Unit 5: Antioxidant Activity - Practice Quiz

BTY301 — Biochemistry Laboratory 60 Questions
0 Correct 0 Wrong 60 Left
0/60

1 What is the main purpose of measuring antioxidant activity in a food sample?

Determination of total antioxidant activity of food sample Easy
A. To identify its microbial species
B. To measure its protein content
C. To determine its water content
D. To estimate its ability to neutralize oxidants

2 Which instrument is commonly used to measure absorbance in an antioxidant assay?

Determination of total antioxidant activity of food sample Easy
A. Autoclave
B. Centrifuge
C. Spectrophotometer
D. Microscope

3 What does a reagent blank usually contain?

Determination of total antioxidant activity of food sample Easy
A. Only the food sample
B. The sample and standard together
C. Only distilled water
D. All reagents except the sample

4 Why is a standard solution used in a total antioxidant activity assay?

Determination of total antioxidant activity of food sample Easy
A. To compare antioxidant activity
B. To increase sample volume
C. To sterilize the food extract
D. To remove the solvent

5 What is an antioxidant?

Determination of total antioxidant activity of food sample Easy
A. A substance that forms starch
B. A substance that digests proteins
C. A substance that always increases oxidation
D. A substance that reduces oxidation

6 What is usually prepared from a food sample before testing its antioxidant activity?

Determination of total antioxidant activity of food sample Easy
A. A metal electrode
B. A suitable sample extract
C. A dry glass plate
D. A bacterial culture

7 What may happen to the absorbance when more colored product is formed in an assay?

Determination of total antioxidant activity of food sample Easy
A. The absorbance may increase
B. The absorbance always becomes zero
C. The cuvette becomes heavier
D. The wavelength disappears

8 Why should the same wavelength be used for comparable assay readings?

Determination of total antioxidant activity of food sample Easy
A. To ensure consistent measurements
B. To remove all antioxidants
C. To prevent pipette calibration
D. To change the sample color

9 What is a common reason for testing a sample in duplicate or triplicate?

Determination of total antioxidant activity of food sample Easy
A. To improve result reliability
B. To change the sample identity
C. To eliminate the need for reagents
D. To avoid measuring absorbance

10 Which type of water is generally preferred for preparing assay solutions?

Determination of total antioxidant activity of food sample Easy
A. Oily water
B. Distilled water
C. Sugary water
D. Seawater

11 What does TLC stand for?

Demonstration of thin layer chromatography Easy
A. Total liquid concentration
B. Transfer layer calculation
C. Thermal laboratory culture
D. Thin-layer chromatography

12 What is the stationary phase in a common TLC plate?

Demonstration of thin layer chromatography Easy
A. A pool of solvent
B. A layer of silica gel
C. A tube of sample solution
D. A strip of filter paper

13 What is the mobile phase in TLC?

Demonstration of thin layer chromatography Easy
A. The pencil used for marking
B. The solvent that moves upward
C. The coated plate surface
D. The sample spot at the origin

14 Where should the sample be applied on a TLC plate?

Demonstration of thin layer chromatography Easy
A. At the top edge
B. Inside the solvent bottle
C. On a marked origin line
D. Below the lower edge

15 Why is pencil commonly used to mark a TLC plate?

Demonstration of thin layer chromatography Easy
A. Pencil removes the stationary phase
B. Graphite does not usually dissolve
C. Pencil ink increases separation
D. Graphite acts as the solvent

16 What is the solvent front in TLC?

Demonstration of thin layer chromatography Easy
A. The thickness of the silica layer
B. The original sample spot
C. The bottom of the plate
D. The furthest point reached by solvent

17 What does an value compare?

Demonstration of thin layer chromatography Easy
A. Sample mass with solvent volume
B. Solute distance with solvent distance
C. Spot color with spot brightness
D. Plate width with plate thickness

18 Which formula represents the TLC retention factor?

Demonstration of thin layer chromatography Easy
A.
B.
C.
D.

19 What does one spot on a TLC plate commonly suggest about a sample?

Demonstration of thin layer chromatography Easy
A. It must contain no compounds
B. It may contain one major component
C. It always contains four components
D. It cannot dissolve in the solvent

20 How can colorless compounds on a TLC plate often be detected?

Demonstration of thin layer chromatography Easy
A. By weighing the plate
B. By freezing the solvent
C. By adding distilled water only
D. By ultraviolet light or a stain

21 In a DPPH assay, a food extract causes the absorbance of the DPPH solution to decrease. What does this decrease primarily indicate?

