Unit6 - Subjective Questions
MTH174 • Practice Questions with Detailed Answers
Evaluate the double integral where is the rectangle defined by and .
Step-by-step Evaluation:
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Set up the double integral limits:
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Integrate with respect to first (treating as a constant):
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Integrate the result with respect to :
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Substitute the limits for :
Final Answer: The value of the double integral is .
Explain the concept of 'Change of Order of Integration' in double integrals and state why it is useful.
Change of Order of Integration:
- Concept: In a double integral , the integration can be performed either with respect to first and then (i.e., ), or with respect to first and then (i.e., ). Changing the order of integration means switching from one sequence to the other.
- Process: To change the order, one must:
- Sketch the region of integration based on the given limits.
- Redefine the region in terms of the new order. For example, if the original vertical strips (integrating first) are used, switch to horizontal strips (integrating first).
- Determine the new limits of integration from the sketch.
- Usefulness/Why it is used:
- Simplification: Some integrals are extremely difficult or impossible to evaluate analytically in one order, but become straightforward in the reversed order.
- Avoiding Discontinuities: It can help bypass functions that lack an elementary antiderivative (e.g., ).
Change the order of integration for the integral and evaluate it.
Step 1: Sketch the region of integration.
The given limits are:
Inner integral (with respect to ): to
Outer integral (with respect to ): to
The region is bounded by the lines , , and the y-axis (). This forms a triangle with vertices , , and .
Step 2: Change the order of integration.
To integrate with respect to first (), we use horizontal strips.
For a fixed , varies from to the line .
The outer limits for are from $0$ to $1$.
The new integral is:
Step 3: Evaluate the new integral.
Integrate with respect to :
Now, integrate with respect to :
Let , then .
Limits: when ; when .
Final Answer:
Describe the process of changing variables in double integrals using the Jacobian.
Change of Variables in Double Integrals:
When converting a double integral from Cartesian coordinates to a new coordinate system , the formula used is:
Process:
- Define Transformations: Identify the transformation equations and .
- Calculate the Jacobian (): The Jacobian determinant scales the area element from one coordinate system to the other. It is defined as:
- Find the Absolute Value: Take the absolute value of the Jacobian, , to ensure area remains positive.
- Substitute Variables: Replace and in the integrand with their expressions in terms of and .
- Determine New Limits: Transform the boundary of the original region in the -plane to find the new region in the -plane to establish the new limits of integration.
- Evaluate: Compute the new double integral over the region .
Convert the integral to polar coordinates and evaluate, where is the region in the first quadrant bounded by the circle .
1. Transformation to Polar Coordinates:
- Let and .
- The area element becomes (since the Jacobian is ).
- The integrand becomes .
2. Determine the Limits:
- The region is in the first quadrant inside the circle of radius .
- Therefore, varies from $0$ to .
- The angle varies from $0$ to (first quadrant).
3. Set up the Integral:
4. Evaluate the Integral:
- Inner integral (w.r.t ):
- Outer integral (w.r.t ):
Final Answer: The evaluated integral is .
How can double integrals be applied to calculate the area of a plane region? Provide the general formula.
Application of Double Integrals to Calculate Area:
A double integral can be used to find the area of a two-dimensional region in the -plane.
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Concept: The double integral of a function over a region calculates the volume under the surface . If we set the function , the "volume" numerically equals the "area" of the base region , because we are multiplying the base area by a height of 1.
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General Formula:
The area of a region is given by:
Depending on the coordinate system used, this translates to:- Cartesian Coordinates:
- Polar Coordinates:
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Methodology:
- Sketch the bounding curves to visualize the region .
- Determine the points of intersection to find the limits of integration.
- Choose the appropriate order of integration ( or ) based on which provides simpler limits (vertical vs. horizontal strips).
- Evaluate the double integral with the integrand as 1.
Find the area enclosed by the parabolas and using a double integral.
Step 1: Find points of intersection.
Set the equations equal to each other:
So, and . The points of intersection are and .
Step 2: Set up the double integral for area.
Formula:
The region is bounded above by and below by .
The limits for are from to .
The limits for are from $0$ to $1$.
Step 3: Evaluate the integral.
- Inner integral:
- Outer integral:
Final Answer: The area enclosed by the parabolas is square units.
