To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Change in cell population over time
B.Change in medium volume over time
C.Change in colony color over time
D.Change in cell shape over time
Correct Answer: Change in cell population over time
Explanation:
A microbial growth curve shows how the number or mass of cells changes with time.
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2Which microorganism is used in this experiment?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Escherichia coli
B.Staphylococcus aureus
C.Bacillus subtilis
D.Saccharomyces cerevisiae
Correct Answer: Escherichia coli
Explanation:
The experiment determines the growth curve of Escherichia coli.
Incorrect! Try again.
3What does turbidity of a culture mainly indicate?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.The cloudiness caused by cells
B.The color produced by cells
C.The temperature reached by cells
D.The acidity caused by cells
Correct Answer: The cloudiness caused by cells
Explanation:
Growing microbial cells scatter light and make the culture appear cloudy.
Incorrect! Try again.
4Which instrument is commonly used to measure culture turbidity?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Spectrophotometer
B.Autoclave
C.Incubator
D.Microscope
Correct Answer: Spectrophotometer
Explanation:
A spectrophotometer measures the optical density of a microbial suspension.
Incorrect! Try again.
5What measurement is commonly used to express turbidity?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Optical density
B.pH value
C.Incubation pressure
D.Colony diameter
Correct Answer: Optical density
Explanation:
Optical density, often written as OD, is used as an estimate of culture turbidity.
Incorrect! Try again.
6What is plotted on the horizontal axis of a basic growth curve?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Cell shape
B.Optical density
C.Medium color
D.Incubation time
Correct Answer: Incubation time
Explanation:
Time is plotted on the horizontal, or x, axis.
Incorrect! Try again.
7What is usually plotted on the vertical axis of a turbidimetric growth curve?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Agar depth
B.Optical density
C.Flask volume
D.Incubation time
Correct Answer: Optical density
Explanation:
Optical density is plotted on the vertical, or y, axis to represent culture turbidity.
Incorrect! Try again.
8Which phase occurs immediately after inoculation when cells adjust to the medium?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Lag phase
B.Death phase
C.Stationary phase
D.Log phase
Correct Answer: Lag phase
Explanation:
During the lag phase, cells adapt to the new environment before rapid division begins.
Incorrect! Try again.
9During which phase do E. coli cells multiply most rapidly?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Stationary phase
B.Log phase
C.Lag phase
D.Death phase
Correct Answer: Log phase
Explanation:
The log, or exponential, phase is characterized by rapid and regular cell division.
Incorrect! Try again.
10What happens to the cell population during the stationary phase?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Only new cells are produced
B.Growth rate equals death rate
C.The culture becomes completely clear
D.All cells stop metabolism
Correct Answer: Growth rate equals death rate
Explanation:
In the stationary phase, nutrient limitation and waste buildup cause growth and death rates to become approximately equal.
Incorrect! Try again.
11What generally occurs during the death phase?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Cells divide at maximum speed
B.Viable cell numbers decrease
C.Turbidity always becomes zero
D.Cells adapt to fresh medium
Correct Answer: Viable cell numbers decrease
Explanation:
During the death phase, the number of living cells decreases.
Incorrect! Try again.
12Why is a sterile uninoculated medium used as a blank?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.To sterilize the culture tube
B.To set the instrument baseline
C.To increase bacterial growth
D.To provide nutrients to cells
Correct Answer: To set the instrument baseline
Explanation:
The blank corrects for light absorption or scattering caused by the medium itself.
Incorrect! Try again.
13Why are readings taken at different incubation times?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.To identify bacterial shape
B.To follow growth changes
C.To measure flask capacity
D.To change the culture medium
Correct Answer: To follow growth changes
Explanation:
Repeated readings show how the turbidity changes as the culture grows.
Incorrect! Try again.
14What should be done before measuring the optical density of a sample?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Remove all liquid from the tube
B.Add agar to the sample
C.Freeze the sample immediately
D.Mix the sample gently
Correct Answer: Mix the sample gently
Explanation:
Gentle mixing distributes cells evenly and helps produce a representative reading.
Incorrect! Try again.
15What is the main purpose of incubating the inoculated culture?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.To provide suitable growth conditions
B.To measure the culture color
C.To remove cells from the medium
D.To prevent all cell division
Correct Answer: To provide suitable growth conditions
Explanation:
Incubation provides a suitable temperature and environment for E. coli growth.
Incorrect! Try again.
16What does an increase in optical density usually indicate?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.A decrease in nutrient concentration only
B.A decrease in culture turbidity
C.A complete loss of viable cells
D.An increase in cell concentration
Correct Answer: An increase in cell concentration
Explanation:
A higher optical density generally indicates more suspended microbial cells.
