Turning supersonic flow toward itself at a compression corner commonly creates an oblique shock.
Incorrect! Try again.
13Which velocity component is used in the normal-shock relations for an oblique shock?
Oblique shock
Easy
A.Stagnation component
B.Spanwise component
C.Tangential component
D.Normal component
Correct Answer: Normal component
Explanation:
The component normal to an oblique shock undergoes the same changes described by normal-shock relations.
Incorrect! Try again.
14For an inviscid oblique shock, what happens to the tangential velocity component?
Oblique shock
Easy
A.It increases until it is equal to the upstream speed
B.It remains unchanged
C.It reverses direction
D.It becomes zero
Correct Answer: It remains unchanged
Explanation:
In inviscid flow, the tangential velocity component is continuous across an oblique shock.
Incorrect! Try again.
15Why can an oblique shock reflect from a solid wall?
Reflection of flow
Easy
A.To make the downstream flow cross through the impermeable wall
B.To create an expansion fan
C.To satisfy the wall condition
D.To eliminate fluid density
Correct Answer: To satisfy the wall condition
Explanation:
The reflected shock turns the flow so that it satisfies the no-penetration condition at the wall.
Incorrect! Try again.
16What may occur when two oblique shock waves meet?
Interaction of oblique shock waves
Easy
A.Boundary evaporation
B.Isentropic stagnation
C.Shock interaction
D.Complete disappearance of every pressure change in the flow
Correct Answer: Shock interaction
Explanation:
Intersecting oblique shocks interact and can generate reflected or transmitted waves and a slip line.
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17In a regular shock reflection, which waves meet at the wall?
Interaction of oblique shock waves
Easy
A.Two expansion fans
B.Incident and reflected shocks
C.A shock and a vortex
D.A normal shock followed by a long viscous wake and separation bubble
Correct Answer: Incident and reflected shocks
Explanation:
Regular reflection consists of an incident shock meeting the wall and a reflected shock leaving the same point.
Incorrect! Try again.
18Which quantity is normally continuous across a slip line in inviscid flow?
Slip line
Easy
A.Tangential velocity
B.Static pressure
C.Stagnation temperature
D.Fluid density
Correct Answer: Static pressure
Explanation:
Static pressure is continuous across a slip line, although density and tangential velocity may differ.
Incorrect! Try again.
19What pressure condition does a shock usually impose on a boundary layer?
Shock-boundary layer interaction
Easy
A.Favorable pressure gradient
B.Uniformly decreasing pressure along the entire solid surface
C.Adverse pressure gradient
D.Zero pressure gradient
Correct Answer: Adverse pressure gradient
Explanation:
The pressure rise through a shock creates an adverse pressure gradient in the boundary layer.
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20A strong shock-boundary layer interaction can cause which flow phenomenon?
Shock-boundary layer interaction
Easy
A.Uniform-flow restoration
B.Boundary-layer separation
C.Complete removal of viscosity from the fluid near the wall
D.Isentropic acceleration
Correct Answer: Boundary-layer separation
Explanation:
A sufficiently strong shock-induced adverse pressure gradient can make the boundary layer separate from the surface.
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21A supersonic flow passes through a sequence of increasingly strong compression waves in a converging region. Why can these waves develop into a normal shock?
Development of normal shocks
Medium
A.Viscous forces accelerate all compression waves to the same speed
B.Compression waves travel slower in the hotter compressed gas and spread apart
C.Expansion waves increase the upstream Mach number and merge
D.Compression waves travel faster in the hotter compressed gas and coalesce
Correct Answer: Compression waves travel faster in the hotter compressed gas and coalesce
Explanation:
The local sound speed rises in compressed, hotter gas. Later compression waves can therefore catch earlier waves, causing them to steepen and merge into a shock.
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22For air with , a normal shock forms at an upstream Mach number of . What is the approximate density ratio ?
Development of normal shocks
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Using gives .
Incorrect! Try again.
23A stationary normal shock occurs in an adiabatic, constant-area duct with no shaft work. Which property remains constant across the shock?
Governing equations
Medium
A.Static pressure
B.Stagnation pressure
C.Specific entropy
D.Stagnation enthalpy
Correct Answer: Stagnation enthalpy
Explanation:
Conservation of energy gives , so stagnation enthalpy remains constant. Entropy increases and stagnation pressure decreases.
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24Air with enters a normal shock at . Using the normal-shock relation, what is the approximate downstream Mach number?
Governing equations
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The relation gives .
Incorrect! Try again.
