1What does the term 'Bipolar' in Bipolar Junction Transistor (BJT) signify?
Junction transistor
Easy
A.Conduction is due to electrons only
B.It has two poles for connection
C.Conduction is due to both electrons and holes
D.It requires two power supplies to operate
Correct Answer: Conduction is due to both electrons and holes
Explanation:
In a BJT, both majority and minority charge carriers (electrons and holes) participate in the conduction process, hence the name 'bipolar'.
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2How many PN junctions are present in a standard Bipolar Junction Transistor?
Junction transistor
Easy
A.Four
B.Two
C.Three
D.One
Correct Answer: Two
Explanation:
A BJT is formed by sandwiching one type of semiconductor material between two layers of the opposite type, creating two PN junctions (Emitter-Base and Collector-Base).
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3Which region of a BJT is the most heavily doped?
Junction transistor
Easy
A.Base
B.Collector
C.Emitter
D.Gate
Correct Answer: Emitter
Explanation:
The emitter is heavily doped because its primary function is to inject a large number of charge carriers into the base.
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4For a BJT to operate in the active region, what must be the biasing conditions of its junctions?
Operation
Easy
A.Emitter-Base is forward biased, Collector-Base is reverse biased
B.Emitter-Base is reverse biased, Collector-Base is forward biased
C.Both junctions are forward biased
D.Both junctions are reverse biased
Correct Answer: Emitter-Base is forward biased, Collector-Base is reverse biased
Explanation:
In the active region, the Emitter-Base junction is forward biased to inject carriers, while the Collector-Base junction is reverse biased to collect them.
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5Which physical region of a BJT is designed to be the largest in size?
Operation
Easy
A.Base
B.Emitter
C.Drain
D.Collector
Correct Answer: Collector
Explanation:
The collector is physically the largest region because it must dissipate the most heat generated during the operation of the transistor.
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6What is the standard relationship between the emitter current (), base current (), and collector current () in a BJT?
Transistor current components
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
By Kirchhoff's Current Law, the total current entering the transistor (emitter current) must equal the sum of the currents leaving it (base and collector currents).
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7Which current component is typically the smallest in a normally operating BJT?
Transistor current components
Easy
A.Emitter current ()
B.Collector current ()
C.Base current ()
D.They are all equal
Correct Answer: Base current ()
Explanation:
The base region is very thin and lightly doped, meaning very few carriers recombine there. As a result, the base current is very small compared to the emitter and collector currents.
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8The ratio of dc collector current () to dc emitter current () is denoted by which symbol?
Transistor current components
Easy
A. (beta)
B. (mu)
C. (gamma)
D. (alpha)
Correct Answer: (alpha)
Explanation:
The common-base current gain, which is the ratio of collector current to emitter current, is denoted by the Greek letter .
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9In the Common Emitter (CE) configuration, which terminal is common to both the input and output circuits?
CE, CB and CC configurations of BJT
Easy
A.Base
B.Emitter
C.Gate
D.Collector
Correct Answer: Emitter
Explanation:
In the Common Emitter configuration, the emitter terminal serves as the common ground or reference point for both the input and output signals.
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10Which BJT configuration is widely known as an 'emitter follower'?
CE, CB and CC configurations of BJT
Easy
A.Common Source
B.Common Emitter
C.Common Collector
D.Common Base
Correct Answer: Common Collector
Explanation:
The Common Collector configuration has a voltage gain of approximately 1, meaning the output voltage at the emitter closely follows the input voltage at the base, hence 'emitter follower'.
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11What is the common-emitter current gain commonly denoted by?
CE, CB and CC configurations of BJT
Easy
A. (alpha)
B. (theta)
C. (gamma)
D. (beta)
Correct Answer: (beta)
Explanation:
The forward current gain in a Common Emitter configuration, defined as the ratio of collector current to base current (), is represented by .
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12Which BJT configuration is most commonly used for voltage and power amplification due to its high voltage and current gains?