Incorrect! Try again.
17Which phase is represented by a nearly horizontal part of the growth curve after rapid growth?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Lag phase
B.Log phase
C.Inoculation phase
D.Stationary phase
Correct Answer: Stationary phase
Explanation:
The curve becomes nearly level when the population reaches the stationary phase.
Incorrect! Try again.
18What is the purpose of plotting the recorded readings?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.To calculate the medium volume
B.To identify growth phases
C.To determine bacterial staining color
D.To sterilize the spectrophotometer
Correct Answer: To identify growth phases
Explanation:
A plot of time against optical density helps display and identify the phases of growth.
Incorrect! Try again.
19Which condition can cause a culture to enter the stationary phase?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Fresh nutrient addition
B.Nutrient depletion
C.Lower sample volume only
D.Shorter observation time
Correct Answer: Nutrient depletion
Explanation:
Limited nutrients can slow cell multiplication and contribute to the stationary phase.
Incorrect! Try again.
20What is the relationship between turbidity and suspended cell mass in a culture?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Easy
A.Turbidity occurs only in sterile medium
B.Cell mass has no effect on turbidity
C.More cell mass always gives less turbidity
D.More cell mass usually gives greater turbidity
Correct Answer: More cell mass usually gives greater turbidity
Explanation:
An increase in suspended cell mass generally scatters more light and raises turbidity.
Incorrect! Try again.
21Why is a sterile uninoculated broth used as a blank before measuring the turbidity of an E. coli culture?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.To convert absorbance directly into cell number
B.To increase bacterial growth during measurement
C.To account for absorbance from the medium
D.To maintain the culture at exponential phase
Correct Answer: To account for absorbance from the medium
Explanation:
The blank corrects for light absorbed or scattered by the broth and other non-cellular components, so the reading mainly represents bacterial turbidity.
Incorrect! Try again.
22Which wavelength is commonly selected for measuring bacterial turbidity because it provides a useful estimate of light scattering by cells?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.600 nm
B.1,200 nm
C.900 nm
D.260 nm
Correct Answer: 600 nm
Explanation:
An optical density reading near 600 nm, often reported as OD600, is commonly used to estimate bacterial turbidity without primarily measuring nucleic acid absorbance.
Incorrect! Try again.
23A culture has OD600 values of 0.10, 0.20, and 0.40 at successive equal time intervals. Which growth phase is most consistent with these observations?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.Stationary phase
B.Death phase
C.Exponential phase
D.Lag phase
Correct Answer: Exponential phase
Explanation:
The optical density doubles at each equal interval, indicating approximately constant proportional growth characteristic of the exponential phase.
Incorrect! Try again.
24Why are growth-curve data commonly plotted as log cell density or log OD against time?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.It converts exponential growth into a straight line
B.It makes all measurements independent of wavelength
C.It removes the need for blank correction
D.It prevents stationary-phase cells from dying
Correct Answer: It converts exponential growth into a straight line
Explanation:
During exponential growth, taking the logarithm of cell density produces a linear relationship with time, making growth-rate analysis easier.
Incorrect! Try again.
25An E. coli culture increases from an OD600 of 0.15 to 0.60 during exponential growth. How many doublings occurred?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.One doubling
B.Four doublings
C.Three doublings
D.Two doublings
Correct Answer: Two doublings
Explanation:
The increase is fourfold, and , so the culture underwent two doublings.
Incorrect! Try again.
26The OD600 of an E. coli culture increases from 0.20 to 0.80 in 60 minutes during exponential growth. What is the approximate generation time?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.15 minutes
B.30 minutes
C.20 minutes
D.60 minutes
Correct Answer: 30 minutes
Explanation:
The OD increases fourfold, equivalent to two generations. Therefore, the generation time is minutes.
Incorrect! Try again.
27Which observation most strongly indicates that an E. coli culture has entered the stationary phase?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.OD is zero after inoculation
B.OD remains nearly constant with time
C.OD decreases immediately after inoculation
D.OD increases rapidly with time
Correct Answer: OD remains nearly constant with time
Explanation:
In the stationary phase, the overall population remains approximately constant because cell formation is balanced by cell death or growth limitation.
Incorrect! Try again.
28A culture shows little change in OD immediately after inoculation, followed by a rapid increase. What is the most likely explanation for the initial period?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.Cells are undergoing maximum lysis
B.Cells are adapting to the new medium
C.The culture has already reached death phase
D.The spectrophotometer is measuring only salts
Correct Answer: Cells are adapting to the new medium
Explanation:
The lag phase occurs while cells adjust their metabolism and synthesize components needed for active division in the new environment.
