1What is the main purpose of the spread plate technique?
To determine total count of bacteria by spread plate technique
Easy
A.To stain bacterial cells
B.To count viable bacterial cells
C.To measure bacterial cell size
D.To identify bacterial shapes
Correct Answer: To count viable bacterial cells
Explanation:
The spread plate technique is used to estimate viable bacteria that can grow into visible colonies.
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2What is spread over the surface of an agar plate in the spread plate method?
To determine total count of bacteria by spread plate technique
Easy
A.A fixed bacterial smear
B.A melted agar mixture
C.A measured bacterial sample
D.A concentrated stain solution
Correct Answer: A measured bacterial sample
Explanation:
A measured volume of the diluted bacterial sample is spread evenly over the agar surface.
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3Which instrument is commonly used to spread the sample on the agar surface?
To determine total count of bacteria by spread plate technique
Easy
A.Sterile measuring cylinder
B.Sterile microscope slide
C.Sterile inoculating needle
D.Sterile glass spreader
Correct Answer: Sterile glass spreader
Explanation:
A sterile glass spreader, also called a spreader or hockey stick, distributes the sample across the agar.
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4Why are serial dilutions made before plating a bacterial sample?
To determine total count of bacteria by spread plate technique
Easy
A.To remove all living bacteria
B.To obtain countable colonies
C.To change bacteria into spores
D.To increase the sample volume
Correct Answer: To obtain countable colonies
Explanation:
Serial dilution reduces the number of bacteria so that separate, countable colonies can develop on the plate.
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5What does one visible colony usually represent in a viable count?
To determine total count of bacteria by spread plate technique
Easy
A.One microscope field
B.One bacterial species
C.One type of culture medium
D.One colony-forming unit
Correct Answer: One colony-forming unit
Explanation:
A visible colony is counted as one colony-forming unit (CFU), which may come from one cell or a group of cells.
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6What is the usual unit for reporting bacterial counts from a liquid sample?
To determine total count of bacteria by spread plate technique
Easy
A.Cells/mm
B.CFU/mL
C.CFU/g
D.Colonies/cm
Correct Answer: CFU/mL
Explanation:
Bacterial concentration in a liquid sample is commonly reported as colony-forming units per milliliter, or CFU/mL.
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7Which type of agar is commonly used for counting bacteria in a general sample?
To determine total count of bacteria by spread plate technique
Easy
A.Indicator paper
B.Distilled water agar
C.Fixation agar
D.Nutrient agar
Correct Answer: Nutrient agar
Explanation:
Nutrient agar provides general nutrients that support the growth of many non-fastidious bacteria.
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8What is the purpose of labeling the agar plates before inoculation?
To determine total count of bacteria by spread plate technique
Easy
A.To identify sample details
B.To prevent dilution of samples
C.To sterilize the agar surface
D.To increase bacterial growth
Correct Answer: To identify sample details
Explanation:
Labels record information such as the sample identity, dilution, date, and plate number.
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9Which condition helps prevent contamination during plating?
To determine total count of bacteria by spread plate technique
Easy
A.Mixing different samples
B.Using aseptic technique
C.Leaving plates uncovered
D.Using unsterilized spreaders
Correct Answer: Using aseptic technique
Explanation:
Aseptic technique reduces the entry of unwanted microorganisms during sample handling and plating.
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10Why should a diluted sample be mixed before transferring it for plating?
To determine total count of bacteria by spread plate technique
Easy
A.To destroy sensitive cells
B.To change the dilution factor
C.To increase agar thickness
D.To distribute cells evenly
Correct Answer: To distribute cells evenly
Explanation:
Mixing helps distribute bacterial cells uniformly so that the transferred portion represents the diluted sample.
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11What is a suitable incubation position for most agar plates?
To determine total count of bacteria by spread plate technique
Easy
A.Inverted with agar upward
B.Upright with agar downward
C.Open with agar upward
D.Sideways with agar outward
Correct Answer: Inverted with agar upward
Explanation:
Plates are commonly incubated inverted to prevent condensation from dripping onto and spreading the colonies.
