1What is the primary molecule that stores genetic information in most living organisms?
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Lipid
B.Cellulose
C.DNA
D.Glucose
Correct Answer: DNA
Explanation:
DNA (deoxyribonucleic acid) is the molecule that stores hereditary information and directs the synthesis of proteins in most organisms.
Incorrect! Try again.
2The process of copying DNA into a complementary RNA molecule is called:
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Translation
B.Replication
C.Transcription
D.Digestion
Correct Answer: Transcription
Explanation:
Transcription is the synthesis of an RNA copy from a DNA template, carried out by RNA polymerase.
Incorrect! Try again.
3Which technique is widely used to amplify specific DNA sequences in the laboratory?
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Chromatography
B.PCR
C.Gram staining
D.ELISA
Correct Answer: PCR
Explanation:
The Polymerase Chain Reaction (PCR) amplifies specific DNA segments exponentially, making it a core tool in molecular biology research.
Incorrect! Try again.
4In the DNA double helix, adenine (A) pairs with which base?
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Uracil
B.Thymine
C.Cytosine
D.Guanine
Correct Answer: Thymine
Explanation:
In DNA, adenine forms two hydrogen bonds with thymine, while guanine pairs with cytosine.
Incorrect! Try again.
5The CRISPR-Cas9 system is primarily used for:
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.pH measurement
B.Genome editing
C.Cell counting
D.Protein staining
Correct Answer: Genome editing
Explanation:
CRISPR-Cas9 is a genome-editing tool that allows precise, targeted modification of DNA sequences.
Incorrect! Try again.
6Which sugar is found in RNA but not in DNA?
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Deoxyribose
B.Glucose
C.Fructose
D.Ribose
Correct Answer: Ribose
Explanation:
RNA contains ribose sugar, whereas DNA contains deoxyribose, which lacks one oxygen atom.
Incorrect! Try again.
7The complete set of genes in an organism is known as its:
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Cytoplasm
B.Ribosome
C.Proteome
D.Genome
Correct Answer: Genome
Explanation:
The genome is the entire set of genetic material (DNA) present in an organism.
Incorrect! Try again.
8Translation is the process by which:
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.DNA is copied into DNA
B.Proteins are broken down
C.RNA is copied into DNA
D.mRNA is decoded to build a protein
Correct Answer: mRNA is decoded to build a protein
Explanation:
During translation, ribosomes read the mRNA sequence and assemble amino acids into a protein.
Incorrect! Try again.
9Which enzyme is responsible for synthesizing new DNA strands during replication?
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Amylase
B.RNA polymerase
C.DNA polymerase
D.Ligase only
Correct Answer: DNA polymerase
Explanation:
DNA polymerase adds nucleotides to a growing DNA strand, synthesizing the new complementary strand during replication.
Incorrect! Try again.
10Gel electrophoresis separates DNA fragments primarily based on their:
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Size
B.Taste
C.Color
D.Temperature
Correct Answer: Size
Explanation:
Gel electrophoresis separates DNA fragments by size, as smaller fragments migrate faster through the gel.
Incorrect! Try again.
11A change in the DNA sequence of a gene is called a:
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Transcription
B.Mutation
C.Translation
D.Digestion
Correct Answer: Mutation
Explanation:
A mutation is any alteration in the nucleotide sequence of DNA, which may affect gene function.
Incorrect! Try again.
12Which base found in RNA replaces thymine of DNA?
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Guanine
B.Adenine
C.Uracil
D.Cytosine
Correct Answer: Uracil
Explanation:
In RNA, uracil takes the place of thymine and pairs with adenine.
Incorrect! Try again.
13The 'central dogma' of molecular biology describes the flow of information from:
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Protein to RNA to DNA
B.Protein to DNA to RNA
C.DNA to RNA to Protein
D.RNA to DNA to Protein
Correct Answer: DNA to RNA to Protein
Explanation:
The central dogma states that genetic information flows from DNA to RNA (transcription) and then to protein (translation).
Incorrect! Try again.
