Unit 5: Interpolation, Differentiation and Integration - Subjective Questions
ECE183 — Mathematics For Robotics • Practice Questions with Detailed Answers
20 questions
Define interpolation. Explain its purpose in numerical analysis and discuss two practical applications of interpolation in robotics.
Interpolation is the process of estimating the value of a function at an intermediate point using a set of known data points.
If the known data are , interpolation constructs a function such that
Purpose:
- It estimates unknown values between measured or tabulated values.
- It replaces a complicated function with a simpler polynomial.
- It is useful when the analytical form of a function is unavailable.
Applications in robotics:
- Estimating robot joint positions between sampled time instants.
- Generating smooth trajectories for the position, velocity, and orientation of a robot manipulator.
- Approximating sensor data and calibration curves.
Derive Newton's divided-difference interpolating polynomial for data points , , and .
For three data points, assume a polynomial of the form
Using gives
Using gives
Using gives
Therefore, Newton's divided-difference polynomial is
The divided differences are defined by
and
Explain the construction of a divided-difference table and state how it is used to form Newton's interpolating polynomial.
A divided-difference table is constructed in successive columns.
For data , the first divided differences are
Higher-order divided differences are calculated using
The table has the following general structure:
- First column: values.
- Second column: function values .
- Third column: first divided differences.
- Fourth column: second divided differences.
- Subsequent columns: higher-order divided differences.
The first entry of each divided-difference column becomes a coefficient in Newton's polynomial:
This form is computationally convenient because a new data point can be added without completely recalculating the existing polynomial.
Using Newton's divided-difference method, find the interpolating polynomial for the points , , and .
The data points are , , and .
The first divided differences are
The second divided difference is
Newton's polynomial is therefore
On simplifying,
Thus, the interpolating polynomial is
Verification:
- .
- .
- .
State and explain the Lagrange interpolating polynomial for data points.
For distinct data points , the Lagrange interpolating polynomial is
where the Lagrange basis polynomial is
Each basis polynomial has the property
Therefore, at ,
Advantages:
- It gives a direct formula for interpolation.
- It does not require a divided-difference table.
- It is suitable for a small number of data points.
Limitation: If a new data point is added, the entire expression generally has to be reconstructed.
Derive the quadratic Lagrange interpolation formula for three points , , and .
For three points, construct three basis polynomials:
The quadratic interpolating polynomial is
Hence,
At each data point, one basis polynomial becomes and the others become , so the polynomial passes through all three points.
Compare Newton's divided-difference interpolation method with Lagrange interpolation.
Both methods produce the unique polynomial of degree at most passing through distinct data points, but their computational forms differ.
| Feature | Newton divided difference | Lagrange method |
|---|---|---|
| Form | Nested or progressive polynomial | Sum of basis polynomials |
| Main computation | Divided-difference table | Lagrange basis functions |
| Adding a point | Relatively easy; add a new term | Usually requires recomputation |
| Numerical implementation | Efficient in incremental form | Direct but may involve more products |
| Interpretation | Coefficients are divided differences | Coefficients are weighted function values |
Newton's form is
Lagrange's form is
Conclusion: Lagrange interpolation is convenient for a fixed small data set, whereas Newton interpolation is preferable when data points may be added successively.
Derive Newton's forward interpolating formula for equally spaced data points.
Let the data points be equally spaced with spacing , and define
For equally spaced data, the divided differences can be expressed in terms of forward differences. The Newton forward interpolation formula is
In general,
Here:
- is the first forward difference.
- is the second forward difference.
- is the uniform interval between successive values of .
- The formula is most accurate when is near the beginning of the table.
Explain Newton's backward interpolating formula and identify the situations in which it is preferred.
Newton's backward formula is used for equally spaced data when the required value of lies near the end of the tabulated interval. Define
where is the last tabulated value and is the equal spacing.
The formula is
In general,
Here, the backward difference operator is defined by
It is preferred when:
- The data points are equally spaced.
- The interpolation point is close to the last entry in the table.
- Backward differences near the end of the table are easier to calculate than forward differences near the beginning.
Distinguish between Newton's forward and backward interpolation formulas.
The main differences are as follows:
| Aspect | Newton forward formula | Newton backward formula |
|---|---|---|
| Reference point | First point | Last point |
| Parameter | ||
| Difference operator | Forward difference | Backward difference |
| Best location | Near the beginning of the table | Near the end of the table |
| First terms | and | and |
The forward formula is
whereas the backward formula is
Both require equally spaced values of and represent the same interpolating polynomial when all terms are retained.
