Unit 1 - Notes
Unit 1: Fundamentals of DC and AC circuits
1. Basic Electrical Quantities and Components
1.1 Voltage (V)
- Definition: Voltage, also known as potential difference or electromotive force (EMF), is the work done per unit charge. It is the electrical pressure that causes charge (current) to flow in a circuit.
- Analogy: Similar to water pressure in a pipe. Higher pressure causes more water to flow.
- Unit: Volt (V). 1 Volt = 1 Joule / Coulomb.
- Measurement: Measured across two points in a circuit using a voltmeter (connected in parallel).
1.2 Current (I)
- Definition: Current is the rate of flow of electric charge (electrons) through a conductor.
- Analogy: Similar to the flow rate of water in a pipe.
- Formula:
I = dQ/dt, whereIis current,Qis charge, andtis time. - Unit: Ampere (A). 1 Ampere = 1 Coulomb / second.
- Measurement: Measured through a component using an ammeter (connected in series).
1.3 Resistance (R)
- Definition: Resistance is the property of a material that opposes the flow of electric current. It dissipates electrical energy in the form of heat.
- Formula:
R = ρ * (L/A), whereρ(rho) is the resistivity of the material,Lis the length, andAis the cross-sectional area. - Unit: Ohm (Ω).
- Symbol:
1.4 Inductance (L)
- Definition: Inductance is the property of an electrical conductor by which a change in current through it induces an electromotive force (voltage) in both the conductor itself (self-inductance) and in any nearby conductors (mutual inductance). It opposes a change in current.
- Energy Storage: Stores energy in a magnetic field.
- Voltage-Current Relationship: The voltage across an inductor is proportional to the rate of change of current through it.
TEXTv(t) = L * (di(t)/dt) - Unit: Henry (H).
- Symbol:
1.5 Capacitance (C)
- Definition: Capacitance is the ability of a component to store electrical energy in an electric field. It is the ratio of the change in an electric charge in a system to the corresponding change in its electric potential. It opposes a change in voltage.
- Energy Storage: Stores energy in an electric field.
- Current-Voltage Relationship: The current through a capacitor is proportional to the rate of change of voltage across it.
TEXTi(t) = C * (dv(t)/dt) - Unit: Farad (F).
- Symbol:
1.6 Power (P) and Energy (W or E)
Power (P)
- Definition: Power is the rate at which energy is consumed or produced in a circuit.
- Formulas:
- General:
P = V * I - For resistors:
P = I² * RorP = V² / R
- General:
- Unit: Watt (W). 1 Watt = 1 Joule / second.
- Sign Convention:
- Power Absorbed: If current flows from the positive (+) terminal to the negative (-) terminal of an element, power is being absorbed or dissipated by that element (e.g., a resistor).
P = +VI. - Power Supplied: If current flows out of the positive (+) terminal of an element, power is being supplied by that element (e.g., a battery).
P = -VI.
- Power Absorbed: If current flows from the positive (+) terminal to the negative (-) terminal of an element, power is being absorbed or dissipated by that element (e.g., a resistor).
Energy (W)
- Definition: Energy is the capacity to do work. It is power integrated over time.
- Formula:
W = P * t - Unit: Joule (J). A common commercial unit is the kilowatt-hour (kWh). 1 kWh = 3.6 x 10⁶ Joules.
2. Fundamental Laws and Circuit Simplification
2.1 Ohm's Law
- Statement: The voltage across a resistor is directly proportional to the current flowing through it, provided the temperature and other physical conditions remain unchanged.
- Formula:
V = I * R - Graphical Representation: The V-I characteristic for a resistor is a straight line passing through the origin, with the slope equal to the resistance
R.
2.2 Kirchhoff’s Laws
Kirchhoff’s Current Law (KCL)
- Principle: Based on the law of conservation of charge.
- Statement: The algebraic sum of currents entering a node (or a closed boundary) is zero.
- Formula:
Σ I_entering = Σ I_leaving -
Example:
At the node shown, KCL gives:
I1 + I4 = I2 + I3orI1 - I2 - I3 + I4 = 0
Kirchhoff’s Voltage Law (KVL)
- Principle: Based on the law of conservation of energy.
- Statement: The algebraic sum of all voltages around any closed loop or mesh in a circuit is equal to zero.
- Formula:
Σ V_rises = Σ V_drops - Sign Convention: When traversing a loop:
- Moving from
-to+across a component is a voltage rise. - Moving from
+to-across a component is a voltage drop.
- Moving from
-
Example:
Applying KVL to the loop (starting from the bottom-left corner and moving clockwise):
-Vs + V_R1 + V_R2 = 0orVs = V_R1 + V_R2
2.3 Voltage Division Rule (VDR)
- Application: Used to find the voltage across a resistor in a series circuit without first calculating the current.