Incorrect! Try again.
29Why should a turbidimetric sample be mixed gently before transferring it to the cuvette?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.To sterilize the suspension
B.To distribute cells uniformly
C.To increase the wavelength
D.To reduce the incubation temperature
Correct Answer: To distribute cells uniformly
Explanation:
Gentle mixing resuspends settled cells and produces a representative sample for the optical density measurement.
Incorrect! Try again.
30An OD600 reading is above the linear range of the spectrophotometer. What should be done before using the value for growth analysis?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.Dilute the sample and multiply by the dilution factor
B.Record the reading without any correction
C.Add sterile cells to lower the absorbance
D.Replace the culture with distilled water
Correct Answer: Dilute the sample and multiply by the dilution factor
Explanation:
Dilution brings the sample into the instrument's reliable range. The original OD is estimated by multiplying the measured value by the dilution factor.
Incorrect! Try again.
31A 1:10 dilution of a culture gives an OD600 of 0.35. What is the estimated OD600 of the undiluted culture, assuming linearity?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.0.35
B.3.5
C.0.035
D.35.0
Correct Answer: 3.5
Explanation:
A 1:10 dilution has a dilution factor of 10, so the estimated original OD is .
Incorrect! Try again.
32Which set of measurements is most suitable for determining the shape of an E. coli growth curve?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.Repeated readings at planned time intervals
B.One reading at the end of incubation
C.A single reading from an uninoculated broth
D.Several readings taken only during inoculation
Correct Answer: Repeated readings at planned time intervals
Explanation:
A growth curve requires changes in turbidity over time, so repeated measurements at regular intervals are necessary to identify growth phases.
Incorrect! Try again.
33If time is plotted on the horizontal axis and OD600 on the vertical axis using a linear scale, what feature is usually expected during exponential growth?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.A horizontal line from the beginning
B.A sudden drop followed by zero readings
C.A straight line with constant slope
D.A gradually steepening upward curve
Correct Answer: A gradually steepening upward curve
Explanation:
On a linear OD-versus-time graph, exponential growth appears curved because the absolute increase becomes larger as the population increases.
Incorrect! Try again.
34Which change would most likely shorten the lag phase when preparing an E. coli growth curve?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.Transferring cells into an unsuitable medium
B.Using a very old stationary culture
C.Using a fresh active inoculum
D.Incubating below the organism's growth range
Correct Answer: Using a fresh active inoculum
Explanation:
Cells taken from an actively growing culture are already metabolically prepared for division, so they generally require less adaptation time.
Incorrect! Try again.
35Why should the same cuvette orientation be maintained when measuring a series of turbidity samples?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.It reduces variation from optical imperfections
B.It increases bacterial multiplication
C.It changes the cells into a standard size
D.It prevents the broth from evaporating
Correct Answer: It reduces variation from optical imperfections
Explanation:
Small differences in cuvette surfaces or scratches can affect light transmission. Consistent orientation improves measurement comparability.
Incorrect! Try again.
36Two replicate OD600 readings at the same time are 0.42 and 0.58. What is the best immediate response?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.Average them without checking technique
B.Choose the larger value as the correct one
C.Repeat the measurements after checking mixing
D.Discard all samples from the experiment
Correct Answer: Repeat the measurements after checking mixing
Explanation:
A large difference may result from poor mixing, bubbles, or cuvette problems. These should be checked before calculating an average.
Incorrect! Try again.
37What is a major limitation of using OD600 alone to estimate viable E. coli cell numbers?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.It cannot detect changes in light scattering
B.It measures turbidity rather than viability
C.It detects only bacterial DNA
D.It requires colonies on agar for every reading
Correct Answer: It measures turbidity rather than viability
Explanation:
Optical density reflects light scattering by particles, including dead cells and debris, so it does not directly distinguish viable from nonviable cells.
Incorrect! Try again.
38During the late part of a growth experiment, OD600 decreases gradually. Which interpretation is most appropriate?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.The blank has become more concentrated
B.The cells have just begun adapting
C.The culture is entering exponential growth
D.The culture may be entering the death phase
Correct Answer: The culture may be entering the death phase
Explanation:
A gradual decrease in turbidity can indicate cell death and lysis after nutrients become depleted or harmful metabolic products accumulate.
Incorrect! Try again.
39The slope of a plot of versus time during exponential growth is . What does this slope represent?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.The initial cell count
B.The dilution factor
C.The wavelength of measurement
D.The specific growth rate
Correct Answer: The specific growth rate
Explanation:
For exponential growth, , so the slope of the logarithmic plot is the specific growth rate .