25Which expression represents the Hugoniot energy relation between states 1 and 2, where is specific volume?
Hugoniot equation
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Combining mass, momentum, and energy conservation across an adiabatic shock gives .
Incorrect! Try again.
26On a pressure-specific-volume diagram, how is the physically possible downstream shock state determined for a specified upstream state and mass flux?
Hugoniot equation
Medium
A.By intersecting the Fanno line with the sonic line
B.By intersecting an isentrope with a constant-volume line
C.By intersecting an isotherm with a constant-pressure line
D.By intersecting the Hugoniot curve with the Rayleigh line
Correct Answer: By intersecting the Hugoniot curve with the Rayleigh line
Explanation:
The Hugoniot curve enforces the energy relation, while the Rayleigh line enforces momentum conservation for the specified mass flux.
Incorrect! Try again.
27Gas moves to the right at while a normal shock moves to the left at . If the upstream sound speed is , what is the upstream Mach number relative to the shock?
Stationary and moving normal shock waves and applications
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Taking rightward velocity as positive, the shock speed is . Thus, .
Incorrect! Try again.
28A normal shock travels at into stationary air whose sound speed is . What upstream Mach number is observed in the shock-fixed frame?
Stationary and moving normal shock waves and applications
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
In the shock-fixed frame, stationary air approaches at the shock speed. Therefore, .
Incorrect! Try again.
29A normal shock stands ahead of a blunt body in supersonic flight. Which change occurs as the flow crosses the shock?
Stationary and moving normal shock waves and applications
Medium
A.Mach number increases and stagnation temperature decreases
B.Mach number decreases and stagnation pressure increases
C.Mach number decreases and stagnation pressure decreases
D.Mach number increases and stagnation pressure remains constant
Correct Answer: Mach number decreases and stagnation pressure decreases
Explanation:
A normal shock makes the flow subsonic and causes an irreversible loss of stagnation pressure, while stagnation temperature remains constant for adiabatic flow.
Incorrect! Try again.
30For air at , an oblique shock has a shock angle . What is the approximate pressure ratio ?
Oblique shock
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The normal Mach number is . Applying the normal-shock pressure relation gives .
Incorrect! Try again.
31For a fixed supersonic upstream Mach number, the wedge deflection angle is increased while remaining below the maximum angle for an attached weak shock. What generally happens?
Oblique shock
Medium
A.Shock angle decreases and downstream Mach number increases
B.Shock angle increases and downstream Mach number increases
C.Shock angle increases and downstream Mach number decreases
D.Shock angle decreases and downstream Mach number decreases
Correct Answer: Shock angle increases and downstream Mach number decreases
Explanation:
A larger compression deflection produces a stronger weak shock. The shock angle and pressure rise increase, while the downstream Mach number generally decreases.
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32At , the Mach angle is . Which shock angle can represent an attached compression shock?
Oblique shock
Medium
A.
B.
C.
D. only
Correct Answer:
Explanation:
An attached oblique shock must have . Thus, is possible, whereas is only the limiting Mach-wave angle.
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33An oblique shock strikes a straight solid wall in a regular reflection. What is the main role of the reflected shock?
Reflection of flow
Medium
A.To restore the upstream stagnation pressure
B.To turn the flow back parallel to the wall
C.To turn the flow further into the wall
D.To convert the flow into an expansion fan
Correct Answer: To turn the flow back parallel to the wall
Explanation:
The incident shock deflects the flow toward the wall. The reflected shock provides an opposing deflection so that the downstream flow satisfies wall tangency.
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34When regular reflection cannot satisfy the required turning and pressure conditions, which pattern commonly develops?
Reflection of flow
Medium
A.A contact surface without reflected waves
B.A Prandtl-Meyer fan and sonic throat
C.A Mach stem, triple point, and slip line
D.A normal shock followed by an isentrope
Correct Answer: A Mach stem, triple point, and slip line
Explanation:
Mach reflection contains an incident shock, reflected shock, and Mach stem meeting at a triple point, with a slip line extending downstream.
Incorrect! Try again.
35Two equal oblique shocks generated by symmetric compression corners meet on the duct centerline. What flow pattern is expected immediately after their symmetric interaction?
Interaction of oblique shock waves
Medium
A.A slip line separates streams at unequal static pressures
B.Expansion fans turn both streams away from the centerline
C.Reflected shocks restore flow parallel to the centerline
D.A normal shock accelerates both streams to supersonic speed
Correct Answer: Reflected shocks restore flow parallel to the centerline
Explanation:
Symmetry requires zero transverse velocity on the centerline. Reflected shocks turn the two streams back so that the downstream flow becomes parallel to it.
