The acid value indicates the amount of free fatty acids present in a fat or oil.
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2The acid value is expressed as the milligrams of which substance required to neutralize free fatty acids in 1 g of fat?
Determination of acid value of fat
Easy
A.Sodium chloride
B.Sodium bicarbonate
C.Hydrochloric acid
D.Potassium hydroxide
Correct Answer: Potassium hydroxide
Explanation:
Acid value is expressed as milligrams of potassium hydroxide, KOH, needed to neutralize the free fatty acids in 1 g of fat.
Incorrect! Try again.
3Which type of titration is commonly used to determine the acid value of a fat?
Determination of acid value of fat
Easy
A.Precipitation titration
B.Redox titration
C.Acid-base titration
D.Complexometric titration
Correct Answer: Acid-base titration
Explanation:
Free fatty acids are neutralized by an alkaline KOH solution, so the analysis is an acid-base titration.
Incorrect! Try again.
4Which reagent is commonly used as the titrant in acid value determination?
Determination of acid value of fat
Easy
A.Standard alcoholic KOH
B.Standard sodium chloride
C.Standard iodine solution
D.Standard aqueous HCl
Correct Answer: Standard alcoholic KOH
Explanation:
A standardized alcoholic potassium hydroxide solution is commonly used to neutralize the free fatty acids.
Incorrect! Try again.
5Which indicator is commonly used in the titration of free fatty acids in fat?
Determination of acid value of fat
Easy
A.Methylene blue
B.Methyl orange
C.Phenolphthalein
D.Starch
Correct Answer: Phenolphthalein
Explanation:
Phenolphthalein changes to a faint pink color when the acidic sample has been neutralized by alkali.
Incorrect! Try again.
6What is the usual endpoint color when phenolphthalein is used in acid value determination?
Determination of acid value of fat
Easy
A.Permanent pale pink
B.Bright yellow
C.Permanent dark blue
D.Deep green
Correct Answer: Permanent pale pink
Explanation:
The endpoint is usually the appearance of a faint, permanent pink color that persists briefly.
Incorrect! Try again.
7A high acid value in a fat generally indicates:
Determination of acid value of fat
Easy
A.Less free fatty acids
B.Less glycerol content
C.More mineral salts
D.More free fatty acids
Correct Answer: More free fatty acids
Explanation:
A high acid value means that more KOH is needed for neutralization, indicating a greater amount of free fatty acids.
Incorrect! Try again.
8Which process commonly causes an increase in the acid value of stored fat?
Determination of acid value of fat
Easy
A.Reduction of pigments
B.Hydrolysis of triglycerides
C.Evaporation of minerals
D.Crystallization of sugars
Correct Answer: Hydrolysis of triglycerides
Explanation:
Hydrolysis breaks triglycerides into glycerol and free fatty acids, increasing the acid value.
Incorrect! Try again.
9Why is a fat sample often dissolved in an alcohol-containing solvent before titration?
Determination of acid value of fat
Easy
A.To remove all fatty acids
B.To form a suitable titration mixture
C.To increase its protein content
D.To convert KOH into an acid
Correct Answer: To form a suitable titration mixture
Explanation:
The solvent helps dissolve or disperse the fat and allows the free fatty acids to react with the alkaline titrant.
Incorrect! Try again.
10In the acid value equation, the sample mass is usually expressed in:
Determination of acid value of fat
Easy
A.Moles
B.Liters
C.Degrees Celsius
D.Grams
Correct Answer: Grams
Explanation:
Acid value is defined per gram of fat, so the sample mass is expressed in grams.
Incorrect! Try again.
11Ascorbic acid is commonly known as:
Determination of ascorbic acid content in fruit juice
Easy
A.Vitamin D
B.Vitamin C
C.Vitamin B12
D.Vitamin A
Correct Answer: Vitamin C
Explanation:
Ascorbic acid is the chemical name for vitamin C.
Incorrect! Try again.
12Which property of ascorbic acid is used in its titrimetric determination?
Determination of ascorbic acid content in fruit juice
Easy
A.Volatile property
B.Reducing property
C.Strongly basic property
D.Precipitating property
Correct Answer: Reducing property
Explanation:
Ascorbic acid acts as a reducing agent and reacts with suitable oxidizing titrants.
