1Which of the following conditions is necessary for Ohm’s Law to be valid?
A.Temperature must vary linearly
B.Temperature and physical dimensions must remain constant
C.Voltage must be inversely proportional to current
D.The circuit must contain active elements only
Correct Answer: Temperature and physical dimensions must remain constant
Explanation:Ohm's Law states that provided that physical conditions, such as temperature and dimensions of the conductor, remain constant.
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2Mathematically, Ohm's law is expressed as:
A.
B.
C.
D.
Correct Answer:
Explanation:According to Ohm's law, Voltage () equals the product of Current () and Resistance ().
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3Ohm’s law is not applicable to which of the following?
A.Copper wire
B.Aluminum resistor
C.Semiconductor diode
D.Filament lamp at constant temperature
Correct Answer: Semiconductor diode
Explanation:Ohm's law applies to linear bilateral elements. A semiconductor diode is a non-linear device; its V-I characteristic is not a straight line passing through the origin.
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4If the voltage across a resistor is doubled while the resistance remains constant, the current will:
A.Remain the same
B.Be halved
C.Double
D.Quadruple
Correct Answer: Double
Explanation:Since , if becomes and is constant, the new current .
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5Kirchhoff’s Current Law (KCL) is based on the principle of conservation of:
A.Energy
B.Charge
C.Momentum
D.Voltage
Correct Answer: Charge
Explanation:KCL states that the algebraic sum of currents at a node is zero, which implies that charge cannot accumulate at a node, reflecting the law of conservation of charge.
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6According to Kirchhoff’s Voltage Law (KVL), the algebraic sum of voltage drops and EMFs in a closed loop is:
A.Equal to the current
B.Equal to the resistance
C.Zero
D.Infinite
Correct Answer: Zero
Explanation:KVL states that in a closed loop, meaning the sum of voltage rises equals the sum of voltage drops.
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7Kirchhoff’s Voltage Law (KVL) deals with the conservation of:
A.Charge
B.Energy
C.Current
D.Power
Correct Answer: Energy
Explanation:Since voltage is energy per unit charge (), summing voltages to zero in a loop means no energy is created or destroyed, satisfying the conservation of energy.
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8In a node where 3 currents enter () and 2 currents leave (), the KCL equation is:
A.
B.
C.
D.
Correct Answer:
Explanation:KCL states: Sum of entering currents = Sum of leaving currents.
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9Two resistors and are connected in series across a voltage source . The voltage across is given by:
A.
B.
C.
D.
Correct Answer:
Explanation:This is the Voltage Division Rule. The voltage across a specific resistor in a series circuit is proportional to its resistance relative to the total resistance.
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10The current division rule is applicable to circuits consisting of resistors connected in:
A.Series
B.Parallel
C.Star
D.Delta
Correct Answer: Parallel
Explanation:In a parallel circuit, the current splits between branches inversely proportional to the resistance of the branches.
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11Two resistors and are connected in parallel with a total current entering the combination. The current through is:
A.
B.
C.
D.
Correct Answer:
Explanation:According to the Current Division Rule, the current through one branch is the total current multiplied by the resistance of the opposite branch divided by the sum of resistances.
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12Which of the following materials is a semiconductor?
A.Copper
B.Silicon
C.Plastic
D.Gold
Correct Answer: Silicon
Explanation:Silicon and Germanium are the most common semiconductor materials used in electronics. Copper/Gold are conductors; Plastic is an insulator.
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13At absolute zero temperature (), an intrinsic semiconductor acts as:
A.A perfect conductor
B.A perfect insulator
C.A superconductor
D.A semiconductor
Correct Answer: A perfect insulator
Explanation:At , there is no thermal energy to break covalent bonds, so the valence band is full and the conduction band is empty, making it an insulator.
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14The energy band gap () for Silicon at room temperature is approximately:
A.
B.
C.
D.
Correct Answer:
Explanation:The forbidden energy gap between the valence and conduction band for Silicon is roughly (and for Germanium).
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15In an intrinsic semiconductor, the number of free electrons () and holes () are related as:
A.
B.
C.
D.
Correct Answer:
Explanation:In a pure (intrinsic) semiconductor, every electron that jumps to the conduction band leaves behind exactly one hole in the valence band.
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16Doping is the process of:
A.Heating the semiconductor
B.Purifying the semiconductor
C.Adding impurities to increase conductivity
D.Removing impurities
Correct Answer: Adding impurities to increase conductivity
Explanation:Doping involves adding specific impurity atoms (pentavalent or trivalent) to intrinsic semiconductors to alter their electrical properties.
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17To obtain an N-type semiconductor, which type of impurity is added to Silicon?
A.Trivalent
B.Pentavalent
C.Tetravalent
D.Monovalent
Correct Answer: Pentavalent
Explanation:Pentavalent atoms (Group V elements like Phosphorus, Arsenic) have 5 valence electrons, providing extra free electrons for conduction, creating N-type material.
