1The change in Gibbs free energy () for a spontaneous biomolecular process is:
Thermodynamics of biomolecular structures
Easy
A.Negative
B.Positive
C.Zero
D.Always equal to
Correct Answer: Negative
Explanation:
A spontaneous process at constant temperature and pressure has , meaning the free energy of the system decreases.
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2The Gibbs free energy equation is given by:
Thermodynamics of biomolecular structures
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
The Gibbs free energy combines enthalpy and entropy contributions as , where is absolute temperature.
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3In thermodynamics, entropy () is best described as a measure of:
Thermodynamics of biomolecular structures
Easy
A.Energy stored in chemical bonds
B.Total heat content of a system
C.Rate of a chemical reaction
D.Disorder or randomness of a system
Correct Answer: Disorder or randomness of a system
Explanation:
Entropy quantifies the degree of disorder or the number of accessible microstates in a system.
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4Enthalpy () primarily reflects the:
Thermodynamics of biomolecular structures
Easy
A.Heat content of a system
B.Disorder of a system
C.Speed of a reaction
D.Volume of a system
Correct Answer: Heat content of a system
Explanation:
Enthalpy represents the total heat content; measures heat absorbed or released at constant pressure.
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5A process in which heat is released to the surroundings is called:
Thermodynamics of biomolecular structures
Easy
A.Exothermic
B.Endothermic
C.Adiabatic
D.Isothermic
Correct Answer: Exothermic
Explanation:
Exothermic processes release heat and have a negative , while endothermic processes absorb heat.
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6The hydrophobic effect is largely driven by an increase in the entropy of:
Thermodynamics of biomolecular structures
Easy
A.Metal ions
B.Surrounding water molecules
C.Peptide bonds
D.Nonpolar side chains
Correct Answer: Surrounding water molecules
Explanation:
When nonpolar groups cluster, ordered water shells are released, increasing water entropy and favoring the folded state.
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7At equilibrium, the change in Gibbs free energy () is:
Thermodynamics of biomolecular structures
Easy
A.Infinite
B.Negative
C.Positive
D.Zero
Correct Answer: Zero
Explanation:
At equilibrium there is no net driving force for change, so .
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8Which type of interaction stabilizes biomolecular structures without involving covalent bonds?
Thermodynamics of biomolecular structures
Easy
A.Ester bonds
B.Hydrogen bonds
C.Peptide bonds
D.Disulfide bonds
Correct Answer: Hydrogen bonds
Explanation:
Hydrogen bonds are non-covalent interactions that help stabilize secondary and tertiary structures of biomolecules.
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9According to Anfinsen's principle, the native structure of a protein is determined by its:
Protein folding: thermodynamics and kinetics
Easy
A.Amino acid sequence
B.Molecular weight
C.Number of disulfide bonds
D.Isoelectric point
Correct Answer: Amino acid sequence
Explanation:
Anfinsen's experiments showed that the primary sequence contains all information needed to fold into the native structure.
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10The native folded state of a protein generally corresponds to the state of:
Protein folding: thermodynamics and kinetics
Easy
A.Highest entropy
B.Highest free energy
C.Maximum surface area
D.Lowest free energy
Correct Answer: Lowest free energy
Explanation:
Under physiological conditions, the native conformation is typically the thermodynamically most stable, lowest free energy state.
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11Levinthal's paradox highlights that proteins cannot fold by:
Protein folding: thermodynamics and kinetics
Easy
A.Following a defined folding pathway
B.Forming secondary structures
C.Randomly sampling all possible conformations
D.Using molecular chaperones
Correct Answer: Randomly sampling all possible conformations
Explanation:
Random sampling of all conformations would take astronomically long, so folding must follow guided pathways or energy landscapes.
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12The energy landscape of protein folding is often described as shaped like a:
Protein folding: thermodynamics and kinetics
Easy
A.Flat plane
B.Sphere
C.Straight line
D.Funnel
Correct Answer: Funnel
Explanation:
The folding funnel model depicts many high-energy unfolded states narrowing toward the low-energy native state at the bottom.
