1What does total viable count measure in an organic manure sample?
Study of the microbial status (total viable count) of organic manures
Easy
A.Mineral particles present in the manure
B.Dead microorganisms visible under a microscope
C.Living microorganisms able to form colonies
D.Water molecules present in the manure
Correct Answer: Living microorganisms able to form colonies
Explanation:
Total viable count estimates the living microorganisms that can grow and form visible colonies under the selected culture conditions.
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2Which unit is commonly used to report the total viable count of solid organic manure?
Study of the microbial status (total viable count) of organic manures
Easy
A.Metres per second
B.CFU per gram
C.Moles per litre
D.Milligrams per litre
Correct Answer: CFU per gram
Explanation:
The microbial count in solid manure is commonly expressed as colony-forming units per gram, written as CFU/g.
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3What does the abbreviation CFU stand for?
Study of the microbial status (total viable count) of organic manures
Easy
A.Culture-filtering unit
B.Cell-fertilizing unit
C.Colony-forming unit
D.Colony-fixing unit
Correct Answer: Colony-forming unit
Explanation:
CFU means colony-forming unit and represents a viable cell or group of cells capable of producing a colony.
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4Why is serial dilution performed before plating a manure sample?
Study of the microbial status (total viable count) of organic manures
Easy
A.To obtain countable colonies
B.To increase manure moisture
C.To sterilize the sample
D.To remove all nutrients
Correct Answer: To obtain countable colonies
Explanation:
Serial dilution lowers the concentration of microorganisms so that separate, countable colonies can develop on the plate.
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5Which laboratory item is commonly used to prepare a tenfold serial dilution?
Study of the microbial status (total viable count) of organic manures
Easy
A.Dry weighing papers
B.Chemical indicator strips
C.Glass microscope slides
D.Sterile dilution blanks
Correct Answer: Sterile dilution blanks
Explanation:
Sterile dilution blanks contain a known volume of diluent and are used to prepare successive dilutions without adding contaminating microorganisms.
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6Which medium is commonly used for a general viable bacterial count?
Study of the microbial status (total viable count) of organic manures
Easy
A.Water agar
B.Silica gel
C.Starch gel
D.Nutrient agar
Correct Answer: Nutrient agar
Explanation:
Nutrient agar is a general-purpose medium that supports the growth of many non-fastidious bacteria.
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7What is the main purpose of incubating an inoculated agar plate?
Study of the microbial status (total viable count) of organic manures
Easy
A.To allow microbial colonies to grow
B.To change the colour of the manure
C.To remove moisture from the medium
D.To measure the manure particle size
Correct Answer: To allow microbial colonies to grow
Explanation:
Incubation provides suitable conditions for viable microorganisms to multiply and form visible colonies.
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8Why should sterile equipment be used during total viable count testing?
Study of the microbial status (total viable count) of organic manures
Easy
A.To increase the dilution factor
B.To raise the sample temperature
C.To prevent external contamination
D.To enlarge microbial colonies
Correct Answer: To prevent external contamination
Explanation:
Sterile equipment prevents unwanted microorganisms from entering the sample and affecting the measured count.
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9Which action helps distribute microorganisms evenly before transferring a diluted sample?
Study of the microbial status (total viable count) of organic manures
Easy
A.Mixing the dilution thoroughly
B.Freezing the tube completely
C.Heating the tube strongly
D.Leaving the tube undisturbed
Correct Answer: Mixing the dilution thoroughly
Explanation:
Thorough mixing produces a more uniform suspension and improves the accuracy of subsequent transfers.
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10What is a visible spot of microbial growth on solid agar called?
Study of the microbial status (total viable count) of organic manures
Easy
A.A pellet
B.A colony
C.A droplet
D.A crystal
Correct Answer: A colony
Explanation:
A visible mass of microorganisms growing on solid medium is called a colony.
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11Which plate is most suitable for estimating a total viable count?
Study of the microbial status (total viable count) of organic manures
Easy
A.A plate completely covered by growth
B.A plate with separate countable colonies
C.A plate with cracked agar only
D.A plate showing no inoculated sample
Correct Answer: A plate with separate countable colonies
Explanation:
A plate with distinct, countable colonies gives a more reliable estimate than one with overcrowded or confluent growth.