Comparisons of transistor amplifier configurations
Easy
A.Common Emitter (CE)
B.Common Base (CB)
C.None of the above
D.Common Collector (CC)
Correct Answer: Common Emitter (CE)
Explanation:
The Common Emitter configuration is the most widely used because it provides both voltage and current gain, leading to a high overall power gain.
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13Which transistor configuration is mainly used for impedance matching due to its high input impedance and low output impedance?
Comparisons of transistor amplifier configurations
Easy
A.Common Base
B.Common Collector
C.Common Gate
D.Common Emitter
Correct Answer: Common Collector
Explanation:
The Common Collector (emitter follower) configuration has a high input impedance and low output impedance, making it ideal for matching a high-impedance source to a low-impedance load.
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14For a BJT to operate faithfully as a linear amplifier, in which region must it be biased?
BJT as an amplifier
Easy
A.Breakdown region
B.Saturation region
C.Cut-off region
D.Active region
Correct Answer: Active region
Explanation:
To avoid distortion and accurately amplify signals, the BJT must operate in the active region where the collector current is proportional to the base current.
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15What is the phase shift between the input signal and the output signal in a Common Emitter (CE) amplifier?
BJT as an amplifier
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
In a Common Emitter amplifier, an increase in input base voltage causes an increase in collector current, which drops more voltage across the collector resistor, thus decreasing the output voltage. This results in a phase inversion.
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16When a BJT acts as a closed switch (ON state), in which region is it primarily operating?
Transistor as a Switch
Easy
A.Active region
B.Cut-off region
C.Saturation region
D.Reverse active region
Correct Answer: Saturation region
Explanation:
When used as a switch in the ON state, the BJT is driven into the saturation region, where both junctions are forward-biased, allowing maximum current to flow like a closed switch.
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17When a BJT is used as an open switch (OFF state), in which region is it operating?
Transistor as a Switch
Easy
A.Cut-off region
B.Linear region
C.Saturation region
D.Active region
Correct Answer: Cut-off region
Explanation:
In the OFF state, the transistor operates in the cut-off region where base current is practically zero, and almost no collector current flows, acting like an open switch.
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18In the cut-off region, what is the biasing status of the BJT junctions?
Transistor as a Switch
Easy
A.Emitter-Base is reverse biased, Collector-Base is forward biased
B.Emitter-Base is forward biased, Collector-Base is reverse biased
C.Both junctions are forward biased
D.Both junctions are reverse biased
Correct Answer: Both junctions are reverse biased
Explanation:
For a BJT to be entirely turned off (cut-off region), both the Emitter-Base and Collector-Base junctions must be reverse biased.
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19What is the term for the time required for the collector current to rise from 10% to 90% of its final maximum value during switching?
Transistor Switching Times
Easy
A.Storage time
B.Fall time
C.Rise time
D.Delay time
Correct Answer: Rise time
Explanation:
Rise time () is specifically defined as the interval during which the output current rises from 10% to 90% of its steady-state or maximum value.
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20Which switching time parameter describes the time required for the minority carriers in the base to be cleared out before the transistor can turn OFF?
Transistor Switching Times
Easy
A.Rise time ()
B.Fall time ()
C.Delay time ()
D.Storage time ()
Correct Answer: Storage time ()
Explanation:
Storage time is the time it takes to remove excess minority carriers stored in the base region when a saturated transistor is being turned off.
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21In a bipolar junction transistor, why is the emitter region heavily doped while the base is kept thin and lightly doped?
Junction transistor
Medium
A.To make the emitter act as a high impedance input terminal.
B.To increase the depletion region width at the emitter-base junction for higher breakdown voltage.
C.To increase the base recombination current and improve switching speed.
D.To ensure most injected charge carriers from the emitter cross over to the collector without recombining in the base.
Correct Answer: To ensure most injected charge carriers from the emitter cross over to the collector without recombining in the base.
Explanation:
A heavily doped emitter injects a large number of charge carriers. A thin, lightly doped base minimizes the recombination of these carriers, allowing the majority of them to reach the collector, which results in a higher current gain ( close to 1).
