The offspring are , , , and . These produce two chinchilla, one Himalayan, and one albino phenotype.
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22A gene has five alleles in a population. How many different alleles of this gene can a normal diploid individual carry at the same time?
Multiple alleles
Medium
A.At most two alleles
B.At most three alleles
C.All five alleles
D.At most four alleles
Correct Answer: At most two alleles
Explanation:
Multiple alleles exist at the population level, but a diploid individual has only two homologous chromosomes and can carry at most two alleles at one locus.
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23A single mutation causes abnormal hemoglobin, anemia, pain during low-oxygen conditions, and resistance to severe malaria. Which genetic phenomenon best explains these effects?
Pleiotropism and pseudoalleles
Medium
A.Incomplete dominance
B.Pleiotropism
C.Codominance
D.Polygenic inheritance
Correct Answer: Pleiotropism
Explanation:
Pleiotropism occurs when one gene influences several phenotypic traits. The altered hemoglobin affects red blood cells and multiple physiological processes.
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24Two recessive mutations produce nearly identical eye defects and map extremely close together. Rare wild-type offspring appear when individuals carrying the mutations on different homologues are crossed. What is the best interpretation?
Pleiotropism and pseudoalleles
Medium
A.The mutations are codominant alleles
B.The mutations are identical alleles
C.The mutations are pseudoalleles
D.The mutations show maternal inheritance
Correct Answer: The mutations are pseudoalleles
Explanation:
Pseudoalleles are distinct, very closely linked loci that affect the same trait. Rare crossing over between them can generate a wild-type chromosome.
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25A person with genotype has children with a person of genotype . What is the probability that a child will have blood group O?
Blood group genetics
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The cross produces , , , and in equal proportions. Only produces blood group O under normal H-antigen expression.
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26A woman has genotype and therefore has the Bombay phenotype. She has children with a man of genotype . Assuming independent assortment, what fraction of their children is expected to show blood group B?
Blood group genetics
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
A child must inherit both from the mother and from the father to express group B. Each event has probability , giving .
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27A woman heterozygous for an X-linked recessive disorder has children with an unaffected man. If they have two sons, what is the probability that exactly one son will be affected?
Sex determination and sex linkage
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Each son has a chance of receiving the mutant X chromosome. The probability that exactly one of two sons is affected is .
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28In a bird species, females are and males are . A dominant Z-linked allele produces barred feathers. A barred female is crossed with an unbarred male . Which result is expected?
Sex determination and sex linkage
Medium
A.All offspring barred regardless of sex
B.Half of each sex barred and half unbarred
C.All sons barred and all daughters unbarred
D.All daughters barred and all sons unbarred
Correct Answer: All sons barred and all daughters unbarred
Explanation:
Sons receive from the mother and from the father, while daughters receive from the mother and from the father.
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29Two X-linked genes are 20 map units apart. A female has genotype and is crossed with an male. What proportion of their sons is expected to inherit the maternal chromosome?
Sex determination and sex linkage
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
A recombination frequency of gives parental gametes. The two parental types, and , each occur at .
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30An allele for pattern baldness is dominant in males but recessive in females. Two heterozygous individuals, , have a son and a daughter. What are their respective probabilities of being bald?
Sex-limited and sex-influenced traits
Medium
A.Son ; daughter
B.Son ; daughter
C.Son ; daughter
D.Son ; daughter
Correct Answer: Son ; daughter
Explanation:
Males with or are bald, giving . Females must be to be bald, giving .
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31A bull carries an allele associated with high milk production but does not produce milk. Several of his daughters show high milk production. How should this trait be classified?
Sex-limited and sex-influenced traits
Medium
A.A cytoplasmic trait
B.A sex-limited trait
C.A sex-influenced trait
D.A sex-linked trait
Correct Answer: A sex-limited trait
Explanation:
The allele can be carried and transmitted by both sexes, but its milk-production phenotype is expressed only in females.
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32In the self-cross , the two genes assort independently. What is the probability that an offspring shows a recessive phenotype for exactly one of the two traits?
Probability and chi-square
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The required phenotypes are or . Their probabilities are each , totaling .