Incorrect! Try again.
13Which reagent is commonly used to estimate ascorbic acid in fruit juice?
Determination of ascorbic acid content in fruit juice
Easy
A.DCPIP solution
B.Barium chloride solution
C.Benedict's reagent
D.Sodium chloride solution
Correct Answer: DCPIP solution
Explanation:
2,6-Dichlorophenolindophenol, or DCPIP, is commonly used because it is reduced by ascorbic acid.
Incorrect! Try again.
14What happens to DCPIP when it reacts with ascorbic acid?
Determination of ascorbic acid content in fruit juice
Easy
A.It is oxidized and becomes black
B.It is reduced and loses its color
C.It forms a white precipitate
D.It produces a gas immediately
Correct Answer: It is reduced and loses its color
Explanation:
Ascorbic acid reduces the colored DCPIP to a colorless reduced form.
Incorrect! Try again.
15What is the usual endpoint in the DCPIP titration of ascorbic acid?
Determination of ascorbic acid content in fruit juice
Easy
A.A bright green solution
B.A permanent black color
C.A permanent white precipitate
D.A persistent faint pink color
Correct Answer: A persistent faint pink color
Explanation:
After all ascorbic acid has reacted, a slight excess of DCPIP gives a faint pink color that persists.
Incorrect! Try again.
16Why is fruit juice usually filtered before determining its ascorbic acid content?
Determination of ascorbic acid content in fruit juice
Easy
A.To destroy all the vitamin C
B.To add more reducing substances
C.To remove pulp and suspended particles
D.To increase the juice temperature
Correct Answer: To remove pulp and suspended particles
Explanation:
Filtration produces a clearer sample and helps suspended material from interfering with the titration.
Incorrect! Try again.
17Ascorbic acid is easily destroyed by exposure to:
Determination of ascorbic acid content in fruit juice
Easy
A.Pure nitrogen only
B.Air and light
C.Distilled water only
D.Dry glassware only
Correct Answer: Air and light
Explanation:
Ascorbic acid can oxidize and degrade when exposed to air, light, and unsuitable storage conditions.
Incorrect! Try again.
18Why should a fruit juice sample be analyzed soon after preparation?
Determination of ascorbic acid content in fruit juice
Easy
A.To reduce vitamin C oxidation
B.To increase sugar fermentation
C.To remove natural pigments
D.To produce more juice volume
Correct Answer: To reduce vitamin C oxidation
Explanation:
Prompt analysis helps prevent oxidation of ascorbic acid and gives a more accurate result.
Incorrect! Try again.
19What is usually prepared before analyzing an unknown fruit juice sample?
Determination of ascorbic acid content in fruit juice
Easy
A.A standard ascorbic acid solution
B.A concentrated oil sample
C.A saturated salt solution
D.A protein suspension
Correct Answer: A standard ascorbic acid solution
Explanation:
A standard ascorbic acid solution is used to standardize the titrant or establish the relationship between titrant volume and vitamin C amount.
Incorrect! Try again.
20The ascorbic acid content of fruit juice is commonly reported as:
Determination of ascorbic acid content in fruit juice
Easy
A.Grams per degree Celsius
B.Moles per kilogram of air
C.Liters per gram
D.Milligrams per 100 mL
Correct Answer: Milligrams per 100 mL
Explanation:
Vitamin C content in beverages is commonly expressed as milligrams of ascorbic acid per 100 mL of juice.
Incorrect! Try again.
21A 2.50 g fat sample requires 1.80 mL of 0.100 M KOH for neutralization. If the blank requires 0.20 mL, what is the acid value of the fat?
Determination of acid value of fat
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Corrected volume is mL. Acid value .
Incorrect! Try again.
22Why is a blank titration performed during acid value determination?
Determination of acid value of fat
Medium
A.To measure the fat's moisture content
B.To correct for alkali consumed by solvents and reagents
C.To determine the molecular mass of the fat
D.To convert free fatty acids into glycerol
Correct Answer: To correct for alkali consumed by solvents and reagents
Explanation:
The blank accounts for alkali consumed by the solvent, indicator, or other reagents rather than by free fatty acids in the sample.