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13Molecular chaperones assist protein folding by:
Protein folding: thermodynamics and kinetics
Easy
A.Changing the amino acid sequence
B.Preventing improper aggregation
C.Adding new peptide bonds
D.Increasing protein molecular weight
Correct Answer: Preventing improper aggregation
Explanation:
Chaperones help proteins fold correctly and prevent misfolding and aggregation, without altering the final native structure.
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14The process by which a protein loses its native structure is called:
Protein folding: thermodynamics and kinetics
Easy
A.Hydration
B.Translation
C.Denaturation
D.Transcription
Correct Answer: Denaturation
Explanation:
Denaturation is the disruption of a protein's higher-order structure, often by heat, pH, or chemical agents.
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15A partially folded intermediate that forms rapidly during folding and has a compact but flexible structure is called a:
Protein folding: thermodynamics and kinetics
Easy
A.Random coil
B.Crystal
C.Fibril
D.Molten globule
Correct Answer: Molten globule
Explanation:
The molten globule is a compact intermediate with native-like secondary structure but loosely packed side chains.
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16Which factor commonly causes protein denaturation?
Protein folding: thermodynamics and kinetics
Easy
A.Normal physiological pH
B.Increased chaperone levels
C.Low salt gradient
D.High temperature
Correct Answer: High temperature
Explanation:
Elevated temperature disrupts non-covalent interactions that maintain protein structure, leading to unfolding.
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17The specific region of an enzyme where the substrate binds is called the:
Functional Design of Proteins
Easy
A.Allosteric loop
B.Active site
C.Terminal domain
D.Signal peptide
Correct Answer: Active site
Explanation:
The active site is the pocket where substrate binding and catalysis occur, shaped by the protein's folded structure.
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18A distinct, independently folding structural unit within a protein is known as a:
Functional Design of Proteins
Easy
A.Ribosome
B.Codon
C.Nucleotide
D.Domain
Correct Answer: Domain
Explanation:
A domain is a compact, semi-independent folding unit that often carries out a specific function within a protein.
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19In allosteric regulation, a molecule binds at a site other than the active site and alters protein:
Functional Design of Proteins
Easy
A.Amino acid sequence
B.Molecular weight
C.Activity
D.Number of domains
Correct Answer: Activity
Explanation:
Allosteric effectors bind at regulatory sites and change the protein's conformation, thereby modulating its activity.
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20The specificity of an enzyme for its substrate is often explained by which model?
Functional Design of Proteins
Easy
A.Random collision model
B.Sliding filament model
C.Lock and key model
D.Funnel model
Correct Answer: Lock and key model
Explanation:
The lock and key model describes how the active site's shape is complementary to a specific substrate, providing specificity.
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21The Gibbs free energy change for a folding reaction is given by . For a protein that folds spontaneously at with and , what is the approximate ?
Thermodynamics of biomolecular structures
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Using : . The negative value confirms spontaneous folding.
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22The hydrophobic effect, a major driving force in biomolecular folding, is primarily entropy-driven at room temperature because:
Thermodynamics of biomolecular structures
Medium
A.Hydrogen bonds between water molecules are broken releasing heat
B.Water molecules gain entropy when ordered cages around nonpolar groups are released
C.Nonpolar side chains form strong covalent bonds when buried
D.The protein backbone gains rotational freedom upon burial of side chains
Correct Answer: Water molecules gain entropy when ordered cages around nonpolar groups are released
Explanation:
Nonpolar surfaces force surrounding water into ordered clathrate-like structures. Burying these groups releases the ordered water, increasing solvent entropy and favoring folding.
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23At the melting temperature of a protein, which thermodynamic condition holds true?
Thermodynamics of biomolecular structures
Medium
A. and the folded and unfolded states are equally populated
B. is at its maximum negative value
C. because no heat is exchanged
D. because both states have equal disorder
Correct Answer: and the folded and unfolded states are equally populated
Explanation:
At , the equilibrium constant equals 1, so . The folded and unfolded populations are equal.
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24For a two-state folding equilibrium with an equilibrium constant favoring the folded state at , the free energy of folding is approximately:
Thermodynamics of biomolecular structures
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
.
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25Cold denaturation of proteins, observed at low temperatures, is best explained by which thermodynamic feature?