14Restriction enzymes are used in molecular biology to:
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Stain cells
B.Measure pH
C.Join amino acids
D.Cut DNA at specific sequences
Correct Answer: Cut DNA at specific sequences
Explanation:
Restriction enzymes recognize specific DNA sequences and cut the DNA, which is essential for cloning and recombinant DNA technology.
Incorrect! Try again.
15A gene is best defined as a:
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Segment of DNA that codes for a product
B.Kind of sugar
C.Type of protein
D.Cell organelle
Correct Answer: Segment of DNA that codes for a product
Explanation:
A gene is a unit of DNA that carries the information for making a functional product, usually a protein or RNA.
Incorrect! Try again.
16Which technology allows scientists to insert a gene from one organism into another?
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Centrifugation
B.Filtration
C.Recombinant DNA technology
D.Distillation
Correct Answer: Recombinant DNA technology
Explanation:
Recombinant DNA technology combines DNA from different sources, enabling the transfer of genes between organisms.
Incorrect! Try again.
17The set of three nucleotides that codes for a specific amino acid is called a:
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Gene
B.Chromosome
C.Codon
D.Ribosome
Correct Answer: Codon
Explanation:
A codon is a triplet of nucleotides in mRNA that specifies a particular amino acid during translation.
Incorrect! Try again.
18Sequencing of the entire human genome was completed under which major project?
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Genome Recycling Project
B.Human Genome Project
C.Apollo Project
D.Manhattan Project
Correct Answer: Human Genome Project
Explanation:
The Human Genome Project mapped and sequenced all the genes of the human genome, a landmark achievement in genetics.
Incorrect! Try again.
19Which structure carries genes and is composed of DNA and protein?
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Vacuole
B.Lysosome
C.Ribosome
D.Chromosome
Correct Answer: Chromosome
Explanation:
Chromosomes are structures made of tightly coiled DNA wrapped around proteins, carrying an organism's genes.
Incorrect! Try again.
20The study of how gene expression changes without altering the DNA sequence is called:
Discussion on thrust research area- Molecular Biology and Genetics
Easy
A.Taxonomy
B.Epigenetics
C.Anatomy
D.Ecology
Correct Answer: Epigenetics
Explanation:
Epigenetics examines heritable changes in gene expression, such as DNA methylation, that occur without changing the underlying DNA sequence.
Incorrect! Try again.
21A researcher wants to selectively amplify a specific 500 bp region from genomic DNA before sequencing. Which technique is most appropriate as the first step?
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Isoelectric focusing
B.Gel filtration chromatography
C.Southern blotting
D.Polymerase Chain Reaction (PCR)
Correct Answer: Polymerase Chain Reaction (PCR)
Explanation:
PCR uses sequence-specific primers to exponentially amplify a defined target region, making it the standard first step before downstream sequencing.
Incorrect! Try again.
22In CRISPR-Cas9 genome editing, the guide RNA primarily functions to:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Ligate the cleaved DNA ends together
B.Synthesize the new complementary strand
C.Direct Cas9 to the complementary target DNA sequence
D.Add methyl groups to cytosine bases
Correct Answer: Direct Cas9 to the complementary target DNA sequence
Explanation:
The guide RNA base-pairs with the target DNA, positioning the Cas9 nuclease to introduce a double-strand break at the correct locus.
Incorrect! Try again.
23A gene of interest shows high mRNA levels but very low protein output in a cell. Which mechanism most likely explains this observation?
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Increased transcription initiation
B.Enhanced DNA replication
C.Loss of the promoter region
D.Translational repression by microRNAs
Correct Answer: Translational repression by microRNAs
Explanation:
microRNAs bind mRNA and block translation or promote degradation, reducing protein output despite abundant transcript.
Incorrect! Try again.
24During a study, a scientist observes that a restriction enzyme cuts a plasmid at a single site, linearizing it. What can be inferred about the recognition sequence?
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.It is absent from the plasmid
B.It is methylated at all sites
C.It occurs at every base pair
D.It occurs only once in the plasmid
Correct Answer: It occurs only once in the plasmid
Explanation:
A single cut producing a linear fragment indicates the enzyme's recognition sequence is present exactly once in the circular plasmid.
