1Which logic gate produces a HIGH output only when all its inputs are HIGH?
Logic Gates
Easy
A.OR gate
B.NOR gate
C.NOT gate
D.AND gate
Correct Answer: AND gate
Explanation:
An AND gate outputs only when every input is ; otherwise the output is .
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2The output of a NOT gate is:
Logic Gates
Easy
A.The product of the inputs
B.The sum of the inputs
C.The complement of the input
D.Always HIGH
Correct Answer: The complement of the input
Explanation:
A NOT gate (inverter) reverses the input, so and .
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3Which gate is known as the universal gate along with NOR?
Logic Gates
Easy
A.XOR gate
B.NAND gate
C.AND gate
D.OR gate
Correct Answer: NAND gate
Explanation:
NAND and NOR are universal gates because any Boolean function can be built using only them.
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4The XOR gate produces a HIGH output when:
Logic Gates
Easy
A.Both inputs are HIGH
B.Both inputs are LOW
C.The inputs are equal
D.The inputs are different
Correct Answer: The inputs are different
Explanation:
An XOR gate outputs when its two inputs differ and when they are the same.
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5For a logic function with input variables, how many rows does its truth table have?
Truth Table
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
A truth table has rows, so for it has rows.
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6A truth table is used to:
Truth Table
Easy
A.List all possible input combinations and their outputs
B.Simplify only using algebra
C.Convert decimal to binary
D.Draw only the gate symbols
Correct Answer: List all possible input combinations and their outputs
Explanation:
A truth table shows the output value for every possible combination of the input variables.
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7According to Boolean algebra, the value of is:
Boolean Algebra
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
By the OR identity law, ORing any variable with always gives .
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8The Boolean expression equals:
Boolean Algebra
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
ANDing any variable with always results in (null law).
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9Which of the following correctly states De Morgan's first theorem?
Boolean Algebra
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
De Morgan's first theorem states the complement of a sum equals the product of the complements.
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10The Boolean expression simplifies to:
Boolean Algebra
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
By the idempotent law, .
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11A minterm is a product term that includes:
Canonical and Standard form Representation
Easy
A.Only two variables
B.All variables of the function, each once
C.Only complemented variables
D.Only one variable
Correct Answer: All variables of the function, each once
Explanation:
A minterm is an AND term containing every variable exactly once, either true or complemented.
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12A canonical Sum of Products (SOP) form is a sum of:
Canonical and Standard form Representation
Easy
A.Minterms
B.Maxterms
C.Constants
D.Literals only
Correct Answer: Minterms
Explanation:
Canonical SOP expresses a function as the OR (sum) of its minterms.
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13A maxterm is represented as a:
Canonical and Standard form Representation
Easy
A.Single literal
B.Sum (OR) of all variables
C.Product (AND) of all variables
D.Constant
Correct Answer: Sum (OR) of all variables
Explanation:
A maxterm is an OR term containing every variable once, true or complemented.
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14SOP stands for:
SOP and POS Simplification
Easy
A.Sum of Positions
B.Series of Products
C.Set of Products
D.Sum of Products
Correct Answer: Sum of Products
Explanation:
SOP means Sum of Products, where product (AND) terms are ORed together.
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15In a POS (Product of Sums) expression, the sum terms are combined using the:
SOP and POS Simplification
Easy
A.XOR operation
B.OR operation
C.NOT operation
D.AND operation
Correct Answer: AND operation
Explanation:
In POS form, individual OR (sum) terms are multiplied together using the AND operation.
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16A Boolean function in SOP form can be directly implemented using:
Implementation of Boolean Functions
Easy
A.Only NOT gates
B.Only XOR gates
C.AND gates followed by an OR gate
D.OR gates followed by an AND gate
Correct Answer: AND gates followed by an OR gate
Explanation:
SOP uses AND gates for the product terms whose outputs feed a final OR gate.
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17Which two-level gate structure is used to implement a POS expression?
Implementation of Boolean Functions
Easy
A.AND-OR
B.NAND-NAND
C.OR-AND
D.NOT-OR
Correct Answer: OR-AND
Explanation:
POS is implemented with OR gates for the sum terms followed by an AND gate.
