ATP stands for adenosine triphosphate, the primary energy currency of the cell, consisting of adenosine bound to three phosphate groups.
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2Which of the following is an electron carrier that is reduced to ?
ATP and electron carriers
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
accepts two electrons and one proton to become , acting as a key electron carrier in metabolism.
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3Energy is released when ATP is hydrolyzed to which molecule?
ATP and electron carriers
Easy
A. and two
B. and
C.Adenine and ribose
D. and
Correct Answer: and
Explanation:
Hydrolysis of ATP typically produces ADP and inorganic phosphate (), releasing energy used to drive cellular processes.
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4In which cellular compartment does glycolysis take place?
glycolysis
Easy
A.Mitochondrial matrix
B.Cytoplasm
C.Endoplasmic reticulum
D.Nucleus
Correct Answer: Cytoplasm
Explanation:
Glycolysis occurs in the cytoplasm (cytosol) and does not require oxygen or membrane-bound organelles.
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5What is the final product of glycolysis?
glycolysis
Easy
A.Lactate
B.Acetyl-CoA
C.Glucose-6-phosphate
D.Pyruvate
Correct Answer: Pyruvate
Explanation:
Glycolysis converts one molecule of glucose into two molecules of pyruvate, a three-carbon compound.
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6What is the net yield of ATP from one molecule of glucose during glycolysis?
glycolysis
Easy
A.4 ATP
B.6 ATP
C.2 ATP
D.1 ATP
Correct Answer: 2 ATP
Explanation:
Glycolysis produces 4 ATP but consumes 2 ATP in the investment phase, giving a net gain of 2 ATP per glucose.
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7Which enzyme catalyzes the first committed and rate-limiting step of glycolysis by phosphorylating fructose-6-phosphate to fructose-1,6-bisphosphate using ATP?
glycolysis
Easy
A.Pyruvate kinase
B.Phosphofructokinase-1
C.Aldolase
D.Hexokinase
Correct Answer: Phosphofructokinase-1
Explanation:
Phosphofructokinase-1 (PFK-1) catalyzes the key regulatory step of glycolysis and is the main control point of the pathway.
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8In human muscle cells during intense exercise, pyruvate is converted into which product by fermentation?
fermentation
Easy
A.Ethanol
B.Acetyl-CoA
C.Lactate
D.Citrate
Correct Answer: Lactate
Explanation:
During oxygen shortage, muscle cells reduce pyruvate to lactate, regenerating so glycolysis can continue.
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9What is the main purpose of fermentation in cells?
fermentation
Easy
A.To synthesize glucose
B.To regenerate
C.To produce large amounts of ATP
D.To store glycogen
Correct Answer: To regenerate
Explanation:
Fermentation regenerates from so that glycolysis can continue producing ATP in the absence of oxygen.
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10Alcoholic fermentation carried out by yeast produces ethanol and which gas?
fermentation
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
In alcoholic fermentation, pyruvate is converted to ethanol with the release of carbon dioxide ().
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11Gluconeogenesis is the metabolic process that synthesizes which molecule?
gluconeogenesis
Easy
A.Glucose
B.Pyruvate
C.Glycogen
D.Lactate
Correct Answer: Glucose
Explanation:
Gluconeogenesis is the synthesis of new glucose from non-carbohydrate precursors such as lactate, amino acids, and glycerol.
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12In which organ does gluconeogenesis primarily occur?
gluconeogenesis
Easy
A.Adipose tissue
B.Brain
C.Liver
D.Skeletal muscle
Correct Answer: Liver
Explanation:
The liver is the principal site of gluconeogenesis, helping maintain blood glucose during fasting; the kidneys also contribute.
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13Which of the following is a common precursor for gluconeogenesis?
gluconeogenesis
Easy
A.Fatty acids
B.Lactate
C.Cellulose
D.Cholesterol
Correct Answer: Lactate
Explanation:
Lactate, produced by anaerobic glycolysis, is a major precursor that can be converted back into glucose via gluconeogenesis.
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14Which important reducing molecule is produced by the pentose phosphate pathway?
pentose phosphate pathway
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
The pentose phosphate pathway generates , which is used in biosynthesis and protecting cells from oxidative stress.
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15The pentose phosphate pathway provides ribose-5-phosphate, which is a precursor for the synthesis of which molecules?
pentose phosphate pathway
Easy
A.Phospholipids
B.Nucleotides
C.Fatty acids
D.Amino acids
Correct Answer: Nucleotides
Explanation:
Ribose-5-phosphate from the pentose phosphate pathway is used to build nucleotides for DNA and RNA.