Thermodynamics of biomolecular structures
Medium
A.A negative enthalpy of unfolding at all temperatures
B.The absence of any entropy contribution at low temperature
C.A temperature-independent Gibbs free energy of folding
D.A large positive heat capacity change () upon unfolding
Correct Answer: A large positive heat capacity change () upon unfolding
Explanation:
The large positive makes of folding a downward-curving parabola in , so stability decreases at both high and low temperatures, causing cold denaturation.
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26The large positive change in heat capacity () upon protein unfolding is primarily attributed to:
Thermodynamics of biomolecular structures
Medium
A.Loss of disulfide bonds in the unfolded state
B.Exposure of buried hydrophobic surfaces to water
C.Formation of new backbone hydrogen bonds
D.Increased vibrational modes of the alpha helix
Correct Answer: Exposure of buried hydrophobic surfaces to water
Explanation:
When hydrophobic groups become solvent-exposed, they order surrounding water, which has a high heat capacity. The amount of newly exposed nonpolar surface correlates strongly with .
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27A protein's stability ( of unfolding) is measured as . What does this indicate about the native state?
Thermodynamics of biomolecular structures
Medium
A.The unfolded state is thermodynamically favored
B.The native state is marginally more stable than the unfolded state
C.The native and unfolded states are equally stable
D.The protein cannot fold spontaneously
Correct Answer: The native state is marginally more stable than the unfolded state
Explanation:
A positive of unfolding means energy is required to unfold, so the native state is more stable. The relatively small magnitude reflects the marginal stability typical of proteins.
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28The Levinthal paradox highlights that:
Protein folding: thermodynamics and kinetics
Medium
A.Proteins fold instantaneously regardless of size
B.Folding is purely determined by kinetic traps
C.A random search of all conformations would take longer than the age of the universe, so folding must be directed
D.The native state is never the global free energy minimum
Correct Answer: A random search of all conformations would take longer than the age of the universe, so folding must be directed
Explanation:
Levinthal noted that sampling every possible conformation randomly is impossibly slow. Since proteins fold in milliseconds to seconds, folding follows guided pathways or funnels rather than random search.
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29In the energy landscape (funnel) model of protein folding, the depth of the funnel represents __ and the width represents __.
Protein folding: thermodynamics and kinetics
Medium
The vertical axis of the folding funnel is free energy (lowest at the native state), while the width reflects conformational entropy (many disordered states at the top, few near the bottom).
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30According to Anfinsen's thermodynamic hypothesis, the native conformation of a protein is determined by:
Protein folding: thermodynamics and kinetics
Medium
A.The order in which it was synthesized on the ribosome
B.The chaperones present during folding
C.Random kinetic trapping during synthesis
D.Its amino acid sequence, corresponding to the global free energy minimum
Correct Answer: Its amino acid sequence, corresponding to the global free energy minimum
Explanation:
Anfinsen's ribonuclease experiments showed that denatured protein refolds to the native state spontaneously, demonstrating the native structure is encoded in the sequence as the thermodynamic minimum.
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31A molten globule folding intermediate is characterized by:
Protein folding: thermodynamics and kinetics
Medium
A.Covalently modified backbone stabilizing the fold
B.Complete absence of secondary structure
C.Fully formed tertiary structure with rigid side-chain packing
D.Native-like secondary structure but loosely packed, fluctuating tertiary structure
The molten globule retains substantial secondary structure and a compact shape but lacks the tightly packed, specific side-chain interactions of the native state.
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32In a -value analysis of folding, a -value close to 1 for a given residue indicates that:
Protein folding: thermodynamics and kinetics
Medium
A.The residue's native interactions are already formed in the transition state
B.The residue has no role in folding
C.The residue is fully unstructured in the transition state
D.The residue destabilizes the native state
Correct Answer: The residue's native interactions are already formed in the transition state
Explanation:
-value analysis compares mutation effects on folding kinetics and stability. A value near 1 means the mutated residue's native contacts are present in the transition state; near 0 means they are absent.