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18A Karnaugh map (K-Map) is mainly used to:
K-Map
Easy
A.Generate clock signals
B.Simplify Boolean expressions
C.Store binary data
D.Convert decimal to hex
Correct Answer: Simplify Boolean expressions
Explanation:
A K-Map is a graphical tool used to minimize Boolean functions easily.
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19How many cells does a K-Map for variables contain?
K-Map
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
A K-Map has cells, so for variables it has cells.
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20A don't care condition in a K-Map is usually denoted by:
Don't Care
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
Don't care conditions are marked with and can be treated as or to aid simplification.
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21Which single logic gate can be used to implement any Boolean function, and is therefore called a universal gate, when its output equals ?
Logic Gates
Medium
A.AND
B.OR
C.XOR
D.NAND
Correct Answer: NAND
Explanation:
The expression is the NAND function. NAND (and NOR) are universal gates because any Boolean function can be realized using only NAND gates.
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22The output of a 2-input XNOR gate is HIGH when:
Logic Gates
Medium
A.Both inputs are LOW only
B.Exactly one input is HIGH
C.Both inputs are equal
D.Both inputs are HIGH only
Correct Answer: Both inputs are equal
Explanation:
XNOR outputs when inputs match (both or both ), i.e. .
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23A truth table for a Boolean function has input variables. How many rows will the complete truth table contain?
Truth Table
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Each of the variables can be or , giving distinct input combinations, hence rows.
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24A function outputs only for the rows and . Which function does this truth table represent?
Truth Table
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Output is only when the inputs differ, which is the definition of the XOR function .
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25Simplify the Boolean expression .
Boolean Algebra
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Using the absorption-type identity , since .
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26According to De Morgan's theorem, is equal to:
Boolean Algebra
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
De Morgan's theorem converts the complement of a sum into the product of complements: .
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27Which of the following is the correct simplification of ?
Boolean Algebra
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
; then . So the result is .
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28A minterm of a Boolean function is a product term in which:
Canonical and Standard form Representation
Medium
A.Only complemented variables are allowed to appear
B.Every variable appears exactly once, either complemented or uncomplemented
C.At least one variable appears in true form
D.Variables are combined using the OR operation exclusively
Correct Answer: Every variable appears exactly once, either complemented or uncomplemented
Explanation:
A minterm is an AND term containing all variables, each appearing once in true or complemented form; it evaluates to for exactly one input combination.
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29For a 3-variable function, the minterm corresponds to which product term?
Canonical and Standard form Representation
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
in binary is , so , giving the minterm .
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30If a function is expressed as for variables , then in maxterm form the same function is:
Canonical and Standard form Representation
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The maxterm indices are the input combinations not listed as minterms. Since minterms are , the maxterms are the remaining .
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31The Product of Sums (POS) form of a Boolean function is a logical:
SOP and POS Simplification
Medium
A.OR of AND terms
B.AND of OR terms
C.OR of OR terms
D.AND of AND terms
Correct Answer: AND of OR terms
Explanation:
In POS, sum (OR) terms are combined using the product (AND) operation, i.e. an AND of OR terms such as .
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32Convert the expression into its simplified SOP form.
SOP and POS Simplification
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
By the distributive law , which is the well-known distributive identity.
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33Which of the following statements about SOP and POS is correct?
SOP and POS Simplification
Medium
A.A canonical POS uses minterms while a canonical SOP uses maxterms
B.SOP and POS forms can never represent the same Boolean function
C.A canonical SOP uses minterms while a canonical POS uses maxterms
D.Both canonical SOP and POS are always built entirely from minterms of the function
Correct Answer: A canonical SOP uses minterms while a canonical POS uses maxterms
Explanation:
Canonical SOP is a sum of minterms (where ), while canonical POS is a product of maxterms (where ). Both represent the same function.
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34To implement the function using only NAND gates, the minimum number of 2-input NAND gates required is:
Implementation of Boolean Functions
Medium
A.5
B.3
C.4
D.2
Correct Answer: 3
Explanation:
Two NAND gates produce and ; a third NAND combining them gives . So gates suffice.
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35A two-level AND-OR logic circuit can be directly converted to an equivalent two-level circuit using only:
Implementation of Boolean Functions
Medium
A.XOR gates
B.AND gates
C.NAND gates
D.OR gates
Correct Answer: NAND gates
Explanation:
Any two-level AND-OR (SOP) circuit maps directly to an all-NAND two-level implementation by replacing every gate with a NAND, since NAND is functionally complete.
