1What does a ratio fundamentally represent in mathematics?
Advanced ratio and proportion : concept of ratio and proportion
Easy
A.The sum of two quantities
B.The difference between two quantities
C.The comparison of two quantities by division
D.The product of two quantities
Correct Answer: The comparison of two quantities by division
Explanation:
A ratio is a relationship between two numbers indicating how many times the first number contains the second, which is calculated using division.
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2If four quantities , , , and are in proportion (), which of the following equations must be true?
Advanced ratio and proportion : concept of ratio and proportion
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
In a proportion , the product of the extremes ( and ) is equal to the product of the means ( and ).
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3What is the simplest form of the ratio ?
Advanced ratio and proportion : concept of ratio and proportion
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
Dividing both sides of the ratio by their greatest common divisor, which is $5$, gives .
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4Find the fourth proportional to $2$, $4$, and $6$.
Advanced ratio and proportion : concept of ratio and proportion
Easy
A.$10$
B.$12$
C.$8$
D.$14$
Correct Answer: $12$
Explanation:
If is the fourth proportional, then . Therefore, , which means .
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5What is the duplicate ratio of ?
Advanced ratio and proportion : concept of ratio and proportion
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
The duplicate ratio of is . For , it is .
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6In a partnership, if two partners invest equal amounts for the same period of time, how is the profit shared?
Advanced ratio and proportion : problems based on ages and partnership
Easy
A.All profit goes to the active partner
B.In the ratio
C.Equally (in the ratio )
D.In the ratio
Correct Answer: Equally (in the ratio )
Explanation:
When the investment amount and the time period are the same for both partners, their profit-sharing ratio is exactly equal ().
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7The profit-sharing ratio in a partnership is fundamentally dependent on which two factors?
Advanced ratio and proportion : problems based on ages and partnership
Easy
A.Time of investment and location of business
B.Capital invested and time of investment
C.Experience and capital invested
D.Age of the partners and capital invested
Correct Answer: Capital invested and time of investment
Explanation:
Profits are divided in the ratio of the products of capital invested and the time period for which it is invested.
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8The ratio of the present ages of A and B is . If the sum of their ages is $30$ years, what is A's present age?
Advanced ratio and proportion : problems based on ages and partnership
Easy
A.$15$ years
B.$20$ years
C.$25$ years
D.$10$ years
Correct Answer: $10$ years
Explanation:
Let the ages be and . The sum is , so and . A's age is $10$ years.
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9P invests twice as much as Q in a business for the same time period. What will be the ratio of their profit shares (P:Q)?
Advanced ratio and proportion : problems based on ages and partnership
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
Since time is constant, the profit ratio is equal to the investment ratio. If P invests twice as much as Q, the ratio is .
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10If a person's present age is years, what was their age '' years ago?
Advanced ratio and proportion : problems based on ages and partnership
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
To find an age in the past, we subtract the number of years passed from the current age, resulting in .
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11What is the rule of alligation primarily used for?
Components and blending : concept of alligation and mixtures
Easy
A.To calculate the profit margin in a partnership
B.To find the average age of a group
C.To find the interest rate of a loan
D.To find the ratio in which two or more ingredients are mixed to produce a mixture of a desired price
Correct Answer: To find the ratio in which two or more ingredients are mixed to produce a mixture of a desired price
Explanation:
The rule of alligation is a mathematical technique used to determine the exact ratio in which two ingredients of different prices must be mixed to obtain a specific target average price.
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12In the rule of alligation, what does the term 'mean price' refer to?
Components and blending : concept of alligation and mixtures
Easy
A.The highest price of the ingredients
B.The selling price of the final product with profit
C.The cost price of a unit quantity of the mixture
D.The lowest price of the ingredients
Correct Answer: The cost price of a unit quantity of the mixture
Explanation:
The mean price is defined as the cost price of one unit quantity of the blended mixture.