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12What does a dilution of mean?
To determine total count of bacteria by spread plate technique
Easy
A.One part in three hundred
B.One part in one thousand
C.One thousand parts in one
D.Three parts in one hundred
Correct Answer: One part in one thousand
Explanation:
A dilution contains one part of the original sample in a total of one thousand parts.
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13Which plates are generally selected for calculating a reliable bacterial count?
To determine total count of bacteria by spread plate technique
Easy
A.Plates with completely merged colonies
B.Plates with no visible colonies
C.Plates with countable colonies
D.Plates with heavy surface contamination
Correct Answer: Plates with countable colonies
Explanation:
Plates with separate, countable colonies provide a more reliable estimate of the bacterial concentration.
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14A plate contains 50 colonies after plating mL of a dilution. What is the bacterial concentration?
To determine total count of bacteria by spread plate technique
Easy
A. CFU/mL
B. CFU/mL
C. CFU/mL
D. CFU/mL
Correct Answer: CFU/mL
Explanation:
Using , the result is CFU/mL. Therefore, the correct option should be CFU/mL.
Incorrect! Try again.
15A plate contains 50 colonies after plating mL of a dilution. What is the bacterial concentration?
To determine total count of bacteria by spread plate technique
Easy
A. CFU/mL
B. CFU/mL
C. CFU/mL
D. CFU/mL
Correct Answer: CFU/mL
Explanation:
The calculation is CFU/mL.
Incorrect! Try again.
16If 100 colonies grow from mL of a dilution, what is the original concentration?
To determine total count of bacteria by spread plate technique
Easy
A. CFU/mL
B. CFU/mL
C. CFU/mL
D. CFU/mL
Correct Answer: CFU/mL
Explanation:
The concentration is CFU/mL.
Incorrect! Try again.
17What may happen if too many bacterial cells are plated on an agar plate?
To determine total count of bacteria by spread plate technique
Easy
A.Colonies may become sterile
B.The agar may become liquid
C.The dilution may disappear
D.Colonies may merge together
Correct Answer: Colonies may merge together
Explanation:
An overcrowded plate can produce merged colonies, making accurate counting difficult.
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18What may happen if a plate receives very few bacterial cells?
To determine total count of bacteria by spread plate technique
Easy
A.The colonies must merge together
B.The count may be less reliable
C.The agar must become contaminated
D.The sample becomes more concentrated
Correct Answer: The count may be less reliable
Explanation:
Very few colonies provide less data and may not represent the bacterial concentration accurately.
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19Why should the spreader be sterilized before use?
To determine total count of bacteria by spread plate technique
Easy
A.To reduce agar nutrients
B.To change the sample color
C.To increase colony size
D.To prevent contamination
Correct Answer: To prevent contamination
Explanation:
Sterilizing the spreader removes unwanted microorganisms that could affect the colony count.
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20Which observation is recorded after incubation in a spread plate count?
To determine total count of bacteria by spread plate technique
Easy
A.Number of visible colonies
B.Length of the spreader
C.Weight of the agar plate
D.Color of the tube label
Correct Answer: Number of visible colonies
Explanation:
The number of visible colonies is recorded and used with the dilution and plated volume to calculate CFU/mL.
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21A sample from a dilution produces 86 colonies on an agar plate. What is the bacterial concentration in the original sample?
To determine total count of bacteria by spread plate technique
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Use . Thus, .
Incorrect! Try again.
22A plate prepared from a dilution has 245 colonies, while a plate from a dilution has 27 colonies. If was spread on each plate, which result is most suitable for calculating the bacterial concentration?
To determine total count of bacteria by spread plate technique
Medium
A.Neither plate because both contain fewer than 300 colonies
B.The plate because it has more colonies
C.The plate because it is less crowded
D.The average of both plates without adjustment
Correct Answer: The plate because it has more colonies
Explanation:
The plate contains 245 colonies, which lies within the commonly acceptable countable range of about 30–300 colonies. The plate has only 27 colonies and is less reliable.
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23Why is a diluted sample used in the spread plate technique?