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18The majority charge carriers in a P-type semiconductor are:
A.Free electrons
B.Holes
C.Ions
D.Neutrons
Correct Answer: Holes
Explanation:P-type material is doped with trivalent impurities (like Boron), creating an abundance of holes (vacancies for electrons).
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19Which of the following is an example of a trivalent impurity?
A.Phosphorus
B.Arsenic
C.Antimony
D.Boron
Correct Answer: Boron
Explanation:Boron (Group III) is a trivalent impurity used to create P-type semiconductors. Phosphorus, Arsenic, and Antimony are pentavalent.
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20In an N-type semiconductor, the position of the Fermi level is:
A.At the center of the forbidden gap
B.Near the valence band
C.Near the conduction band
D.Inside the valence band
Correct Answer: Near the conduction band
Explanation:Due to the higher concentration of electrons, the Fermi level shifts upwards towards the conduction band in N-type semiconductors.
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21A PN junction is formed by:
A.Connecting a P-type wire to an N-type wire physically
B.Soldering P-type and N-type blocks
C.Doping a single crystal with acceptor and donor impurities on two sides
D.Placing P-type and N-type materials in a vacuum
Correct Answer: Doping a single crystal with acceptor and donor impurities on two sides
Explanation:A PN junction is created within a single continuous crystal structure to ensure proper lattice continuity, not by mechanically joining two separate pieces.
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22The depletion region in a PN junction contains:
A.Mobile electrons only
B.Mobile holes only
C.Immobile positive and negative ions
D.Neutral atoms
Correct Answer: Immobile positive and negative ions
Explanation:The depletion region is depleted of mobile charge carriers (electrons and holes) and contains uncovered immobile ions resulting from recombination near the junction.
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23The typical knee voltage (cut-in voltage) for a Silicon PN junction diode is:
A.
B.
C.
D.
Correct Answer:
Explanation:Silicon diodes typically require a forward bias of approximately to overcome the potential barrier and conduct significant current.
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24Under forward bias conditions, the width of the depletion layer:
A.Increases
B.Decreases
C.Remains constant
D.Becomes infinite
Correct Answer: Decreases
Explanation:Forward bias pushes majority carriers towards the junction, neutralizing some ions and effectively narrowing the depletion width.
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25In Reverse Bias, the P-type side of the diode is connected to the:
A.Positive terminal of supply
B.Negative terminal of supply
C.Ground
D.Open circuit
Correct Answer: Negative terminal of supply
Explanation:Reverse bias occurs when the P-side (anode) is connected to the negative terminal and the N-side (cathode) is connected to the positive terminal.
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26The small current that flows in a reverse-biased diode is called:
A.Forward current
B.Reverse saturation current ()
C.Eddy current
D.Displacement current
Correct Answer: Reverse saturation current ()
Explanation:This current is caused by thermally generated minority carriers and is typically very small (micro/nano-amperes).
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27Zener breakdown occurs primarily due to:
A.High temperature
B.Collision of accelerated carriers
C.High electric field breaking covalent bonds
D.Low doping concentration
Correct Answer: High electric field breaking covalent bonds
Explanation:Zener breakdown happens in heavily doped diodes where a strong electric field directly tears electrons from their covalent bonds.
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28Avalanche breakdown occurs in:
A.Lightly doped diodes at high reverse voltage
B.Heavily doped diodes at low reverse voltage
C.Forward biased diodes
D.Intrinsic semiconductors only
Correct Answer: Lightly doped diodes at high reverse voltage
Explanation:Avalanche breakdown is caused by carrier multiplication due to high-velocity collisions in wider depletion regions (lightly doped).
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29A rectifier is a circuit that converts:
A.DC to AC
B.AC to DC
C.High voltage to Low voltage
D.Current to Voltage
Correct Answer: AC to DC
Explanation:Rectifiers use diodes to convert alternating current (AC) into pulsating direct current (DC).
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30The maximum efficiency of a Half Wave Rectifier is:
A.
B.
C.
D.
Correct Answer:
Explanation:The theoretical maximum efficiency for a half-wave rectifier is .
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31In a Full Wave Bridge Rectifier, how many diodes are used?
A.1
B.2
C.4
D.6
Correct Answer: 4
Explanation:A bridge rectifier configuration utilizes 4 diodes to rectify both halves of the AC cycle.
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32The Peak Inverse Voltage (PIV) rating required for a diode in a Center-Tapped Full Wave Rectifier is:
A.
B.
C.
D.
Correct Answer:
Explanation:In a center-tapped rectifier, the non-conducting diode must withstand twice the peak secondary voltage () across the transformer half.
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33Ripple factor is defined as the ratio of:
A.DC component to AC component
B.RMS value of AC component to DC component
C.Peak voltage to RMS voltage
D.Input power to Output power
Correct Answer: RMS value of AC component to DC component
Explanation:Ripple factor indicates the purity of the DC output. .
