The integral can be separated into three identical parts: . For , it is . The volume of the unit cube is $1$. So, the total is .
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31Find the volume of the solid bounded by the planes , , , and .
application of triple integrals to calculate volume
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Volume .
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32Calculate the volume of a sphere of radius using triple integration in spherical coordinates.
application of triple integrals to calculate volume
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Volume . Evaluating gives .
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33Evaluate .
double integrals
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Inner integral w.r.t : . Outer integral w.r.t : . Let , . Limit changes to $1$ to $0$. The integral becomes .
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34The integral after changing the order of integration becomes:
change of order of integration
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The region is bounded by , , , . This means . The limits for are from $0$ to $2$.
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35Evaluate the integral where is the disk using polar coordinates.
change of variables
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
In polar coordinates, the integrand is , and . The integral is .
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36Find the area of the circle using double integration.
application of double integrals to calculate area and volume
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Area .
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37Evaluate where is the region , , .
triple integrals
Medium
A.$6$
B.$1.5$
C.$2$
D.$3$
Correct Answer: $3$
Explanation:
The integral is .
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38Calculate the volume of the cylinder bounded by the planes and .
application of triple integrals to calculate volume
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Volume .
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39If transforming coordinates using and , what is the absolute value of the Jacobian ?
change of variables
Medium
A.
B.$2$
C.
D.$1$
Correct Answer: $2$
Explanation:
The Jacobian determinant . The absolute value is $2$.
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40Evaluate .
double integrals
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
By changing the order of integration, the region is and . The integral becomes .
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41Evaluate the integral .
double integrals
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Converting to polar coordinates, the integral becomes . Let , . The inner integral is . Multiplying by yields .
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42What is the value of the double integral , where ?
double integrals
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
By symmetry, the integral is . The region where is a triangle. .
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43Evaluate where is the unit disk .
double integrals
Hard
A.
B.$0$
C.
D.
Correct Answer: $0$
Explanation:
In polar coordinates, the integral is . As , this limit approaches $0$.
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44Change the order of integration for . Which of the following is the correct equivalent integral?
change of order of integration
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The original region is bounded by below and above, for . This forms a parabolic region. When changing the order, ranges from $0$ to $1$. For a given , ranges from the left branch of the parabola () to the right branch ().
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45Evaluate by reversing the order of integration.
change of order of integration
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The region is and . Reversing the order gives and . The integral becomes .
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46Consider the integral . After changing the order of integration, what are the new limits?
change of order of integration
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The region is defined by and . The lowest value of is and highest is . For a fixed , the values range from to .
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47If , find the value of using change of order.
change of order of integration
Hard
A.
B.$1$
C.$2$
D.$0$
Correct Answer: $2$
Explanation:
The region is and . Reversing the order, and . The integral is .
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48Find the Jacobian for the transformation and .
change of variables
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The Jacobian determinant is defined as . Here, , , , and . .
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49Use the transformation , to evaluate , where is the region bounded by .
change of variables
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The region in the -plane is and . The Jacobian of with respect to is . The integral becomes . We can integrate with respect to first: . Integration by parts gives .
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50Evaluate the integral over the triangle with vertices using the substitution , .
change of variables
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The vertices in the -plane are . The region is and . The Jacobian . The integral is . The inner integral is . Wait, symmetry implies it evaluates to 0? The question might be evaluated over the region where applies. The correct integral evaluates to zero due to odd symmetry, but if bounded differently, here the region is symmetric, so the integral evaluates to 0. (Assuming standard substitution limits, the options provided are generic test traps). Actually, if it's over the first quadrant, it yields 0.
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51Find the volume of the solid bounded by the paraboloid and the -plane.
application of double integrals to calculate area and volume
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The volume is given by , where is the region . Using polar coordinates, .
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52Calculate the area of the region bounded by the lemniscate .
application of double integrals to calculate area and volume
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The area is .
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53Find the volume common to the cylinders and .
application of double integrals to calculate area and volume
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Using symmetry, the volume is $8$ times the volume in the first octant. .
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54Determine the area of the region outside the circle and inside the cardioid .
application of double integrals to calculate area and volume
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The intersection points are where . The area is .
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55Evaluate , where is the solid tetrahedron bounded by the planes , , , and .
triple integrals
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The integral is . The innermost integral is . The middle integral evaluates to . Finally, the outer integral is .
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56Evaluate where is the region bounded by .
triple integrals
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
By symmetry, . Using spherical coordinates, the integral of is . Thus, .
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57Using cylindrical coordinates, set up the triple integral for the volume of the solid bounded above by the sphere and below by the paraboloid .
triple integrals
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The intersection of (or ) and (or ) occurs when , meaning or . Since , we take , giving , so . The limits for are from the paraboloid to the sphere . The volume integral is .
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58Find the volume of the region bounded by the ellipsoid .
application of triple integrals to calculate volume
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Applying the transformation , the Jacobian is . The region becomes , which is a unit sphere. The volume is .
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59Calculate the volume of the solid bounded by the cone and the sphere .
application of triple integrals to calculate volume
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The sphere equation is . The cone corresponds to . The volume is . Evaluating the inner integral gives . The middle integral is . Multiplying by gives .
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60Determine the volume of the solid enclosed by the cylinder and the planes and .
application of triple integrals to calculate volume
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The volume is given by the double integral of the difference in heights over the circular base . The upper surface is and the lower surface is . Volume = . Since the integral of over a symmetric region about the x-axis is zero, the integral reduces to .