Incorrect! Try again.
25In quantitative real-time PCR (qPCR), a lower cycle threshold () value indicates:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.A lower initial amount of target template
B.A higher initial amount of target template
C.Presence of primer dimers only
D.Failure of the amplification reaction
Correct Answer: A higher initial amount of target template
Explanation:
More starting template crosses the detection threshold in fewer cycles, so a lower corresponds to higher initial abundance.
Incorrect! Try again.
26A transgenic plant is engineered to express a bacterial gene. For the gene to be expressed correctly, the construct must include a:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Prokaryotic origin of replication only
B.Restriction site at every codon
C.Bacterial ribosome binding site only
D.Eukaryotic promoter recognized by the host
Correct Answer: Eukaryotic promoter recognized by the host
Explanation:
Expression in a plant requires a promoter the plant's transcription machinery can recognize; bacterial regulatory elements alone are insufficient.
Incorrect! Try again.
27RNA interference (RNAi) is being used to knock down a target gene. The functional molecule that guides degradation of the target mRNA is:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.A histone protein complex
B.A double-stranded DNA probe
C.A ribosomal subunit
D.A small interfering RNA (siRNA) loaded into RISC
Correct Answer: A small interfering RNA (siRNA) loaded into RISC
Explanation:
siRNA is incorporated into the RISC complex, where it directs sequence-specific cleavage of the complementary mRNA.
Incorrect! Try again.
28A DNA sample analyzed by gel electrophoresis migrates faster than a known 1 kb marker. This suggests the sample fragment is:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Smaller than 1 kb
B.Exactly 1 kb
C.Circular and supercoiled only
D.Larger than 1 kb
Correct Answer: Smaller than 1 kb
Explanation:
In agarose gel electrophoresis smaller fragments migrate faster, so a band running ahead of the 1 kb marker is smaller than 1 kb.
Incorrect! Try again.
29A point mutation changes a codon from UAC to UAA. What is the most likely consequence for the protein?
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Frameshift of the reading frame
B.A silent change with no effect
C.Addition of an extra amino acid
D.Premature termination of translation
Correct Answer: Premature termination of translation
Explanation:
UAA is a stop codon, so this nonsense mutation halts translation early, producing a truncated protein.
Incorrect! Try again.
30In a Western blot experiment, the antibodies are used to detect:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Specific proteins
B.Whole intact cells
C.Specific DNA sequences
D.Specific RNA transcripts
Correct Answer: Specific proteins
Explanation:
Western blotting separates proteins by size and detects a target protein using specific primary and secondary antibodies.
Incorrect! Try again.
31A researcher observes that a gene is silenced without any change in its DNA sequence, and silencing is heritable across cell divisions. This is best explained by:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.A frameshift deletion in the coding region
B.Epigenetic modification such as DNA methylation
C.Loss of the entire chromosome
D.A nonsense mutation in the promoter
Correct Answer: Epigenetic modification such as DNA methylation
Explanation:
Heritable gene silencing without sequence change is a hallmark of epigenetic mechanisms like promoter DNA methylation and histone modification.
Incorrect! Try again.
32Next-generation sequencing (NGS) offers a major advantage over Sanger sequencing primarily because it enables:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Amplification without primers
B.Reading only one fragment at a time
C.Detection of proteins directly
D.Massively parallel sequencing of many fragments
Correct Answer: Massively parallel sequencing of many fragments
Explanation:
NGS sequences millions of fragments simultaneously, giving far higher throughput than the single-read Sanger method.
Incorrect! Try again.
33A cloning vector must contain a selectable marker so that researchers can:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Translate the insert into protein
B.Cut the insert DNA precisely
C.Identify cells that took up the vector
D.Increase the vector's copy number
Correct Answer: Identify cells that took up the vector
Explanation:
A selectable marker (e.g., antibiotic resistance) allows only transformed cells to survive selection, identifying successful uptake.
Incorrect! Try again.
