Unit 5: Antioxidant Activity - Practice Quiz

BTY301 — Biochemistry Laboratory 60 Questions
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1 What is the main purpose of measuring antioxidant activity in a food sample?

Determination of total antioxidant activity of food sample Easy
A. To estimate its ability to neutralize oxidants
B. To measure its protein content
C. To identify its microbial species
D. To determine its water content

2 Which instrument is commonly used to measure absorbance in an antioxidant assay?

Determination of total antioxidant activity of food sample Easy
A. Spectrophotometer
B. Microscope
C. Autoclave
D. Centrifuge

3 What does a reagent blank usually contain?

Determination of total antioxidant activity of food sample Easy
A. The sample and standard together
B. All reagents except the sample
C. Only the food sample
D. Only distilled water

4 Why is a standard solution used in a total antioxidant activity assay?

Determination of total antioxidant activity of food sample Easy
A. To increase sample volume
B. To compare antioxidant activity
C. To sterilize the food extract
D. To remove the solvent

5 What is an antioxidant?

Determination of total antioxidant activity of food sample Easy
A. A substance that digests proteins
B. A substance that forms starch
C. A substance that always increases oxidation
D. A substance that reduces oxidation

6 What is usually prepared from a food sample before testing its antioxidant activity?

Determination of total antioxidant activity of food sample Easy
A. A bacterial culture
B. A suitable sample extract
C. A dry glass plate
D. A metal electrode

7 What may happen to the absorbance when more colored product is formed in an assay?

Determination of total antioxidant activity of food sample Easy
A. The cuvette becomes heavier
B. The wavelength disappears
C. The absorbance may increase
D. The absorbance always becomes zero

8 Why should the same wavelength be used for comparable assay readings?

Determination of total antioxidant activity of food sample Easy
A. To prevent pipette calibration
B. To ensure consistent measurements
C. To change the sample color
D. To remove all antioxidants

9 What is a common reason for testing a sample in duplicate or triplicate?

Determination of total antioxidant activity of food sample Easy
A. To avoid measuring absorbance
B. To change the sample identity
C. To improve result reliability
D. To eliminate the need for reagents

10 Which type of water is generally preferred for preparing assay solutions?

Determination of total antioxidant activity of food sample Easy
A. Seawater
B. Sugary water
C. Distilled water
D. Oily water

11 What does TLC stand for?

Demonstration of thin layer chromatography Easy
A. Thin-layer chromatography
B. Thermal laboratory culture
C. Transfer layer calculation
D. Total liquid concentration

12 What is the stationary phase in a common TLC plate?

Demonstration of thin layer chromatography Easy
A. A strip of filter paper
B. A tube of sample solution
C. A pool of solvent
D. A layer of silica gel

13 What is the mobile phase in TLC?

Demonstration of thin layer chromatography Easy
A. The sample spot at the origin
B. The solvent that moves upward
C. The pencil used for marking
D. The coated plate surface

14 Where should the sample be applied on a TLC plate?

Demonstration of thin layer chromatography Easy
A. On a marked origin line
B. Inside the solvent bottle
C. At the top edge
D. Below the lower edge

15 Why is pencil commonly used to mark a TLC plate?

Demonstration of thin layer chromatography Easy
A. Graphite acts as the solvent
B. Pencil removes the stationary phase
C. Pencil ink increases separation
D. Graphite does not usually dissolve

16 What is the solvent front in TLC?

Demonstration of thin layer chromatography Easy
A. The furthest point reached by solvent
B. The original sample spot
C. The thickness of the silica layer
D. The bottom of the plate

17 What does an value compare?

Demonstration of thin layer chromatography Easy
A. Spot color with spot brightness
B. Solute distance with solvent distance
C. Plate width with plate thickness
D. Sample mass with solvent volume

18 Which formula represents the TLC retention factor?

Demonstration of thin layer chromatography Easy
A.
B.
C.
D.

19 What does one spot on a TLC plate commonly suggest about a sample?

Demonstration of thin layer chromatography Easy
A. It cannot dissolve in the solvent
B. It must contain no compounds
C. It always contains four components
D. It may contain one major component

20 How can colorless compounds on a TLC plate often be detected?

Demonstration of thin layer chromatography Easy
A. By weighing the plate
B. By freezing the solvent
C. By adding distilled water only
D. By ultraviolet light or a stain

21 In a DPPH assay, a food extract causes the absorbance of the DPPH solution to decrease. What does this decrease primarily indicate?