To determine total count of bacteria by spread plate technique
Medium
A.To eliminate the need for sterile technique
B.To prevent bacteria from growing on agar
C.To increase the original bacterial concentration
D.To obtain separated and countable colonies
Correct Answer: To obtain separated and countable colonies
Explanation:
Dilution reduces the number of cells deposited on the agar surface, allowing individual viable cells to form separate colonies that can be counted.
Incorrect! Try again.
24A portion of a dilution gives 64 colonies. What is the concentration of bacteria in the original sample?
To determine total count of bacteria by spread plate technique
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The concentration is .
Incorrect! Try again.
25Two replicate plates from the same dilution contain 92 and 108 colonies. What concentration should be reported if of a dilution was plated?
To determine total count of bacteria by spread plate technique
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The mean count is colonies. Therefore, .
Incorrect! Try again.
26A student plates of a dilution and observes a confluent lawn. What is the best next step?
To determine total count of bacteria by spread plate technique
Medium
A.Repeat using a higher dilution
B.Add more agar to the same plate
C.Incubate the plate for a shorter time
D.Count the lawn as one colony
Correct Answer: Repeat using a higher dilution
Explanation:
A confluent lawn indicates that too many cells were plated for reliable counting. A higher dilution should be used to obtain discrete colonies.
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27A plate from a dilution contains 312 colonies, and a plate from a dilution contains 34 colonies. Which plate should be selected for the most reliable calculation?
To determine total count of bacteria by spread plate technique
Medium
A.The plate because dilution is lower
B.The plate because its count is countable
C.Neither plate because counts must exceed 100
D.Both plates because their counts differ tenfold
Correct Answer: The plate because its count is countable
Explanation:
The plate slightly exceeds the usual upper limit of about 300 colonies. The plate has 34 colonies and falls within the acceptable counting range.
Incorrect! Try again.
28Why should the diluted sample be mixed thoroughly immediately before transferring an aliquot for plating?
To determine total count of bacteria by spread plate technique
Medium
A.To distribute cells evenly throughout the suspension
B.To increase the volume delivered by the pipette
C.To sterilize the diluted suspension
D.To make all bacterial cells form larger colonies
Correct Answer: To distribute cells evenly throughout the suspension
Explanation:
Cells may settle or become unevenly distributed. Thorough mixing helps ensure that the aliquot represents the actual concentration of the dilution.
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29A dilution gives 150 colonies when is plated. If of the same dilution had been plated, approximately how many colonies would be expected?
To determine total count of bacteria by spread plate technique
Medium
A.30 colonies
B.300 colonies
C.750 colonies
D.150 colonies
Correct Answer: 750 colonies
Explanation:
The plated volume is increased fivefold, so the expected count is colonies.
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30A sample is diluted by transferring into of sterile diluent. What is the dilution factor of this tube?
To determine total count of bacteria by spread plate technique
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The final volume is , and is sample. Therefore, the dilution is .
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31A dilution is followed by a dilution in a serial dilution scheme. What is the overall dilution relative to the original sample?
To determine total count of bacteria by spread plate technique
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Serial dilution factors are multiplied: .
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32A plate prepared from a dilution has 72 colonies after plating . What result would be expected from plating the same volume of a dilution?
To determine total count of bacteria by spread plate technique
Medium
A.Approximately 720 colonies
B.Approximately 72 colonies
C.Approximately 7,200 colonies
D.Approximately 7 colonies
Correct Answer: Approximately 7 colonies
Explanation:
The dilution is ten times more dilute than , so the expected count is approximately colonies.
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33A spread plate contains several merged colonies that cannot be distinguished individually. How should this plate be treated during calculation?
To determine total count of bacteria by spread plate technique
Medium
A.Count each merged area as one colony
B.Record it as unsuitable for accurate counting
C.Divide the merged area by the dilution factor
D.Use it as an exact count without adjustment
Correct Answer: Record it as unsuitable for accurate counting
Explanation:
Merged colonies prevent reliable enumeration because separate viable units cannot be distinguished. The plate should be reported as crowded or unsuitable for accurate counting.