Determination of total antioxidant activity of food sample Medium
A. The extract has increased the reaction temperature
B. The extract has absorbed all assay solvent
C. The extract has reduced DPPH radicals
D. The extract has increased DPPH radicals

22 A sample has an initial DPPH absorbance of 0.800 and a final absorbance of 0.320. What is the percentage of radical-scavenging activity?

Determination of total antioxidant activity of food sample Medium
A. 40%
B. 50%
C. 60%
D. 72%

23 Why is a reagent blank included when determining antioxidant activity spectrophotometrically?

Determination of total antioxidant activity of food sample Medium
A. To increase the sample antioxidant concentration
B. To convert antioxidants into colored products
C. To measure solvent or reagent absorbance
D. To establish the sample extraction temperature

24 A calibration curve for a standard antioxidant is used mainly to:

Determination of total antioxidant activity of food sample Medium
A. Identify the food sample's chromatographic solvent
B. Convert absorbance into equivalent antioxidant concentration
C. Remove interfering pigments from the sample extract
D. Determine the wavelength of maximum solvent absorption

25 If the absorbance of a sample is higher than the reagent control in a colorimetric antioxidant assay, the most appropriate first action is to:

Determination of total antioxidant activity of food sample Medium
A. Increase the incubation time without further checks
B. Check for sample color interference
C. Assume the sample contains no antioxidants
D. Report the result as maximum activity

26 Why should replicate measurements be performed for a food antioxidant assay?

Determination of total antioxidant activity of food sample Medium
A. To increase the wavelength used for measurement
B. To estimate precision and reduce random error
C. To eliminate the need for a calibration curve
D. To guarantee that all antioxidants are identified

27 An antioxidant assay is performed on 2.0 g of food, and the extract is made up to 25 mL. Which change would most directly affect the reported activity per gram?

Determination of total antioxidant activity of food sample Medium
A. Changing the cuvette optical path label
B. Changing the color of the laboratory coat
C. Changing the final extract volume
D. Changing the order of sample names in the worksheet

28 Why is a fixed incubation time important in a DPPH antioxidant assay?

Determination of total antioxidant activity of food sample Medium
A. The solvent becomes chemically inert after incubation
B. The cuvette path length changes during incubation
C. The food extract becomes a chromatographic stationary phase
D. The reaction may continue changing with time

29 A diluted extract gives an antioxidant activity within the calibration range, while the undiluted extract exceeds it. Which result is preferable for quantification?

Determination of total antioxidant activity of food sample Medium
A. The undiluted result extrapolated beyond the curve
B. The average of both results without correction
C. The diluted result reported without concentration correction
D. The diluted result after applying its dilution factor

30 If two extracts show 80% and 40% DPPH inhibition at the same concentration, what is the most reasonable conclusion?

Determination of total antioxidant activity of food sample Medium
A. The second extract has greater radical-scavenging activity
B. The result proves that the first extract has no pigments
C. Both extracts necessarily contain equal antioxidant amounts
D. The first extract has greater radical-scavenging activity

31 In thin layer chromatography, the stationary phase is usually:

Demonstration of thin layer chromatography Medium
A. A colored sample solution
B. A mixture of volatile solvents
C. A stream of developing vapor
D. A thin layer of silica gel

32 A compound travels 3.0 cm while the solvent front travels 6.0 cm. What is the compound's value?

Demonstration of thin layer chromatography Medium
A. 0.25
B. 0.50
C. 1.50
D. 2.00

33 Why must the sample spot be placed above the solvent level in the developing chamber?

Demonstration of thin layer chromatography Medium
A. To prevent the solvent front from moving upward
B. To force every compound to have the same
C. To prevent the sample from dissolving into the solvent reservoir
D. To make the stationary phase completely nonpolar

34 A mixture produces three separate spots on a TLC plate. This observation most directly suggests that the mixture:

Demonstration of thin layer chromatography Medium
A. Was applied below the solvent level
B. Contains only one component at three concentrations
C. Has failed to interact with the stationary phase
D. Contains at least three detectable components

35 For a silica TLC plate, which compound would generally have the lower in the same solvent system?

Demonstration of thin layer chromatography Medium
A. A compound with a smaller spot
B. A less polar compound
C. A more polar compound
D. A compound applied in a smaller volume