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13If you mix sugar priced at Rs. $10$/kg and Rs. $20$/kg to get a mixture worth Rs. $15$/kg, what is the ratio of the cheaper sugar to the dearer sugar?
Components and blending : concept of alligation and mixtures
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
Using alligation: Ratio = .
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14A $50$ liter mixture of milk and water contains them in a ratio of . How many liters of milk are in the mixture?
Components and blending : concept of alligation and mixtures
Easy
A.$10$ liters
B.$40$ liters
C.$30$ liters
D.$20$ liters
Correct Answer: $30$ liters
Explanation:
Total parts = . One part = liters. Amount of milk = liters.
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15Let be the cost of a cheaper ingredient, be the cost of a dearer ingredient, and be the mean price. According to the rule of alligation, the ratio of cheaper to dearer quantity is:
Components and blending : concept of alligation and mixtures
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
The rule of alligation states that Quantity of Cheaper / Quantity of Dearer = (Price of Dearer - Mean Price) / (Mean Price - Price of Cheaper) = .
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16When a certain quantity of a uniformly blended mixture is removed from a vessel, what happens to the ratio of its ingredients in the remaining mixture?
Components and blending : problems based on removal of mixture
Easy
A.It decreases
B.It remains exactly the same
C.It increases
D.It becomes zero
Correct Answer: It remains exactly the same
Explanation:
In a perfectly uniform mixture, removing any amount of the mixture does not change the ratio of the ingredients in the portion that is left behind.
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17In the standard removal and replacement formula , what does '' represent?
Components and blending : problems based on removal of mixture
Easy
A.The volume removed in each step
B.The concentration of the final mixture
C.The initial volume of the mixture
D.The total number of removal and replacement operations
Correct Answer: The total number of removal and replacement operations
Explanation:
The exponent '' stands for the number of times the process of removing and replacing the mixture is repeated.
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18A vessel contains $100$ liters of pure milk. If $10$ liters are removed and replaced with water, how much pure milk remains?
Components and blending : problems based on removal of mixture
Easy
A.$90$ liters
B.$100$ liters
C.$110$ liters
D.$80$ liters
Correct Answer: $90$ liters
Explanation:
Initial volume is $100$L. $10$L of pure milk is taken out. Remaining milk = liters.
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19If a certain volume of a mixture is drawn out and replaced by an equal volume of pure water, what remains constant throughout the process?
Components and blending : problems based on removal of mixture
Easy
A.The total quantity of milk in the vessel
B.The total volume of the liquid in the vessel
C.The ratio of milk to water
D.The cost of the mixture
Correct Answer: The total volume of the liquid in the vessel
Explanation:
Because the volume taken out is exactly replaced by an equal volume of water, the overall total volume of the liquid in the vessel does not change.
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20A container holds $40$ liters of pure acid. $4$ liters of acid are drawn out and replaced with water. What is the amount of pure acid left in the container?
Components and blending : problems based on removal of mixture
Easy
A.$36$ liters
B.$30$ liters
C.$32$ liters
D.$34$ liters
Correct Answer: $36$ liters
Explanation:
Using the formula: . Acid left = liters.
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21Two numbers are in the ratio . If $9$ is subtracted from each, the new numbers are in the ratio . Find the smaller number.
Advanced ratio and proportion : concept of ratio and proportion
Medium
A.$27$
B.$55$
C.$45$
D.$33$
Correct Answer: $33$
Explanation:
Let the numbers be and . According to the problem, . Cross-multiplying gives , which simplifies to . Solving for , we get , so . The smaller number is .
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22A bag contains $50$ P, $25$ P, and $10$ P coins in the ratio , amounting to Rs. $206$. Find the number of $50$ P coins.
Advanced ratio and proportion : concept of ratio and proportion
Medium
A.$160$
B.$240$
C.$200$
D.$360$
Correct Answer: $200$
Explanation:
Let the number of $50$ P, $25$ P, and $10$ P coins be , , and respectively. The value equation in Rupees is: . Simplifying: , which gives . Solving for gives . The number of $50$ P coins is .