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33Molecular chaperones such as GroEL/GroES assist folding by:
Protein folding: thermodynamics and kinetics
Medium
A.Providing an isolated environment that prevents aggregation and allows productive folding
B.Directly determining the final tertiary structure independent of sequence
C.Covalently linking the protein to speed up folding
D.Lowering the thermodynamic stability of the native state
Correct Answer: Providing an isolated environment that prevents aggregation and allows productive folding
Explanation:
Chaperones do not dictate the native fold (still sequence-determined) but shield folding intermediates in an enclosed chamber, preventing off-pathway aggregation and giving the protein chances to fold correctly.
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34A folding reaction with a rate constant that increases as denaturant concentration decreases suggests that the transition state is:
Protein folding: thermodynamics and kinetics
Medium
A.Identical in solvent exposure to the unfolded state
B.Independent of denaturant entirely
C.More compact (buries surface) relative to the unfolded state
D.Fully solvent-exposed like the denatured state
Correct Answer: More compact (buries surface) relative to the unfolded state
Explanation:
Denaturants stabilize exposed surfaces. If lowering denaturant speeds folding, the transition state buries more surface than the unfolded state, meaning it is partially compact.
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35Which statement correctly distinguishes the thermodynamics from the kinetics of protein folding?
Protein folding: thermodynamics and kinetics
Medium
A.Thermodynamics governs folding speed; kinetics governs final stability
B.Thermodynamics governs which state is most stable; kinetics governs how fast it is reached
C.Both determine only the final structure
D.Both determine only the folding rate
Correct Answer: Thermodynamics governs which state is most stable; kinetics governs how fast it is reached
Explanation:
Thermodynamics predicts the equilibrium (most stable) state via , while kinetics describes the rate and pathway to reach that state via activation barriers.
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36The concept of 'marginal stability' in functional proteins is important because:
Functional Design of Proteins
Medium
A.It prevents any allosteric transitions
B.It maximizes the number of disulfide bonds
C.It allows the conformational flexibility needed for function and regulation
D.It ensures proteins never unfold under any condition
Correct Answer: It allows the conformational flexibility needed for function and regulation
Explanation:
Proteins are only marginally stable (often 20–60 kJ/mol) so they can undergo conformational changes, be regulated, and be degraded when needed. Excess rigidity would impair function.
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37Enzymes accelerate reactions primarily by:
Functional Design of Proteins
Medium
A.Lowering the activation free energy by stabilizing the transition state
B.Increasing the free energy difference between products and reactants
C.Changing the equilibrium constant of the reaction
D.Providing energy that shifts to negative values
Correct Answer: Lowering the activation free energy by stabilizing the transition state
Explanation:
Enzymes bind and stabilize the transition state, lowering the activation barrier and increasing rate. They do not alter the overall or the equilibrium position.
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38In an allosteric protein displaying positive cooperativity, binding of a ligand to one subunit:
Functional Design of Proteins
Medium
A.Permanently locks the protein in one conformation
B.Has no effect on other subunits
C.Decreases the affinity of the remaining subunits
D.Increases the binding affinity of the remaining subunits
Correct Answer: Increases the binding affinity of the remaining subunits
Explanation:
Positive cooperativity means the first binding event favors the high-affinity conformation, raising affinity at the other sites. This produces the characteristic sigmoidal binding curve, as in hemoglobin.
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39The functional design principle that binding energy is used to lower the activation barrier rather than to maximize substrate affinity explains why enzymes:
Functional Design of Proteins
Medium
A.Avoid binding the transition state to prevent inhibition
B.Bind substrate as tightly as possible in the ground state
C.Release product very slowly to increase specificity
D.Bind the transition state more tightly than the substrate itself
Correct Answer: Bind the transition state more tightly than the substrate itself
Explanation:
Optimal catalysis requires preferential binding of the transition state over the ground-state substrate. Overly tight substrate binding would create a deep well that hinders reaching the transition state.
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40The coupling of an energetically unfavorable conformational change to a favorable ligand-binding event in a functional protein is an example of:
Functional Design of Proteins
Medium
A.An irreversible covalent modification
B.Violation of the second law of thermodynamics
C.A purely kinetic phenomenon with no free energy change
D.Thermodynamic coupling that makes the overall process spontaneous
Correct Answer: Thermodynamic coupling that makes the overall process spontaneous
Explanation:
When two processes are coupled, their free energy changes add. A favorable binding can drive an unfavorable conformational change if the sum is negative, keeping the overall process spontaneous.