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36Two unequal oblique shocks intersect, producing downstream regions that initially have different pressures and flow directions. What structure commonly completes the interaction?
Interaction of oblique shock waves
Medium
A.A single isentropic compression without discontinuities
B.Adjustment waves accompanied by a slip line
C.A constant-pressure region bounded by Mach waves
D.Two expansion fans with no contact surface
Correct Answer: Adjustment waves accompanied by a slip line
Explanation:
Additional shocks or expansion waves adjust pressure and flow direction. A slip line then separates streams that can differ in density, entropy, and speed.
Incorrect! Try again.
37Which set of conditions is appropriate across an inviscid slip line?
Slip line
Medium
A.Temperature and entropy are continuous, but pressure may change
B.Density and tangential velocity are continuous, but pressure may change
C.Pressure and density are continuous, but normal velocity may change
D.Pressure and normal velocity are continuous, but density may change
Correct Answer: Pressure and normal velocity are continuous, but density may change
Explanation:
A slip line is a contact discontinuity. Pressure and normal velocity match across it, while density, entropy, and tangential velocity may be discontinuous.
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38Why is there no mass flow across a steady slip line even though the velocities on its two sides may differ?
Slip line
Medium
A.Both velocity magnitudes must be exactly equal
B.Both velocity vectors are tangent to the slip line
C.The static pressure prevents all tangential motion
D.The density on the slip line must become zero
Correct Answer: Both velocity vectors are tangent to the slip line
Explanation:
A steady slip line is a streamline for both adjacent flows. Their normal velocity components vanish, although tangential speeds may differ.
Incorrect! Try again.
39A strong shock imposes a rapid pressure rise on a boundary layer. Which response is most likely if the boundary layer has insufficient momentum?
Shock-boundary layer interaction
Medium
A.Separation caused by the adverse pressure gradient
B.Expansion caused by an increased stagnation pressure
C.Acceleration caused by an unchanged static pressure
D.Relaminarization caused by a favorable pressure gradient
Correct Answer: Separation caused by the adverse pressure gradient
Explanation:
The shock creates a strong adverse pressure gradient. Low-momentum fluid near the wall may reverse direction, producing boundary-layer separation.
Incorrect! Try again.
40Why can the pressure rise from a shock influence the boundary layer upstream of the nominal shock location?
Shock-boundary layer interaction
Medium
A.The wall converts every shock into an upstream expansion wave
B.The subsonic near-wall region can transmit pressure disturbances upstream
C.The stagnation pressure increases inside the viscous sublayer
Correct Answer: The subsonic near-wall region can transmit pressure disturbances upstream
Explanation:
Velocity is low near the wall, so part of the boundary layer is locally subsonic. Pressure information can propagate upstream through this region.
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41A finite-amplitude one-dimensional compression disturbance propagates into initially uniform gas. Which mechanism causes it to evolve into a normal shock?
Development of normal shocks
Hard
A.The leading portion loses stagnation enthalpy and decelerates relative to the rear
B.The compressed rear portion has smaller and falls behind the leading portion
C.The leading portion gains entropy continuously while all characteristics remain parallel
D.The compressed rear portion has larger and overtakes the leading portion
Correct Answer: The compressed rear portion has larger and overtakes the leading portion
Explanation:
Compression raises both flow velocity and sound speed, so rearward compression characteristics propagate faster. Their coalescence produces a shock discontinuity.
Incorrect! Try again.
42Air with passes through a stationary normal shock at . Which set of downstream ratios and Mach number is correct?
Governing equations
Hard
A., , ,
B., , ,
C., , ,
D., , ,
Correct Answer: , , ,
Explanation:
Applying mass, momentum, and energy conservation gives and . Thus and .
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43For a calorically perfect gas with , the measured Mach number immediately behind a normal shock is . What was the upstream Mach number?
Governing equations
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Using and setting gives , hence .
Incorrect! Try again.
44Let denote specific volume. For a calorically perfect gas, which pressure-volume relation represents the shock Hugoniot through state 1?
Hugoniot equation
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Combining with produces this pressure-volume Hugoniot relation.
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45States 1 and 2 lie on both a Rayleigh line and the shock Hugoniot. If the mass flux through the shock is , which expression follows from momentum conservation?
Hugoniot equation
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Momentum conservation gives . Therefore , and the Rayleigh-line slope in the - plane is .
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46A normal shock moves at speed into stationary air with . What is the gas velocity immediately behind the shock in the laboratory frame?