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34An ideal diode acts as a switch. When forward biased, it acts as a:
A.Open switch
B.Closed switch (Short circuit)
C.Resistor
D.Capacitor
Correct Answer: Closed switch (Short circuit)
Explanation:Ideally, a forward-biased diode has zero resistance and acts as a closed switch.
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35What is the primary function of a capacitor filter in a rectifier circuit?
A.To increase the voltage amplitude
B.To convert DC to AC
C.To remove AC ripples and smooth the output
D.To protect the diode
Correct Answer: To remove AC ripples and smooth the output
Explanation:A capacitor charges during the peak and discharges slowly during the drop, smoothing out the pulsating DC.
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36BJT stands for:
A.Bi-junction Transfer
B.Bipolar Junction Transistor
C.Basic Junction Transistor
D.Binary Junction Transistor
Correct Answer: Bipolar Junction Transistor
Explanation:BJT stands for Bipolar Junction Transistor because conduction involves both holes and electrons.
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37The three terminals of a BJT are called:
A.Anode, Cathode, Gate
B.Source, Gate, Drain
C.Emitter, Base, Collector
D.Input, Output, Ground
Correct Answer: Emitter, Base, Collector
Explanation:The BJT terminals are Emitter (E), Base (B), and Collector (C).
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38Which terminal of the BJT is the most heavily doped?
A.Base
B.Collector
C.Emitter
D.All are equally doped
Correct Answer: Emitter
Explanation:The Emitter is heavily doped to inject a large number of carriers into the base. Order: Emitter > Collector > Base.
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39Which terminal of the BJT is physically the largest?
A.Base
B.Collector
C.Emitter
D.None
Correct Answer: Collector
Explanation:The Collector is the largest region to dissipate the heat generated during operation. Order: Collector > Emitter > Base.
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40The fundamental current equation for a BJT is:
A.
B.
C.
D.
Correct Answer:
Explanation:The Emitter current is the sum of the Base current and Collector current.
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41For a BJT to operate in the Active Region (for amplification):
A.Emitter-Base junction is Forward Biased, Collector-Base is Forward Biased
B.Emitter-Base junction is Reverse Biased, Collector-Base is Forward Biased
C.Emitter-Base junction is Forward Biased, Collector-Base is Reverse Biased
D.Both junctions are Reverse Biased
Correct Answer: Emitter-Base junction is Forward Biased, Collector-Base is Reverse Biased
Explanation:This is the standard biasing requirement for a BJT to function as a linear amplifier.
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42If both junctions of a BJT are Forward Biased, the transistor operates in:
A.Active Region
B.Cut-off Region
C.Saturation Region
D.Breakdown Region
Correct Answer: Saturation Region
Explanation:In Saturation, the transistor acts like a closed switch (maximum current).
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43In Common Emitter (CE) configuration, the input is applied between:
A.Base and Collector
B.Emitter and Collector
C.Base and Emitter
D.Emitter and Ground
Correct Answer: Base and Emitter
Explanation:In CE mode, the Emitter is common. Input is at the Base-Emitter, output is at the Collector-Emitter.
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44The Current Gain in Common Emitter configuration is denoted by:
A. (alpha)
B. (beta)
C. (gamma)
D. (delta)
Correct Answer: (beta)
Explanation: is the common-emitter current gain, defined as .
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45The relationship between and is given by:
A.
B.
C.
D.
Correct Answer:
Explanation:Since and and , the derivation leads to .
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46In a Common Emitter amplifier, the phase shift between input and output voltage is:
A.
B.
C.
D.
Correct Answer:
Explanation:A CE amplifier inverts the input signal, resulting in a phase shift.
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47The 'Cut-off' region in the BJT output characteristics corresponds to:
A.
B.
C. is maximum
D.Both junctions Forward Biased
Correct Answer:
Explanation:Cut-off occurs when the base current is zero (or below threshold), resulting in zero collector current (ideal switch open).
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48Which configuration provides the highest power gain?
A.Common Base (CB)
B.Common Collector (CC)
C.Common Emitter (CE)
D.All are equal
Correct Answer: Common Emitter (CE)
Explanation:CE configuration provides both significant voltage gain and current gain, resulting in the highest overall power gain among the three configurations.
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49The Common Collector configuration is also known as:
A.Voltage Follower
B.Current Mirror
C.Rectifier
D.Oscillator
Correct Answer: Voltage Follower
Explanation:In CC configuration, the output voltage follows the input voltage (Voltage gain ), hence the name Emitter Follower or Voltage Follower.
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50In the construction of a BJT, the Base region is:
A.Thick and heavily doped
B.Thin and lightly doped
C.Thick and lightly doped
D.Thin and heavily doped
Correct Answer: Thin and lightly doped
Explanation:The base is made very thin and lightly doped to allow the majority of carriers from the emitter to pass through to the collector with minimal recombination.