- Derivation: In a series circuit with resistors
R1, R2, ..., Rnand total voltageVs, the total resistance isReq = R1 + R2 + ... + Rn. The current isI = Vs / Req. The voltage across a specific resistorRxisVx = I * Rx. SubstitutingI, we get the formula. - Formula (for two resistors): For a voltage
Vsacross two series resistorsR1andR2, the voltageV2acrossR2is:
TEXTV2 = Vs * (R2 / (R1 + R2))
2.4 Current Division Rule (CDR)
- Application: Used to find the current flowing through a resistor in a parallel circuit without first calculating the voltage.
- Derivation: In a parallel circuit with total current
Issplitting between branches, the voltageVacross all branches is the same.V = Is * Req. The currentIxthrough a specific resistorRxisIx = V / Rx. SubstitutingV, we get the formula. - Formula (for two resistors): For a total current
Issplitting between two parallel resistorsR1andR2, the currentI2throughR2is:
TEXTI2 = Is * (R1 / (R1 + R2))
Note: The numerator contains the other resistor's value.
3. Circuit Analysis Methods
3.1 Dependent and Independent Sources
-
Independent Sources: Provide a specified voltage or current that is completely independent of other circuit variables.
- Independent Voltage Source: Maintains a specified voltage across its terminals. An ideal source has zero internal resistance.
- Independent Current Source: Maintains a specified current through its terminals. An ideal source has infinite internal resistance.
-
Dependent (or Controlled) Sources: The value of the source depends on a voltage or current elsewhere in the circuit. They are essential for modeling active devices like transistors and amplifiers.
- Voltage-Controlled Voltage Source (VCVS):
V = μ * Vx - Current-Controlled Voltage Source (CCVS):
V = r * Ix - Voltage-Controlled Current Source (VCCS):
I = g * Vx - Current-Controlled Current Source (CCCS):
I = β * Ix
- Voltage-Controlled Voltage Source (VCVS):
3.2 Mesh Analysis
-
Basis: Applies KVL to find unknown currents.
-
Procedure:
- Identify Meshes: A mesh is a loop that does not contain any other loops within it.
- Assign Mesh Currents: Assign a distinct current variable (e.g.,
i1,i2) to each mesh, typically in a clockwise direction. - Apply KVL: Write a KVL equation for each mesh.
- The voltage drop across a resistor is
I * R. - For a resistor shared between two meshes (e.g.,
Rbetween mesh 1 and mesh 2), the current through it is the difference of the two mesh currents (i1 - i2ori2 - i1, depending on the direction of KVL traversal).
- The voltage drop across a resistor is
- Solve: Solve the resulting system of simultaneous linear equations to find the mesh currents.
-
Example:
- Mesh 1 (left loop): Start at the bottom left, go clockwise.
-V1 + R1*i1 + R2*(i1 - i2) = 0
(R1 + R2)*i1 - R2*i2 = V1(Equation 1) - Mesh 2 (right loop): Start at the bottom of R2, go clockwise.
R2*(i2 - i1) + R3*i2 + V2 = 0
-R2*i1 + (R2 + R3)*i2 = -V2(Equation 2) - Solve these two equations for
i1andi2.
- Mesh 1 (left loop): Start at the bottom left, go clockwise.
3.3 Nodal Analysis
-
Basis: Applies KCL to find unknown node voltages.
-
Procedure:
- Identify Nodes: A node is a point where two or more circuit elements connect.
- Select Reference Node: Choose one node as the reference node (ground), which is defined to have a potential of 0V.
- Assign Node Voltages: Assign a voltage variable (e.g.,
V1,V2) to each of the other non-reference nodes. These voltages are relative to the reference node. - Apply KCL: Write a KCL equation for each non-reference node. Assume all unknown currents are leaving the node. The current flowing from node A to node B through a resistor
Ris(VA - VB) / R. - Solve: Solve the resulting system of simultaneous linear equations to find the node voltages.
-
Example:
- Reference Node: Bottom wire is 0V.
- Node 1 (V1): Apply KCL.
(V1 - Vs)/R1 + V1/R2 + (V1 - V2)/R3 = 0 - Node 2 (V2): Apply KCL.
(V2 - V1)/R3 + V2/R4 - Is = 0 - Rearrange and solve these two equations for
V1andV2.
4. Network Theorems
4.1 Thevenin’s Theorem
-
Statement: Any linear two-terminal circuit can be replaced by an equivalent circuit consisting of a single voltage source (
V_th) in series with a single resistor (R_th). This simplifies analysis of a complex circuit connected to a load. -
Procedure:
- Identify Load: Identify the portion of the circuit to be analyzed (the "load,"
R_L), and remove it from the circuit. - Calculate V_th (Thevenin Voltage): Find the open-circuit voltage across the two terminals where the load was connected. This can be found using mesh, nodal analysis, or other simplification techniques.