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36A POS (OR-AND) implementation can be replaced by a two-level circuit using only which universal gate?
Implementation of Boolean Functions
Medium
A.NAND
B.XNOR
C.AND
D.NOR
Correct Answer: NOR
Explanation:
An OR-AND (POS) structure maps directly to an all-NOR two-level circuit, just as AND-OR maps to all-NAND.
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37In a 4-variable Karnaugh map, a group of 8 adjacent cells (an octet) eliminates how many variables from the resulting product term?
K-Map
Medium
A.3
B.2
C.1
D.4
Correct Answer: 3
Explanation:
Grouping cells eliminates variables. An octet contains cells, so variables are eliminated, leaving one variable.
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38Why must adjacent cells in a Karnaugh map differ in the value of exactly one variable when moving horizontally or vertically?
K-Map
Medium
A.Because the cells are arranged in Gray code order so that only one bit changes between neighbours, allowing valid grouping
B.Because it reduces the total number of cells needed in the map
C.Because binary counting order is used to label the rows and columns
D.Because it forces the output column to alternate between and
Correct Answer: Because the cells are arranged in Gray code order so that only one bit changes between neighbours, allowing valid grouping
Explanation:
K-map rows and columns follow Gray code, so adjacent cells differ in one variable. This adjacency lets a variable be eliminated when cells are grouped.
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39A K-map grouping of 4 cells for a 3-variable function results in a product term containing how many literals?
K-Map
Medium
A.0
B.1
C.3
D.2
Correct Answer: 1
Explanation:
For variables, a group of cells eliminates variables, leaving literal in the term.
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40Don't-care conditions in a Karnaugh map are useful because they:
Don't Care
Medium
A.Must always be treated as 1 to guarantee a valid output for every input
B.Can be treated as either 0 or 1 to form larger groups and achieve greater simplification
C.Represent inputs that force the function output to remain permanently at 0
D.Are ignored entirely and never influence how groups are formed on the map
Correct Answer: Can be treated as either 0 or 1 to form larger groups and achieve greater simplification
Explanation:
Don't-care terms () may be assigned or as convenient. Including them in groups when it helps forms larger groups and yields a simpler minimized expression.
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41Simplify the Boolean expression to its minimal form.
Boolean Algebra
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
First . Then .
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42For , what is the minimal SOP expression using a K-map?
K-Map
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Grouping the eight cells with gives . Remaining minterms 8,12,14 combine as (m0,2,8,... ) is incorrect; careful grouping yields covering all minterms.
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43Given with don't cares , what is the simplest SOP?
Don't Care
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Minterms 3,7,11,15 form group . Minterm 1 with don't cares 0,2,5 groups into , giving the minimal .
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44A 2-input gate outputs only when both inputs differ, and its output is then inverted. Which single gate is functionally equivalent to this description?
Logic Gates
Hard
A.NAND gate
B.NOR gate
C.XOR gate
D.XNOR gate
Correct Answer: XNOR gate
Explanation:
Inputs differing gives XOR ; inverting XOR yields XNOR, which outputs when inputs are equal. The inverted 'differ' condition is exactly XNOR.
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45Convert into its minimal SOP form for variables .
SOP and POS Simplification
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Maxterms 0,2,4,6 correspond to rows. So when , meaning when . Thus .
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46The function is expressed as a product of maxterms. Which is correct?
Canonical and Standard form Representation
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The maxterms are the indices not present in the minterm list. Since minterms are 1,4,5,6,7, the missing indices 0,2,3 form the maxterm (POS) representation.
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47What is the minimum number of two-input NAND gates required to implement ?
Implementation of Boolean Functions
Hard
A.3
B.2
C.5
D.4
Correct Answer: 3
Explanation:
Using NAND-NAND logic: two NANDs produce and , and a third NAND combines them: . Total three gates.
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48For a 4-variable K-map, a prime implicant that is the only cover for some minterm is called what?
K-Map
Hard
A.Non-essential prime implicant
B.Redundant prime implicant
C.Selective prime implicant
D.Essential prime implicant
Correct Answer: Essential prime implicant
Explanation:
An essential prime implicant is a prime implicant that covers at least one minterm not covered by any other prime implicant, so it must be included in the minimal expression.