Stationary and moving normal shock waves and applications
Hard
A. in the shock-propagation direction
B. opposite the shock-propagation direction
C. in the shock-propagation direction
D. in the shock-propagation direction
Correct Answer: in the shock-propagation direction
Explanation:
In the shock-fixed frame, and . Hence .
Incorrect! Try again.
47An ideal Pitot probe is placed in an air stream at with . Accounting for the detached normal shock ahead of the probe, what pressure ratio does it approximately measure relative to upstream static pressure?
Stationary and moving normal shock waves and applications
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
For , and . Isentropic deceleration behind the shock gives .
Incorrect! Try again.
48A weak oblique shock in air has and shock angle . Which pair most closely gives the flow deflection and downstream Mach number?
Oblique shock
Hard
A.,
B.,
C.,
D.,
Correct Answer: ,
Explanation:
The -- relation gives . Applying normal-shock relations to and resolving downstream gives .
Incorrect! Try again.
49A two-dimensional compression corner turns a Mach 2 air stream through . Assuming , what shock structure should be expected near the corner?
Oblique shock
Hard
A.A detached curved shock because exceeds the attached-shock limit
B.A centered compression fan because compression characteristics must diverge
C.An attached strong shock because every turning angle has a strong solution
D.An attached weak shock because is below the Mach angle
Correct Answer: A detached curved shock because exceeds the attached-shock limit
Explanation:
At and , the maximum attached deflection is about . A turn therefore cannot support an attached oblique shock.
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50For a deflection below , weak and strong oblique-shock solutions exist at the same upstream Mach number. Which comparison is generally correct?
Oblique shock
Hard
A.The weak branch has larger , larger entropy rise, and always subsonic downstream flow
B.The strong branch has larger , larger pressure rise, and usually subsonic downstream flow
C.The strong branch has smaller , smaller pressure rise, and always supersonic downstream flow
D.The weak branch has normal-shock angle, zero turning, and unchanged stagnation pressure
Correct Answer: The strong branch has larger , larger pressure rise, and usually subsonic downstream flow
Explanation:
The strong solution lies closer to the normal-shock limit, producing stronger compression and entropy generation. Its downstream state is generally subsonic, unlike most weak-branch solutions.
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51An incident oblique shock turns a supersonic flow toward a straight wall. Which condition is required for regular reflection from that wall?
Reflection of flow
Hard
A.The reflected shock must have the same angle and pressure ratio as the incident shock
B.The post-incident flow must admit a reflected shock that exactly restores wall tangency
C.The wall pressure must remain equal to the undisturbed upstream static pressure
D.The incident shock must reduce the post-shock Mach number below unity everywhere
Correct Answer: The post-incident flow must admit a reflected shock that exactly restores wall tangency
Explanation:
The reflected shock must turn the post-incident velocity back to a direction parallel to the wall. If that required turn exceeds the available attached-shock limit, regular reflection is impossible.
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52As the incidence angle increases, regular reflection transitions to Mach reflection. Which feature distinguishes the Mach-reflection configuration?
Reflection of flow
Hard
A.A centered expansion replaces the incident shock at the reflection point
B.An incident shock, reflected shock, and Mach stem meet at a triple point
C.Two identical reflected shocks intersect without forming a contact surface
D.A single normal shock attaches directly to the compression-corner vertex
Correct Answer: An incident shock, reflected shock, and Mach stem meet at a triple point
Explanation:
Mach reflection contains a near-normal Mach stem joined to the incident and reflected shocks at a triple point. A slip line also emerges because the adjoining downstream states differ.
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53A fixed total compression turn is produced either by one oblique shock or by several weaker oblique shocks with intermediate flow alignment. In the weak-shock limit, which arrangement best preserves stagnation pressure?
Interaction of oblique shock waves
Hard
A.One stronger shock, because stagnation pressure loss is linear in the total turning angle
B.Both arrangements, because stagnation pressure depends only on the final static pressure
C.Several weaker shocks, because shock entropy generation scales approximately with the cube of strength
D.One stronger shock, because each additional shock restores part of the stagnation pressure
Correct Answer: Several weaker shocks, because shock entropy generation scales approximately with the cube of strength
Explanation:
Dividing a fixed compression into weaker shocks reduces total entropy production. This is why staged compression can retain more stagnation pressure than one strong shock.
Incorrect! Try again.
54Two oblique shocks intersect, producing different shock sequences on the two sides of a downstream discontinuity. What compatibility conditions must the final states satisfy along that discontinuity?