Explain how double integrals are used to calculate the volume of a solid under a surface.
Volume Calculation using Double Integrals:
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Geometric Interpretation: The double integral of a continuous, non-negative function over a region in the -plane represents the volume of the solid cylinder whose base is and whose top is bounded by the surface .
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Formula:
Where is the differential area element ( or in Cartesian, in polar). -
Volume between two surfaces: If a solid is bounded above by a surface and below by a surface over a region , the volume is given by:
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Procedure:
- Identify the function representing the upper boundary of the solid.
- Determine the region in the -plane which is the projection (base) of the solid.
- Find the limits of integration for the region .
- Evaluate the double integral of over .
Set up and evaluate a triple integral to find the volume of a rectangular box bounded by the planes , and .
Step 1: Formula for Volume using Triple Integrals
The volume of a region is given by the triple integral of 1 over that region:
Step 2: Identify limits of integration
The region is a rectangular box with constant limits:
varies from $0$ to
varies from $0$ to
varies from $0$ to
Step 3: Set up the integral
Step 4: Evaluate the integral
- Integrate w.r.t :
- Integrate w.r.t :
- Integrate w.r.t :
Final Answer: The volume of the rectangular box is , which matches the standard geometric formula for a rectangular prism (length width height).
Evaluate the triple integral .
Step 1: Inner integral with respect to
Step 2: Middle integral with respect to
Upper limit ():
Lower limit ():
Step 3: Outer integral with respect to
Upper limit ():
Lower limit (): $
Final Answer:
Compare and contrast double and triple integrals in terms of their geometric interpretations and applications.
Comparison of Double and Triple Integrals:
| Feature | Double Integrals () | Triple Integrals () |
|---|---|---|
| Domain of Integration | A 2D region in the -plane. | A 3D solid region in -space. |
| Differential Element | Area element ( or ). | Volume element (, etc.). |
| Geometric Interpretation () | Represents the Area of the 2D region . | Represents the Volume of the 3D solid region . |
| Geometric Interpretation ( or ) | Calculates the Volume under the surface over region . | Calculates the "hypervolume" or physically represents total mass, charge, etc., if is a density function. |
| Applications | - Area of plane regions.<br>- Volume under a surface.<br>- Mass, center of mass, moments of inertia for 2D laminas. | - Volume of 3D solids.<br>- Mass, center of mass, moments of inertia for 3D objects with variable density. |
| Coordinate Transformations | Often transformed to Polar coordinates using Jacobian . | Often transformed to Cylindrical (Jacobian ) or Spherical (Jacobian ) coordinates. |
Define the Jacobian used in change of variables for triple integrals from Cartesian to spherical coordinates, and state its value.
Jacobian for Spherical Coordinates:
- Definition: When changing variables in a triple integral from Cartesian coordinates to spherical coordinates , the Jacobian determinant relates the differential volume element to .
- Transformations: The standard relations are:
- Jacobian Matrix: The Jacobian is the determinant of the partial derivatives:
- Value: Upon calculating this determinant, the absolute value of the Jacobian is found to be:
- Resulting Volume Element: Therefore, the volume element transforms as:
Use a triple integral to calculate the volume of a sphere of radius .
Step 1: Choose the coordinate system.
Spherical coordinates are best for evaluating integrals over a sphere.
The volume element is .
Step 2: Determine the limits of integration.
For a full sphere of radius centered at the origin:
- Radius goes from $0$ to .
- Azimuthal angle goes from $0$ to .
- Polar angle goes from $0$ to .
Step 3: Set up the integral.
Step 4: Evaluate the integral.
Since the limits are constants and the integrand is separable, we can evaluate them independently:
Step 5: Multiply the results.
Final Answer: The volume derived using triple integration is .
Change the order of integration for . Assume .
Step 1: Analyze the original limits.
Inner limits (for ): to
Outer limits (for ): to
Step 2: Sketch the region.
The equation represents the upper half of a circle centered at the origin with radius (since ).
Since goes from $0$ to and goes from $0$ to the circle, the region is the quarter circle in the first quadrant.
Step 3: Determine new limits.
To change the order to , we use horizontal strips.
For a fixed , goes from the y-axis () to the circular boundary.
Solving for in the first quadrant gives .
The y-values for the entire region range from to .
Step 4: Write the new integral.