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49Using the consensus theorem, simplify .
Boolean Algebra
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The consensus term of and is , which is redundant and can be removed. Hence .
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50A 3-input function outputs when an odd number of inputs are . How many rows of its truth table have output ?
Truth Table
Hard
A.3
B.5
C.2
D.4
Correct Answer: 4
Explanation:
Odd-parity for 3 inputs is true for combinations with one or three 1s: and , totaling 4 rows.
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51Minimize .
SOP and POS Simplification
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Grouping minterms 0,1 gives ; minterms 1,3 give ; minterms 6,7 give . Combined minimal SOP is .
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52For with , which minimal expression is valid?
Don't Care
Hard
A.
B.
C. giving -type forms
D.
Correct Answer:
Explanation:
Minterms 2,8,10 with don't cares 0 combine into ; don't cares 1,3 help form -type groups; minterm 15 needs . This yields a valid minimal cover.
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53Which statement about the universality of NOR gates is correct?
Logic Gates
Hard
A.A NOR gate can realize AND and OR but not NOT
B.A NOR gate can realize NOT and OR but not AND
C.A NOR gate alone can realize AND, OR, and NOT functions
D.A NOR gate can only realize the OR function
Correct Answer: A NOR gate alone can realize AND, OR, and NOT functions
Explanation:
NOR is a universal gate. NOT is a NOR with tied inputs, OR is a NOR followed by NOR-inverter, and AND is realized by inverting inputs then NOR. Thus all basic functions are achievable.
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54Apply DeMorgan's theorem to simplify .
Boolean Algebra
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
using DeMorgan twice.
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55To implement any arbitrary 3-variable Boolean function using a single multiplexer, how many selection lines and data inputs are needed?
Implementation of Boolean Functions
Hard
A.3 selection lines and 4 data inputs
B.2 selection lines and 8 data inputs
C.3 selection lines and 8 data inputs
D.4 selection lines and 8 data inputs
Correct Answer: 3 selection lines and 8 data inputs
Explanation:
An MUX has 3 select lines carrying the 3 variables and 8 data inputs set to each minterm's output value, directly implementing any 3-variable function.
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56The standard SOP form differs from the canonical SOP form in that standard SOP:
Canonical and Standard form Representation
Hard
A.Allows product terms that are not full minterms
B.Cannot be simplified further
C.Uses only maxterms in the expression
D.Requires every term to contain all variables
Correct Answer: Allows product terms that are not full minterms
Explanation:
Canonical SOP requires each term to be a minterm containing all variables. Standard (minimized) SOP allows product terms with fewer literals, i.e., not necessarily full minterms.
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57In a 5-variable K-map, two mirrored cells across the axis of symmetry that hold the same value can be combined. What does such a combination eliminate?
K-Map
Hard
A.The variable distinguishing the two map halves
B.The output variable
C.None of the input variables
D.Two variables simultaneously
Correct Answer: The variable distinguishing the two map halves
Explanation:
The 5-variable K-map is drawn as two 4-variable maps. Mirror-image cells differ only in the fifth (most significant) variable, so combining them eliminates that distinguishing variable.
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58A function of 4 variables has exactly 6 minterms set to . What is the number of maxterms in its POS canonical form?
Truth Table
Hard
A.10
B.4
C.6
D.16
Correct Answer: 10
Explanation:
A 4-variable function has rows. Maxterms correspond to rows where output is : maxterms.
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59Which pair of expressions represents the same function, demonstrating SOP–POS duality?
SOP and POS Simplification
Hard
A. and for 2 variables
B. and for 2 variables
C. and for 2 variables
D. and for 2 variables
Correct Answer: and for 2 variables
Explanation:
For a 2-variable function ( terms), the maxterm indices are those absent from the minterm list. Minterms leave index as the only maxterm, so .
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60A function is to be implemented. What is the minimum number of 2-input gates (any type) after full simplification?
Implementation of Boolean Functions
Hard
A. needing 1 gate
B. needing 2 gates
C. needing 3 gates
D. needs 5 gates with no simplification
Correct Answer: needing 3 gates
Explanation:
(one XOR gate). Adding requires an AND gate plus an OR gate, giving with 3 gates total.
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