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12What does confluent growth on an agar plate mean?
Study of the microbial status (total viable count) of organic manures
Easy
A.Colonies have merged into continuous growth
B.Colonies have changed into mineral crystals
C.Colonies occur only beneath the plate
D.Colonies are absent from the agar surface
Correct Answer: Colonies have merged into continuous growth
Explanation:
Confluent growth occurs when colonies are so numerous that they merge, making accurate counting difficult.
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13What is the purpose of an uninoculated control plate?
Study of the microbial status (total viable count) of organic manures
Easy
A.To calculate the manure moisture content
B.To determine the manure particle size
C.To increase the number of colonies
D.To check the medium for contamination
Correct Answer: To check the medium for contamination
Explanation:
An uninoculated control should remain free of growth, confirming that the medium and handling were not contaminated.
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14Which instrument is commonly used to transfer a measured liquid volume during dilution?
Study of the microbial status (total viable count) of organic manures
Easy
A.A metal spatula
B.A pH indicator strip
C.A glass thermometer
D.A sterile pipette
Correct Answer: A sterile pipette
Explanation:
A sterile pipette transfers an accurately measured volume while reducing the risk of contamination.
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15A sample is diluted by mixing 1 mL with 9 mL of sterile diluent. What is the resulting dilution?
Study of the microbial status (total viable count) of organic manures
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
The sample forms 1 mL of a total 10 mL volume, giving a dilution of .
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16Which factor is needed when calculating CFU/g from a diluted manure sample?
Study of the microbial status (total viable count) of organic manures
Easy
A.The plate diameter
B.The colony colour
C.The dilution factor
D.The agar colour
Correct Answer: The dilution factor
Explanation:
The dilution factor is used to convert the colonies counted on the diluted plate back to the estimated count in the original sample.
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17If 50 colonies grow from 1 mL of a dilution, what is the estimated count in the original sample?
Study of the microbial status (total viable count) of organic manures
Easy
A. CFU/mL
B. CFU/mL
C. CFU/mL
D. CFU/mL
Correct Answer: CFU/mL
Explanation:
The count is CFU/mL because 1 mL was plated.
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18Why are replicate plates used in total viable count testing?
Study of the microbial status (total viable count) of organic manures
Easy
A.To improve the reliability of the result
B.To sterilize the original manure sample
C.To make every colony the same size
D.To eliminate the need for incubation
Correct Answer: To improve the reliability of the result
Explanation:
Replicate plates help account for normal variation and allow a more reliable average count to be calculated.
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19Why may total viable count underestimate the total number of microorganisms in manure?
Study of the microbial status (total viable count) of organic manures
Easy
A.Agar converts mineral particles into living cells
B.Some living microbes may not grow on the chosen medium
C.Dilution causes microorganisms to multiply immediately
D.Every dead microbe forms several visible colonies
Correct Answer: Some living microbes may not grow on the chosen medium
Explanation:
Only microorganisms able to grow under the selected medium and incubation conditions are detected by the viable count method.
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20What does a higher CFU/g value generally indicate in an organic manure sample?
Study of the microbial status (total viable count) of organic manures
Easy
A.A larger viable microbial population
B.A smaller quantity of moisture
C.A lower amount of organic matter
D.A greater concentration of minerals
Correct Answer: A larger viable microbial population
Explanation:
A higher CFU/g value indicates that more viable, colony-forming microorganisms are present per gram of manure.
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21A technician plates mL of a dilution of an organic manure suspension and counts 84 colonies. What is the total viable count of the manure?
Study of the microbial status (total viable count) of organic manures
Medium
A. CFU/g
B. CFU/g
C. CFU/g
D. CFU/g
Correct Answer: CFU/g
Explanation:
TVC is calculated as CFU/g.
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22Duplicate plates inoculated with mL of a dilution contain 142 and 158 colonies. What is the estimated mean viable count?
Study of the microbial status (total viable count) of organic manures
Medium
A. CFU/g
B. CFU/g
C. CFU/g
D. CFU/g
Correct Answer: CFU/g
Explanation:
The mean colony count is . Thus, TVC is CFU/g.
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23Plates from three consecutive dilutions contain 326, 74, and 8 colonies. Which plate should normally be selected for calculating bacterial TVC?