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16What sugar molecule serves as the starting substrate of the pentose phosphate pathway?
pentose phosphate pathway
Easy
A.Ribulose-5-phosphate
B.Pyruvate
C.Glucose-6-phosphate
D.Fructose-6-phosphate
Correct Answer: Glucose-6-phosphate
Explanation:
The pentose phosphate pathway begins with glucose-6-phosphate, which is oxidized by glucose-6-phosphate dehydrogenase.
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17The breakdown of glycogen into glucose units is called what?
glycogen breakdown
Easy
A.Glycogenesis
B.Glycolysis
C.Gluconeogenesis
D.Glycogenolysis
Correct Answer: Glycogenolysis
Explanation:
Glycogenolysis is the enzymatic breakdown of glycogen to release glucose-1-phosphate and glucose.
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18Which enzyme is chiefly responsible for cleaving glucose units from glycogen during its breakdown?
glycogen breakdown
Easy
A.Glycogen synthase
B.Hexokinase
C.Glycogen phosphorylase
D.Amylase
Correct Answer: Glycogen phosphorylase
Explanation:
Glycogen phosphorylase removes glucose residues from glycogen by phosphorolysis, producing glucose-1-phosphate.
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19The process of forming glycogen from glucose is known as which of the following?
glycogen synthesis
Easy
A.Glycolysis
B.Lipogenesis
C.Glycogenolysis
D.Glycogenesis
Correct Answer: Glycogenesis
Explanation:
Glycogenesis is the synthesis of glycogen from glucose, storing excess glucose primarily in the liver and muscle.
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20Which enzyme adds glucose units to a growing glycogen chain during glycogen synthesis?
glycogen synthesis
Easy
A.Phosphofructokinase
B.Glycogen phosphorylase
C.Glycogen synthase
D.Pyruvate kinase
Correct Answer: Glycogen synthase
Explanation:
Glycogen synthase catalyzes the addition of glucose units (from UDP-glucose) to form the -1,4 linkages of glycogen.
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21During oxidation of one molecule of through the electron transport chain, approximately how many ATP are synthesized (using the conventional P/O ratio)?
ATP and electron carriers
Medium
A.3.5 ATP
B.4.0 ATP
C.1.5 ATP
D.2.5 ATP
Correct Answer: 2.5 ATP
Explanation:
Under the modern consensus P/O ratios, oxidation of one yields about 2.5 ATP, while yields about 1.5 ATP because electrons from enter at Complex II, bypassing one proton-pumping site.
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22Why is energetically 'worth' fewer ATP than in oxidative phosphorylation?
ATP and electron carriers
Medium
A.It carries only one electron instead of two
B.Its electrons enter the chain at Complex II, skipping one proton pump
C.It is located outside the mitochondrial matrix
D.It cannot be reoxidized by oxygen
Correct Answer: Its electrons enter the chain at Complex II, skipping one proton pump
Explanation:
donates electrons at Complex II (succinate dehydrogenase), which does not pump protons. Because fewer protons are translocated compared to (entering at Complex I), less ATP is produced.
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23In glycolysis, which enzyme catalyzes the first committed and irreversible step that is subject to allosteric regulation?
glycolysis
Medium
A.Hexokinase
B.Pyruvate kinase
C.Aldolase
D.Phosphofructokinase-1
Correct Answer: Phosphofructokinase-1
Explanation:
PFK-1 catalyzes the conversion of fructose-6-phosphate to fructose-1,6-bisphosphate, the committed step of glycolysis. It is allosterically inhibited by ATP and citrate and activated by AMP and fructose-2,6-bisphosphate.
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24What is the net ATP yield per molecule of glucose during glycolysis?
glycolysis
Medium
A.6 ATP
B.4 ATP
C.2 ATP
D.1 ATP
Correct Answer: 2 ATP
Explanation:
Glycolysis produces 4 ATP by substrate-level phosphorylation but consumes 2 ATP in the investment phase, giving a net gain of 2 ATP per glucose.
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25Which glycolytic step generates ?
glycolysis
Medium
A.Glyceraldehyde-3-phosphate to 1,3-bisphosphoglycerate
B.Fructose-6-phosphate to fructose-1,6-bisphosphate
C.Phosphoenolpyruvate to pyruvate
D.Glucose to glucose-6-phosphate
Correct Answer: Glyceraldehyde-3-phosphate to 1,3-bisphosphoglycerate
Explanation:
Glyceraldehyde-3-phosphate dehydrogenase oxidizes G3P and reduces to while adding inorganic phosphate, forming the high-energy compound 1,3-bisphosphoglycerate.