36 Why is a pencil preferred over ink for marking the origin and solvent front on a TLC plate?

Demonstration of thin layer chromatography Medium
A. Graphite reacts with every sample component
B. Graphite does not usually dissolve and migrate
C. Ink always increases silica polarity uniformly
D. Ink prevents the solvent from entering the plate

37 If the solvent front is not marked immediately after removing the TLC plate, the calculated value may be inaccurate because:

Demonstration of thin layer chromatography Medium
A. All analytes return to the origin after removal
B. The solvent can continue evaporating from the plate
C. The sample spots become chemically identical
D. The silica changes into a liquid stationary phase

38 Two compounds have identical values in one solvent system. What is the best interpretation?

Demonstration of thin layer chromatography Medium
A. They must have different stationary phases
B. They may be identical, but identity is not proven
C. They definitely have different molecular formulas
D. They cannot be separated in any solvent system

39 A TLC spot remains near the origin even after development. Which adjustment would most likely improve its movement?

Demonstration of thin layer chromatography Medium
A. Replace the silica plate with a dry filter paper without testing
B. Apply the sample directly into the solvent reservoir
C. Use a more polar mobile phase
D. Use a shorter development distance

40 Why should a TLC sample be applied as a small, concentrated spot rather than a large wet spot?

Demonstration of thin layer chromatography Medium
A. To increase the plate thickness during development
B. To ensure the sample never contacts silica
C. To obtain sharper and better-separated bands
D. To make the solvent front stop at the origin

41 A food extract gives an absorbance of 0.620 at 695 nm. The ascorbic-acid calibration equation is , where is in . If the extract was diluted 20-fold before measurement and prepared from 0.50 g of food to a final volume of 25 mL, what is the antioxidant activity in mg ascorbic-acid equivalents per gram of food?

Determination of total antioxidant activity of food sample Hard
A. 24.0 mg AAE/g
B. 60.0 mg AAE/g
C. 48.0 mg AAE/g
D. 50.0 mg AAE/g

42 In a phosphomolybdenum total antioxidant assay, the sample absorbance is 0.410, the reagent blank is 0.080, and the sample matrix blank without molybdate reagent is 0.050. The standard curve is . Which concentration should be used to calculate the sample antioxidant equivalent?

Determination of total antioxidant activity of food sample Hard
A. 38.0
B. 33.0
C. 35.0
D. 30.0

43 A calibration curve is linear from 10 to 80 . A diluted sample produces an absorbance corresponding to 135 . Which action gives the most defensible result?

Determination of total antioxidant activity of food sample Hard
A. Report 135 directly
B. Extrapolate the calibration line to 135
C. Subtract the highest standard from the sample signal
D. Dilute the sample further and repeat the measurement

44 Two food extracts have identical total antioxidant-equivalent values by the phosphomolybdenum assay, but one has a much higher ferric-reducing power. What is the best interpretation?

Determination of total antioxidant activity of food sample Hard
A. The assays respond differently to antioxidant compounds
B. The phosphomolybdenum assay has no quantitative value
C. The extracts contain identical antioxidant molecules
D. The assays must have identical selectivity

45 A sample is tested at two dilutions. The 10-fold dilution gives 0.88 absorbance, whereas the 20-fold dilution gives 0.47. The calibration range is 0.10–0.80 absorbance. Which result should be accepted for quantification?

Determination of total antioxidant activity of food sample Hard
A. The 10-fold result because it is less diluted
B. The average because both readings are reproducible
C. Neither result because dilution changes antioxidant chemistry
D. The 20-fold result because it lies within range

46 A food sample is extracted twice. The first extraction recovers 82% of the final measured antioxidant activity, and the second recovers the remaining 18%. If only the first extract is assayed, what is the principal consequence?

Determination of total antioxidant activity of food sample Hard
A. The antioxidant concentration is overestimated
B. The reagent blank becomes negligible
C. The calibration slope becomes steeper
D. The antioxidant concentration is underestimated

47 A sample extract is intensely colored at the assay wavelength. The reaction mixture has an absorbance of 0.900, while a sample blank containing extract and solvent but no assay reagent has an absorbance of 0.300. What is the primary correction?

Determination of total antioxidant activity of food sample Hard
A. Ignore the blank because color is sample-specific
B. Divide the reaction value by the sample blank
C. Add the blank absorbance to the reaction value
D. Subtract the sample blank from the reaction value

48 For a standard curve, concentrations are 0, 20, 40, 60, and 80 , with absorbances 0.02, 0.19, 0.37, 0.55, and 0.73. The unknown gives 0.46. Which concentration is the most appropriate estimate by linear interpolation?