Determination of total antioxidant activity of food sample Medium
A. The extract has reduced DPPH radicals
B. The extract has increased the reaction temperature
C. The extract has absorbed all assay solvent
D. The extract has increased DPPH radicals

22 A sample has an initial DPPH absorbance of 0.800 and a final absorbance of 0.320. What is the percentage of radical-scavenging activity?

Determination of total antioxidant activity of food sample Medium
A. 72%
B. 50%
C. 60%
D. 40%

23 Why is a reagent blank included when determining antioxidant activity spectrophotometrically?

Determination of total antioxidant activity of food sample Medium
A. To measure solvent or reagent absorbance
B. To increase the sample antioxidant concentration
C. To establish the sample extraction temperature
D. To convert antioxidants into colored products

24 A calibration curve for a standard antioxidant is used mainly to:

Determination of total antioxidant activity of food sample Medium
A. Remove interfering pigments from the sample extract
B. Identify the food sample's chromatographic solvent
C. Convert absorbance into equivalent antioxidant concentration
D. Determine the wavelength of maximum solvent absorption

25 If the absorbance of a sample is higher than the reagent control in a colorimetric antioxidant assay, the most appropriate first action is to:

Determination of total antioxidant activity of food sample Medium
A. Check for sample color interference
B. Assume the sample contains no antioxidants
C. Increase the incubation time without further checks
D. Report the result as maximum activity

26 Why should replicate measurements be performed for a food antioxidant assay?

Determination of total antioxidant activity of food sample Medium
A. To estimate precision and reduce random error
B. To increase the wavelength used for measurement
C. To eliminate the need for a calibration curve
D. To guarantee that all antioxidants are identified

27 An antioxidant assay is performed on 2.0 g of food, and the extract is made up to 25 mL. Which change would most directly affect the reported activity per gram?

Determination of total antioxidant activity of food sample Medium
A. Changing the cuvette optical path label
B. Changing the final extract volume
C. Changing the color of the laboratory coat
D. Changing the order of sample names in the worksheet

28 Why is a fixed incubation time important in a DPPH antioxidant assay?

Determination of total antioxidant activity of food sample Medium
A. The solvent becomes chemically inert after incubation
B. The cuvette path length changes during incubation
C. The reaction may continue changing with time
D. The food extract becomes a chromatographic stationary phase

29 A diluted extract gives an antioxidant activity within the calibration range, while the undiluted extract exceeds it. Which result is preferable for quantification?

Determination of total antioxidant activity of food sample Medium
A. The diluted result after applying its dilution factor
B. The undiluted result extrapolated beyond the curve
C. The average of both results without correction
D. The diluted result reported without concentration correction

30 If two extracts show 80% and 40% DPPH inhibition at the same concentration, what is the most reasonable conclusion?

Determination of total antioxidant activity of food sample Medium
A. The second extract has greater radical-scavenging activity
B. Both extracts necessarily contain equal antioxidant amounts
C. The result proves that the first extract has no pigments
D. The first extract has greater radical-scavenging activity

31 In thin layer chromatography, the stationary phase is usually:

Demonstration of thin layer chromatography Medium
A. A thin layer of silica gel
B. A mixture of volatile solvents
C. A colored sample solution
D. A stream of developing vapor

32 A compound travels 3.0 cm while the solvent front travels 6.0 cm. What is the compound's value?

Demonstration of thin layer chromatography Medium
A. 1.50
B. 0.50
C. 0.25
D. 2.00

33 Why must the sample spot be placed above the solvent level in the developing chamber?

Demonstration of thin layer chromatography Medium
A. To make the stationary phase completely nonpolar
B. To prevent the solvent front from moving upward
C. To force every compound to have the same
D. To prevent the sample from dissolving into the solvent reservoir

34 A mixture produces three separate spots on a TLC plate. This observation most directly suggests that the mixture:

Demonstration of thin layer chromatography Medium
A. Contains only one component at three concentrations
B. Contains at least three detectable components
C. Was applied below the solvent level
D. Has failed to interact with the stationary phase

35 For a silica TLC plate, which compound would generally have the lower in the same solvent system?

Demonstration of thin layer chromatography Medium
A. A more polar compound
B. A less polar compound
C. A compound applied in a smaller volume
D. A compound with a smaller spot