Study of the microbial status (total viable count) of organic manures
Medium
A.The mean of all three plates
B.The plate containing 74 colonies
C.The plate containing 326 colonies
D.The plate containing 8 colonies
Correct Answer: The plate containing 74 colonies
Explanation:
A bacterial plate with 30–300 colonies is generally considered countable. The 74-colony plate falls within this range.
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24A manure sample gives a lower TVC by the pour-plate method than by the spread-plate method under otherwise similar conditions. Which explanation is most reasonable?
Study of the microbial status (total viable count) of organic manures
Medium
A.Serial dilution increased the number of viable cells
B.Surface spreading sterilized some resistant cells
C.Pour plating prevented colonies from entering agar
D.Molten agar injured some heat-sensitive cells
Correct Answer: Molten agar injured some heat-sensitive cells
Explanation:
The warm molten agar used in pour plating can injure heat-sensitive microorganisms, producing a lower viable count.
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25An aerobic plate count of composted manure is reported as CFU/g. Which conclusion is scientifically appropriate?
Study of the microbial status (total viable count) of organic manures
Medium
A.The manure is free from all pathogenic microorganisms
B.The count represents culturable organisms under the test conditions
C.The manure contains exactly that many microbial cells
D.The count includes every aerobic and anaerobic organism present
Correct Answer: The count represents culturable organisms under the test conditions
Explanation:
TVC measures organisms able to form colonies on the selected medium under the specified incubation conditions, not every cell present.
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26During serial dilution, a technician transfers mL into mL blanks but fails to mix each tube before the next transfer. What is the most likely effect?
Study of the microbial status (total viable count) of organic manures
Medium
A.All microorganisms will lose their viability
B.The final dilution will remain exactly accurate
C.The dilution series may give irregular colony counts
D.The medium will become completely selective
Correct Answer: The dilution series may give irregular colony counts
Explanation:
Without adequate mixing, microorganisms are unevenly distributed, so transferred portions may not represent the intended dilution.
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27A manure sample has a TVC of CFU/g on a wet-weight basis and contains 60% moisture. What is its TVC on a dry-weight basis?
Study of the microbial status (total viable count) of organic manures
Medium
A. CFU/g
B. CFU/g
C. CFU/g
D. CFU/g
Correct Answer: CFU/g
Explanation:
The dry-matter fraction is . Therefore, dry-weight TVC is CFU/g.
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28During composting, the TVC decreases from CFU/g to CFU/g. What is the logarithmic reduction?
Study of the microbial status (total viable count) of organic manures
Medium
A. log reduction
B. log reduction
C. log reduction
D. log reduction
Correct Answer: log reduction
Explanation:
The count decreased by a factor of , which corresponds to a log reduction.
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29A dilution plate is too numerous to count, while a dilution plate inoculated with mL contains 46 colonies. What TVC should be reported?
Study of the microbial status (total viable count) of organic manures
Medium
A. CFU/g
B. CFU/g
C. CFU/g
D. CFU/g
Correct Answer: CFU/g
Explanation:
The countable plate is used: CFU/g.
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30Colonies appear on an uninoculated sterility-control plate during manure TVC analysis. What is the most appropriate response?
Study of the microbial status (total viable count) of organic manures
Medium
A.Accept the results if sample plates are countable
B.Subtract the control colonies from every sample plate
C.Reject the affected batch and repeat the analysis
D.Increase the calculated dilution factor by ten
Correct Answer: Reject the affected batch and repeat the analysis
Explanation:
Growth on a sterility control indicates contamination of the medium or procedure, making the associated results unreliable.
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31Direct microscopic examination shows many more bacterial cells than the TVC obtained by plating. What best explains this difference?
Study of the microbial status (total viable count) of organic manures
Medium
A.Microscopy detects dead and nonculturable cells
B.Plating counts each cell several times
C.Microscopy destroys most viable bacterial cells
D.Plating counts viruses as bacterial colonies
Correct Answer: Microscopy detects dead and nonculturable cells
Explanation:
Microscopy can detect cells regardless of culturability, whereas TVC includes only cells that form visible colonies under the chosen conditions.
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32Two laboratories obtain different TVCs for the same manure sample. One incubates plates at C and the other at C. Why can their results differ?