Interaction of oblique shock waves
Hard
A.Equal density and speed, but possibly unequal static pressure and direction
B.Equal Mach number and entropy, but possibly unequal velocity direction
C.Equal static pressure and parallel velocity, but possibly unequal density and speed
D.Equal stagnation pressure and temperature, but possibly unequal static pressure
Correct Answer: Equal static pressure and parallel velocity, but possibly unequal density and speed
Explanation:
The downstream discontinuity is a slip line. Pressure and normal velocity must be continuous, while entropy, density, tangential velocity, and stagnation pressure may differ.
Incorrect! Try again.
55In a shock-polar construction for the interaction of two supersonic streams, what does a physically admissible intersection of the downstream shock polars represent?
Interaction of oblique shock waves
Hard
A.A common stagnation pressure and entropy compatible with an expansion fan
B.A common downstream pressure and flow direction compatible with a slip line
C.A common shock angle and velocity magnitude compatible with wall reflection
D.A common downstream density and Mach number compatible with a normal shock
Correct Answer: A common downstream pressure and flow direction compatible with a slip line
Explanation:
Intersecting shock polars identify states having equal static pressure and matching flow direction. These are the mechanical compatibility requirements across the resulting slip line.
Incorrect! Try again.
56For an inviscid stationary slip line, which set of quantities is constrained to be continuous across the line?
Slip line
Hard
A.Entropy and tangential velocity
B.Static pressure and tangential velocity
C.Density and normal velocity
D.Static pressure and normal velocity
Correct Answer: Static pressure and normal velocity
Explanation:
A slip line is a contact discontinuity. Pressure and normal velocity are continuous, whereas density, entropy, temperature, and tangential velocity may jump.
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57Two streams originate from the same uniform calorically perfect gas and pass through unequal adiabatic shock sequences before meeting at a slip line. Which statement is correct?
Slip line
Hard
A.Their stagnation temperatures remain equal, while their stagnation pressures may differ
B.Their stagnation pressures remain equal, while their stagnation temperatures may differ
C.Their static temperatures must be equal, while their static pressures may differ
D.Their densities must be equal, while their velocity magnitudes may differ
Correct Answer: Their stagnation temperatures remain equal, while their stagnation pressures may differ
Explanation:
Adiabatic shocks conserve stagnation enthalpy and therefore stagnation temperature. Unequal entropy generation causes unequal stagnation pressures despite pressure compatibility at the slip line.
Incorrect! Try again.
58During shock-induced boundary-layer separation, which local condition most directly identifies incipient separation at the wall?
Shock-boundary layer interaction
Hard
A. when the displacement thickness reaches its minimum value
B. at the maximum boundary-layer thickness
C. before local reverse flow develops
D. while the external Mach number remains greater than unity
Correct Answer: before local reverse flow develops
Explanation:
Incipient separation occurs when wall shear stress vanishes. A stronger adverse pressure gradient then produces negative wall shear and local reversed flow.
Incorrect! Try again.
59Why can a compression-induced pressure rise influence a turbulent boundary layer upstream of the nominal shock impingement point even when the external stream is supersonic?
Shock-boundary layer interaction
Hard
A.The low-speed near-wall region contains subsonic paths that transmit pressure disturbances upstream
B.The inviscid supersonic core carries acoustic disturbances upstream along both Mach lines
C.The shock converts all upstream boundary-layer fluid into an incompressible potential flow
D.The wall directly transmits pressure information upstream without involving the fluid
Correct Answer: The low-speed near-wall region contains subsonic paths that transmit pressure disturbances upstream
Explanation:
Velocity approaches zero at the wall, so part of the boundary layer is locally subsonic. Pressure information can propagate upstream through this region, causing boundary-layer thickening or separation.
Incorrect! Try again.
60A strong shock impinges on a boundary layer and creates a separated region with a characteristic -shock pattern. What primarily forms the upstream leg of this pattern?
Shock-boundary layer interaction
Hard
A.Acoustic waves reflected from the wall combine into an isentropic compression fan
B.Vorticity waves from the inviscid core merge into a contact discontinuity at the wall
C.Expansion waves generated at reattachment coalesce into a normal shock ahead of separation
D.Compression waves generated by boundary-layer displacement and separation coalesce into a separation shock
Correct Answer: Compression waves generated by boundary-layer displacement and separation coalesce into a separation shock
Explanation:
The separated boundary layer acts as an effective compression ramp. Its upstream influence generates compression waves that merge into the forward leg of the structure.
Incorrect! Try again.
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