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22An NPN transistor is biased in the active region. How does the Early effect (Base-width modulation) impact the effective base width () when the reverse bias voltage is increased?
Operation
Medium
A.The effective base width decreases because the emitter region injects fewer electrons.
B.The effective base width increases because the emitter-base depletion region narrows.
C.The effective base width decreases because the collector-base depletion region penetrates deeper into the lightly doped base.
D.The effective base width remains unchanged as long as is constant.
Correct Answer: The effective base width decreases because the collector-base depletion region penetrates deeper into the lightly doped base.
Explanation:
Increasing the reverse bias widens the collector-base depletion region. Since the base is lightly doped compared to the collector, this depletion region extends primarily into the base, reducing the effective neutral base width. This is known as the Early effect.
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23A BJT has a common-emitter current gain . If the emitter current is , what is the approximate value of the collector current ?
Transistor current components
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The correct option follows directly from the given concept and definitions.
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24In a BJT, the reverse leakage current is . If the transistor has an of $0.98$, what is the common-emitter leakage current ?
Transistor current components
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The relationship between and is . Substituting the given values: .
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25In the Common Emitter (CE) configuration, the output characteristics show a slight upward slope in the active region instead of being perfectly horizontal. Which phenomenon is responsible for this?
CE, CB and CC configurations of BJT
Medium
A.Zener breakdown
B.High-level injection
C.Early effect (Base-width modulation)
D.Avalanche breakdown
Correct Answer: Early effect (Base-width modulation)
Explanation:
The upward slope in the CE output characteristics indicates that increases slightly with . This occurs due to the Early effect, where an increase in reduces the effective base width, causing the current gain to increase slightly, thereby increasing .
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26Why is the Common Collector (CC) configuration frequently used as a buffer amplifier?
CE, CB and CC configurations of BJT
Medium
A.It has a high voltage gain and low current gain.
B.It provides maximum power gain compared to other configurations.
C.It has a high input impedance and a low output impedance with a voltage gain close to unity.
D.It introduces a 180-degree phase shift to stabilize the output signal.
Correct Answer: It has a high input impedance and a low output impedance with a voltage gain close to unity.
Explanation:
The Common Collector (CC) configuration, or emitter follower, features high input impedance and low output impedance, making it ideal for impedance matching or buffering between a high-impedance source and a low-impedance load. Its voltage gain is approximately 1.
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27Compare the phase relationships between the input and output voltages for the three BJT configurations. Which of the following statements is true?
Comparisons of transistor amplifier configurations
Medium
A.CE configuration has a phase shift, while CB and CC have a phase shift.
B.All configurations introduce a phase shift at mid-band frequencies.
C.CB and CE configurations have a phase shift, while CC has a phase shift.
D.CC configuration has a phase shift, while CE and CB have a phase shift.
Correct Answer: CE configuration has a phase shift, while CB and CC have a phase shift.
Explanation:
In a Common Emitter (CE) amplifier, an increase in base voltage increases collector current, which drops more voltage across the collector resistor, thus decreasing the output collector voltage (a phase inversion). CB and CC configurations do not invert the signal.
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28Which BJT amplifier configuration is most suitable if a circuit requires both significant voltage gain and significant current gain simultaneously?
Comparisons of transistor amplifier configurations
Medium
A.Darlington Pair
B.Common Collector (CC)
C.Common Emitter (CE)
D.Common Base (CB)
Correct Answer: Common Emitter (CE)
Explanation:
The Common Emitter (CE) configuration provides both moderate-to-high voltage gain and moderate-to-high current gain. Because power gain is the product of voltage and current gains, CE yields the highest power gain of the three basic configurations.
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29For a BJT operating as a linear amplifier, the quiescent (Q) point must be stabilized. If the Q-point moves too close to the saturation region due to a temperature increase, what distortion will occur to a large AC input signal?
BJT as an amplifier
Medium
A.Crossover distortion will appear near the zero-crossing of the signal.
