggregation driven purely by charge neutralization
C.Formation of a continuous -barrel spanning both subunits with no shared elements
D.Exchange of an equivalent structural element between two monomers to recreate the monomeric fold intermolecularly
Correct Answer: Exchange of an equivalent structural element between two monomers to recreate the monomeric fold intermolecularly
Explanation:
In 3D domain swapping, a segment (e.g., a helix or strand) of one monomer replaces the same segment of a partner monomer, so each subunit's fold is completed by the other. The same interactions present in the monomer are reformed across the interface, making it a specific, native-like association rather than nonspecific aggregation.
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