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23The ratio of incomes of A and B is and the ratio of their expenditures is . If at the end of the year, each saves Rs. $1600$, what is the income of A?
Advanced ratio and proportion : concept of ratio and proportion
Medium
A.$4000$
B.Rs. $5000$
C.Rs. $3200$
D.Rs. $4800$
Correct Answer: $4000$
Explanation:
Let incomes be and , and expenditures be and . The savings are and . Thus, , meaning . Substituting for in the first equation gives , so , and . A's income is .
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24A sum of money is divided among A, B, and C in the ratio . If C gets Rs. $1200$ more than B, what is A's share?
Advanced ratio and proportion : concept of ratio and proportion
Medium
A.Rs. $800$
B.Rs. $600$
C.Rs. $2400$
D.Rs. $1200$
Correct Answer: Rs. $1200$
Explanation:
Let the shares be , , and . C gets Rs. $1200$ more than B, so . This gives , so . A's share is .
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25What is the fourth proportional to $5, 8, 15$?
Advanced ratio and proportion : concept of ratio and proportion
Medium
A.$20$
B.$24$
C.$18$
D.$30$
Correct Answer: $24$
Explanation:
Let the fourth proportional be . Then . This means . Solving for , we get , so .
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26A is two years older than B who is twice as old as C. If the sum of the ages of A, B, and C is $27$, how old is B?
Advanced ratio and proportion : problems based on ages and partnership
Medium
A.$12$
B.$8$
C.$7$
D.$10$
Correct Answer: $10$
Explanation:
Let C's age be . Then B's age is , and A's age is . The sum of their ages is . This simplifies to , so and . Thus, B's age is .
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27The ratio of the present ages of A and B is . After $5$ years, the ratio becomes . Find A's present age.
Advanced ratio and proportion : problems based on ages and partnership
Medium
A.$20$ years
B.$24$ years
C.$16$ years
D.$25$ years
Correct Answer: $20$ years
Explanation:
Let present ages be and . After $5$ years, the ratio is . Cross-multiplying: , yielding , so . A's present age is years.
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28A and B invest in a business in the ratio . If of the total profit goes to charity and A's share is Rs. $855$, what is the total profit?
Advanced ratio and proportion : problems based on ages and partnership
Medium
A.Rs. $1800$
B.Rs. $1425$
C.Rs. $1600$
D.Rs. $1500$
Correct Answer: Rs. $1500$
Explanation:
Let total profit be . Amount left after charity is . A's share is of the remaining profit, so . Given , we find .
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29A starts a business with Rs. $3500$. After $5$ months, B joins with A as his partner. After a year, the profit is divided in the ratio . What is B's contribution?
Advanced ratio and proportion : problems based on ages and partnership
Medium
A.Rs. $8000$
B.Rs. $8500$
C.Rs. $9000$
D.Rs. $7500$
Correct Answer: Rs. $9000$
Explanation:
A invested for $12$ months, so A's equivalent capital is . B invested for $7$ months (since he joined after $5$ months), so B's equivalent capital is . The ratio of their profits is . This simplifies to , leading to and .
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30The sum of the ages of a father and son is $45$ years. Five years ago, the product of their ages was $34$. What are the present ages of the father and son respectively?
Advanced ratio and proportion : problems based on ages and partnership
Medium
A.$35$ and $10$
B.$40$ and $5$
C.$39$ and $6$
D.$38$ and $7$
Correct Answer: $39$ and $6$
Explanation:
Let present ages be and . We know . Five years ago, . Substitute into the second equation: . Expanding yields , or . Solving gives or . Since the son must be younger, and .
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31In what ratio must a grocer mix two varieties of tea worth Rs. $60$ per kg and Rs. $65$ per kg so that by selling the mixture at Rs. $68.20$ per kg he may gain ?