B.Both half-cycles will be symmetrically clipped.
C.The positive half-cycle of the output voltage waveform will be clipped.
D.The negative half-cycle of the output voltage waveform will be clipped.
Correct Answer: The negative half-cycle of the output voltage waveform will be clipped.
Explanation:
If the Q-point is near saturation, a large AC input that increases base current will drive the transistor fully into saturation, causing to drop to . Because the CE amplifier inverts the signal, this corresponds to the negative peak of the output voltage waveform being clipped.
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30A simple CE amplifier has a collector resistance and operates at a quiescent collector current of . Assuming thermal voltage , what is the approximate magnitude of the intrinsic voltage gain () if the Early effect is ignored?
BJT as an amplifier
Medium
A.40
B.125
C.100
D.80
Correct Answer: 80
Explanation:
The transconductance is . The voltage gain magnitude for a simple CE amplifier is .
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31When a BJT is used as a switch, it is driven between the cut-off and saturation regions. Which biasing conditions correctly describe a BJT in deep saturation?
Transistor as a Switch
Medium
A.Emitter-Base junction is reverse-biased, Collector-Base junction is reverse-biased.
B.Emitter-Base junction is reverse-biased, Collector-Base junction is forward-biased.
C.Emitter-Base junction is forward-biased, Collector-Base junction is forward-biased.
D.Emitter-Base junction is forward-biased, Collector-Base junction is reverse-biased.
Correct Answer: Emitter-Base junction is forward-biased, Collector-Base junction is forward-biased.
Explanation:
In saturation, the transistor acts like a closed switch. Both the Emitter-Base and the Collector-Base junctions must be forward-biased to achieve a very low (typically around ).
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32To ensure a BJT turns on quickly and enters deep saturation, the base current provided () is often made much larger than the minimum base current required for saturation (). What is the main disadvantage of this 'overdrive' technique?
Transistor as a Switch
Medium
A.It significantly increases the turn-on delay time ().
B.It causes the transistor to operate in the reverse active mode.
C.It significantly increases the storage time () during turn-off.
D.It decreases the overall current gain () permanently.
Correct Answer: It significantly increases the storage time () during turn-off.
Explanation:
Overdriving the base pushes excess minority carriers into the base region. When the switch is turned off, these excess carriers must be removed or recombine before the collector current can start to fall. This results in a much longer storage time (), delaying the turn-off process.
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33The total turn-on time () of a transistor switch is defined as the sum of two time intervals. Which are they?
Transistor Switching Times
Medium
A.Storage time () and Fall time ()
B.Delay time () and Rise time ()
C.Delay time () and Storage time ()
D.Rise time () and Fall time ()
Correct Answer: Delay time () and Rise time ()
Explanation:
Turn-on time () is the time required for the transistor to transition from the cut-off state to the ON state. It consists of the delay time (, time to charge the junction capacitances) and the rise time (, time for the collector current to rise to 90% of its maximum value).
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34During the turn-off transient of a saturated BJT, the collector current remains constant at its maximum value for a short period after the base drive is removed. What causes this delay?
Transistor Switching Times
Medium
A.The removal of excess minority charge stored in the base region.
B.The inductive kickback from the collector load.
C.The discharge of the base-emitter junction capacitance.
D.The transit time of carriers across the collector depletion region.
Correct Answer: The removal of excess minority charge stored in the base region.
Explanation:
This period is called the storage time (). When a BJT is in saturation, excess minority carriers accumulate in the base. Before the transistor can re-enter the active region and the collector current can decrease, these excess carriers must be swept out or recombine.
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35What is 'punch-through' (or reach-through) in a BJT?
Operation
Medium
A.A condition where the emitter-base junction breaks down due to excessive forward current.
B.The point at which thermal runaway irreparably damages the crystal structure.
C.A condition where the collector-base depletion region extends completely across the base, touching the emitter depletion region.
D.The tunneling of electrons across a heavily doped Zener diode.
Correct Answer: A condition where the collector-base depletion region extends completely across the base, touching the emitter depletion region.