Study of the microbial status (total viable count) of organic manures
Medium
A.Higher temperature always doubles every colony count
B.Temperature changes the dilution factor mathematically
C.Different temperatures favor different microbial populations
D.Lower temperature converts viable cells into spores
Correct Answer: Different temperatures favor different microbial populations
Explanation:
Incubation temperature determines which microorganisms can grow and form colonies, so TVC results depend on the selected temperature.
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33A manure heap is visibly heterogeneous. Which sampling approach is most suitable for estimating its overall microbial status?
Study of the microbial status (total viable count) of organic manures
Medium
A.Select only material containing visible fungal growth
B.Collect one portion from the warmest central area
C.Combine portions from several locations and homogenize
D.Collect one portion from the driest surface area
Correct Answer: Combine portions from several locations and homogenize
Explanation:
A composite, homogenized sample reduces location bias and better represents the average microbial status of a heterogeneous manure heap.
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34Which medium is most appropriate when the objective is to estimate the general aerobic bacterial TVC of organic manure?
Study of the microbial status (total viable count) of organic manures
Medium
A.A highly selective enteric pathogen medium
B.A virus-specific host-cell culture medium
C.A broad-spectrum nonselective nutrient medium
D.A medium containing several antibacterial agents
Correct Answer: A broad-spectrum nonselective nutrient medium
Explanation:
A general-purpose, nonselective medium supports a broad range of culturable aerobic bacteria and is suitable for estimating TVC.
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35A spread plate prepared with mL of a dilution contains 120 colonies. Why must the calculation include a factor of 10 for plated volume?
Study of the microbial status (total viable count) of organic manures
Medium
A.The dilution becomes ten times weaker during incubation
B.Each visible colony represents exactly ten bacterial cells
C.The agar medium increases sample volume to one millilitre
D.The plated volume represents one-tenth of a millilitre
Correct Answer: The plated volume represents one-tenth of a millilitre
Explanation:
Because only mL was plated, the colony count is multiplied by to express the result per millilitre.
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36Duplicate plates from the same manure dilution contain 52 and 241 colonies. Both are within the nominal countable range. What should the analyst do?
Study of the microbial status (total viable count) of organic manures
Medium
A.Use only the plate containing 241 colonies
B.Use only the plate containing 52 colonies
C.Add both counts without checking variability
D.Investigate the discrepancy and repeat the plating
Correct Answer: Investigate the discrepancy and repeat the plating
Explanation:
Such a large difference between duplicate plates suggests poor mixing, plating error, or contamination and should be investigated by repeating the test.
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37No colonies grow after plating mL of a manure dilution. Based on this plating scheme, what is the practical detection limit?
Study of the microbial status (total viable count) of organic manures
Medium
A. CFU/g
B. CFU/g
C. CFU/g
D. CFU/g
Correct Answer: CFU/g
Explanation:
One detectable colony would represent CFU/g.
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38A fresh manure sample has CFU/g, while a treated sample has CFU/g. By what factor did the viable count decrease?
Study of the microbial status (total viable count) of organic manures
Medium
A.A factor of 3
B.A factor of 300
C.A factor of 3000
D.A factor of 30
Correct Answer: A factor of 30
Explanation:
The reduction factor is .
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39A manure suspension is allowed to stand for 20 minutes before aliquots are removed for dilution. How might this affect the TVC result?
Study of the microbial status (total viable count) of organic manures
Medium
A.All microbial clumps separate into individual cells
B.Standing automatically sterilizes the manure suspension
C.Settling may cause a nonrepresentative aliquot to be sampled
D.The dilution factor increases continuously with time
Correct Answer: Settling may cause a nonrepresentative aliquot to be sampled
Explanation:
Particles and attached microorganisms may settle during standing, so an unmixed aliquot may contain more or fewer organisms than the original suspension.
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40Why is a total viable count generally reported as CFU/g rather than as the exact number of viable cells per gram?
Study of the microbial status (total viable count) of organic manures
Medium
A.The gram unit prevents colonies from being counted directly
B.Colonies form only from microorganisms that are already dead
C.Every viable cell always produces several separate colonies
D.One colony may arise from a cell or a cell cluster
Correct Answer: One colony may arise from a cell or a cell cluster
Explanation:
A colony-forming unit may originate from one cell or from a clump of viable cells, so CFU does not necessarily equal the exact cell number.