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26What is the primary metabolic purpose of lactate fermentation in vigorously contracting muscle?
fermentation
Medium
A.To synthesize glucose from pyruvate
B.To store energy as glycogen
C.To generate additional ATP directly from lactate
D.To regenerate so glycolysis can continue
Correct Answer: To regenerate so glycolysis can continue
Explanation:
Under anaerobic conditions, lactate dehydrogenase reduces pyruvate to lactate, oxidizing back to . This sustains the glyceraldehyde-3-phosphate dehydrogenase step and keeps glycolytic ATP production going.
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27In alcoholic fermentation by yeast, which two products are formed from pyruvate?
fermentation
Medium
A.Lactate and
B.Ethanol and
C.Acetaldehyde and lactate
D.Acetate and
Correct Answer: Ethanol and
Explanation:
Pyruvate decarboxylase releases to form acetaldehyde, which alcohol dehydrogenase then reduces to ethanol, regenerating in the process.
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28Which enzyme allows gluconeogenesis to bypass the irreversible pyruvate kinase step of glycolysis by converting oxaloacetate to phosphoenolpyruvate?
gluconeogenesis
Medium
A.Fructose-1,6-bisphosphatase
B.Glucose-6-phosphatase
C.Pyruvate carboxylase
D.PEP carboxykinase
Correct Answer: PEP carboxykinase
Explanation:
After pyruvate carboxylase converts pyruvate to oxaloacetate, PEP carboxykinase converts oxaloacetate to phosphoenolpyruvate, bypassing the irreversible pyruvate kinase reaction.
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29Why can acetyl-CoA (from fatty acid oxidation) not be used for net glucose synthesis in humans?
gluconeogenesis
Medium
A.It is oxidized before reaching the liver
B.It inhibits pyruvate carboxylase completely
C.It is too large to enter the cytosol
D.The pyruvate dehydrogenase reaction is irreversible
Correct Answer: The pyruvate dehydrogenase reaction is irreversible
Explanation:
The conversion of pyruvate to acetyl-CoA by pyruvate dehydrogenase is irreversible, so carbon in acetyl-CoA cannot be converted back to pyruvate for net glucose synthesis.
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30How many ATP equivalents are required to synthesize one glucose molecule from two pyruvate molecules?
gluconeogenesis
Medium
A.8 ATP equivalents
B.2 ATP equivalents
C.6 ATP equivalents
D.4 ATP equivalents
Correct Answer: 6 ATP equivalents
Explanation:
Gluconeogenesis consumes 6 high-energy phosphates: 2 ATP (pyruvate carboxylase), 2 GTP (PEP carboxykinase), and 2 ATP (phosphoglycerate kinase), per glucose made from two pyruvates.
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31What are the two major biosynthetic products of the oxidative phase of the pentose phosphate pathway?
pentose phosphate pathway
Medium
A. and fructose-6-phosphate
B.ATP and glucose-6-phosphate
C. and pyruvate
D. and ribose-5-phosphate
Correct Answer: and ribose-5-phosphate
Explanation:
The oxidative phase generates (for reductive biosynthesis and antioxidant defense) and produces ribulose-5-phosphate, which is converted to ribose-5-phosphate for nucleotide synthesis.
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32Which enzyme catalyzes the committed, rate-limiting step of the pentose phosphate pathway?
pentose phosphate pathway
Medium
A.Transaldolase
B.Transketolase
C.6-phosphogluconate dehydrogenase
D.Glucose-6-phosphate dehydrogenase
Correct Answer: Glucose-6-phosphate dehydrogenase
Explanation:
Glucose-6-phosphate dehydrogenase (G6PD) catalyzes the first oxidative step and is the rate-limiting enzyme, regulated mainly by the ratio.
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33A deficiency in glucose-6-phosphate dehydrogenase makes red blood cells especially vulnerable to oxidative stress because they cannot adequately produce which molecule?
pentose phosphate pathway
Medium
A. for the electron transport chain
B.ATP for membrane pumps
C. to regenerate reduced glutathione
D.Ribose-5-phosphate for DNA repair
Correct Answer: to regenerate reduced glutathione
Explanation:
Without G6PD, cells lack , which is needed to keep glutathione reduced. Reduced glutathione neutralizes reactive oxygen species; its deficiency causes hemolysis under oxidative stress.
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34What is the primary product released when glycogen phosphorylase cleaves an -1,4 glycosidic bond in glycogen?
glycogen breakdown
Medium
A.UDP-glucose
B.Free glucose
C.Glucose-1-phosphate
D.Glucose-6-phosphate
Correct Answer: Glucose-1-phosphate
Explanation:
Glycogen phosphorylase uses inorganic phosphate to cleave -1,4 bonds by phosphorolysis, releasing glucose-1-phosphate, which is then converted to glucose-6-phosphate by phosphoglucomutase.