Determination of total antioxidant activity of food sample Hard
A. 40.0
B. 50.0
C. 45.0
D. 55.0

49 A standard curve has slope 0.015 absorbance units per and an intercept of 0.025. Replicate sample readings are 0.410, 0.414, and 0.620. Which statistical decision is most appropriate before calculating antioxidant activity?

Determination of total antioxidant activity of food sample Hard
A. Investigate the high reading as a possible outlier
B. Discard the lowest reading automatically
C. Use only the middle reading as the result
D. Average all readings without inspection

50 A result is reported as 12.6 mg Trolox equivalents per gram using a 0.200 g sample extracted to 10.0 mL. If the analyst accidentally records the sample mass as 0.0200 g during back-calculation, how will the reported value change?

Determination of total antioxidant activity of food sample Hard
A. It will be ten times too high
B. It will be unchanged
C. It will be one hundred times too high
D. It will be ten times too low

51 A TLC plate has a solvent-front distance of 8.0 cm. Compound X travels 2.4 cm and compound Y travels 5.6 cm. Which conclusion is justified?

Demonstration of thin layer chromatography Hard
A. The of X is 0.70 and Y is 0.30
B. The of X is 0.30 and Y is 0.70
C. Y must have twice the molecular mass of X
D. X is always more polar than Y

52 On a silica TLC plate developed with a relatively nonpolar solvent, an antioxidant spot remains near the origin while a second spot travels close to the solvent front. Which interpretation is most likely?

Demonstration of thin layer chromatography Hard
A. The front spot is necessarily more polar
B. The origin spot interacts more strongly with silica
C. The solvent front was measured from the origin incorrectly
D. The origin spot has the lower molecular mass

53 A sample spot is applied below the solvent level in the developing chamber. What chromatographic artifact is most expected?

Demonstration of thin layer chromatography Hard
A. The stationary phase will become chemically nonpolar
B. The sample will dissolve directly into the solvent reservoir
C. The solvent front will move without capillary action
D. The spot will remain sharply fixed at the origin

54 A TLC plate develops with a curved solvent front, and compounds near the edges show different values from identical compounds in the center. Which procedural change best addresses the problem?

Demonstration of thin layer chromatography Hard
A. Use a level chamber and pre-equilibrate it
B. Increase the spotting volume at the plate edges
C. Scratch deeper channels across the stationary phase
D. Measure all distances from the plate midpoint

55 A sample produces one visible spot in solvent system A but three well-separated spots in solvent system B. What is the strongest conclusion?

Demonstration of thin layer chromatography Hard
A. Solvent B chemically synthesized two new compounds
B. Solvent A permanently destroyed the stationary phase
C. The sample is pure because one system gives one spot
D. The sample contains components resolved more effectively by B

56 The solvent front reaches the top edge of a TLC plate before the plate is removed. Why are the resulting values less reliable?

Demonstration of thin layer chromatography Hard
A. All compounds become permanently fluorescent
B. The denominator approaches the plate length limit
C. The silica layer becomes completely soluble
D. The solvent front becomes impossible to identify

57 A compound gives in a solvent system. Which adjustment is most likely to improve separation from the solvent front?

Demonstration of thin layer chromatography Hard
A. Apply a larger sample spot
B. Use a more polar mobile phase
C. Use a less polar mobile phase
D. Increase the chamber temperature sharply

58 A TLC spot appears as a broad streak rather than a compact band. Which combination of causes is most plausible?

Demonstration of thin layer chromatography Hard
A. Excess sample and incomplete drying between applications
B. A perfectly saturated chamber and a tiny sample
C. A short origin distance and a fresh silica surface
D. A low analyte concentration and immediate development

59 Two antioxidant standards have values of 0.42 and 0.44, while an unknown gives one spot at 0.43 under the same conditions. What is the strongest defensible claim?

Demonstration of thin layer chromatography Hard
A. The unknown contains neither standard under any condition
B. The unknown contains both standards in equal amounts
C. The unknown has exactly the same molecular structure as both standards
D. The unknown may contain a compound matching either standard

60 A TLC plate is viewed under UV light, but the antioxidant compound is not visible. The solvent front and a reference standard are visible. Which explanation is most likely?

Demonstration of thin layer chromatography Hard
A. The solvent front converted the compound into silica
B. The compound must have an greater than one
C. The compound may lack a UV-active chromophore
D. The reference standard proves the sample was absent