- Calculate R_th (Thevenin Resistance): Find the equivalent resistance looking back into the open-circuited terminals.
- Turn off all independent sources:
- Independent Voltage Sources are replaced by a short circuit (0V).
- Independent Current Sources are replaced by an open circuit (0A).
- Do NOT turn off dependent sources. If they are present, you must use a test source (voltage or current) at the terminals to find
R_th = V_test / I_test.
- Draw Equivalent Circuit: The Thevenin equivalent circuit is
V_thin series withR_th. The loadR_Lcan now be reconnected to this simplified circuit to easily calculate load voltage and current (I_L = V_th / (R_th + R_L)).
- Identify Load: Identify the portion of the circuit to be analyzed (the "load,"
4.2 Norton’s Theorem
-
Statement: Any linear two-terminal circuit can be replaced by an equivalent circuit consisting of a single current source (
I_n) in parallel with a single resistor (R_n). -
Procedure:
- Identify Load: Identify and remove the load resistor
R_L. - Calculate I_n (Norton Current): Find the short-circuit current that flows through the terminals where the load was connected (i.e., place a short circuit across the terminals and find the current through it).
- Calculate R_n (Norton Resistance): The Norton resistance
R_nis calculated in the exact same way as the Thevenin resistanceR_th.R_n = R_th. - Draw Equivalent Circuit: The Norton equivalent circuit is
I_nin parallel withR_n. The loadR_Lcan be reconnected to find the load current using the current divider rule.
- Identify Load: Identify and remove the load resistor
-
Source Transformation (Thevenin-Norton Equivalence):
- A Thevenin circuit can be converted to a Norton circuit, and vice-versa.
V_th = I_n * R_nI_n = V_th / R_thR_th = R_n
5. Fundamentals of AC Circuits
5.1 Alternating Current (AC) and Voltage
- Definition: Alternating Current (AC) is an electric current which periodically reverses direction, in contrast to Direct Current (DC) which flows only in one direction.
- Waveform: While AC can have many waveforms (square, triangular), the most common is the sinusoidal waveform.
- Mathematical Representation: A sinusoidal voltage or current can be expressed as:
TEXTv(t) = Vm * sin(ωt + φ) i(t) = Im * sin(ωt + φ)
where:v(t)ori(t)is the instantaneous value at timet.VmorImis the maximum value, or Amplitude.ωis the angular frequency in radians/sec.φ(phi) is the phase angle in radians or degrees.
5.2 Definitions of Amplitude and Phase
- Amplitude (Vm, Im): The peak or maximum value of the waveform, measured from the zero axis. Also called peak voltage or peak current. The peak-to-peak voltage is
2 * Vm. - Period (T): The time taken to complete one full cycle of the waveform. Unit: seconds (s).
- Frequency (f): The number of cycles completed per second. It is the reciprocal of the period.
f = 1/T. Unit: Hertz (Hz). - Angular Frequency (ω): The rate of change of the phase angle.
ω = 2πf = 2π/T. Unit: radians/sec. - Phase (φ): The phase angle represents the horizontal shift of the waveform from a reference point (usually
t=0). It describes the position of the waveform at the starting point.- In Phase: Two signals are in phase if their phase difference is 0°. They reach their maximum and minimum points at the same time.
- Out of Phase (Leading/Lagging): If
v1(t) = Vm*sin(ωt)andv2(t) = Vm*sin(ωt - θ), thenv2lagsv1byθ, orv1leadsv2byθ.
5.3 Average and RMS Value of an AC Signal
Average Value
- Definition: The average value of any periodic waveform is its integral over one period, divided by the period.
TEXTV_avg = (1/T) * ∫[from 0 to T] v(t) dt - For a Symmetrical Sinusoid: The average value over one full cycle is zero, because the positive and negative half-cycles cancel each other out.
- For a Half-Cycle (Half-Wave Rectified): The average value is calculated over the first half-cycle.
TEXTV_avg = (2/π) * Vm ≈ 0.637 * Vm
RMS (Root Mean Square) Value
- Concept: The RMS value of an AC signal is its "effective" value. It is the equivalent DC value that would deliver the same average power to a resistor as the AC signal.
- Definition: It is found by taking the square Root of the Mean of the Square of the signal's instantaneous values.
TEXTV_rms = sqrt( (1/T) * ∫[from 0 to T] v(t)² dt ) - Formula for a Sinusoidal Waveform: For a pure sine wave, the RMS value is the peak value divided by the square root of 2.
TEXTV_rms = Vm / √2 ≈ 0.707 * Vm
Similarly,I_rms = Im / √2. - Importance: Standard AC voltmeters and ammeters are calibrated to read RMS values. Power calculations in AC circuits are almost always done using RMS values. For example, the power dissipated in a resistor is
P = (V_rms)² / R = (I_rms)² * R.