Components and blending : concept of alligation and mixtures
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
To apply alligation, find the cost price (CP) of the mixture. . Using the rule of alligation: Quantity of cheaper / Quantity of dearer = . The ratio is .
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32A merchant has $1000$ kg of sugar, part of which he sells at profit and the rest at profit. He gains on the whole. What is the quantity sold at profit?
Components and blending : concept of alligation and mixtures
Medium
A.$700$ kg
B.$400$ kg
C.$500$ kg
D.$600$ kg
Correct Answer: $600$ kg
Explanation:
Using alligation on profit percentages: One part is , the other is , mean is . Ratio of quantities = . The quantity sold at profit is of kg.
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33Two vessels A and B contain spirit and water mixed in the ratio and respectively. Find the ratio in which these mixtures be mixed to obtain a new mixture containing spirit and water in the ratio .
Components and blending : concept of alligation and mixtures
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Fraction of spirit in A is , in B is , and in the target mixture is . By alligation, the ratio is . Multiplying both sides by $91$ gives .
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34A mixture of $40$ litres of milk and water contains water. How much water must be added to make the mixture contain water?
Components and blending : concept of alligation and mixtures
Medium
A.$8$ litres
B.$10$ litres
C.$4$ litres
D.$5$ litres
Correct Answer: $5$ litres
Explanation:
Initial milk volume = of litres. Let litres of water be added. The new total volume is . We want milk to be of the new mixture, so . Solving for : litres.
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35The cost of Type 1 rice is Rs. $15$ per kg and Type 2 rice is Rs. $20$ per kg. If both are mixed in the ratio of , then the price per kg of the mixed variety of rice is:
Components and blending : concept of alligation and mixtures
Medium
A.Rs. $17$
B.Rs. $18.50$
C.Rs. $19$
D.Rs. $18$
Correct Answer: Rs. $18$
Explanation:
Using the weighted average method: Average Cost = .
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36A container contains $40$ litres of milk. From this container, $4$ litres of milk was taken out and replaced by water. This process was repeated two more times. How much milk is now contained by the container?
Components and blending : problems based on removal of mixture
Medium
A.$29.16$ litres
B.$32.40$ litres
C.$26.34$ litres
D.$28.16$ litres
Correct Answer: $29.16$ litres
Explanation:
The formula for the final quantity of milk is , where , , and . litres.
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37$8$ litres are drawn from a cask full of wine and it is then filled with water. This operation is performed three more times (total four times). The ratio of the quantity of wine now left in the cask to that of water is . How much wine did the cask originally hold?
Components and blending : problems based on removal of mixture
Medium
A.$18$ litres
B.$24$ litres
C.$32$ litres
D.$40$ litres
Correct Answer: $24$ litres
Explanation:
Let the original volume be . The ratio of wine to total volume left is . Using the formula . Taking the fourth root of both sides gives . Therefore, , meaning litres.
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38A vessel is full of a mixture of methanol and ethanol in which there is ethanol. $10$ litres of the mixture are drawn off and replaced with pure methanol. If the ethanol is now , what is the total capacity of the vessel?
Components and blending : problems based on removal of mixture
Medium
A.$30$ litres
B.$35$ litres
C.$50$ litres
D.$40$ litres
Correct Answer: $40$ litres
Explanation:
Let the capacity be . The original ethanol volume is . When $10$ L is drawn, of L of ethanol is removed. Replacing with methanol doesn't add any ethanol. The new ethanol volume is , which equals of the total volume (). litres.
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39From a cask of milk containing $30$ litres, $6$ litres are drawn out and the cask is filled up with water. If the same process is repeated one more time, what is the ratio of milk to water in the resulting mixture?
Components and blending : problems based on removal of mixture
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Amount of milk left = litres. The total volume remains $30$ litres, so the water is litres. The ratio of milk to water is .