34In a diploid organism, an autosomal recessive disease allele has frequency . Under Hardy-Weinberg equilibrium, the expected frequency of affected individuals is:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Affected individuals are homozygous recessive, with frequency .
Incorrect! Try again.
35A reverse transcriptase enzyme is essential in cDNA synthesis because it:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Adds a poly-A tail to mRNA
B.Synthesizes RNA from a DNA template
C.Synthesizes DNA from an RNA template
D.Degrades single-stranded DNA
Correct Answer: Synthesizes DNA from an RNA template
Explanation:
Reverse transcriptase reads an RNA template and produces complementary DNA, the basis for making cDNA libraries.
Incorrect! Try again.
36A microarray experiment shows a set of genes strongly upregulated after drug treatment. The most direct interpretation is that the drug increased:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.The cell membrane permeability only
B.mRNA levels of those genes
C.The DNA copy number of the genome
D.Protein degradation of those genes
Correct Answer: mRNA levels of those genes
Explanation:
Microarrays measure transcript abundance, so upregulated signals indicate increased mRNA levels for those genes.
Incorrect! Try again.
37Two genes located close together on the same chromosome tend to be inherited together. This phenomenon is called:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Independent assortment
B.Genetic linkage
C.Genetic drift
D.Random mutation
Correct Answer: Genetic linkage
Explanation:
Genes physically close on a chromosome are linked and co-inherited more often than expected by independent assortment.
Incorrect! Try again.
38A researcher uses a GFP reporter fused to a promoter to study gene expression. Fluorescence intensity in the cells serves as a measure of:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Ribosome number
B.Cell membrane integrity
C.DNA replication rate
D.Promoter activity
Correct Answer: Promoter activity
Explanation:
When GFP is placed under a promoter, fluorescence reflects transcriptional activity driven by that promoter.
Incorrect! Try again.
39During DNA replication, the leading and lagging strands differ because DNA polymerase can only synthesize DNA in the:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Direction set by RNA polymerase
B.Both directions equally
C. direction
D. direction
Correct Answer: direction
Explanation:
DNA polymerase adds nucleotides only to the 3' end, so synthesis proceeds , requiring discontinuous synthesis on the lagging strand.
Incorrect! Try again.
40A knockout mouse is generated to study a gene's function. The expected outcome of a successful knockout is:
Discussion on thrust research area- Molecular Biology and Genetics
Medium
A.Overexpression of the targeted gene
B.Random silencing of all genes
C.Loss of function of the targeted gene
D.Duplication of the targeted gene
Correct Answer: Loss of function of the targeted gene
Explanation:
A gene knockout disrupts or removes the target gene, eliminating its function so researchers can study the resulting phenotype.
Incorrect! Try again.
41In a CRISPR-Cas9 experiment, a researcher observes high off-target cleavage. Switching to a high-fidelity Cas9 variant (e.g., HiFi-Cas9) reduces off-targets but also lowers on-target efficiency. Which mechanistic explanation best accounts for this trade-off?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.High-fidelity variants increase gRNA degradation, reducing all cleavage uniformly
B.High-fidelity variants weaken non-specific DNA contacts, raising the energetic threshold for stable R-loop formation at both mismatched and perfectly matched sites
D.High-fidelity variants convert Cas9 into a nickase, halving cleavage everywhere
Correct Answer: High-fidelity variants weaken non-specific DNA contacts, raising the energetic threshold for stable R-loop formation at both mismatched and perfectly matched sites
Explanation:
Engineered high-fidelity Cas9 variants attenuate non-specific protein–DNA interactions. This proofreading raises the threshold for stable R-loop formation, suppressing mismatched off-targets but slightly penalizing bona fide on-target activity.
Incorrect! Try again.
42A gene with two alleles shows allele frequencies and . Under Hardy–Weinberg equilibrium, a researcher finds the observed heterozygote frequency is instead of the expected value. What is the fixation index ?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Expected . , indicating a heterozygote deficit.
Incorrect! Try again.