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33A dihybrid cross produces four phenotypic classes with observed counts 315, 108, 101, and 32. Under a expectation, the expected counts are 312.75, 104.25, 104.25, and 34.75. What is the approximate value of ?
Probability and chi-square
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Using gives approximately . This small value indicates close agreement with the expected ratio.
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34Parallel bacterial cultures started from small inocula produce highly variable numbers of antibiotic-resistant colonies before exposure to the antibiotic. What does this observation support?
Mutation
Medium
A.All resistant colonies arise after antibiotic exposure
B.Antibiotics direct cells to form useful mutations
C.Resistance mutations arise spontaneously before selection
D.Resistance results only from temporary physiological changes
Correct Answer: Resistance mutations arise spontaneously before selection
Explanation:
Large variation among cultures is expected when spontaneous mutations occur at different times before selection. The antibiotic selects existing resistant mutants.
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35A DNA base pair changes from to . How is this base substitution classified?
Classification of mutations
Medium
A.A frameshift mutation
B.A transition mutation
C.A deletion mutation
D.A transversion mutation
Correct Answer: A transition mutation
Explanation:
The purine is replaced by the purine , while the complementary pyrimidine changes accordingly. A purine-to-purine substitution is a transition.
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36One nucleotide is inserted near the beginning of a protein-coding sequence. No compensating insertion or deletion occurs. What is the most likely consequence?
Classification of mutations
Medium
A.A silent change affecting one codon
B.An inversion affecting the entire chromosome
C.A transition affecting one amino acid
D.A frameshift affecting many downstream codons
Correct Answer: A frameshift affecting many downstream codons
Explanation:
An insertion not divisible by three changes the reading frame, altering downstream codons and often introducing a premature stop codon.
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37A point mutation changes the mRNA codon , which encodes tyrosine, into . What type of mutation has occurred?
Classification of mutations
Medium
A.A nonsense mutation
B.A frameshift mutation
C.A silent mutation
D.A missense mutation
Correct Answer: A nonsense mutation
Explanation:
is a stop codon. Changing an amino-acid codon into a stop codon is a nonsense mutation and can truncate the protein.
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38A researcher wants to determine an effective ultraviolet dose for inducing mutations in fungal spores. Which experimental design is most appropriate?
Methods of inducing mutations
Medium
A.Treat all groups with one UV dose and omit an untreated control
B.Expose groups to several UV doses and measure survival and mutant frequency
C.Select spontaneous mutants first and expose only those mutants to UV
D.Expose one group to UV and compare only its total growth rate
Correct Answer: Expose groups to several UV doses and measure survival and mutant frequency
Explanation:
A dose series with an untreated control allows the researcher to identify a treatment that increases mutation frequency while retaining enough survivors for screening.
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39A chemical inserts between stacked DNA base pairs and frequently causes single-base insertions or deletions during replication. Which type of mutagen is it?
Mutagenic agents
Medium
A.A deaminating agent
B.An intercalating agent
C.An alkylating agent
D.A base analog
Correct Answer: An intercalating agent
Explanation:
Intercalating agents distort DNA by inserting between base pairs. Replication across the distorted region can produce insertions or deletions and therefore frameshifts.
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40Seeds are treated with EMS to induce recessive mutations. Why are plants with new recessive phenotypes commonly screened in the generation rather than only in the generation?
Induction of mutation
Medium
A.Every induced mutation is eliminated from the generation
B.Recessive mutations can become homozygous after plants self-fertilize
C.Dominant mutations are converted into recessive mutations in
D.EMS remains inactive until the seeds begin germination
Correct Answer: Recessive mutations can become homozygous after plants self-fertilize
Explanation:
A new recessive mutation is usually heterozygous and masked in an plant. Self-fertilization can produce homozygous mutant individuals in the generation.
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41At a locus with four alleles, , , , and , every pair of alleles produces a distinct phenotype, including homozygotes. How many phenotypically distinct genotypes are possible in a diploid population?
Multiple alleles
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The number of unordered diploid genotypes is . Because every genotype has a distinct phenotype, all are phenotypically distinguishable.
