Unit 5: Multivariable integration and applications - Subjective Questions
MTH165 — Mathematics For Engineers • Practice Questions with Detailed Answers
20 questions
Define a double integral over a rectangular region and explain its geometric interpretation.
Definition: Let be continuous on the rectangle . Its double integral is defined as the limit of Riemann sums:
Here, and .
- If , the integral represents the volume below the surface and above .
- If assumes both positive and negative values, it gives the signed volume.
- By Fubini's theorem, for continuous ,
Evaluate the double integral .
First integrate with respect to :
Now integrate with respect to :
Therefore,
Explain the difference between Type I and Type II plane regions used in double integration.
- Type I region: A region bounded vertically, represented as
Its integral is written as
- Type II region: A region bounded horizontally, represented as
Its integral is written as
The choice depends on which description gives simpler limits. Some regions can be represented in both forms, while others must be split into subregions for one of the orders.
Change the order of integration in and describe the region.
The original limits imply
Thus, the region is the triangular part of the unit square bounded by
- ,
- ,
- .
For a fixed , varies from to . The overall range of is . Therefore, after changing the order,
Change the order of integration and evaluate .
Direct integration with respect to is difficult because has no elementary antiderivative.
The region is
Reversing the order gives
Hence,
Integrating with respect to ,
Using , ,
Therefore,
Evaluate , where is bounded by and in the first quadrant.
The curves intersect where
For , the parabola lies below the line . Therefore,
Integrating with respect to ,
Thus,
State Fubini's theorem for double integrals and explain its significance.
Fubini's theorem: If is continuous on the rectangle , then
Significance:
- It converts a double integral into two successive single integrals.
- It permits the order of integration to be interchanged under suitable conditions.
- It allows the easier order to be selected when one iterated integral is difficult.
- For nonrectangular regions, the limits must be adjusted according to the geometry of the region.
- A more general version applies to integrable functions, even when continuity is not available everywhere.
Define a triple integral and explain its physical and geometric interpretations.
For a bounded solid region and an integrable function , the triple integral is
Interpretations:
- If , then gives the volume of .
- If is mass density, then gives the total mass.
- If represents charge density, the integral gives total charge.
- If may be negative, the result is a signed accumulation.
In Cartesian coordinates,
with the order chosen according to the description of the solid.
Evaluate , where .
Write the triple integral as
Integrating with respect to ,
Then,
Finally,
Therefore,
Describe Cartesian, cylindrical, and spherical coordinate systems, including their volume elements.
Cartesian coordinates:
They are suitable for boxes and solids bounded by planes.
Cylindrical coordinates:
They are suitable for cylinders, cones, and solids with symmetry about an axis.
Spherical coordinates:
They are suitable for spheres and solids with radial symmetry. The extra factors and are the corresponding Jacobians.
Explain the change-of-variables formula for double integrals and define the Jacobian.
Suppose
is a continuously differentiable, one-to-one transformation from a region in the -plane to a region in the -plane. Then
The Jacobian is
- Its absolute value measures the local area-scaling factor.
- The absolute value is used because area must be nonnegative.
- The transformation should have a nonzero Jacobian except possibly on boundary sets of zero area.
Derive the area element in polar coordinates using the Jacobian.
The polar transformation is
The Jacobian is
Evaluating the determinant,
Therefore,
where . Hence the change-of-variables formula becomes
The factor accounts for the increase in the area of a polar sector as its distance from the origin increases.
Use polar coordinates to evaluate , where is the disk .
In polar coordinates,
The disk is described by
Therefore,
Thus,
Using a double integral, find the area enclosed between the curves and .
The curves intersect at
For , the region satisfies
Area is obtained by integrating over the region:
Integrating,
Therefore,
Use a double integral to find the volume below the plane and above the triangular region in the -plane bounded by , , and .
The triangular base region is
Since on , the volume is
Thus,
Let . The inner integral is
Hence,
Therefore,
cubic units.
Find the volume under the paraboloid and above the -plane.
The surface meets the -plane when
Thus, the base is the disk . Using polar coordinates,
The volume is
The radial integral is
Therefore,
cubic units.
Use a triple integral in cylindrical coordinates to derive the volume of a right circular cylinder of radius and height .
For a cylinder whose axis is the -axis, the cylindrical-coordinate limits are
The cylindrical volume element is
Therefore,
Integrating successively,
Hence,
Use a triple integral in spherical coordinates to derive the volume of a sphere of radius .
For a sphere of radius , the spherical-coordinate limits are
The volume element is
Therefore,
The separate factors are
and
Hence,
Find the volume of the tetrahedron in the first octant bounded by the coordinate planes and the plane using a triple integral.
Solving the plane equation for gives
Suitable limits are
Thus,
Integrating with respect to and then gives
Let , so . Then
Therefore,
Apply the transformation and to evaluate , where is bounded by , , , and .
Under the transformation
the region becomes the rectangle
Solving for and ,
The Jacobian is
Hence,
Also, . Therefore,
Define a double integral over a rectangular region and explain its geometric interpretation.
Definition: Let be continuous on the rectangle . Its double integral is defined as the limit of Riemann sums:
Here, and .
- If , the integral represents the volume below the surface and above .
- If assumes both positive and negative values, it gives the signed volume.
- By Fubini's theorem, for continuous ,
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