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40Why should bubbles be removed from a cuvette before recording OD600?
To study and plot the growth curve of Escherichia coli by turbidimetric method
Medium
A.Bubbles prevent the blank from being prepared
B.Bubbles scatter light and falsely raise the reading
C.Bubbles consume nutrients and lower cell viability
D.Bubbles convert OD600 into a cell count
Correct Answer: Bubbles scatter light and falsely raise the reading
Explanation:
Air bubbles act as additional scattering surfaces and can produce an artificially high or unstable turbidity value.
Incorrect! Try again.
41An E. coli culture gives blank-corrected OD readings of 0.08, 0.16, and 0.32 at 20-minute intervals during exponential growth. What is the estimated specific growth rate?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The OD doubles every 20 minutes, so .
Incorrect! Try again.
42A culture has an observed OD of 0.62, while the uninoculated medium has an OD of 0.08. The culture is diluted fourfold before measurement. What is the estimated original culture OD?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.0.54
B.2.16
C.2.48
D.1.54
Correct Answer: 2.16
Explanation:
The corrected diluted OD is . Multiplying by the dilution factor gives .
Incorrect! Try again.
43The corrected OD of an E. coli culture increases from 0.10 to 0.80 during a 90-minute interval in exponential phase. What is the approximate generation time?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.15 minutes
B.30 minutes
C.45 minutes
D.60 minutes
Correct Answer: 30 minutes
Explanation:
The OD increases eightfold, equivalent to three doublings. Therefore, the generation time is minutes.
Incorrect! Try again.
44A plot of versus time gives a slope of during exponential growth. What is the corresponding generation time?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.20.0 minutes
B.24.0 minutes
C.12.0 minutes
D.34.7 minutes
Correct Answer: 24.0 minutes
Explanation:
Generation time is . Thus, minutes.
Incorrect! Try again.
45An OD-versus-time curve reaches a stable plateau. Which conclusion is scientifically justified from turbidimetric data alone?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.All nutrients have been quantitatively exhausted
B.The cells have completely lost viability
C.The culture has entered a genetically stable phase
D.The culture has entered a non-increasing turbidity phase
Correct Answer: The culture has entered a non-increasing turbidity phase
Explanation:
A plateau indicates that turbidity is no longer increasing. It does not identify the exact limiting factor or prove that the cells are nonviable.
Incorrect! Try again.
46The observed OD of a culture is 0.42, and the medium blank is 0.12. What OD should be plotted for the culture?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.0.54
B.0.42
C.0.12
D.0.30
Correct Answer: 0.30
Explanation:
The culture turbidity is corrected by subtracting the medium contribution: .
Incorrect! Try again.
47An E. coli sample gives an OD of 1.40, exceeding the validated linear range of the spectrophotometer. What is the best procedure?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.Increase the wavelength until the reading becomes linear
B.Use 1.40 directly in the growth plot
C.Dilute the sample into range and multiply by the dilution factor
D.Convert 1.40 to cell number without dilution
Correct Answer: Dilute the sample into range and multiply by the dilution factor
Explanation:
Measurements outside the linear range are unreliable. A diluted sample should be measured within range and corrected using the dilution factor.
Incorrect! Try again.
48Which plotting strategy most reliably identifies the exponential phase from turbidimetric measurements?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.Plot elapsed time against the blank OD
B.Plot inverse OD against elapsed time
C.Plot raw OD against elapsed time
D.Plot against elapsed time
Correct Answer: Plot against elapsed time
Explanation:
Exponential growth follows , so versus time should be linear during exponential phase.
Incorrect! Try again.
49Two cultures have identical initial OD values, but one was prepared from a late-stationary-phase inoculum and shows a prolonged delay before exponential increase. What is the most likely explanation?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.The inoculum has a different physiological state
B.The medium blank has increased the viable cell count
C.The spectrophotometer has automatically changed its wavelength
D.The stationary phase always produces a higher growth rate
Correct Answer: The inoculum has a different physiological state
Explanation:
Cells taken from different physiological states may require different adaptation periods, producing different lag phases despite equal initial turbidity.
Incorrect! Try again.
50During apparent exponential growth, one OD reading is unexpectedly lower than the preceding reading, although the culture is otherwise healthy. Which procedural issue is most plausible?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.The wavelength was correct for every possible cuvette
B.The culture was not mixed consistently before measurement
C.The blank correction increased the cell concentration
Correct Answer: The culture was not mixed consistently before measurement
Explanation:
Poor resuspension, settling, or clumping can cause variable light scattering and produce an artificial decrease in OD.