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34A sample produces 48 colonies from of a dilution. If the same sample is plated at of the same dilution, what count is expected?
To determine total count of bacteria by spread plate technique
Medium
A.480 colonies
B.24 colonies
C.96 colonies
D.48 colonies
Correct Answer: 96 colonies
Explanation:
Doubling the plated volume doubles the expected number of colonies: colonies.
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35What is the primary purpose of spreading the inoculum evenly over the agar surface with a sterile spreader?
To determine total count of bacteria by spread plate technique
Medium
A.To concentrate cells at the plate center
B.To distribute cells for separate colony formation
C.To prevent nutrient absorption by the agar
D.To reduce the incubation temperature of the agar
Correct Answer: To distribute cells for separate colony formation
Explanation:
Even spreading helps distribute cells across the agar surface so that individual cells or clusters can develop into separated colonies.
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36A plate from a dilution has 125 colonies, and was plated. What is the original bacterial concentration?
To determine total count of bacteria by spread plate technique
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Using gives .
Incorrect! Try again.
37A negative control plate receives sterile diluent instead of the bacterial sample and develops colonies. What is the most appropriate interpretation?
To determine total count of bacteria by spread plate technique
Medium
A.The dilution factor should be increased
B.The agar naturally produces bacterial colonies
C.Contamination likely occurred during the procedure
D.The sample concentration is unusually high
Correct Answer: Contamination likely occurred during the procedure
Explanation:
A negative control should remain free of colonies. Growth indicates contamination of the diluent, agar, spreader, workspace, or another component.
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38A plate has 260 colonies, but 20 are clearly different in color and morphology from the others. If only the target organism is being counted, what number should be used?
To determine total count of bacteria by spread plate technique
Medium
A.20 colonies
B.240 colonies
C.260 colonies
D.280 colonies
Correct Answer: 240 colonies
Explanation:
When colonies are distinguishable by morphology, only colonies matching the target organism should be included. Thus, colonies.
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39Three replicate plates from the same dilution have counts of 82, 85, and 143 colonies. What is the best action before reporting the result?
To determine total count of bacteria by spread plate technique
Medium
A.Use only the lowest count
B.Investigate the variable replicate
C.Average all counts without review
D.Use only the highest count
Correct Answer: Investigate the variable replicate
Explanation:
The count of 143 differs substantially from the other two replicates. Possible pipetting, mixing, or counting errors should be checked before calculating a final mean.
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40A dilution plate has 40 colonies from . A dilution plate has 38 colonies from . What is the most likely explanation?
To determine total count of bacteria by spread plate technique
Medium
A.The dilution series was prepared accurately
B.The plates prove the sample has no bacteria
C.The lower dilution must always have fewer colonies
D.The higher dilution contains more viable cells
Correct Answer: The dilution series was prepared accurately
Explanation:
The counts should differ by about tenfold if both dilutions are accurate. Similar counts suggest a dilution, labeling, or pipetting error that should be investigated.
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41A aliquot of a dilution produces 146 colonies. What is the bacterial concentration in the original sample?
To determine total count of bacteria by spread plate technique
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Use . Thus, .
Incorrect! Try again.
42Two replicate plates from a dilution contain 32 and 38 colonies. If was spread from each plate, what concentration should be reported?
To determine total count of bacteria by spread plate technique
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The mean count is . Therefore, .
Incorrect! Try again.
43A serial dilution is prepared by transferring into of diluent four consecutive times. A sample from the final tube produces 82 colonies. What is the original concentration?
To determine total count of bacteria by spread plate technique
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Four tenfold transfers give a dilution of . Therefore, , not . Wait: because , the correct result is .
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44A sample is diluted 1:100 and then diluted 1:10. A aliquot of the second dilution gives 63 colonies. What is the original bacterial concentration?
To determine total count of bacteria by spread plate technique
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The combined dilution is . Including the plated volume, the effective dilution is , so the concentration is .
Incorrect! Try again.
45Counts from successive tenfold dilutions are 248 colonies at and 29 colonies at , with plated. Which result is most defensible?