Using Newton's forward interpolation formula, estimate from the data , , and .
The spacing is , and choose . Thus,
The forward-difference table is:
- , , .
- .
- .
- .
Using the quadratic forward formula,
we obtain
Therefore,
Hence, the estimated value is
Define numerical integration and explain why it is important in robotics.
Numerical integration is the process of approximating a definite integral using a finite number of function values.
For a function , the integral
may be difficult or impossible to evaluate analytically. Numerical integration replaces the function by an approximating polynomial or geometric shape and integrates that approximation.
Importance in robotics:
- Computing displacement from velocity data:
- Computing robot joint position from measured angular velocity.
- Estimating energy or work from force and displacement data.
- Integrating equations of motion in robot simulation.
- Processing sampled sensor data when only discrete measurements are available.
Common methods include the trapezoidal rule and Simpson's rules.
Explain the Newton-Cotes formulae and distinguish between the closed and open forms.
Newton-Cotes formulae approximate a definite integral by replacing the function with an interpolation polynomial constructed at equally spaced points.
If the interval is divided into equal subintervals, the integral is approximated by
where is an interpolation polynomial.
Closed Newton-Cotes formulae:
- Include both endpoints and .
- Use points such as and .
- The trapezoidal rule and Simpson's rules are closed formulas.
Open Newton-Cotes formulae:
- Do not include the endpoints.
- Use interior points only.
- They can be useful when the function is undefined or difficult to evaluate at an endpoint.
For equally spaced points, the general approximation has the form
where is the spacing and are Newton-Cotes weights.
Derive the composite trapezoidal rule from linear interpolation.
Consider two adjacent points and , where
The linear interpolating polynomial between the points is
Integrating from to gives
For equal subintervals, summing all individual trapezoids gives
where
The composite trapezoidal rule gives greater accuracy than a single trapezoid because it uses several smaller intervals.
State the trapezoidal rule, derive its error term, and explain the effect of decreasing the step size.
For one interval , the trapezoidal rule is
For equal subintervals, with , the composite rule is
If has a continuous second derivative, the composite truncation error is
for some .
Therefore, the error is of order . If the step size is reduced by half, the approximate error is reduced by a factor of four, provided the function is sufficiently smooth.
The rule is exact for all polynomials of degree one or less.
Apply the composite trapezoidal rule with to approximate .
Given
we have
The function values are
Using the composite trapezoidal rule,
Substitution gives
Thus,
Therefore,
The exact value is , so the trapezoidal rule overestimates this convex function.
Derive Simpson's rule using a quadratic interpolating polynomial.
Consider three equally spaced points , , and . A quadratic polynomial is fitted through the function values , , and .
Using a local coordinate centered at , let . The three points correspond to . The quadratic interpolation formula is
Integrating from to gives
After integration,
This is Simpson's rule. It is exact for polynomials of degree three or less, even though it is derived from a quadratic interpolating polynomial.
State the composite Simpson's rule and specify the condition on the number of subintervals.
For equal subintervals, where is even, define
The composite Simpson's rule is
The weights follow the pattern
Condition: The number of subintervals must be even because Simpson's rule applies a quadratic approximation over pairs of subintervals.
For two subintervals, the formula reduces to
Apply Simpson's rule to approximate using subintervals.
Here,
The step size is
The function values are
Using the composite Simpson's rule,
Therefore,
Thus,
Hence,
Since Simpson's rule is exact for cubic polynomials, the exact integral is also .
Derive the error term for Simpson's rule and state its order of accuracy.
For one application of Simpson's rule over two subintervals of width ,
If has a continuous fourth derivative, the truncation error is
for some .
For the composite Simpson's rule over with even and , the error is
Thus, Simpson's rule has order , whereas the composite trapezoidal rule has order .
The rule is exact for polynomials of degree three or less, because their fourth derivative is zero.
Define interpolation. Explain its purpose in numerical analysis and discuss two practical applications of interpolation in robotics.
Interpolation is the process of estimating the value of a function at an intermediate point using a set of known data points.
If the known data are , interpolation constructs a function such that
Purpose:
- It estimates unknown values between measured or tabulated values.
- It replaces a complicated function with a simpler polynomial.
- It is useful when the analytical form of a function is unavailable.
Applications in robotics:
- Estimating robot joint positions between sampled time instants.
- Generating smooth trajectories for the position, velocity, and orientation of a robot manipulator.
- Approximating sensor data and calibration curves.
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