Incorrect! Try again.
23A fat sample is titrated with 0.050 M KOH. The sample mass is 4.00 g, and the blank-corrected titre is 3.00 mL. What is the acid value?
Determination of acid value of fat
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Using , .
Incorrect! Try again.
24An increased acid value in an oil sample most directly indicates:
Determination of acid value of fat
Medium
A.Complete absence of hydrolytic rancidity
B.Lower concentration of free fatty acids
C.Greater triglyceride synthesis
D.Greater free fatty acid formation
Correct Answer: Greater free fatty acid formation
Explanation:
Acid value measures the alkali required to neutralize free fatty acids. Hydrolysis of triglycerides generally increases the acid value.
Incorrect! Try again.
25If the fat sample mass is doubled while the amount of free fatty acid remains proportional to the sample mass, what happens to the acid value?
Determination of acid value of fat
Medium
A.It remains approximately unchanged
B.It becomes equal to the titre volume
C.It approximately doubles
D.It approximately halves
Correct Answer: It remains approximately unchanged
Explanation:
Acid value is expressed per gram of fat. When both sample mass and neutralization requirement increase proportionally, their ratio remains constant.
Incorrect! Try again.
26Which endpoint observation is generally used when phenolphthalein is the indicator in acid value determination?
Determination of acid value of fat
Medium
A.A temporary yellow color
B.A permanent deep blue color
C.A permanent green precipitate
D.A permanent pale pink color
Correct Answer: A permanent pale pink color
Explanation:
Phenolphthalein is colorless in acidic solution and becomes pale pink in slightly alkaline solution. The endpoint is the first persistent pale pink color.
Incorrect! Try again.
27A 5.00 g fat sample gives a titre of 4.50 mL with 0.100 N KOH. The blank titre is 0.50 mL. What is the acid value?
Determination of acid value of fat
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The corrected titre is mL. Therefore, .
Incorrect! Try again.
28Why is the fat commonly dissolved in a neutralized alcohol-containing solvent before titration?
Determination of acid value of fat
Medium
A.To dissolve the fat and permit reaction with alkali
B.To precipitate potassium salts before titration
C.To increase the molecular mass of triglycerides
D.To oxidize all fatty acids into aldehydes
Correct Answer: To dissolve the fat and permit reaction with alkali
Explanation:
The solvent provides a homogeneous medium in which the fat's free fatty acids can react effectively with the standard alcoholic KOH.
Incorrect! Try again.
29A technician uses 0.200 N KOH instead of 0.100 N KOH in the calculation without changing the recorded titre. What is the effect on the calculated acid value?
Determination of acid value of fat
Medium
A.It becomes zero after blank correction
B.It is reported approximately twice the true value
C.It is unaffected by the concentration error
D.It is reported approximately half the true value
Correct Answer: It is reported approximately twice the true value
Explanation:
Acid value is directly proportional to the alkali normality used in the calculation. Using twice the actual normality doubles the calculated result.
Incorrect! Try again.
30Which procedural mistake would most likely produce an acid value that is too high?
Determination of acid value of fat
Medium
A.Reading the burette at eye level
B.Subtracting the blank titre correctly
C.Overshooting the phenolphthalein endpoint
D.Using a larger sample mass accurately
Correct Answer: Overshooting the phenolphthalein endpoint
Explanation:
Overshooting adds excess KOH to the recorded titre, so the calculated amount of neutralized acid and the acid value are artificially increased.
Incorrect! Try again.
31In the DCPIP method, ascorbic acid is quantified because it:
Determination of ascorbic acid content in fruit juice
Medium
A.Forms an insoluble salt with DCPIP
B.Oxidizes DCPIP to a blue precipitate
C.Acts as an indicator without reacting
D.Reduces DCPIP to its colorless form
Correct Answer: Reduces DCPIP to its colorless form
Explanation:
Ascorbic acid is a reducing agent. It reduces colored DCPIP, and the endpoint is reached when a slight excess of unreduced dye persists.
Incorrect! Try again.
32A standard solution contains 1.00 mg of ascorbic acid and requires 2.00 mL of DCPIP. A 10.0 mL juice aliquot requires 1.50 mL of DCPIP. How much ascorbic acid is present in the aliquot?