To determine total count of bacteria by spread plate technique
Hard
A. based on the lower dilution
B. based on the dilution average
C. based on both plates
D. based on the countable plate
Correct Answer: based on the countable plate
Explanation:
The 248-colony plate lies within the usual countable range, whereas 29 is below it. Thus, .
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46A sterile-diluent control plate receives the same volume and incubation conditions as the sample plates but develops 6 colonies. How should the sample counts be handled?
To determine total count of bacteria by spread plate technique
Hard
A.Subtract six colonies from every sample plate
B.Average the control colonies with sample colonies
C.Treat the sample run as contaminated and repeat it
D.Report the sample counts without any adjustment
Correct Answer: Treat the sample run as contaminated and repeat it
Explanation:
Growth on a sterile control indicates contamination during dilution, plating, or incubation. Mathematical subtraction cannot establish that the contaminants were evenly distributed.
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47A plate shows a nearly continuous lawn with several isolated colonies, although the calculated count would exceed 300 colonies. What is the principal analytical problem?
To determine total count of bacteria by spread plate technique
Hard
A.The colony count is likely underestimated by coalescence
B.The organisms were all killed during incubation
C.The dilution factor becomes irrelevant at high counts
D.The spreader converted colonies into nonviable cells
Correct Answer: The colony count is likely underestimated by coalescence
Explanation:
Overcrowded growth causes neighboring colonies to merge, so visible colonies no longer represent individual viable propagules. The plate should be classified as too numerous to count.
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48A bacterial suspension contains many cell aggregates. Compared with a well-dispersed suspension, the spread-plate result will most likely show which pattern?
To determine total count of bacteria by spread plate technique
Hard
A.A zero CFU value because aggregates cannot grow
B.An inflated CFU value because aggregates multiply faster
C.An unchanged CFU value because each cell forms a colony
D.An underestimated CFU value because aggregates form single colonies
Correct Answer: An underestimated CFU value because aggregates form single colonies
Explanation:
A colony-forming unit may originate from one cell or a cluster. Aggregation therefore causes several cells to be counted as one CFU.
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49Why is spreading rather than on a standard agar surface often unsuitable without modification?
To determine total count of bacteria by spread plate technique
Hard
A.The volume changes the dilution inside the sample tube
B.The larger volume prevents bacterial metabolism
C.The larger volume always sterilizes the agar surface
D.The agar surface may not absorb the volume rapidly
Correct Answer: The agar surface may not absorb the volume rapidly
Explanation:
Excess liquid can produce pooling, uneven distribution, delayed drying, and merged colonies. A more concentrated dilution or an alternative plating method may be required.
Incorrect! Try again.
50A aliquot from a dilution yields 25 colonies. Assuming the plate is acceptable for the method, what is the calculated concentration?
To determine total count of bacteria by spread plate technique
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The effective dilution is . Therefore, .
Incorrect! Try again.
51Three replicate plates from one dilution contain 64, 68, and 72 colonies. What conclusion is best supported by these results?
To determine total count of bacteria by spread plate technique
Hard
A.The mean count should be replaced by the highest count
B.The replicate variation is reasonably low
C.The dilution series is certainly inaccurate
D.The plates must contain three different species
Correct Answer: The replicate variation is reasonably low
Explanation:
The mean is 68 colonies and the sample standard deviation is approximately 4, giving a coefficient of variation near , which indicates acceptable replicate consistency.
Incorrect! Try again.
52A sample is plated on a medium containing an antibiotic that suppresses some bacteria. The resulting count should be interpreted as what?
To determine total count of bacteria by spread plate technique
Hard
A.The count of bacterial genomes in the sample
B.The count of bacteria able to grow under the selection
C.The total count of all bacteria in the sample
D.The direct microscopic count of living bacteria
Correct Answer: The count of bacteria able to grow under the selection
Explanation:
Selective media measure organisms that are both viable under the incubation conditions and able to grow in the presence of the antibiotic. They do not provide an unrestricted total bacterial count.
Incorrect! Try again.
53Which statement most accurately distinguishes a spread-plate viable count from a direct microscopic total count?