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40A vessel contains $60$ liters of a mixture of milk and water in the ratio . $12$ liters of the mixture are drawn off and replaced by water. Find the final ratio of milk to water.
Components and blending : problems based on removal of mixture
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Initially, milk = L, water = $10$ L. Removing $12$ L takes away L milk and $2$ L water. Remaining milk = L; remaining water = L. Adding $12$ L of water brings water to L. The final ratio of milk to water is .
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41A precious diamond falls and breaks into four pieces whose weights are in the ratio . The value of the diamond is directly proportional to the square of its weight. If the loss incurred due to the breakage is Rs. 70,000, what was the original value of the unbroken diamond?
Advanced ratio and proportion : concept of ratio and proportion
Hard
A.Rs. 1,50,000
B.Rs. 1,00,000
C.Rs. 90,000
D.Rs. 1,20,000
Correct Answer: Rs. 1,00,000
Explanation:
Let the weights of the four pieces be . The total weight of the original diamond was .
The value is proportional to the square of the weight.
Original value .
Sum of the values of the pieces .
Loss .
Given , so .
Original value .
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42The ratio of the incomes of A, B, and C is and the ratio of their expenditures is . If A saves of his income, what is the ratio of the savings of A, B, and C?
Advanced ratio and proportion : concept of ratio and proportion
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Let incomes be and expenditures be .
A's saving . We are given that .
This simplifies to .
Let and .
Incomes: .
Expenditures: .
Savings: , , .
Ratio is .
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43If the same number is subtracted from , and , the resulting numbers are in proportion. What is the mean proportional between and ?
Advanced ratio and proportion : concept of ratio and proportion
Hard
A.18
B.16
C.24
D.20
Correct Answer: 20
Explanation:
For the numbers to be in proportion: .
Cross multiplying: .
.
.
Substitute into the expressions:
First term .
Second term .
Mean proportional .
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44A sum of money is divided among A, B, C, and D such that the ratio of the shares of A and B is , B and C is , and C and D is . If the difference between the shares of C and A is Rs. 840, what is the share of D?
Advanced ratio and proportion : concept of ratio and proportion
Hard
A.Rs. 1800
B.Rs. 2800
C.Rs. 2100
D.Rs. 2400
Correct Answer: Rs. 2100
Explanation:
Combine the ratios:
So, .
Now, . To combine with , find LCM of 15 and 6, which is 30.
and .
Combined ratio .
Difference between C and A is units.
Given units unit .
Share of D .
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45The ratio of land to water on Earth is . In the Northern Hemisphere, this ratio is . What is the ratio of land to water in the Southern Hemisphere?
Advanced ratio and proportion : concept of ratio and proportion
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Let the total surface area of the Earth be 30 units (a multiple of 3 and 5).
Total land units, Total water units.
The Northern Hemisphere has an area of 15 units.
Land in NH units, Water in NH units.
The Southern Hemisphere also has an area of 15 units.
Land in SH Total Land - Land in NH units.
Water in SH Total Water - Water in NH units.
The ratio is .
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46A says to B, "I am twice as old as you were when I was as old as you are." The sum of their present ages is 63 years. What is the present age of A?
Advanced ratio and proportion : problems based on ages and partnership
Hard
A.42 years
B.32 years
C.45 years
D.36 years
Correct Answer: 36 years
Explanation:
Let A's present age be and B's be .
The time difference when A was B's current age is years ago.
B's age at that time was .
According to the statement, .
.
The sum of their ages is 7 units unit .
A's age years.
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47A, B, and C started a business with initial investments in the ratio . At the end of every quarter, A halves his capital, B doubles his capital, and C leaves his capital unchanged. If the total profit at the end of the year is Rs. 49,000, find the difference between the profit shares of B and A.