43During RNA-seq analysis, a lncRNA shows strong nuclear enrichment and physically associates with chromatin-modifying complexes. Which functional hypothesis is most strongly supported by these data alone?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.It serves mainly as a template for reverse transcription
B.It acts as a scaffold guiding epigenetic modifiers to specific genomic loci
C.It is translated into a small regulatory peptide
D.It functions primarily as a miRNA sponge in the cytoplasm
Correct Answer: It acts as a scaffold guiding epigenetic modifiers to specific genomic loci
Explanation:
Nuclear enrichment plus association with chromatin-modifying complexes points to a scaffolding/guide role in epigenetic regulation. miRNA sponging is cytoplasmic and would not explain chromatin association.
Incorrect! Try again.
44A qPCR experiment yields a standard curve with slope . What is the approximate amplification efficiency, and what does it indicate?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.; sub-optimal efficiency, possibly due to inhibitors or primer issues
B.; ideal doubling each cycle
C.; over-amplification artifact
D.; failed reaction requiring redesign
Correct Answer: ; sub-optimal efficiency, possibly due to inhibitors or primer issues
Explanation:
Efficiency , i.e. ~90%. A slope of corresponds to 100%; indicates slightly reduced efficiency.
Incorrect! Try again.
45A two-point cross gives a recombination frequency of 12% between loci A and B, and 8% between B and C. A three-point cross between A and C gives 18%. What does this discrepancy most likely indicate?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.The loci are on different chromosomes
B.Recombination frequency exceeds 50% between A and C
C.Double crossovers between A and C are undetected in the direct A–C measurement
D.Gene C is a transposable element
Correct Answer: Double crossovers between A and C are undetected in the direct A–C measurement
Explanation:
The sum (12% + 8% = 20%) exceeds the observed A–C distance (18%) because double crossovers cancel out and are scored as parental, underestimating the direct distance. Additive map distances are more accurate.
Incorrect! Try again.
46In next-generation sequencing, a variant appears at 3% allele frequency in a tumor sample with 500x coverage. Why might this be a challenging call even at high depth?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.Sequencing error rates can approach the variant frequency, requiring error models to distinguish true low-frequency somatic variants
C.High coverage always guarantees accurate low-frequency calls
D.The variant must be a germline polymorphism
Correct Answer: Sequencing error rates can approach the variant frequency, requiring error models to distinguish true low-frequency somatic variants
Explanation:
Per-base sequencing/PCR error rates (often ~0.1–1%) can generate false positives near 3%. Distinguishing true subclonal somatic variants requires background error modeling, UMIs, or duplex sequencing.
Incorrect! Try again.
47A protein-coding gene undergoes alternative splicing producing an isoform lacking exon 5, which contains a stop codon in the retained transcript. The full-length mRNA is degraded, while the skipped isoform is stable. This regulation is best described as:
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.RNA editing introducing a premature stop codon
B.Post-translational proteasomal degradation of the isoform
C.Simple transcriptional repression of the gene
D.Alternative splicing coupled to nonsense-mediated decay (AS-NMD) controlling protein output
Correct Answer: Alternative splicing coupled to nonsense-mediated decay (AS-NMD) controlling protein output
Explanation:
When splicing generates a premature termination codon (here in the exon-5-retaining transcript), NMD degrades it. AS-NMD is a widespread mechanism tuning functional protein levels.
Incorrect! Try again.
48A researcher performs ChIP-seq for a transcription factor and finds strong binding peaks in regions lacking the canonical motif. Which explanation is most plausible?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.Indirect recruitment via protein–protein interactions tethering the factor to DNA
B.The antibody has zero cross-reactivity, so peaks are false
C.Transcription factors never bind without motifs
D.The peaks represent sequencing adapter contamination only
Correct Answer: Indirect recruitment via protein–protein interactions tethering the factor to DNA
Explanation:
TFs can be recruited indirectly through partner proteins (tethering), producing peaks without direct motif contact. Co-motif analysis of partner factors often reveals such indirect binding.
Incorrect! Try again.