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35Why can only the liver, and not muscle, release free glucose into the blood from glycogen breakdown?
glycogen breakdown
Medium
A.Only the liver contains phosphoglucomutase
B.Muscle cannot form glucose-1-phosphate
C.Muscle lacks glycogen phosphorylase
D.Only the liver has glucose-6-phosphatase
Correct Answer: Only the liver has glucose-6-phosphatase
Explanation:
The liver expresses glucose-6-phosphatase, which removes the phosphate so free glucose can leave the cell. Muscle lacks this enzyme, so its glucose-6-phosphate is used only internally for glycolysis.
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36The debranching enzyme is required during glycogenolysis to handle which type of linkage?
glycogen breakdown
Medium
A.-1,6 glycosidic bonds
B.-1,4 glycosidic bonds
C.Phosphodiester bonds
D.-1,4 glycosidic bonds
Correct Answer: -1,6 glycosidic bonds
Explanation:
Glycogen phosphorylase stops near branch points. The debranching enzyme transfers the remaining glucose units and hydrolyzes the -1,6 bond, releasing free glucose and allowing continued phosphorolysis.
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37Which activated sugar donor is used by glycogen synthase to add glucose units to a growing glycogen chain?
glycogen synthesis
Medium
A.ADP-glucose
B.UDP-glucose
C.Glucose-6-phosphate
D.Glucose-1-phosphate
Correct Answer: UDP-glucose
Explanation:
In animals, UDP-glucose, formed by UDP-glucose pyrophosphorylase, is the activated donor. Glycogen synthase transfers its glucose to the non-reducing end forming an -1,4 bond.
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38Which enzyme is responsible for creating the -1,6 branch points in glycogen?
glycogen synthesis
Medium
A.Glycogen synthase
B.Glycogenin
C.Branching enzyme
D.Phosphoglucomutase
Correct Answer: Branching enzyme
Explanation:
The branching enzyme (amylo-(1,4→1,6)-transglycosylase) transfers a block of about 6-7 glucose residues to form an -1,6 linkage, increasing solubility and the number of sites for rapid synthesis and breakdown.
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39How does insulin promote glycogen synthesis in response to high blood glucose?
glycogen synthesis
Medium
A.It stimulates glycogen phosphorylase
B.It activates a phosphatase that dephosphorylates glycogen synthase
C.It phosphorylates and activates glycogen synthase
D.It inhibits UDP-glucose pyrophosphorylase
Correct Answer: It activates a phosphatase that dephosphorylates glycogen synthase
Explanation:
Insulin activates protein phosphatase-1, which dephosphorylates glycogen synthase, converting it to its active form while simultaneously inactivating glycogen phosphorylase, favoring glycogen storage.
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40Complete oxidation of one glucose molecule via glycolysis, the citric acid cycle, and oxidative phosphorylation yields approximately how many ATP (modern estimate)?
ATP and electron carriers
Medium
A.Around 12 ATP
B.Around 20 ATP
C.Around 30-32 ATP
D.Around 45 ATP
Correct Answer: Around 30-32 ATP
Explanation:
Using the modern P/O ratios (2.5 ATP per , 1.5 per ), full oxidation of glucose yields approximately 30-32 ATP, lower than the older textbook value of 36-38.
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41The standard free energy of hydrolysis of ATP is kJ/mol. In a cell where mM, mM, and mM, the actual of hydrolysis (at 310 K, kJ/mol) is closest to which value?
ATP and electron carriers
Hard
A. kJ/mol
B. kJ/mol
C. kJ/mol
D. kJ/mol
Correct Answer: kJ/mol
Explanation:
. The mass-action ratio . kJ/mol. So , closest to kJ/mol. Cellular conditions make hydrolysis far more favorable than standard.
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42NADH and NADPH have nearly identical redox potentials, yet cells maintain a high ratio and a low ratio. What is the primary functional rationale?
ATP and electron carriers
Hard
A.NADPH has a more negative standard potential making it a stronger reductant intrinsically
B.The extra phosphate on NADPH prevents it from participating in electron transfer
C.NADPH pools are kept reduced to drive biosynthetic reductions, while NAD pools are kept oxidized to accept electrons in catabolism
D.NADH cannot be used in anabolism because it lacks the 2'-phosphate
Correct Answer: NADPH pools are kept reduced to drive biosynthetic reductions, while NAD pools are kept oxidized to accept electrons in catabolism
Explanation:
The 2'-phosphate is a recognition tag, not a redox modifier. By keeping NADPH highly reduced, the actual (non-standard) free-energy change favors donating electrons to biosynthesis; keeping NAD oxidized favors accepting electrons from catabolic oxidations. Compartmentalized ratios, not different standard potentials, drive the directionality.