Advanced ratio and proportion : problems based on ages and partnership
Hard
A.Rs. 15,000
B.Rs. 20,000
C.Rs. 12,000
D.Rs. 18,000
Correct Answer: Rs. 15,000
Explanation:
Let the initial capitals be . The year has 4 quarters.
A's effective capital units.
B's effective capital units.
C's effective capital units.
The ratio of profits .
Total ratio units .
units unit .
Difference between B and A units .
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48A father's present age is 3 times the sum of the ages of his two children. After 5 years, his age will be twice the sum of the ages of his two children. Find the present age of the father.
Advanced ratio and proportion : problems based on ages and partnership
Hard
A.45 years
B.50 years
C.40 years
D.55 years
Correct Answer: 45 years
Explanation:
Let the sum of the present ages of the two children be .
Father's present age .
After 5 years, father's age will be .
The sum of the ages of the two children will be .
Given: .
Substitute :
.
Father's present age years.
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49A, B, and C enter into a partnership. A invests Rs. 4000 for the full year. B invests Rs. 6000 initially but withdraws Rs. 2000 after 6 months. C invests Rs. 8000 but only for the last 8 months. The total profit is Rs. 17,200. If A receives 10% of the total profit for managing the business, what is B's total share in the remaining profit?
Advanced ratio and proportion : problems based on ages and partnership
Hard
A.Rs. 6,400
B.Rs. 5,400
C.Rs. 6,000
D.Rs. 4,800
Correct Answer: Rs. 5,400
Explanation:
A's management fee .
Remaining profit to be shared .
A's investment .
B's investment .
C's investment .
Ratio of their shares .
Total ratio units .
B's share .
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50In a family consisting of a father, mother, son, and daughter, the age of the father is 4 times that of the son. The age of the daughter is that of the mother. The wife is 6 years younger than her husband, and the sister is 3 years older than her brother. What is the mother's present age?
Advanced ratio and proportion : problems based on ages and partnership
Hard
A.60 years
B.48 years
C.52 years
D.54 years
Correct Answer: 54 years
Explanation:
Let Father = , Mother = , Son = , Daughter = .
Given:
Substitute and into the second equation:
.
Multiply by 3: .
Substitute :
.
Then .
Mother's age years.
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51Three equal glasses are filled with mixtures of milk and water. The ratios of milk to water in the glasses are , , and respectively. If the contents of all three glasses are mixed into a single vessel, what is the ratio of milk to water in the final mixture?
Components and blending : concept of alligation and mixtures
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The capacities are equal. The sum of parts in the given ratios are 4, 8, and 16.
To make the capacities equal, take the LCM of 4, 8, and 16, which is 16.
Multiply the ratios to have 16 units each:
Glass 1 (): units milk, units water.
Glass 2 (): units milk, units water.
Glass 3 (): units milk, units water.
Total milk .
Total water .
The final ratio is .
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52Two alloys contain gold and silver in the ratio and respectively. How many kilograms of the first alloy must be melted with 21 kg of the second alloy to form a new alloy that contains equal quantities of gold and silver?
Components and blending : concept of alligation and mixtures
Hard
A.7 kg
B.14 kg
C.10.5 kg
D.21 kg
Correct Answer: 7 kg
Explanation:
The target ratio of gold to silver is , meaning gold is of the total.
Fraction of gold in first alloy .
Fraction of gold in second alloy .
Using alligation:
Ratio of first to second alloy
.
If 3 parts kg, then 1 part kg.
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53In what ratio should water be mixed with milk costing Rs. 40 per liter so as to make a profit of 25% by selling the resulting mixture at Rs. 40 per liter?
Components and blending : concept of alligation and mixtures
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Selling price of the mixture .
Profit .
Cost price of the mixture .
Cost of water is Rs. 0. Cost of pure milk is Rs. 40.
Using alligation:
Ratio of Water to Milk .
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54Two vessels A and B contain mixtures of acid and water in the ratio and respectively. If a mixture is formed by taking quantities from A and B in the ratio and pouring them into a third vessel C, what will be the ratio of acid to water in C?