49In a bisulfite sequencing experiment, a CpG island shows near-complete conversion of cytosines to uracil except at specific sites. What do the unconverted cytosines indicate?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.The bisulfite reaction failed entirely
B.Those positions contain thymine, not cytosine
C.Those cytosines are 5-methylated, protecting them from bisulfite conversion
D.Those cytosines are unmethylated and freely converted
Correct Answer: Those cytosines are 5-methylated, protecting them from bisulfite conversion
Explanation:
Bisulfite converts unmethylated cytosine to uracil, but 5-methylcytosine resists conversion. Unconverted (retained) cytosines therefore mark methylated CpG sites.
Incorrect! Try again.
50A quantitative trait shows broad-sense heritability but narrow-sense heritability . What does this gap most directly imply for a selective breeding program?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.The trait is entirely environmentally determined
B.Much of the genetic variance is non-additive (dominance/epistasis), limiting response to selection
C.The trait has no genetic basis
D.Selection will produce rapid, predictable gains
Correct Answer: Much of the genetic variance is non-additive (dominance/epistasis), limiting response to selection
Explanation:
captures additive variance driving selection response, while includes all genetic variance. The large gap means dominance/epistatic variance dominates, so mass selection yields limited gains.
Incorrect! Try again.
51A GWAS identifies a significant SNP in an intergenic region far from any gene. Which follow-up interpretation is most scientifically sound?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.Intergenic SNPs cannot influence phenotype
B.The SNP is definitely the causal mutation altering protein sequence
C.The SNP may tag a regulatory element or be in linkage disequilibrium with the causal variant
D.The association must be a statistical artifact since it is intergenic
Correct Answer: The SNP may tag a regulatory element or be in linkage disequilibrium with the causal variant
Explanation:
GWAS tag SNPs are often proxies via LD, and intergenic regions can harbor enhancers/regulatory elements. Fine-mapping and functional assays are needed to identify the causal variant.
Incorrect! Try again.
52During cloning, a researcher fails to obtain recombinant colonies despite successful ligation. The vector self-ligates efficiently. Which strategy most directly reduces vector self-ligation?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.Extending the ligation incubation time
B.Using a lower insert-to-vector ratio
C.Increasing the ligase concentration tenfold
D.Dephosphorylation of the linearized vector 5' ends with alkaline phosphatase
Correct Answer: Dephosphorylation of the linearized vector 5' ends with alkaline phosphatase
Explanation:
Removing 5' phosphates from the vector prevents self-ligation because ligase requires a 5'-phosphate. The insert supplies the phosphates, favoring recombinant formation.
Incorrect! Try again.
53A single-cell RNA-seq dataset shows a cluster of cells with high mitochondrial gene content and low total counts. What is the most appropriate interpretation before downstream analysis?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.These likely represent stressed or dying cells and should be filtered as quality-control artifacts
B.These are a novel high-metabolism cell type to prioritize
C.These cells have the highest data quality
D.Mitochondrial content is irrelevant to scRNA-seq QC
Correct Answer: These likely represent stressed or dying cells and should be filtered as quality-control artifacts
Explanation:
High mitochondrial fraction with low total counts is a hallmark of dying/lysed cells where cytoplasmic mRNA leaked out. Standard QC removes such cells before clustering.
Incorrect! Try again.
54A knockout mouse for a gene shows no phenotype, yet the gene is highly conserved across vertebrates. Which explanation best reconciles conservation with the absence of a phenotype?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.The knockout was incomplete in all tissues by definition
B.Conserved genes never produce visible phenotypes
C.Functional redundancy from paralogs may compensate under standard laboratory conditions
D.Conservation is meaningless for function
Correct Answer: Functional redundancy from paralogs may compensate under standard laboratory conditions
Explanation:
Genetic redundancy or robustness can mask phenotypes under benign lab conditions. Conserved genes may show phenotypes only under stress or when paralogs are also removed.
Incorrect! Try again.