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43In glycolysis, the reaction catalyzed by phosphoglycerate kinase and the reaction catalyzed by pyruvate kinase both produce ATP. Which statement correctly distinguishes them thermodynamically and mechanistically?
glycolysis
Hard
A.Both are substrate-level phosphorylations; PGK is near-equilibrium and reversible in vivo, whereas pyruvate kinase is highly exergonic and physiologically irreversible
B.Both are near-equilibrium; PGK is regulated allosterically while pyruvate kinase is not
C.PGK uses oxidative phosphorylation while pyruvate kinase uses substrate-level phosphorylation
D.Pyruvate kinase is reversible in vivo while PGK is the committed irreversible step
Correct Answer: Both are substrate-level phosphorylations; PGK is near-equilibrium and reversible in vivo, whereas pyruvate kinase is highly exergonic and physiologically irreversible
Explanation:
Both make ATP by substrate-level phosphorylation. PGK operates near equilibrium (used in reverse during gluconeogenesis). Pyruvate kinase has a large negative in vivo, is essentially irreversible, and is bypassed in gluconeogenesis by PEP carboxykinase and pyruvate carboxylase.
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44Arsenate () is a phosphate analog that can substitute for in the glyceraldehyde-3-phosphate dehydrogenase reaction. What is the net metabolic consequence when arsenate replaces phosphate at this step?
glycolysis
Hard
A.Glycolysis proceeds but net ATP yield from the payoff phase is lost because the 1-arseno intermediate spontaneously hydrolyzes
B.Glycolysis halts completely because GAPDH is inhibited
C.ATP yield doubles because arsenate is a stronger phosphoryl donor
D.Fructose-1,6-bisphosphate accumulates and blocks upstream enzymes
Correct Answer: Glycolysis proceeds but net ATP yield from the payoff phase is lost because the 1-arseno intermediate spontaneously hydrolyzes
Explanation:
Arsenate forms 1-arseno-3-phosphoglycerate instead of the high-energy 1,3-bisphosphoglycerate. This acyl-arsenate is unstable and hydrolyzes spontaneously to 3-phosphoglycerate, bypassing phosphoglycerate kinase. Carbon flux continues but the substrate-level ATP normally made by PGK is not captured — arsenate 'uncouples' this step.
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45The phosphofructokinase-1 (PFK-1) reaction is a key control point. Fructose-2,6-bisphosphate () strongly activates PFK-1. Which combination of hormonal signal and enzyme state raises in liver?
glycolysis
Hard
A.Insulin phosphorylates the enzyme via PKA, activating the phosphatase domain
B.Insulin signaling dephosphorylates PFK-2/FBPase-2, activating the kinase domain to raise
C.Glucagon signaling dephosphorylates the bifunctional enzyme, raising
D.Glucagon activates the kinase domain via PKA phosphorylation, raising
Correct Answer: Insulin signaling dephosphorylates PFK-2/FBPase-2, activating the kinase domain to raise
Explanation:
In liver, the bifunctional enzyme PFK-2/FBPase-2 is controlled by phosphorylation. Insulin (via phosphatase action) leads to dephosphorylation, which activates the kinase (PFK-2) domain and inactivates the phosphatase domain, raising and stimulating glycolysis. Glucagon/PKA does the opposite (phosphorylation lowers ).
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46During intense anaerobic exercise, lactate dehydrogenase regenerates . If this regeneration were blocked, glycolysis would stall specifically because:
fermentation
Hard
A.Pyruvate kinase would lack ADP as a substrate
B.GAPDH would run out of oxidized needed to oxidize glyceraldehyde-3-phosphate
C.Aldolase would be unable to cleave fructose-1,6-bisphosphate
D.Hexokinase would be inhibited by accumulating glucose-6-phosphate
Correct Answer: GAPDH would run out of oxidized needed to oxidize glyceraldehyde-3-phosphate
Explanation:
Glycolysis consumes at the GAPDH step. Without O or an electron shuttle, the only way to regenerate is fermentation (lactate or ethanol). Blocking LDH depletes cytosolic , so GAPDH cannot proceed and glycolytic flux halts even though glucose and ADP are available.