Components and blending : concept of alligation and mixtures
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Fraction of acid in A . Fraction of acid in B .
Since they are mixed in the ratio , the total acid fraction in C is:
.
The fraction of water is .
The ratio of acid to water is .
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55A merchant buys two kinds of tea at Rs. 80 per kg and Rs. 120 per kg. He mixes them and sells the mixture at Rs. 112 per kg, making a profit of 25%. What is the ratio in which he mixed the two kinds of tea?
Components and blending : concept of alligation and mixtures
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Selling price .
Profit .
Cost price of mixture .
Using alligation on the cost prices:
Quantity 1 (Rs. 80) : Quantity 2 (Rs. 120)
.
Multiply by 10 to remove decimals: .
Divide by 16: .
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56From a cask completely filled with 24 liters of pure wine, a certain amount is drawn out and replaced with water. This process is done 4 times in total. If the ratio of wine left in the cask to water is now , how many liters were drawn out each time?
Components and blending : problems based on removal of mixture
Hard
A.6 liters
B.4 liters
C.12 liters
D.8 liters
Correct Answer: 8 liters
Explanation:
Let the volume drawn out each time be liters. Total volume liters.
Final ratio of wine to water is .
Total mixture units.
The fraction of wine left is .
The formula for remaining quantity after replacements is:
.
So, .
Taking the fourth root on both sides:
.
liters.
Incorrect! Try again.
57A container holds 50 liters of pure milk. First, 5 liters of milk are taken out and replaced by water. Then, 10 liters of the resulting mixture are taken out and replaced by water. Finally, 15 liters of this mixture are taken out and replaced by water. How much milk is left in the container?
Components and blending : problems based on removal of mixture
Hard
A.20.4 liters
B.22.5 liters
C.27.6 liters
D.25.2 liters
Correct Answer: 25.2 liters
Explanation:
If different quantities are removed and replaced successively from a volume , the final quantity of the original substance is:
liters.
Incorrect! Try again.
58From a vessel containing 100 liters of pure wine, 10% is drawn out and replaced with water. This process is repeated until the concentration of wine drops below 70% for the first time. How many times must this process be performed in total?
Components and blending : problems based on removal of mixture
Hard
A.4 times
B.5 times
C.3 times
D.2 times
Correct Answer: 4 times
Explanation:
Removing 10% means the fraction remaining after each step is .
After 1st time: .
After 2nd time: .
After 3rd time: .
After 4th time: .
Since is below , the process must be performed 4 times.
Incorrect! Try again.
59A vessel is full of a mixture of spirit and water in the ratio . What fraction of the mixture must be drawn off and replaced with pure water so that the final ratio of spirit to water becomes ?
Components and blending : problems based on removal of mixture
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Let the total volume of the mixture be . Initially, Spirit , Water .
Let be the fraction of the mixture drawn off. The amount of spirit drawn off is .
The spirit remaining is .
Since the target is a ratio, the remaining spirit must be half of the total volume (i.e., ).
.
Incorrect! Try again.
60A 40-liter mixture of milk and water contains 10% water. 8 liters of the mixture is removed and replaced with pure milk. Then, 10 liters of the new mixture is removed and replaced with pure milk. What is the final percentage of water in the mixture?
Components and blending : problems based on removal of mixture
Hard
A.5%
B.7.2%
C.6%
D.4.5%
Correct Answer: 6%
Explanation:
Initial volume L. Water = 10% of 40 = 4L.
Step 1: 8L (which is of the total mixture) is removed.
Water removed = L. Water remaining = L.
The 8L is replaced with milk, so the total volume is back to 40L, but water is still 3.2L.
Step 2: 10L (which is of the total mixture) is removed.
Water removed = L.
Water remaining = L.
This is replaced with milk, leaving water at 2.4L out of 40L.
Final percentage of water = .