Determination of ascorbic acid content in fruit juice
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
DCPIP equivalence is mg per mL. Thus, mg of ascorbic acid is present.
Incorrect! Try again.
33A 10.0 mL juice aliquot contains 0.75 mg of ascorbic acid. What is the concentration of ascorbic acid in the juice?
Determination of ascorbic acid content in fruit juice
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The concentration is mg/mL. Multiplying by 100 gives .
Incorrect! Try again.
34Why should a fruit juice sample be analyzed promptly or protected from air and light?
Determination of ascorbic acid content in fruit juice
Medium
A.Ascorbic acid becomes a stronger base in darkness
B.Sugars are converted quantitatively into ascorbic acid
C.DCPIP is produced naturally by the juice
D.Ascorbic acid can oxidize during storage
Correct Answer: Ascorbic acid can oxidize during storage
Explanation:
Exposure to oxygen, light, and heat can oxidize ascorbic acid, lowering the measured concentration.
Incorrect! Try again.
35A 25.0 mL juice sample is diluted to 100.0 mL. A 10.0 mL portion of the diluted sample contains 2.00 mg of ascorbic acid. What is the ascorbic acid content of the original juice?
Determination of ascorbic acid content in fruit juice
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The diluted 100 mL contains mg. This amount came from 25.0 mL original juice, so the original concentration is mg per 100 mL. Therefore, the correct option should be .
Incorrect! Try again.
36A 25.0 mL juice sample is diluted to 100.0 mL. A 10.0 mL portion of the diluted sample contains 2.00 mg of ascorbic acid. What is the ascorbic acid content of the original juice?
Determination of ascorbic acid content in fruit juice
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The 100 mL diluted sample contains mg. Since this came from 25.0 mL original juice, the concentration is .
Incorrect! Try again.
37What indicates the endpoint in a DCPIP titration of ascorbic acid?
Determination of ascorbic acid content in fruit juice
Medium
A.A deep green color disappears completely
B.A yellow precipitate forms immediately
C.A colorless solution remains permanently
D.A faint pink color persists briefly
Correct Answer: A faint pink color persists briefly
Explanation:
Once all ascorbic acid has reacted, a slight excess of DCPIP remains unreduced, producing a faint persistent pink color.
Incorrect! Try again.
38If a juice aliquot is diluted twofold before titration and the dilution is not included in the calculation, the reported ascorbic acid concentration will be:
Determination of ascorbic acid content in fruit juice
Medium
A.Unchanged because dilution does not affect titration
B.Approximately half the true concentration
C.Approximately twice the true concentration
D.Zero because the indicator is diluted
Correct Answer: Approximately half the true concentration
Explanation:
The measured concentration applies to the diluted sample. Omitting a twofold dilution factor causes the original juice concentration to be underestimated by a factor of two.
Incorrect! Try again.
39A standardization shows that 1.00 mL DCPIP is equivalent to 0.400 mg ascorbic acid. If 15.0 mL of juice requires 2.50 mL DCPIP, what is the concentration in the juice?
Determination of ascorbic acid content in fruit juice
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The aliquot contains mg. Therefore, concentration is . Thus, the correct option should be .
Incorrect! Try again.
40A standardization shows that 1.00 mL DCPIP is equivalent to 0.400 mg ascorbic acid. If 15.0 mL of juice requires 2.50 mL DCPIP, what is the concentration in the juice?
Determination of ascorbic acid content in fruit juice
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The aliquot contains mg. Therefore, the concentration is .
Incorrect! Try again.
41A fat sample requires of alcoholic KOH, while the reagent blank requires . What is the acid value of the fat?
Determination of acid value of fat
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The corrected volume is . Thus, acid value .
Incorrect! Try again.
42A fat sample is titrated using alcoholic KOH that was standardized with potassium hydrogen phthalate (molar mass ). The KHP requires of the KOH solution. What is the actual normality of the KOH?
Determination of acid value of fat
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
KHP reacts in a equivalent ratio. Therefore, .
Incorrect! Try again.
43A fat sample requires of KOH, and the blank requires . Which result is closest to the acid value?
Determination of acid value of fat
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Using the blank-corrected volume, acid value .