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42In a multiple-allele system, allele is dominant to , while both are dominant to . A phenotypically dominant individual is crossed with an individual of genotype , producing offspring in the ratio dominant phenotype to intermediate phenotype to recessive phenotype. Which genotype best describes the first parent?
Multiple alleles
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The first parent must produce , , and possibly no gametes. Crossing gives dominant, intermediate, and recessive classes in equal proportions.
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43A mutation in gene causes reduced pigment, abnormal eye development, and impaired fertility. The most appropriate interpretation is that gene demonstrates:
Pleiotropism and pseudoalleles
Hard
A.Complementation
B.Pleiotropism
C.Recombination
D.Position effect
Correct Answer: Pleiotropism
Explanation:
Pleiotropism occurs when one gene influences multiple phenotypic traits, as seen here with pigment, eye development, and fertility.
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44Two recessive mutations, and , affect the same visible trait. In a trans arrangement, progeny include wild-type recombinants at a frequency of . Which conclusion is most justified?
Pleiotropism and pseudoalleles
Hard
A.The mutations are pseudoalleles at closely linked loci
B.The mutations are independently assorting alleles
C.The mutations are dominant alleles with incomplete penetrance
D.The mutations are alleles at one inseparable locus
Correct Answer: The mutations are pseudoalleles at closely linked loci
Explanation:
Rare wild-type recombinants from mutations affecting the same apparent locus indicate recombination between very closely linked functional units, characteristic of pseudoalleles.
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45A woman with blood group A has a mother with blood group O. She has children with a man of blood group B whose mother had blood group O. What fraction of their children is expected to have blood group O?
Blood group genetics
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The woman must be , and the man must be . Their cross gives , , , and in equal proportions, so blood group O occurs in of offspring.
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46A child is blood group AB and Rh-negative. The mother is blood group A, Rh-positive, and the father is blood group B, Rh-positive. Which parental genotypes are required for this child?
Blood group genetics
Hard
A. and
B. and
C. and
D. and
Correct Answer: and
Explanation:
An AB child requires one and one allele, while an Rh-negative child requires . Therefore, both Rh-positive parents must be heterozygous .
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47In a species with an XX-XO system, females are XX and males are XO. A nondisjunction event during meiosis in a female produces an egg containing two X chromosomes. If this egg is fertilized by a normal male gamete, the resulting offspring will most likely be:
Sex determination and sex linkage
Hard
A.An XXY male
B.A normal XX female
C.An XO male
D.An XXX female
Correct Answer: An XXX female
Explanation:
In an XX-XO system, the male contributes no sex chromosome. An egg containing two X chromosomes therefore produces an XXX individual, which is phenotypically female in the usual chromosome-based model.
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48A recessive X-linked disorder is carried by a woman whose father was affected and whose mother was homozygous normal. She has children with a normal man. What is the probability that a randomly selected child will be an affected son?
Sex determination and sex linkage
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The woman must be a carrier because her affected father gave her the mutant X. A child must be male with probability and inherit the mutant X from her with probability , giving .
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49A father expresses an X-linked dominant trait, while the mother does not carry the allele. Which inheritance pattern is expected among their children?
Sex determination and sex linkage
Hard
A.Half of both sons and daughters are affected
B.All sons and no daughters are affected
C.Affected offspring occur only when both parents carry the allele
D.All daughters and no sons are affected
Correct Answer: All daughters and no sons are affected
Explanation:
The father transmits his X chromosome to every daughter and his Y chromosome to every son. Therefore, all daughters inherit the dominant allele and no sons do.
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50A trait is sex-limited: allele is required for the trait, but the phenotype is expressed only in males. A heterozygous male is crossed with a homozygous recessive female. Assuming equal sex ratios, what fraction of all offspring will express the trait?
Sex-limited and sex-influenced traits
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Half of the offspring inherit , and half of all offspring are male. Thus, the expected fraction expressing the trait is .
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51In a sex-influenced trait, allele is dominant in males but recessive in females. A heterozygous male and a heterozygous female mate. Which outcome is expected?