Explanation:
Punch-through occurs when a high reverse-bias voltage is applied across the collector-base junction, causing its depletion region to widen so much that it completely spans the lightly doped base and touches the emitter-base depletion region, resulting in a large, uncontrolled current.
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36A Common Base (CB) amplifier is often used in high-frequency applications. Which characteristic of the CB configuration primarily makes it suitable for this?
CE, CB and CC configurations of BJT
Medium
A.It naturally limits the bandwidth to eliminate high-frequency noise.
B.It has a very high input impedance, minimizing source loading.
C.It lacks the Miller effect capacitance that typically degrades high-frequency response in CE amplifiers.
D.It provides the highest current gain of all configurations.
Correct Answer: It lacks the Miller effect capacitance that typically degrades high-frequency response in CE amplifiers.
Explanation:
In a CB amplifier, the base is grounded, effectively isolating the input (emitter) and output (collector). This grounding prevents the feedback capacitance () from being multiplied by the Miller effect, giving the CB configuration superior high-frequency performance.
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37Which of the following configurations acts as a current buffer, having a low input impedance, high output impedance, and a current gain approximately equal to 1?
Comparisons of transistor amplifier configurations
Medium
A.Common Base (CB)
B.Common Collector (CC)
C.Common Emitter (CE)
D.Cascaded CE
Correct Answer: Common Base (CB)
Explanation:
The Common Base (CB) configuration has low input impedance, high output impedance, and a current gain () just slightly less than 1. This makes it an ideal current buffer, effectively passing the input current to the output while shifting from a low to a high impedance level.
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38How can the storage time () of a BJT switch be minimized in practical switching circuits?
Transistor Switching Times
Medium
A.By increasing the positive base drive current to maximum limits.
B.By adding a large capacitor in parallel with the collector resistor.
C.By applying a negative (reverse) voltage pulse to the base during turn-off.
D.By heavily doping the base region.
Correct Answer: By applying a negative (reverse) voltage pulse to the base during turn-off.
Explanation:
Applying a negative voltage pulse (reverse base drive) during turn-off actively pulls the excess minority carriers out of the base region rather than waiting for them to slowly recombine. This significantly reduces the storage time ().
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39In standard BJT manufacturing, NPN transistors are generally preferred over PNP transistors for high-speed switching and high-frequency applications. What is the fundamental physical reason for this?
Junction transistor
Medium
A.The NPN structure prevents the Early effect completely.
B.Electrons have higher mobility than holes, leading to shorter transit times.
C.N-type silicon is cheaper to manufacture than P-type silicon.
D.Holes have a higher thermal conductivity, which causes overheating in PNP devices.
Correct Answer: Electrons have higher mobility than holes, leading to shorter transit times.
Explanation:
In an NPN transistor, the majority carriers in the base are electrons. Since electrons have significantly higher mobility than holes (which are the majority carriers in the base of a PNP transistor), they cross the base region faster, resulting in better high-frequency and high-speed performance.
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40The emitter injection efficiency () is a critical parameter for a BJT. How is defined in an NPN transistor?
Transistor current components
Medium
A.The ratio of collector current to base current.
B.The ratio of electron current injected from emitter to base, to the total emitter current.
C.The ratio of base recombination current to total emitter current.
D.The ratio of hole current from base to emitter, to the total emitter current.
Correct Answer: The ratio of electron current injected from emitter to base, to the total emitter current.
Explanation:
Emitter injection efficiency () represents the fraction of the total emitter current that is made up of the desired charge carriers (electrons in an NPN transistor) moving from emitter to base. Ideally, it is very close to 1, which is achieved by heavily doping the emitter.
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41In an NPN BJT operating in the active region, increasing the collector-base reverse bias while keeping constant causes the Early effect. How does this specifically affect the recombination base current and the emitter injection current ?
Operation
Hard
A.Both and decrease.
B.Both and increase.
C. increases, and decreases.
D. decreases, and increases.
Correct Answer: decreases, and increases.