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41For a two-state protein unfolding transition, . At the melting temperature K, if kJ/mol, what is the value of ?
Thermodynamics of biomolecular structures
Hard
A. J/mol·K
B. J/mol·K
C. J/mol·K
D. J/mol·K
Correct Answer: J/mol·K
Explanation:
At , , so J/mol·K.
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42The hydrophobic effect driving biomolecular folding is dominated at physiological temperatures primarily by which thermodynamic feature?
Thermodynamics of biomolecular structures
Hard
A.A large positive entropy change of water released from ordered clathrate cages upon burial of nonpolar surface
B.A large favorable enthalpy from van der Waals contacts between buried side chains that overwhelms all entropic contributions
C.A decrease in the conformational entropy of the polypeptide backbone
D.A negative heat capacity change arising solely from newly formed hydrogen bonds in the folded core
Correct Answer: A large positive entropy change of water released from ordered clathrate cages upon burial of nonpolar surface
Explanation:
At room/physiological temperature the hydrophobic effect is entropically driven: burying nonpolar groups releases structured water, increasing solvent entropy. The large positive signature reflects this.
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43A positive heat capacity change () accompanies protein unfolding. Which consequence does this have for the stability curve ?
Thermodynamics of biomolecular structures
Hard
A.It makes increase linearly and without limit as temperature rises
B.It ensures the protein is most stable at K
C.It produces a curved (parabolic) stability profile with both a cold- and heat-denaturation temperature
D.It eliminates any temperature of maximum stability
Correct Answer: It produces a curved (parabolic) stability profile with both a cold- and heat-denaturation temperature
Explanation:
A nonzero makes and temperature-dependent, giving a downward-curving parabola that crosses zero twice—predicting both cold and heat denaturation.
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44Using the Gibbs–Helmholtz relation, if a protein has kJ/mol at K and kJ/mol·K, what is the approximate of unfolding at K?
Thermodynamics of biomolecular structures
Hard
A. kJ/mol
B. kJ/mol
C. kJ/mol
D. kJ/mol
Correct Answer: kJ/mol
Explanation:
Using : first term ; second term ; sum kJ/mol, positive so folded state is stable.
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45According to the 'new view' of protein folding, the folding energy landscape is best described as:
Protein folding: thermodynamics and kinetics
Hard
A.A rugged funnel where the native state occupies the global minimum and many pathways converge toward it
B.A single narrow pathway with one obligatory intermediate that every molecule must traverse
C.A perfectly smooth golf-course surface with a random search to the native hole
D.A flat surface where all conformations are isoenergetic until the last step
Correct Answer: A rugged funnel where the native state occupies the global minimum and many pathways converge toward it
Explanation:
The funnel model resolves the Levinthal paradox: the biased, funnel-shaped landscape guides many parallel trajectories downhill in free energy toward the native minimum, with ruggedness producing kinetic traps.
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46The Levinthal paradox argues that a protein cannot fold by random search because:
Protein folding: thermodynamics and kinetics
Hard
A.Random search is thermodynamically forbidden by the second law
B.The native state is not the lowest-energy conformation
C.The astronomical number of possible conformations would require timescales far exceeding the age of the universe
D.Peptide bonds cannot rotate fast enough to sample conformations
Correct Answer: The astronomical number of possible conformations would require timescales far exceeding the age of the universe
Explanation:
Sampling all conformations sequentially (e.g., states) at picosecond rates would take longer than cosmological time, yet proteins fold in milliseconds to seconds—so folding must be directed, not random.
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47A -value analysis yields for a specific residue. This indicates that in the transition state, the residue's structure is:
Protein folding: thermodynamics and kinetics
Hard
A.Involved exclusively in nonspecific hydrophobic collapse
B.Completely unstructured and native-like only after the rate-limiting step
C.Destabilizing to the transition state relative to the native state
D.Nearly as native-like as in the folded state, forming early in the folding pathway
Correct Answer: Nearly as native-like as in the folded state, forming early in the folding pathway
Explanation:
-value means the mutation affects the transition state and native state almost equally, implying that residue's native contacts are already formed in the transition state (a folding nucleus).