55In a codon optimization strategy for heterologous protein expression, replacing rare codons with frequent ones sometimes reduces protein solubility. What is the most likely mechanistic cause?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.Rare codons increase mRNA stability tenfold
B.Faster translation can disrupt co-translational folding rhythms encoded by rare-codon-induced pausing
C.Codon changes always alter the amino acid sequence
D.Frequent codons introduce premature stop codons
Correct Answer: Faster translation can disrupt co-translational folding rhythms encoded by rare-codon-induced pausing
Explanation:
Translational pausing at rare codons can be functionally important for proper co-translational domain folding. Eliminating these pauses may cause misfolding and aggregation despite higher expression.
Incorrect! Try again.
56A researcher uses RNAi and observes off-target phenotypes. Which property of the siRNA most commonly drives these off-target effects?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.The siRNA being double-stranded
B.Perfect full-length complementarity to the intended target only
siRNAs can act like miRNAs, silencing transcripts via short seed-region matches in 3' UTRs. This is the dominant source of RNAi off-target effects.
Incorrect! Try again.
57A mutation in a splice donor site (GT) at an intron boundary is identified. Which outcome is LEAST likely to result from this mutation?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.Introduction of a synonymous change with no effect on the mRNA
B.Activation of a cryptic splice site nearby
C.Exon skipping of the adjacent exon
D.Intron retention in the mature transcript
Correct Answer: Introduction of a synonymous change with no effect on the mRNA
Explanation:
Disrupting a canonical GT splice donor typically causes intron retention, cryptic site use, or exon skipping. A 'silent, no-effect' outcome is least likely because splicing itself is disrupted.
Incorrect! Try again.
58In differential expression analysis with limited replicates, why do methods like DESeq2 model counts with a negative binomial rather than a Poisson distribution?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.The negative binomial accommodates overdispersion where variance exceeds the mean in RNA-seq counts
B.RNA-seq counts always have variance equal to the mean
C.The Poisson distribution cannot handle integer counts
D.The negative binomial requires no dispersion estimation
Correct Answer: The negative binomial accommodates overdispersion where variance exceeds the mean in RNA-seq counts
Explanation:
RNA-seq counts show biological variability making variance exceed the mean (overdispersion). The Poisson assumes variance = mean; the negative binomial adds a dispersion parameter to model this.
Incorrect! Try again.
59A base editor (cytosine base editor) is used to install a C→T edit but produces unexpected edits at nearby cytosines within the target window. What is the primary cause?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.The base editor reverts edits during replication
B.The gRNA anneals to multiple genomic sites simultaneously
C.The Cas9 nuclease cuts both strands randomly
D.The deaminase acts on all accessible cytosines within the single-stranded R-loop editing window (bystander editing)
Correct Answer: The deaminase acts on all accessible cytosines within the single-stranded R-loop editing window (bystander editing)
Explanation:
Cytosine deaminases edit multiple cytosines exposed in the single-stranded window created by Cas9. This bystander editing is a key limitation, addressed by narrowing the window or engineering deaminase specificity.
Incorrect! Try again.
60A pedigree shows a trait transmitted only through mothers to all offspring, with variable severity among siblings. Which inheritance pattern and phenomenon best explain this?
Discussion on thrust research area- Molecular Biology and Genetics
Hard
A.Genomic imprinting of a paternal allele
B.Mitochondrial inheritance with heteroplasmy causing variable expressivity
C.X-linked recessive inheritance
D.Autosomal dominant with complete penetrance
Correct Answer: Mitochondrial inheritance with heteroplasmy causing variable expressivity
Explanation:
Maternal-only transmission to all offspring indicates mitochondrial inheritance. Variable severity reflects heteroplasmy—differing proportions of mutant mtDNA segregating among cells and individuals.
Incorrect! Try again.
Did this save you a night before the exam?
LPU Notes is free, and it stays free. Ads cover part of the server bill.
The rest comes out of a student's own pocket: the domain, the storage,
and keeping the site up through the weeks everyone needs it at once.
The payment button didn't load. An ad blocker or a filtered network is the usual reason.
to try again.
Nothing here is ever locked, and nothing unlocks. Chip in only if it was worth it.
What it pays for →