Explanation:
Increasing widens the collector-base depletion region, reducing the effective base width. A narrower base increases the minority carrier concentration gradient, increasing . Simultaneously, the smaller base volume reduces the total recombination of carriers, thereby decreasing .
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42Consider a BJT operating at high collector voltages where avalanche multiplication occurs in the collector-base junction, denoted by a multiplication factor . What is the modified expression for the collector-to-emitter leakage current in terms of the common-base current gain and the collector-base reverse saturation current ?
Transistor current components
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
With avalanche multiplication, the collector current becomes . Since , and for we set , substituting yields . Solving for (which is here) gives .
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43Using the exact h-parameter conversion formulas, which of the following expressions correctly relates the common-emitter input impedance to the common-base h-parameters?
CE, CB and CC configurations of BJT
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The exact transformation from CB to CE parameters dictates that , where is the determinant of the CB h-parameter matrix (approximating to the given correct option formula). The widely used is only an approximation when and are considered negligible.
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44In the charge-control model of a BJT, the storage time during the turn-off transient is determined by the time required to remove excess base charge. If a transistor is driven into saturation with a base current and turned off using a reverse base current , what is the mathematical expression for ?
Transistor Switching Times
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The storage time is given by , where is the base current required to just reach the edge of saturation. Substituting for the reverse turn-off current changes the minus signs to plus signs.
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45Punch-through (or reach-through) in a BJT occurs when the collector-base depletion region extends completely through the base to the emitter-base junction. Which of the following physical configurations significantly lowers the punch-through voltage ?
Junction transistor
Hard
A.A lightly doped base region and a very narrow physical base width.
B.A lightly doped emitter region and a heavily doped collector region.
C.A heavily doped base region and a highly wide physical base width.
D.A heavily doped collector region and a heavily doped base region.
Correct Answer: A lightly doped base region and a very narrow physical base width.
Explanation:
The depletion region extends predominantly into the lighter doped side of a junction. If the base is lightly doped, the collector-base depletion region penetrates deeply into the base. Combined with a narrow physical base width, this causes the depletion region to reach the emitter at a much lower reverse-bias voltage.
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46A designer needs to cascade two amplifier stages to connect a very high-impedance source to a very low-impedance load while achieving the maximum possible overall power gain without signal phase inversion. Which combination of configurations is most appropriate?
Comparisons of transistor amplifier configurations
Hard
A.Common Collector (CC) followed by Common Collector (CC)
B.Common Collector (CC) followed by Common Emitter (CE)
C.Common Collector (CC) followed by Common Base (CB)
D.Common Emitter (CE) followed by Common Base (CB)
Correct Answer: Common Collector (CC) followed by Common Collector (CC)
Explanation:
The CC configuration (emitter follower) features high input impedance, low output impedance, and no phase inversion. A single CC stage provides current gain but no voltage gain. Cascading two CC stages (a Darlington pair configuration) multiplies the current gain, thereby achieving maximum power gain under these specific severe impedance matching constraints without inverting the phase.
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47An NPN transistor is utilized as a switch. If the transistor is driven into deep saturation, the forced beta () is defined as . How does relate to the natural active-region current gain , and what is the impact on the turn-off storage time ?
Transistor as a Switch
Hard
A., which stores excessive minority carriers in the base, severely increasing .
B., which minimizes excess base charge and reduces .
C., which depletes the base region of minority carriers, minimizing .
D., which balances conduction losses and eliminates .
Correct Answer: , which stores excessive minority carriers in the base, severely increasing .
Explanation:
In deep saturation, is much larger than necessary to support , making (often significantly so, ). This large base drive injects a massive excess of minority carriers into the base, which must be swept out before the transistor can turn off, leading to a long storage time .
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48In the small-signal hybrid- model of a BJT at high frequencies, the Miller effect significantly impacts the input capacitance. If the amplifier has an unloaded midband voltage gain , the effective input capacitance is approximately:
BJT as an amplifier
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
According to Miller's theorem, an impedance connecting the input and output nodes of an inverting amplifier (gain , which is a negative value for CE) reflects to the input as . For a capacitance , impedance is inversely proportional to capacitance, so the equivalent capacitance is . Total input capacitance is in parallel with this, giving .