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47Ethanol fermentation in yeast converts pyruvate to ethanol in two steps. Which pair of enzymes and cofactor is required, and what is the redox bookkeeping per glucose?
fermentation
Hard
A.Pyruvate decarboxylase (TPP) then alcohol dehydrogenase; 2 NADH oxidized to 2 per glucose
B.Pyruvate carboxylase (biotin) then aldehyde reductase; net 4 NADH consumed per glucose
C.Lactate dehydrogenase then alcohol dehydrogenase; no net redox change per glucose
D.Pyruvate dehydrogenase (lipoamide) then alcohol dehydrogenase; 2 reduced per glucose
Correct Answer: Pyruvate decarboxylase (TPP) then alcohol dehydrogenase; 2 NADH oxidized to 2 per glucose
Explanation:
Pyruvate decarboxylase (thiamine pyrophosphate–dependent) converts pyruvate to acetaldehyde + CO. Alcohol dehydrogenase then reduces acetaldehyde to ethanol using NADH. Two NADH made in glycolysis are reoxidized to two , keeping glycolysis running with no net NADH accumulation.
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48Gluconeogenesis from pyruvate requires bypassing the pyruvate kinase step. This bypass uses two reactions consuming high-energy phosphates. What is the total nucleoside triphosphate cost of converting one pyruvate to one PEP?
gluconeogenesis
Hard
A.2 GTP (both by PEP carboxykinase)
B.2 ATP (both by pyruvate carboxylase)
C.1 ATP (pyruvate carboxylase) + 1 GTP (PEP carboxykinase)
Pyruvate carboxylase uses 1 ATP to make oxaloacetate (adding CO). PEP carboxykinase then uses 1 GTP to decarboxylate and phosphorylate OAA to PEP. So converting each pyruvate to PEP costs one ATP plus one GTP; per glucose (two pyruvates) this is 2 ATP + 2 GTP.
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49Why must oxaloacetate be shuttled out of the mitochondrion as malate (or aspartate) during gluconeogenesis in most tissues?
gluconeogenesis
Hard
A.Malate export generates the GTP needed by cytosolic PEPCK
B.OAA is toxic and must be detoxified as malate before leaving
C.Cytosolic PEP carboxykinase requires malate rather than OAA as substrate
D.The inner mitochondrial membrane lacks an OAA transporter, so OAA is reduced to malate for export and reoxidized in the cytosol
Correct Answer: The inner mitochondrial membrane lacks an OAA transporter, so OAA is reduced to malate for export and reoxidized in the cytosol
Explanation:
There is no direct OAA carrier in the inner mitochondrial membrane. When PEPCK is cytosolic, mitochondrial OAA is reduced to malate (by malate dehydrogenase), exported, and reoxidized to OAA in the cytosol. This also conveniently transfers reducing equivalents (NADH) needed for the later GAPDH-reverse step in cytosolic gluconeogenesis.
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50A patient with a deficiency in fructose-1,6-bisphosphatase presents with fasting hypoglycemia and lactic acidosis. Which explanation best accounts for the lactic acidosis?
gluconeogenesis
Hard
A.Loss of the enzyme increases pyruvate carboxylase flux, producing lactate
B.Excess fructose-1,6-bisphosphate is oxidized directly to lactate
C.Blocked gluconeogenesis causes accumulation of upstream three-carbon precursors that are converted to lactate
Correct Answer: Blocked gluconeogenesis causes accumulation of upstream three-carbon precursors that are converted to lactate
Explanation:
FBPase-1 catalyzes a key gluconeogenic bypass step. Its loss prevents conversion of gluconeogenic precursors (lactate, alanine, glycerol) into glucose. Precursors and pyruvate accumulate and are shunted toward lactate, causing lactic acidosis, while the block in glucose production causes fasting hypoglycemia.
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51A cell needs large amounts of NADPH but little ribose-5-phosphate. How does the pentose phosphate pathway accommodate this demand?
pentose phosphate pathway
Hard
A.Ribose-5-phosphate is recycled via transketolase and transaldolase back into fructose-6-phosphate and glyceraldehyde-3-phosphate, which re-enter the oxidative branch as glucose-6-phosphate
B.The non-oxidative branch produces additional NADPH to meet demand
C.The oxidative branch runs in reverse to consume ribose-5-phosphate
D.Ribose-5-phosphate is excreted from the cell to prevent accumulation
Correct Answer: Ribose-5-phosphate is recycled via transketolase and transaldolase back into fructose-6-phosphate and glyceraldehyde-3-phosphate, which re-enter the oxidative branch as glucose-6-phosphate
Explanation:
When NADPH demand exceeds ribose demand, the non-oxidative reactions (transketolase/transaldolase) interconvert pentose phosphates into F6P and G3P. Gluconeogenic reactions regenerate G6P, which re-enters the oxidative branch to make more NADPH. Net effect: G6P is fully oxidized to CO with maximal NADPH yield and no net ribose.