The new inner limits are to .
The new outer limits are to .
Final Answer:
Find the volume of the solid generated bounded by the cylinder and the planes and .
Step 1: Set up the integral formula.
The volume is given by
Here, and .
The region in the -plane is the circle .
Step 2: Convert to Polar Coordinates.
Let , , and .
The region is a circle of radius 2, so limits are:
from $0$ to $2$
from $0$ to
Step 3: Evaluate Inner Integral.
Step 4: Evaluate Outer Integral.
Final Answer: The volume is .
What does a triple integral represent if the integrand is a density function ? How does this differ from calculating purely geometric volume?
Physical Meaning of Triple Integrals with Density Function:
- Total Mass: If the integrand represents the mass density (mass per unit volume) of an object occupying a solid region , then the triple integral calculates the Total Mass () of that object.
- Explanation: The integral breaks the solid into infinitesimal volume elements . The mass of each element is . Summing (integrating) these infinitesimal masses over the entire volume yields the total mass.
- Other Interpretations: Depending on the context, if is charge density, the integral gives total charge. If it represents probability density, the integral gives total probability.
Difference from Geometric Volume:
- Volume: To calculate purely geometric volume, the integrand is precisely $1$ (i.e., uniform density of 1 unit).
- Distinction: Volume is a purely spatial property measuring how much 3D space an object occupies. When evaluating a triple integral with a non-constant density function , the result is no longer a spatial measure but a physical quantity (like mass) that accounts for how 'heavy' or 'concentrated' the material is at different points within that space.
Describe the process of evaluating a triple integral using cylindrical coordinates.
Evaluating Triple Integrals using Cylindrical Coordinates:
Cylindrical coordinates are a 3D extension of polar coordinates, useful for regions possessing symmetry about an axis (usually the z-axis).
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Transformations: Convert Cartesian coordinates to cylindrical:
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Volume Element: The differential volume element becomes:
(The factor is the Jacobian of the transformation). -
Substitute Variables: Replace all occurrences of in the integrand with their cylindrical equivalents to get .
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Determine Limits:
- z-limits: Find the bounding surfaces in the z-direction, often expressing in terms of and . This is usually the innermost integral.
- r-limits: Project the 3D solid onto the -plane to get a 2D region . Determine the limits for (distance from origin) which may depend on .
- -limits: Determine the angular sweep of the region in the -plane.
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Evaluate: Compute the integral:
Evaluate where is the region bounded by , , and .
Step 1: Sketch and define limits for region R.
The region is a triangle in the first quadrant bounded by the axes and the line .
Using vertical strips:
Outer limits (): $0$ to $1$
Inner limits (): $0$ to
Step 2: Set up the double integral.
Step 3: Evaluate inner integral w.r.t .
Expand .
Inner result:
Step 4: Evaluate outer integral w.r.t .
Find a common denominator (12):
Final Answer: The value of the integral is .
Change the variables to evaluate the double integral where is the parallelogram bounded by the lines , and .
Step 1: Define the transformation.
Let and .
Based on the boundary equations, the new region in the -plane is a rectangle bounded by:
,
,
Step 2: Calculate the Jacobian.
First, find partials for w.r.t :
Since , we have:
The absolute value of the Jacobian is .
So, .
Step 3: Set up the new integral.
The integrand becomes .
Step 4: Evaluate.
Since limits are constant, separate the integrals:
Final Answer:
Set up the triple integral to find the volume of a right circular cone of base radius and height using cylindrical coordinates.
Step 1: Place the cone in the coordinate system.
Place the vertex of the cone at the origin and the central axis along the z-axis, opening upwards. The base is at .
The equation of the lateral surface of a cone in cylindrical coordinates is given by proportional triangles: .
Alternatively, place base at and vertex at . Surface is . Let's use the first setup (vertex at origin) as it's often simpler.
Step 2: Determine limits of integration.
Using the order :
- z-limits: For a fixed , a vertical line enters the cone at the lateral surface and exits at the top base .
- r-limits: The projection of the solid onto the -plane is a circle of radius . So, goes from $0$ to .
- -limits: Full circle, so goes from $0$ to .
Step 3: Set up the integral.
The volume is . In cylindrical coordinates, .
(Note: While the question only asks to set it up, evaluating this gives , confirming the standard formula).