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49According to the Ebers-Moll equations for a BJT, the emitter current and collector current are defined in terms of the forward and reverse transport factors (, ) and the saturation currents (, ). Which fundamentally required reciprocity relationship must hold for the Ebers-Moll model to be physically valid?
Operation
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The Ebers-Moll reciprocity theorem states that the fraction of the emitter injection current that reaches the collector is exactly related to the fraction of the collector injection current that reaches the emitter. Mathematically, this dictates that , which ensures thermodynamics and detailed balance hold true.
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50The base transport factor of a BJT is limited by carrier recombination in the base, while the emitter injection efficiency is limited by reverse injection from the base into the emitter. If a BJT is designed with a very short base width () but with an equal doping concentration in both the emitter and the base (), what is the expected limiting value of the common-base current gain ?
Transistor current components
Hard
A., because is severely degraded.
B., because equal doping prevents junction formation.
C., because dominates.
D., as doping levels do not affect if .
Correct Answer: , because is severely degraded.
Explanation:
The overall alpha is . A short base makes . However, emitter injection efficiency depends heavily on the doping ratio . If , the forward injection (emitter to base) and reverse injection (base to emitter) are roughly equal, meaning . Thus, will be limited to approximately 0.5.
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51In the Common Base (CB) configuration, the output characteristics ( vs ) show a slight upward slope in the active region. Which h-parameter strictly models this non-ideal slope, and what physical phenomenon causes it?
CE, CB and CC configurations of BJT
Hard
A., caused by thermal runaway
B., caused by emitter injection efficiency limits
C., caused by avalanche multiplication
D., caused by base width modulation (Early effect)
Correct Answer: , caused by base width modulation (Early effect)
Explanation:
The slope of the output characteristic curve ( vs ) is defined by the output admittance, which is in the common-base configuration. This slope exists because an increase in decreases the effective base width (Early effect), increasing the gradient of minority carriers and causing a slight increase in .
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52A BJT CE amplifier is biased with a fixed collector current at room temperature (). If the temperature increases to while the biasing circuit perfectly maintains at , what happens to the small-signal transconductance ?
BJT as an amplifier
Hard
A. increases by approximately 10%.
B. remains completely unchanged because is constant.
C. increases exponentially due to the intrinsic carrier concentration .
D. decreases by approximately 9%.
Correct Answer: decreases by approximately 9%.
Explanation:
The transconductance is given by , where the thermal voltage . Since is directly proportional to the absolute temperature , a 10% increase in temperature (from 300 K to 330 K) causes a 10% increase in . Therefore, scales by a factor of , representing roughly a 9% decrease.
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53When a BJT operates in the reverse active mode (emitter and collector roles swapped), it generally exhibits a very low current gain () and a low breakdown voltage. What is the fundamental physical reason for the low breakdown voltage in this mode?
Transistor as a Switch
Hard
A.The base transport factor collapses due to the reversed built-in electric fields in the base region.
B.The original collector-base junction is now forward-biased, drawing excessive thermal current.
C.The original emitter is heavily doped, creating a very narrow depletion region at the emitter-base junction with a low Zener/avalanche breakdown threshold.
D.The physical area of the emitter is much smaller than the collector, causing current crowding.
Correct Answer: The original emitter is heavily doped, creating a very narrow depletion region at the emitter-base junction with a low Zener/avalanche breakdown threshold.
Explanation:
In reverse active mode, the original emitter-base junction operates as the reverse-biased collector junction. Because the emitter is heavily doped (to ensure high injection efficiency in normal operation), the emitter-base depletion region is very narrow, leading to high electric fields and a very low breakdown voltage (typically 5-7 V, called ).