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48In a chevron plot ( vs. denaturant concentration), a pronounced downward 'rollover' at low denaturant most commonly indicates:
Protein folding: thermodynamics and kinetics
Hard
A.An error in the spectroscopic baseline
B.Complete loss of cooperativity and unfolding
C.Accumulation of a folding intermediate that changes the rate-limiting step
D.Perfect two-state folding with no intermediates
Correct Answer: Accumulation of a folding intermediate that changes the rate-limiting step
Explanation:
A linear V-shaped chevron signals two-state kinetics; curvature (rollover) in the folding arm reveals a populated intermediate or movement of the transition state, breaking the simple two-state model.
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49For a two-state folder, is kJ/mol and kJ/mol at K. What fraction of molecules is in the unfolded state at equilibrium?
Protein folding: thermodynamics and kinetics
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
. Since this is tiny, fraction unfolded .
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50Which statement about the role of molecular chaperones (e.g., GroEL/GroES) in folding thermodynamics is correct?
Protein folding: thermodynamics and kinetics
Hard
A.They do not alter the native state's free-energy minimum but lower kinetic barriers and prevent off-pathway aggregation
B.They covalently modify substrates to lock in the folded conformation
C.They shift the equilibrium by making the native state thermodynamically more stable than in their absence
D.They supply the free energy that makes folding thermodynamically favorable
Correct Answer: They do not alter the native state's free-energy minimum but lower kinetic barriers and prevent off-pathway aggregation
Explanation:
Chaperones act kinetically: they sequester folding intermediates, prevent aggregation, and give molecules more chances to reach the native state, but the native structure remains encoded by sequence and its thermodynamic stability is unchanged.
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51Cold denaturation of proteins occurs because at low temperature:
Protein folding: thermodynamics and kinetics
Hard
A.Water becomes a better solvent for the folded core through increased enthalpy
B.Hydrogen bonds spontaneously break due to increased thermal motion
D.The hydrophobic effect weakens as the entropic penalty of solvating nonpolar groups diminishes, destabilizing the folded state
Correct Answer: The hydrophobic effect weakens as the entropic penalty of solvating nonpolar groups diminishes, destabilizing the folded state
Explanation:
The temperature dependence of (from ) means at low the hydrophobic driving force weakens; the enthalpic cost of exposing nonpolar surface can exceed the entropic benefit of folding, so the protein unfolds upon cooling.
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52The Eyring/transition-state expression predicts that if the folding activation free energy decreases by , the folding rate will:
Protein folding: thermodynamics and kinetics
Hard
A.Remain unchanged
B.Increase by a factor of
C.Increase by a factor of
D.Decrease by a factor of
Correct Answer: Increase by a factor of
Explanation:
A decrease of by gives -fold enhancement of the exponential term, so the rate rises tenfold.
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53The two-state assumption for a folding transition is most rigorously validated when:
Protein folding: thermodynamics and kinetics
Hard
A.The melting temperature is above °C
B.The van't Hoff enthalpy from the transition curve equals the calorimetric enthalpy measured by DSC
C.The unfolding is irreversible under all conditions
D.The protein has a single tryptophan residue
Correct Answer: The van't Hoff enthalpy from the transition curve equals the calorimetric enthalpy measured by DSC
Explanation:
A ratio indicates a single cooperative unit with no populated intermediates—the hallmark of true two-state behavior. Deviations reveal intermediates or oligomerization.
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54Many enzymes are only marginally stable (– kJ/mol). The prevailing functional rationale is that:
Functional Design of Proteins
Hard
A.Marginal stability maximizes the melting temperature
B.Highly stable proteins cannot form peptide bonds during synthesis
C.Stability is irrelevant because enzymes function only in the unfolded state
D.Marginal stability provides the conformational flexibility required for catalysis, allostery, and regulated turnover
Correct Answer: Marginal stability provides the conformational flexibility required for catalysis, allostery, and regulated turnover
Explanation:
Function requires dynamics: substrate binding, conformational changes, and controlled degradation all benefit from a native state that is stable enough to fold but flexible enough to move—hence proteins are typically only marginally stable.