To determine total count of bacteria by spread plate technique
Hard
A.A spread plate counts DNA molecules, whereas microscopy counts enzymes
B.A spread plate counts all cells, whereas microscopy counts colonies
Spread plating estimates viable or culturable CFUs under defined conditions. Direct microscopy generally counts cells regardless of their ability to form colonies.
Incorrect! Try again.
54Counts are 280 at , 4 at , and too numerous to count at ; each plate received . Which value should normally be reported?
To determine total count of bacteria by spread plate technique
Hard
A. from both numeric plates
B. from all dilution levels
C. from the countable plate
D. from the most dilute plate
Correct Answer: from the countable plate
Explanation:
The 280-colony plate is within the usual countable range. The four-colony plate is too sparse, and the plate is uncountable. Thus, .
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55A student transfers into of diluent and labels the tube as a tenfold dilution. What is the actual dilution and the likely effect on the calculated original count?
To determine total count of bacteria by spread plate technique
Hard
A.It is and causes a hundredfold underestimate
B.It is and causes a tenfold overestimate
C.It is and causes a tenfold overestimate
D.It is and causes a tenfold underestimate
Correct Answer: It is and causes a tenfold overestimate
Explanation:
The transferred fraction is . If recorded as , the calculation uses a dilution ten times too large and overestimates the original concentration tenfold.
Incorrect! Try again.
56One milliliter of sample is added to 99 mL of diluent, followed by transferring into 9.9 mL of diluent. A aliquot from the final tube gives 75 colonies. What is the original concentration?
To determine total count of bacteria by spread plate technique
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The first dilution is and the second is , giving . Including the plated volume gives , so . Therefore, the correct option is .
Incorrect! Try again.
57Two plates from the same dilution contain 118 and 182 colonies, although the plating volumes and dilution labels are identical. Which response is most appropriate before reporting a result?
To determine total count of bacteria by spread plate technique
Hard
A.Multiply both counts by their difference and report the product
B.Report the lower plate because it avoids crowding
C.Report the higher plate because it is more sensitive
D.Investigate mixing and plating variability before averaging
Correct Answer: Investigate mixing and plating variability before averaging
Explanation:
The large discrepancy suggests inadequate homogenization, pipetting error, uneven spreading, or contamination. Averaging without assessing the cause may conceal a procedural failure.
Incorrect! Try again.
58A sample is spread immediately after adding inoculum, but the agar surface is visibly wet and colonies later appear as streaks or merged patches. Which factor most directly compromises enumeration?
To determine total count of bacteria by spread plate technique
Hard
A.Excess surface moisture causing nonuniform cell distribution
B.High agar concentration preventing all colony formation
C.Insufficient dilution causing every cell to remain dormant
D.Low incubation temperature causing dilution reversal
Correct Answer: Excess surface moisture causing nonuniform cell distribution
Explanation:
A wet surface allows the inoculum to flow rather than remain evenly distributed. This produces merged colonies and spatially biased counts.
Incorrect! Try again.
59A plate from a dilution contains 7 colonies after spreading . What is the most important limitation of reporting the resulting value without qualification?
To determine total count of bacteria by spread plate technique
Hard
A.The colonies necessarily represent dead bacterial cells
B.The low count has high relative sampling uncertainty
C.The dilution factor cannot be used with spread plates
D.The calculated value is mathematically impossible
Correct Answer: The low count has high relative sampling uncertainty
Explanation:
The point estimate is , but seven colonies provide poor precision because Poisson relative error is approximately . A less dilute, countable plate is preferable.
Incorrect! Try again.
60A dilution is prepared correctly, but the analyst accidentally records it as . A plate with 156 colonies is then used for calculation. How will the reported concentration compare with the true value?
To determine total count of bacteria by spread plate technique
Hard
A.It will be one-tenth of the true concentration
B.It will be one hundred times the true concentration
C.It will be ten times the true concentration
D.It will be equal to the true concentration
Correct Answer: It will be one-tenth of the true concentration
Explanation:
Using instead of the actual makes the denominator ten times smaller, so the calculated concentration is ten times smaller than the true value.
Incorrect! Try again.
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