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52Transketolase transfers a two-carbon unit and requires a specific cofactor; transaldolase transfers a three-carbon unit and does not. Which cofactor does transketolase require, and what shared reaction feature explains why transaldolase needs no such cofactor?
pentose phosphate pathway
Hard
A.Transketolase needs TPP to stabilize the two-carbon carbanion; transaldolase uses a Schiff-base lysine so no coenzyme is required
B.Transketolase needs NADPH; transaldolase uses a covalent flavin
C.Transketolase needs lipoic acid; transaldolase uses a metal-bound hydride
Correct Answer: Transketolase needs TPP to stabilize the two-carbon carbanion; transaldolase uses a Schiff-base lysine so no coenzyme is required
Explanation:
Transketolase uses thiamine pyrophosphate to stabilize the carbanion (active aldehyde) formed during two-carbon transfer. Transaldolase forms a covalent Schiff base between an active-site lysine and the substrate carbonyl, stabilizing the three-carbon carbanion internally, so it requires no separate coenzyme.
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53Individuals with glucose-6-phosphate dehydrogenase (G6PD) deficiency are prone to hemolysis under oxidative stress. What is the mechanistic link between the enzyme defect and red cell lysis?
pentose phosphate pathway
Hard
A.The defect prevents glycolysis, starving the cell of energy
B.Reduced NADPH lowers reduced glutathione, so cells cannot neutralize peroxides, causing membrane and hemoglobin oxidative damage
C.The defect blocks ATP production so red cells lose ion homeostasis
D.Excess ribose-5-phosphate crystallizes and ruptures the membrane
Correct Answer: Reduced NADPH lowers reduced glutathione, so cells cannot neutralize peroxides, causing membrane and hemoglobin oxidative damage
Explanation:
G6PD catalyzes the first, rate-limiting oxidative step of the PPP, the main NADPH source in red cells. NADPH keeps glutathione reduced (via glutathione reductase). Without it, reactive oxygen species oxidize hemoglobin (Heinz bodies) and membrane lipids, leading to hemolysis, especially after oxidant drugs, infections, or fava beans.
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54Glycogen phosphorylase cleaves -1,4 bonds but stops four residues from an -1,6 branch point. The debranching enzyme resolves this using two activities. What are they, and what is the product distribution near the branch?
glycogen breakdown
Hard
A.A 4--glucanotransferase moves three residues to a nearby chain end, then an -1,6-glucosidase releases the branch residue as free glucose
B.A 1,6-glucosidase first cleaves the branch, then phosphorylase completes hydrolysis to glucose-1-phosphate
C.An amylase randomly hydrolyzes both 1,4 and 1,6 bonds to yield only glucose-6-phosphate
D.A transferase adds UDP-glucose to extend the branch before glucosidase cleavage
Correct Answer: A 4--glucanotransferase moves three residues to a nearby chain end, then an -1,6-glucosidase releases the branch residue as free glucose
Explanation:
The bifunctional debranching enzyme first transfers three of the four residues (transferase activity) to the end of another chain, extending it with -1,4 bonds. Then its -1,6-glucosidase activity hydrolyzes the single remaining branch residue, releasing free glucose (not glucose-1-phosphate). Phosphorylase then continues along the exposed chain.
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55Most glucose residues released from glycogen leave as glucose-1-phosphate, but a smaller fraction leaves as free glucose. Given a linear chain of many residues between branch points, roughly what fraction of released monomers is free glucose, and why?
glycogen breakdown
Hard
A.None, because all residues become glucose-1-phosphate
B.About 9 in 10, because phosphorylase mainly produces free glucose
C.About half, because phosphorylase and glucosidase alternate residue by residue
D.About 1 in 10 (the branch-point residues released by the debranching glucosidase), while the rest exit as glucose-1-phosphate via phosphorylase
Correct Answer: About 1 in 10 (the branch-point residues released by the debranching glucosidase), while the rest exit as glucose-1-phosphate via phosphorylase
Explanation:
Phosphorylase releases the many -1,4-linked residues as glucose-1-phosphate. Only the -1,6 branch-point residues are hydrolyzed to free glucose by the debranching enzyme. Since branch points occur roughly every ~10 residues, about 90% exits as glucose-1-phosphate and ~10% as free glucose.
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56Phosphorylase uses inorganic phosphate rather than water to cleave glycogen. What is the primary energetic advantage of this phosphorolysis over hydrolysis for the cell?
glycogen breakdown
Hard
A.It prevents glucose from leaving the cell by keeping it charged
B.The product glucose-1-phosphate is already phosphorylated, conserving the ATP that would be needed to phosphorylate free glucose
C.It directly generates ATP by substrate-level phosphorylation
D.Phosphorolysis releases more heat, warming the tissue during exercise
Correct Answer: The product glucose-1-phosphate is already phosphorylated, conserving the ATP that would be needed to phosphorylate free glucose
Explanation:
By using , phosphorylase produces glucose-1-phosphate, which is converted to glucose-6-phosphate (by phosphoglucomutase) and enters glycolysis without spending ATP at hexokinase. Hydrolysis would give free glucose, which would then require ATP to be phosphorylated. Phosphorolysis saves one ATP per residue mobilized within the cell.