Incorrect! Try again.
51A calibration relationship states that an OD of 1.00 corresponds to cells/mL. What cell concentration corresponds to a corrected OD of 0.45?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A. cells/mL
B. cells/mL
C. cells/mL
D. cells/mL
Correct Answer: cells/mL
Explanation:
Using the calibration relationship, cells/mL.
Incorrect! Try again.
52The corrected OD increases from 0.20 to 0.50 in 40 minutes during exponential growth. What is the approximate generation time?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.30.3 minutes
B.40.0 minutes
C.20.0 minutes
D.24.8 minutes
Correct Answer: 30.3 minutes
Explanation:
The specific growth rate is . Therefore, minutes.
Incorrect! Try again.
53A sample is mixed with an equal volume of sterile diluent. Its measured OD is 0.20, and the blank-corrected value is negligible. What is the estimated original OD?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.0.20
B.0.40
C.0.10
D.0.60
Correct Answer: 0.40
Explanation:
Equal-volume dilution produces a twofold dilution. The original OD is therefore .
Incorrect! Try again.
54Why can a straight line on a raw OD-versus-time plot be misleading when identifying exponential growth?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.Raw OD values are unrelated to cell concentration
B.Turbidity decreases whenever the cell number increases
C.Exponential growth is linear only after taking a logarithm
D.A straight raw-OD segment proves that growth has stopped
Correct Answer: Exponential growth is linear only after taking a logarithm
Explanation:
Exponential growth becomes linear when is plotted against time, not necessarily when raw OD is plotted.
Incorrect! Try again.
55Triplicate OD readings for one time point are 0.31, 0.32, and 0.47, while adjacent time points are consistent. What is the most appropriate response?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.Check for bubbles, mixing, and instrument error before repeating
B.Average all three values without inspection
C.Replace 0.47 with the value from the prior time point
D.Delete the entire growth curve from the experiment
Correct Answer: Check for bubbles, mixing, and instrument error before repeating
Explanation:
The isolated high value is a potential technical outlier. Its cause should be investigated and the measurement repeated before exclusion.
Incorrect! Try again.
56Why should the medium blank ideally be incubated and measured under the same conditions as the inoculated culture?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.To account for time-dependent changes in medium background
B.To ensure the blank contains the same number of cells
C.To increase the culture's generation time artificially
D.To make the blank absorb more light than the culture
Correct Answer: To account for time-dependent changes in medium background
Explanation:
Medium color, precipitates, or other background changes during incubation can affect turbidity measurements and should be corrected with a matched blank.
Incorrect! Try again.
57An E. coli culture has reached a turbidity plateau. Which additional measurement is most useful for determining whether viable cell numbers are declining?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.A second reading of the same saturated OD
B.A viable count obtained by serial dilution and plating
C.The color of the uninoculated medium
D.The wavelength setting without any sample dilution
Correct Answer: A viable count obtained by serial dilution and plating
Explanation:
Turbidity reflects suspended particles and may remain constant while viability changes. Colony counts provide evidence about viable cells.
Incorrect! Try again.
58Repeatedly removing aliquots from a single culture flask can distort a growth curve primarily because it changes the culture volume and may introduce contamination. What is the best design for frequent sampling?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.Use separate identically inoculated flasks for each time point
B.Estimate later OD values from the initial reading
C.Add sterile water after every sample removal
D.Remove increasingly large aliquots from one flask
Correct Answer: Use separate identically inoculated flasks for each time point
Explanation:
Parallel flasks allow destructive sampling without changing the volume, aeration, or contamination risk in the remaining cultures.
Incorrect! Try again.
59The corrected OD rises from 0.125 to 1.000 in 75 minutes during exponential growth. What is the generation time?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.75 minutes
B.37.5 minutes
C.18.75 minutes
D.25 minutes
Correct Answer: 25 minutes
Explanation:
The OD increases eightfold, corresponding to three doublings. Thus, the generation time is minutes.
Incorrect! Try again.
60An exponential-phase fit gives and an initial corrected OD of 0.20. What is the predicted OD after 60 minutes, and what experimental concern follows?
To study and plot the growth curve of Escherichia coli by turbidimetric method.
Hard
A.0.42; the culture will be below the detection limit
B.1.10; the culture will certainly be in lag phase
C.2.21; the value may exceed the validated linear range
D.4.80; the blank correction must be omitted
Correct Answer: 2.21; the value may exceed the validated linear range
Explanation:
Using gives approximately . This may require dilution before reliable measurement.
Incorrect! Try again.
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