Sex-limited and sex-influenced traits
Hard
A.All offspring express the trait
B.All male offspring and no female offspring express the trait
C.Only heterozygous offspring express the trait
D.Half of male and one-quarter of female offspring express the trait
Correct Answer: Half of male and one-quarter of female offspring express the trait
Explanation:
The cross produces , , and . In males, and express the trait, giving , while in females only expresses it, giving . Thus, the listed half-and-quarter statement is not correct.
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52In a sex-influenced trait, allele is dominant in males but recessive in females. A heterozygous male and a heterozygous female mate. Which outcome is expected?
Sex-limited and sex-influenced traits
Hard
A.All males and one-quarter of females express the trait
B. of males and of females express the trait
C. of males and of females express the trait
D. of males and of females express the trait
Correct Answer: of males and of females express the trait
Explanation:
The genotypic ratio is . Males express the trait with or , whereas females express it only with .
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53Two heterozygous individuals are crossed for three independently assorting genes, each showing complete dominance. What is the probability that an offspring will display the dominant phenotype for exactly two of the three traits?
Probability and chi-square
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
For each gene, the dominant phenotype has probability and the recessive phenotype has probability . Exactly two dominant phenotypes occur with probability .
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54A testcross produces observed progeny counts of , , , and for four expected classes in a ratio. What is the approximate chi-square value?
Probability and chi-square
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The total is , so each expected class is . Therefore, .
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55A genetic cross gives observed counts of dominant and recessive offspring. Under a hypothesized ratio, what is the correct conclusion at the significance level with degree of freedom?
Probability and chi-square
Hard
A.Accept the hypothesis because the dominant class is larger
B.Reject the hypothesis because exceeds
C.Reject the hypothesis because the sample is too small
D.Accept the hypothesis because the ratio is exactly
Correct Answer: Reject the hypothesis because exceeds
Explanation:
Expected counts are and . The chi-square value is approximately , which is below , so the hypothesis should not be rejected. Therefore, this option is incorrect.
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56A genetic cross gives observed counts of dominant and recessive offspring. Under a hypothesized ratio, what is the correct conclusion at the significance level with degree of freedom?
Probability and chi-square
Hard
A.Reject the hypothesis because the recessive class is below
B.Fail to reject the hypothesis because is approximately
C.Fail to reject the hypothesis only if the ratio is exactly
D.Reject the hypothesis because is approximately
Correct Answer: Fail to reject the hypothesis because is approximately
Explanation:
Expected counts are and , giving . Since this is below the critical value , the observed deviation is not statistically significant.
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57A mutation changes a codon from to . What type of molecular consequence is most directly produced?
Mutation
Hard
A.In-frame insertion
B.Missense substitution
C.Nonsense substitution
D.Silent substitution
Correct Answer: Nonsense substitution
Explanation:
encodes tyrosine, whereas is a stop codon. The substitution therefore introduces premature termination of translation.
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58A single-nucleotide deletion occurs near the beginning of a protein-coding sequence and changes every downstream codon until a premature stop codon appears. This mutation is best classified as:
Classification of mutations
Hard
A.A synonymous mutation
B.A transition mutation
C.A frameshift mutation
D.A reciprocal translocation
Correct Answer: A frameshift mutation
Explanation:
Deletion of one nucleotide shifts the reading frame, altering downstream codons and often generating a premature stop codon.
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59A chromosome segment ABCDEFG becomes ABEDCFG after rearrangement. Which structural mutation is represented?
Classification of mutations
Hard
A.Deletion of C
B.Translocation of CDE
C.Inversion of CDE
D.Duplication of CDE
Correct Answer: Inversion of CDE
Explanation:
The segment CDE has changed to EDC while remaining on the same chromosome, indicating an inversion.
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60A researcher wants to generate a large collection of random point mutations throughout a plant genome while preserving chromosome structure as much as possible. Which treatment is most appropriate?
Methods of inducing mutations
Hard
A.High-temperature denaturation
B.Restriction enzyme digestion in vitro
C.Low-dose EMS treatment
D.Colchicine treatment alone
Correct Answer: Low-dose EMS treatment
Explanation:
Ethyl methanesulfonate, or EMS, is a chemical mutagen commonly used to induce numerous random point mutations, especially base substitutions.
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