36 Why is a pencil preferred over ink for marking the origin and solvent front on a TLC plate?

Demonstration of thin layer chromatography Medium
A. Ink always increases silica polarity uniformly
B. Graphite does not usually dissolve and migrate
C. Graphite reacts with every sample component
D. Ink prevents the solvent from entering the plate

37 If the solvent front is not marked immediately after removing the TLC plate, the calculated value may be inaccurate because:

Demonstration of thin layer chromatography Medium
A. All analytes return to the origin after removal
B. The silica changes into a liquid stationary phase
C. The solvent can continue evaporating from the plate
D. The sample spots become chemically identical

38 Two compounds have identical values in one solvent system. What is the best interpretation?

Demonstration of thin layer chromatography Medium
A. They must have different stationary phases
B. They may be identical, but identity is not proven
C. They cannot be separated in any solvent system
D. They definitely have different molecular formulas

39 A TLC spot remains near the origin even after development. Which adjustment would most likely improve its movement?

Demonstration of thin layer chromatography Medium
A. Use a shorter development distance
B. Use a more polar mobile phase
C. Replace the silica plate with a dry filter paper without testing
D. Apply the sample directly into the solvent reservoir

40 Why should a TLC sample be applied as a small, concentrated spot rather than a large wet spot?

Demonstration of thin layer chromatography Medium
A. To increase the plate thickness during development
B. To obtain sharper and better-separated bands
C. To ensure the sample never contacts silica
D. To make the solvent front stop at the origin

41 A food extract gives an absorbance of 0.620 at 695 nm. The ascorbic-acid calibration equation is , where is in . If the extract was diluted 20-fold before measurement and prepared from 0.50 g of food to a final volume of 25 mL, what is the antioxidant activity in mg ascorbic-acid equivalents per gram of food?

Determination of total antioxidant activity of food sample Hard
A. 60.0 mg AAE/g
B. 24.0 mg AAE/g
C. 50.0 mg AAE/g
D. 48.0 mg AAE/g

42 In a phosphomolybdenum total antioxidant assay, the sample absorbance is 0.410, the reagent blank is 0.080, and the sample matrix blank without molybdate reagent is 0.050. The standard curve is . Which concentration should be used to calculate the sample antioxidant equivalent?

Determination of total antioxidant activity of food sample Hard
A. 38.0
B. 33.0
C. 30.0
D. 35.0

43 A calibration curve is linear from 10 to 80 . A diluted sample produces an absorbance corresponding to 135 . Which action gives the most defensible result?

Determination of total antioxidant activity of food sample Hard
A. Extrapolate the calibration line to 135
B. Subtract the highest standard from the sample signal
C. Report 135 directly
D. Dilute the sample further and repeat the measurement

44 Two food extracts have identical total antioxidant-equivalent values by the phosphomolybdenum assay, but one has a much higher ferric-reducing power. What is the best interpretation?

Determination of total antioxidant activity of food sample Hard
A. The assays respond differently to antioxidant compounds
B. The extracts contain identical antioxidant molecules
C. The phosphomolybdenum assay has no quantitative value
D. The assays must have identical selectivity

45 A sample is tested at two dilutions. The 10-fold dilution gives 0.88 absorbance, whereas the 20-fold dilution gives 0.47. The calibration range is 0.10–0.80 absorbance. Which result should be accepted for quantification?

Determination of total antioxidant activity of food sample Hard
A. Neither result because dilution changes antioxidant chemistry
B. The 10-fold result because it is less diluted
C. The average because both readings are reproducible
D. The 20-fold result because it lies within range

46 A food sample is extracted twice. The first extraction recovers 82% of the final measured antioxidant activity, and the second recovers the remaining 18%. If only the first extract is assayed, what is the principal consequence?

Determination of total antioxidant activity of food sample Hard
A. The antioxidant concentration is underestimated
B. The antioxidant concentration is overestimated
C. The calibration slope becomes steeper
D. The reagent blank becomes negligible

47 A sample extract is intensely colored at the assay wavelength. The reaction mixture has an absorbance of 0.900, while a sample blank containing extract and solvent but no assay reagent has an absorbance of 0.300. What is the primary correction?

Determination of total antioxidant activity of food sample Hard
A. Add the blank absorbance to the reaction value
B. Ignore the blank because color is sample-specific
C. Divide the reaction value by the sample blank
D. Subtract the sample blank from the reaction value

48 For a standard curve, concentrations are 0, 20, 40, 60, and 80 , with absorbances 0.02, 0.19, 0.37, 0.55, and 0.73. The unknown gives 0.46. Which concentration is the most appropriate estimate by linear interpolation?