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54For a given source resistance and load resistance , it is observed that a Common Emitter (CE) amplifier provides both voltage and current gain. If the same transistor is reconfigured into a Common Collector (CC) amplifier, how does the voltage gain mathematically approach its theoretical upper limit?
Comparisons of transistor amplifier configurations
Hard
A., which approaches 1 as
B., which approaches 1 as
C., which approaches as
D.
Correct Answer: , which approaches 1 as
Explanation:
For a CC amplifier (emitter follower), the input impedance looking into the base is approximately . The voltage at the emitter (output) is an unloaded voltage divider formed by and the reflected load . Thus, the exact voltage gain is . As becomes very large compared to , the fraction approaches exactly 1.
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55During the turn-on transient of a BJT switch, the delay time is the time elapsed before the collector current reaches 10% of its maximum saturation value. Which of the following physical processes is the PRIMARY contributor to ?
Transistor Switching Times
Hard
A.The charging of the diffusion capacitance in the forward-biased emitter-base junction.
B.The time required to sweep out excess minority carriers from the base.
C.The transit time of minority carriers crossing the neutral base region.
D.The charging of the emitter-base and collector-base junction depletion capacitances to the threshold forward-bias voltage.
Correct Answer: The charging of the emitter-base and collector-base junction depletion capacitances to the threshold forward-bias voltage.
Explanation:
Before minority carriers can be injected into the base to start the conduction process (which relates to diffusion capacitance and transit time), the reverse bias on the emitter-base junction must be overcome. This requires charging the depletion (junction) capacitances and to the cut-in voltage, which constitutes the bulk of the delay time .
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56In a basic CE amplifier circuit with a collector resistor and Early voltage , the intrinsic voltage gain (assuming an ideal infinite load and source) is limited by the transistor's output resistance . What is the theoretical maximum intrinsic voltage gain ?
BJT as an amplifier
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The intrinsic voltage gain is given by . We know that , and (assuming ). Therefore, . This represents the absolute highest gain a single BJT stage can achieve, entirely independent of the bias current.
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57For a BJT in the Common Emitter (CE) configuration, the short-circuit forward current gain exhibits a strong frequency dependence. If the transition frequency is and the low-frequency gain is , at what frequency does the magnitude of drop by 3 dB, and what is the exact relationship between and ?
CE, CB and CC configurations of BJT
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The parameter is the 3-dB cutoff frequency for the common-emitter short-circuit current gain. The transition frequency is the frequency at which drops to unity (1). Because the gain rolls off at 20 dB/decade past , the gain-bandwidth product is constant, yielding the relationship , or .
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58A given BJT has a common-base current gain that is highly sensitive to temperature. If increases from $0.990$ to $0.995$ due to internal heating, what is the corresponding percentage change in the common-emitter current gain ?
Transistor current components
Hard
A.100%
B.50%
C.5%
D.0.5%
Correct Answer: 100%
Explanation:
The relationship is . Initially, . After the temperature increase, . The change is from 99 to 199, which is a of 100. The percentage change is , closely approximating 100%.
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59To prevent thermal runaway in a BJT power amplifier, a stability factor is defined as . For a standard voltage-divider bias circuit with emitter degradation (resistors , , , and ), what is the exact expression for , and how is stability optimized?
BJT as an amplifier
Hard
A.; optimized by setting
B.; optimized by setting
C.; optimized by setting
D.; optimized by setting
Correct Answer: ; optimized by setting
Explanation:
The standard stability factor against variations in leakage current is . From the bias loop, . Substituting this yields . Ideal stability () is achieved when the denominator is maximized, which occurs when .
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60In the derivation of minority carrier distributions in a PNP transistor's base region, the base transport factor deviates from unity due to bulk recombination. If the base width is and the minority carrier diffusion length in the base is , the fraction of injected holes surviving recombination is approximated by evaluating the hyperbolic cosine solution of the continuity equation. What is the standard approximation for when ?
Junction transistor
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The exact expression for the base transport factor is . Using the Taylor series expansion for (for small ), we get . Using the binomial approximation , this simplifies to .