Unit 4: Calculus - Subjective Questions
CSE333 — Combinatorial Studies-I • Practice Questions with Detailed Answers
20 questions
Define the limit of a function at a point. Explain the - definition of .
Definition: The statement means that the values of can be made arbitrarily close to by taking sufficiently close to, but not equal to, .
- definition: For every , there exists a such that
Here, represents the required closeness of to , while represents the corresponding closeness of to .
Important point: The value of need not be equal to for the limit to exist.
Evaluate and explain the result.
The standard trigonometric limit is
Explanation: For , the geometrical inequality
holds. Dividing by gives
Taking reciprocals,
As , both and approach . Therefore, by the squeeze theorem,
The same result holds for approaching zero from the left.
State and explain the conditions for continuity of a function at a point.
A function is continuous at if and only if all the following conditions are satisfied:
- is defined.
- The limit exists.
- The limit is equal to the value of the function:
Equivalently, continuity requires
If any one of these conditions fails, the function is discontinuous at . A function is continuous on an interval if it is continuous at every point of that interval.
Determine the value of for which the function is continuous at .
For continuity at , the left-hand limit, right-hand limit, and function value must be equal.
The left-hand limit is
The right-hand limit and function value are
Equating these values,
Therefore,
Answer: The function is continuous at when
For this value, both one-sided limits equal , and .
Define differentiability and explain the relationship between differentiability and continuity.
Differentiability: A function is differentiable at if the derivative
exists as a finite number.
Relationship:
- If a function is differentiable at , then it is necessarily continuous at .
- A function may be continuous at without being differentiable there.
To prove the first statement, write
As , the first factor tends to and the second tends to . Hence
which implies .
For example, is continuous at but not differentiable there because its left and right derivatives are different.
Find the derivative of for using logarithmic differentiation.
Let
Taking natural logarithms on both sides,
Differentiating with respect to ,
Therefore,
Since ,
The condition ensures that is defined.
State Rolle's theorem and verify it for on the interval .
Rolle's theorem: If a function is continuous on , differentiable on , and satisfies , then there exists at least one such that
For :
- It is a polynomial, so it is continuous on and differentiable on .
- .
- .
Thus, . Its derivative is
Setting the derivative equal to zero,
Since , Rolle's theorem is verified.
State the Mean Value Theorem and explain its geometrical interpretation.
Mean Value Theorem: If is continuous on and differentiable on , then there exists at least one point such that
The expression on the right is the slope of the secant line joining and . The derivative is the slope of the tangent at .
Geometrical interpretation: At some interior point , the tangent to the curve is parallel to the secant line joining the endpoints.
Rolle's theorem is a special case of the Mean Value Theorem when .
Use the Mean Value Theorem to prove that for all real numbers and .
Assume first that . The function is continuous on and differentiable on . By the Mean Value Theorem, there exists such that
Taking absolute values,
Since ,
If , interchanging and gives the same result. Hence the inequality holds for all real and .
Explain the first derivative test for finding local maxima and minima of a function.
The first derivative test uses the sign of around a critical point .
- If changes from positive to negative at , then changes from increasing to decreasing. Therefore, is a local maximum.
- If changes from negative to positive at , then changes from decreasing to increasing. Therefore, is a local minimum.
- If the sign of does not change at , then the test does not give a local maximum or minimum.
Critical points occur where
or where does not exist, provided is defined.
The test is applied by constructing a sign chart for on intervals around each critical point.
Find the local maxima and minima of .
Differentiate the function:
The critical points are
The sign of is:
- Positive for .
- Negative for .
- Positive for .
Thus, changes from increasing to decreasing at , so there is a local maximum there. Its value is
At , the function changes from decreasing to increasing, so there is a local minimum. Its value is
Answer:
State the second derivative test for determining local maxima and minima.
Suppose and exists.
- If , the graph is concave upward near , and is a local minimum.
- If , the graph is concave downward near , and is a local maximum.
- If , the test is inconclusive, and the first derivative test or another method must be used.
For example, if and , then the function has a local minimum at .
Solve the optimization problem: Find the dimensions of the rectangle of maximum area that can be inscribed in a circle of radius .
Let the rectangle have length and width . Since its diagonal is the diameter of the circle,
The area is
Solving for ,
Thus,
A simpler argument uses the inequality
Since ,
Therefore,
Equality holds when , so the rectangle is a square.
Answer: The rectangle of maximum area is a square with side length
and maximum area
Define an indefinite integral and explain the meaning of the constant of integration.
An indefinite integral of is the family of all functions whose derivative is . It is written as
where
The symbol is called the constant of integration. It is included because the derivative of every constant is zero. For example,
and
Therefore,
The indefinite integral represents a family of curves differing only by vertical translations.
Evaluate using substitution.
Let
Then
so
Substituting,
Therefore,
Replacing by gives
Explain integration by parts and derive its formula.
Start with the product rule:
Multiplying by gives
Rearranging,
Integrating both sides,
Hence, the integration by parts formula is
It is useful when the integrand is a product of two functions, such as a polynomial multiplied by an exponential, logarithmic, or trigonometric function. The choice of is commonly guided by the priority order logarithmic, inverse trigonometric, algebraic, trigonometric, and exponential functions.
Evaluate using integration by parts.
Choose
Then
Using integration by parts,
Therefore,
Thus,
The result is valid for , where is defined.
State the Fundamental Theorem of Calculus and explain how differentiation and definite integration are related.
The Fundamental Theorem of Calculus has two main parts.
Part I: If is continuous on and
then
Thus, differentiation reverses the accumulation represented by integration.
Part II: If is any antiderivative of , so that , then
Therefore, a definite integral can be evaluated by finding an antiderivative and subtracting its values at the upper and lower limits.
Evaluate the definite integral and interpret its value geometrically.
An antiderivative of is . Therefore,
Evaluating the limits,
Hence,
Geometrically, this value represents the area under the curve
above the -axis and between and .
Compare continuity and differentiability, giving suitable examples.
Continuity and differentiability are related but distinct properties.
Continuity: A function is continuous at if
It means that the graph has no break, jump, or hole at that point.
Differentiability: A function is differentiable at if the finite derivative
exists. It means that the function has a well-defined tangent at that point.
Comparison:
- Differentiability at a point implies continuity at that point.
- Continuity does not imply differentiability.
- The function is continuous at , but its left derivative is and its right derivative is , so it is not differentiable at .
- The polynomial is both continuous and differentiable everywhere.
Define the limit of a function at a point. Explain the - definition of .
Definition: The statement means that the values of can be made arbitrarily close to by taking sufficiently close to, but not equal to, .
- definition: For every , there exists a such that
Here, represents the required closeness of to , while represents the corresponding closeness of to .
Important point: The value of need not be equal to for the limit to exist.
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