Determination of total antioxidant activity of food sample Hard
A. 55.0
B. 50.0
C. 45.0
D. 40.0

49 A standard curve has slope 0.015 absorbance units per and an intercept of 0.025. Replicate sample readings are 0.410, 0.414, and 0.620. Which statistical decision is most appropriate before calculating antioxidant activity?

Determination of total antioxidant activity of food sample Hard
A. Use only the middle reading as the result
B. Average all readings without inspection
C. Investigate the high reading as a possible outlier
D. Discard the lowest reading automatically

50 A result is reported as 12.6 mg Trolox equivalents per gram using a 0.200 g sample extracted to 10.0 mL. If the analyst accidentally records the sample mass as 0.0200 g during back-calculation, how will the reported value change?

Determination of total antioxidant activity of food sample Hard
A. It will be one hundred times too high
B. It will be ten times too high
C. It will be unchanged
D. It will be ten times too low

51 A TLC plate has a solvent-front distance of 8.0 cm. Compound X travels 2.4 cm and compound Y travels 5.6 cm. Which conclusion is justified?

Demonstration of thin layer chromatography Hard
A. X is always more polar than Y
B. Y must have twice the molecular mass of X
C. The of X is 0.70 and Y is 0.30
D. The of X is 0.30 and Y is 0.70

52 On a silica TLC plate developed with a relatively nonpolar solvent, an antioxidant spot remains near the origin while a second spot travels close to the solvent front. Which interpretation is most likely?

Demonstration of thin layer chromatography Hard
A. The front spot is necessarily more polar
B. The origin spot interacts more strongly with silica
C. The origin spot has the lower molecular mass
D. The solvent front was measured from the origin incorrectly

53 A sample spot is applied below the solvent level in the developing chamber. What chromatographic artifact is most expected?

Demonstration of thin layer chromatography Hard
A. The stationary phase will become chemically nonpolar
B. The sample will dissolve directly into the solvent reservoir
C. The solvent front will move without capillary action
D. The spot will remain sharply fixed at the origin

54 A TLC plate develops with a curved solvent front, and compounds near the edges show different values from identical compounds in the center. Which procedural change best addresses the problem?

Demonstration of thin layer chromatography Hard
A. Measure all distances from the plate midpoint
B. Scratch deeper channels across the stationary phase
C. Increase the spotting volume at the plate edges
D. Use a level chamber and pre-equilibrate it

55 A sample produces one visible spot in solvent system A but three well-separated spots in solvent system B. What is the strongest conclusion?

Demonstration of thin layer chromatography Hard
A. The sample is pure because one system gives one spot
B. Solvent B chemically synthesized two new compounds
C. The sample contains components resolved more effectively by B
D. Solvent A permanently destroyed the stationary phase

56 The solvent front reaches the top edge of a TLC plate before the plate is removed. Why are the resulting values less reliable?

Demonstration of thin layer chromatography Hard
A. The silica layer becomes completely soluble
B. All compounds become permanently fluorescent
C. The denominator approaches the plate length limit
D. The solvent front becomes impossible to identify

57 A compound gives in a solvent system. Which adjustment is most likely to improve separation from the solvent front?

Demonstration of thin layer chromatography Hard
A. Use a less polar mobile phase
B. Increase the chamber temperature sharply
C. Use a more polar mobile phase
D. Apply a larger sample spot

58 A TLC spot appears as a broad streak rather than a compact band. Which combination of causes is most plausible?

Demonstration of thin layer chromatography Hard
A. A low analyte concentration and immediate development
B. A perfectly saturated chamber and a tiny sample
C. A short origin distance and a fresh silica surface
D. Excess sample and incomplete drying between applications

59 Two antioxidant standards have values of 0.42 and 0.44, while an unknown gives one spot at 0.43 under the same conditions. What is the strongest defensible claim?

Demonstration of thin layer chromatography Hard
A. The unknown may contain a compound matching either standard
B. The unknown contains neither standard under any condition
C. The unknown has exactly the same molecular structure as both standards
D. The unknown contains both standards in equal amounts

60 A TLC plate is viewed under UV light, but the antioxidant compound is not visible. The solvent front and a reference standard are visible. Which explanation is most likely?

Demonstration of thin layer chromatography Hard
A. The solvent front converted the compound into silica
B. The compound may lack a UV-active chromophore
C. The reference standard proves the sample was absent
D. The compound must have an greater than one