Incorrect! Try again.
44If the endpoint is exceeded by during titration of a sample with KOH, what is the resulting error in the reported acid value?
Determination of acid value of fat
Hard
A.An overestimation of
B.An underestimation of
C.An overestimation of
D.An underestimation of
Correct Answer: An overestimation of
Explanation:
The error is . Extra titrant produces an overestimate.
Incorrect! Try again.
45A fat has an acid value of . Assuming its free fatty acids are entirely oleic acid, what is the approximate percentage of free oleic acid by mass? Use molar mass of oleic acid .
Determination of acid value of fat
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The mass fraction is .
Incorrect! Try again.
46Two samples are titrated with KOH. Sample A weighs and consumes after a blank correction. Sample B weighs and consumes after the same correction. Which interpretation is correct?
Determination of acid value of fat
Hard
A.Both samples have the same acid value
B.Sample B has the higher acid value by a factor of two
C.Sample A has the higher acid value by a factor of two
D.The comparison is impossible without saponification data
Correct Answer: Both samples have the same acid value
Explanation:
For A, the corrected volume is ; for B, it is . Since B has twice the mass and twice the corrected volume, both give the same acid value.
Incorrect! Try again.
47Why is a reagent blank essential in acid-value determination even when the fat itself is the only intended acid source?
Determination of acid value of fat
Hard
A.It converts acid value into saponification value
B.It measures alkali consumed by triglyceride hydrolysis
C.It measures alkali consumed by the solvent and reagents
D.It compensates for the molecular mass of fatty acids
Correct Answer: It measures alkali consumed by the solvent and reagents
Explanation:
Alcohol, dissolved carbon dioxide, and other reagent impurities may consume KOH. Subtracting the blank isolates alkali neutralization attributable to acidic constituents of the sample.
Incorrect! Try again.
48A poorly dried fat sample contains water by mass. If the measured acid value is calculated using the wet sample mass, how will the result compare with the acid value calculated on a dry-mass basis, assuming water consumes no KOH?
Determination of acid value of fat
Hard
A.Both values are identical
B.The wet-basis value is lower
C.The wet-basis value is higher
D.The wet-basis value is lower
Correct Answer: The wet-basis value is lower
Explanation:
For wet sample, dry fat is . The dry-basis value is multiplied by , so the wet-basis result is about lower.
Incorrect! Try again.
49Which observation most strongly indicates that an acid-value titration result may be falsely high because of incomplete sample dissolution?
Determination of acid value of fat
Hard
A.A blank volume slightly smaller than the sample volume
B.A stable pale-pink endpoint after vigorous mixing
C.A duplicate result differing by less than one percent
Correct Answer: A gradually fading endpoint requiring repeated titrant additions
Explanation:
Undissolved acidic material can enter the reaction mixture slowly, causing the endpoint to fade and leading to excess KOH delivery and a falsely high acid value.
Incorrect! Try again.
50Which statement best distinguishes acid value from saponification value?
Determination of acid value of fat
Hard
A.Acid value measures free acids; saponification value includes ester-bound acids
B.Both values measure only free fatty acids in the sample
C.Both values are determined from identical blank-corrected titrations
D.Acid value measures ester-bound acids; saponification value measures free acids
Correct Answer: Acid value measures free acids; saponification value includes ester-bound acids
Explanation:
Acid value quantifies alkali needed to neutralize free fatty acids. Saponification value additionally accounts for alkali required to hydrolyze ester bonds in glycerides.
Incorrect! Try again.
51A fruit juice sample is diluted to . A aliquot requires of DCPIP, and DCPIP is equivalent to ascorbic acid. What is the ascorbic acid concentration in the original juice?
Determination of ascorbic acid content in fruit juice
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The aliquot contains . The full diluted sample contains , which originated from juice; therefore, the original juice contains .
Incorrect! Try again.
52A DCPIP solution is standardized using pure ascorbic acid, requiring DCPIP. A juice sample then requires . What mass of ascorbic acid is present per juice?
Determination of ascorbic acid content in fruit juice
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The factor is . The aliquot contains , so the original juice contains .
Incorrect! Try again.