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57Glycogen synthase adds glucose from UDP-glucose to a growing chain. Considering the cost of making UDP-glucose and regenerating UTP, what is the true ATP-equivalent cost of incorporating one glucose-6-phosphate into glycogen?
glycogen synthesis
Hard
A.3 ATP equivalents, because UDP-glucose formation consumes two UTP
B.1 ATP equivalent, only for the phosphoglucomutase step
C.2 ATP equivalents: one to form UDP-glucose (UTP + G1P, then PP hydrolysis) and one to regenerate UTP from UDP
D.0 ATP equivalents, because pyrophosphate hydrolysis fully pays the cost
Correct Answer: 2 ATP equivalents: one to form UDP-glucose (UTP + G1P, then PP hydrolysis) and one to regenerate UTP from UDP
Explanation:
UDP-glucose pyrophosphorylase joins UTP + glucose-1-phosphate, releasing PP; PP hydrolysis pulls this forward (one high-energy phosphate spent). After glycogen synthase transfers the glucosyl unit, UDP must be rephosphorylated to UTP by nucleoside diphosphate kinase using ATP (a second high-energy phosphate). Net cost ≈ 2 ATP equivalents per glucose added.
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58Glycogen synthase can only extend existing chains and needs a primer. Which molecule provides the initial primer, and what is its distinctive feature?
glycogen synthesis
Hard
A.Free glucose-1-phosphate, which spontaneously polymerizes
B.A short RNA primer synthesized by primase
C.Amylopectin, a plant polysaccharide imported into the cell
D.Glycogenin, a self-glucosylating protein that autocatalytically attaches the first glucose residues to a tyrosine
Correct Answer: Glycogenin, a self-glucosylating protein that autocatalytically attaches the first glucose residues to a tyrosine
Explanation:
Glycogenin primes glycogen synthesis by catalyzing its own glucosylation, attaching the first glucose to a specific tyrosine residue and extending a short -1,4 chain (about 8 residues). Glycogen synthase then elongates this primer. Glycogenin remains attached at the core of the mature glycogen granule.
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59Both glycogen synthase and glycogen phosphorylase are regulated by phosphorylation, but with opposite outcomes. Under high glucagon (liver, fasting), what are the activity states of the two enzymes and why is this coordinated?
glycogen synthesis
Hard
A.Phosphorylation activates synthase and inactivates phosphorylase, favoring storage
B.Phosphorylation inactivates both enzymes, halting all glycogen metabolism
C.Phosphorylation activates both enzymes, maximizing glycogen turnover
D.Phosphorylation activates phosphorylase and inactivates synthase, so glycogen is broken down and not simultaneously synthesized
Correct Answer: Phosphorylation activates phosphorylase and inactivates synthase, so glycogen is broken down and not simultaneously synthesized
Explanation:
PKA-driven phosphorylation (via glucagon/epinephrine) converts phosphorylase to its active 'a' form while inactivating glycogen synthase (synthase 'b'). This reciprocal control ensures glycogen is mobilized during fasting without a futile cycle of simultaneous synthesis and degradation. Insulin reverses both via dephosphorylation.
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60Muscle uses the malate-aspartate and glycerol-3-phosphate shuttles to move cytosolic NADH reducing equivalents into mitochondria. Why does the glycerol-3-phosphate shuttle yield less ATP per cytosolic NADH than the malate-aspartate shuttle?
ATP and electron carriers
Hard
A.It delivers electrons to FAD (making FADH/ubiquinol), entering the chain past Complex I, so fewer protons are pumped
B.It regenerates cytosolic NADH twice, doubling the electron cost
C.It consumes an extra ATP during transport, lowering net yield
D.It delivers electrons directly to oxygen, bypassing all pumping
Correct Answer: It delivers electrons to FAD (making FADH/ubiquinol), entering the chain past Complex I, so fewer protons are pumped
Explanation:
In the glycerol-3-phosphate shuttle, mitochondrial glycerol-3-phosphate dehydrogenase passes electrons to FAD, feeding ubiquinone and bypassing Complex I. Fewer protons are pumped, so ~1.5 ATP form per cytosolic NADH. The malate-aspartate shuttle regenerates mitochondrial NADH, which uses Complex I, yielding ~2.5 ATP.
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