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55Enzymes achieve rate enhancement primarily by:
Functional Design of Proteins
Hard
A.Preferentially binding and stabilizing the transition state, thereby lowering
B.Increasing the equilibrium constant of the overall reaction beyond its thermodynamic value
C.Raising the substrate's ground-state free energy to make it inherently reactive
D.Supplying additional Gibbs free energy directly to the substrate
Correct Answer: Preferentially binding and stabilizing the transition state, thereby lowering
Explanation:
Catalysts lower activation barriers without altering the overall or . Enzymes bind the transition state more tightly than substrate, reducing and accelerating both forward and reverse rates equally.
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56In a thermodynamic linkage (allosteric) scheme, if ligand binding at site 1 increases the affinity for a ligand at site 2, then by the principle of reciprocity:
B.Ligand binding at site 2 must decrease the affinity at site 1
C.Ligand binding at site 2 must equally increase the affinity for the ligand at site 1
D.The coupling free energy must be zero
Correct Answer: Ligand binding at site 2 must equally increase the affinity for the ligand at site 1
Explanation:
Thermodynamic linkage is reciprocal: the coupling free energy between two sites is symmetric, so cooperativity observed in one direction is quantitatively mirrored in the reverse direction.
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57The cooperative binding of oxygen to hemoglobin is best captured thermodynamically by which concept?
Functional Design of Proteins
Hard
A.A single-site hyperbolic binding isotherm with no inter-subunit communication
B.Independent binding at all four sites with identical microscopic constants
C.Irreversible covalent bonding of to the iron centers
D.Positive coupling free energy between subunits that shifts the population from a low-affinity (T) to a high-affinity (R) state
Correct Answer: Positive coupling free energy between subunits that shifts the population from a low-affinity (T) to a high-affinity (R) state
Explanation:
Cooperativity arises from allosteric coupling: binding at one heme raises the affinity of others via the T→R quaternary transition, producing the sigmoidal binding curve rather than a hyperbolic one.
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58A designed protein with maximized thermodynamic stability but a rigid, fully packed core is often catalytically inactive because:
Functional Design of Proteins
Hard
A.A packed core cannot form disulfide bonds
B.High stability abolishes the peptide backbone hydrogen bonds
C.Increased stability prevents the protein from ever folding
D.Excessive rigidity suppresses the conformational motions needed for substrate binding and turnover
Correct Answer: Excessive rigidity suppresses the conformational motions needed for substrate binding and turnover
Explanation:
There is a stability–function tradeoff: over-optimizing packing/stability removes the dynamic flexibility (breathing motions, induced fit) essential for catalysis, so hyperstable designs frequently lose activity.
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59For the coupled reaction ATP hydrolysis ( kJ/mol) driving an unfavorable step with kJ/mol, the overall standard free energy of the coupled process is:
Functional Design of Proteins
Hard
A. kJ/mol, requiring additional input
B. kJ/mol, making it strongly nonspontaneous
C. kJ/mol, releasing all the energy as heat
D. kJ/mol, making the coupled reaction spontaneous
Correct Answer: kJ/mol, making the coupled reaction spontaneous
Explanation:
Coupling adds the free energies: kJ/mol. The favorable hydrolysis drives the unfavorable step, giving a net negative and a spontaneous coupled reaction.
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60Intrinsically disordered proteins (IDPs) challenge the classical structure–function paradigm because they:
Functional Design of Proteins
Hard
A.Cannot bind any ligand due to lack of a defined pocket
B.Perform function while remaining unfolded, often folding only upon binding a partner (coupled folding-binding)
C.Are thermodynamically identical to globular proteins in every property
D.Always aggregate irreversibly and are therefore nonfunctional
Correct Answer: Perform function while remaining unfolded, often folding only upon binding a partner (coupled folding-binding)
Explanation:
IDPs lack a fixed native fold yet are functional; many undergo disorder-to-order transitions upon partner binding, trading conformational entropy for binding enthalpy, which enables high specificity with tunable (often low) affinity.
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