53A juice sample is diluted to . A aliquot requires DCPIP, standardized as ascorbic acid. What is the concentration in the original juice?
Determination of ascorbic acid content in fruit juice
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The aliquot contains . The diluted flask contains , originating from juice. Scaling to gives .
Incorrect! Try again.
54In an ascorbic acid titration with DCPIP, the endpoint is identified by a faint pink color that persists briefly. The persistence occurs because:
Determination of ascorbic acid content in fruit juice
Hard
A.The juice becomes strongly alkaline at equivalence
B.All DCPIP has been reduced by excess ascorbate
C.A slight excess of unreduced DCPIP remains after ascorbate is consumed
D.The indicator permanently binds to all fruit pigments
Correct Answer: A slight excess of unreduced DCPIP remains after ascorbate is consumed
Explanation:
Ascorbic acid reduces colored DCPIP to its reduced form. Once ascorbate is consumed, the next slight excess of DCPIP remains colored and produces the endpoint.
Incorrect! Try again.
55Why is metaphosphoric acid or another suitable stabilizing acid commonly used during preparation of fruit-juice samples for ascorbic acid analysis?
Determination of ascorbic acid content in fruit juice
Hard
A.It accelerates oxidation by atmospheric oxygen
B.It converts DCPIP into a stronger reducing agent
C.It stabilizes ascorbate and helps precipitate interfering proteins
D.It hydrolyzes all sugars into titratable acids
Correct Answer: It stabilizes ascorbate and helps precipitate interfering proteins
Explanation:
An acidic stabilizing medium slows oxidative degradation of ascorbic acid and can remove protein-based turbidity or reactive interferences, improving endpoint reliability.
Incorrect! Try again.
56A juice contains a strongly colored pigment that masks the DCPIP endpoint. Which modification most directly improves the analytical result without changing the redox chemistry?
Determination of ascorbic acid content in fruit juice
Hard
A.Replace the aliquot with an equal volume of distilled water
B.Use a reagent blank containing the juice matrix without ascorbate
C.Titrate the juice after prolonged exposure to air
D.Increase the DCPIP concentration until the color is permanent
Correct Answer: Use a reagent blank containing the juice matrix without ascorbate
Explanation:
A matrix blank accounts for background color or non-ascorbate reagent consumption. The sample signal can then be corrected without arbitrarily changing titrant concentration or oxidation conditions.
Incorrect! Try again.
57A juice sample gives titration volumes of , , and DCPIP. What is the most appropriate treatment before calculating the ascorbic acid content?
Determination of ascorbic acid content in fruit juice
Hard
A.Use only the largest value
B.Subtract the smallest value from the largest value
C.Reject the outlier and average the concordant values
D.Average all three values directly
Correct Answer: Reject the outlier and average the concordant values
Explanation:
The first two values are concordant, whereas is inconsistent. The concordant titrations should be investigated and averaged, with the outlier excluded only under a justified laboratory criterion.
Incorrect! Try again.
58If a juice sample is left exposed to air and light for several hours before DCPIP titration, the measured ascorbic acid content will most likely be:
Determination of ascorbic acid content in fruit juice
Hard
A.Lower because ascorbate is oxidized before titration
B.Unchanged because DCPIP measures total vitamin C derivatives
C.Higher because pigments become stronger reducing agents
D.Higher because oxygen creates additional ascorbate
Correct Answer: Lower because ascorbate is oxidized before titration
Explanation:
Ascorbic acid is readily oxidized by oxygen, especially in the presence of light, heat, and catalytic metals. Oxidized material is not measured equivalently by the DCPIP reduction endpoint.
Incorrect! Try again.
59A juice aliquot requires DCPIP. A matrix blank requires , and the standardized factor is ascorbic acid per milliliter of DCPIP. What mass of ascorbic acid is in the aliquot?
Determination of ascorbic acid content in fruit juice
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The corrected titrant volume is . Therefore, ascorbic acid mass .
Incorrect! Try again.
60A method reports ascorbic acid in a juice, but the juice was first diluted and the analyst forgot to apply the dilution factor. What should the corrected concentration be?
Determination of ascorbic acid content in fruit juice
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
A dilution makes the measured solution five times less concentrated. The original concentration is therefore .
Incorrect! Try again.
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