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41A manure suspension is prepared so that the plated tube represents an overall sample dilution of . Duplicate plates inoculated with give 72 and 78 colonies. What is the estimated total viable count?
Study of the microbial status (total viable count) of organic manures
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The mean count is 75. Thus, .
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42Using the weighted plate-count formula , two pour plates at contain 145 and 168 colonies, while two at contain 21 and 18 colonies. What is ?
Study of the microbial status (total viable count) of organic manures
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Here, , , and . Therefore, .
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43A manure containing 60% moisture has a total viable count of on a wet-mass basis. What is its count on a dry-mass basis?
Study of the microbial status (total viable count) of organic manures
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The dry-matter fraction is . Therefore, the dry-basis count is .
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44An organic manure plate has 280 colonies at , while the plate is uncountable and the plate has 24 colonies. If was spread and the accepted countable range is 30–300 colonies, which result should be reported?
Study of the microbial status (total viable count) of organic manures
Hard
A. from the plate
B. from the plate
C. from the plate
D. from both countable plates
Correct Answer: from the plate
Explanation:
Only the 280-colony plate is within the specified range. Its count is .
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45Adding a validated, non-toxic dispersant during homogenization increases the measured count from to without permitting microbial growth. What is the most defensible interpretation?
Study of the microbial status (total viable count) of organic manures
Hard
A.The original plates contained excessive dilution blank nutrients
C.The original method counted cell aggregates as single CFUs
D.The dispersant converted dead cells into viable organisms
Correct Answer: The original method counted cell aggregates as single CFUs
Explanation:
A CFU can arise from a cell cluster rather than one cell. Improved dispersion separates clusters and increases colony numbers without changing actual viability.
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46Three plates inoculated from an overall sample dilution show zero colonies. Using one expected CFU in the total plated sample equivalent as the detection-limit criterion, what is the detection limit?
Study of the microbial status (total viable count) of organic manures
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The three plates represent of sample. The detection limit is .
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47Four replicate plates collectively contain 100 colonies. If colony occurrence follows an independent Poisson process and dilution uncertainty is negligible, what is the approximate relative standard error of the pooled count?
Study of the microbial status (total viable count) of organic manures
Hard
A.10%
B.25%
C.1%
D.5%
Correct Answer: 10%
Explanation:
For a Poisson count, the relative standard error is approximately . Thus, , or 10%.
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48Composting reduces the aerobic total viable count from to . Which description is correct?
Study of the microbial status (total viable count) of organic manures
Hard
A.A 3-log reduction corresponding to 99.0%
B.A 4-log reduction corresponding to 99.99%
C.A 2-log reduction corresponding to 99.0%
D.A 3-log reduction corresponding to 99.9%
Correct Answer: A 3-log reduction corresponding to 99.9%
Explanation:
The count decreased by a factor of . This is a 3-log reduction, leaving 0.1% and therefore corresponding to 99.9% reduction.
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49Microscopy indicates intact bacterial cells per gram of manure, but aerobic plating yields . Which conclusion is scientifically justified?
Study of the microbial status (total viable count) of organic manures
Hard
A.The microscope overestimated the population by three logs
B.Only a fraction formed colonies under the selected conditions
C.Each colony must have arisen from one thousand cells
D.Exactly 99.9% of the observed cells are dead
Correct Answer: Only a fraction formed colonies under the selected conditions
Explanation:
Plate counts are operational and detect only organisms able to form colonies under the chosen medium, atmosphere, temperature, and incubation time.
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50An acidic manure gives unexpectedly low plate counts, and the pH of the first dilution remains 4.0. Which modification best tests whether acid carryover is suppressing recovery?
Study of the microbial status (total viable count) of organic manures
Hard
A.Use a validated buffered diluent and verify post-dilution pH
B.Count only colonies that appear during the first incubation day
C.Increase agar concentration while retaining the acidic diluent
D.Shorten incubation to prevent acid-sensitive colonies from merging
Correct Answer: Use a validated buffered diluent and verify post-dilution pH
Explanation:
A buffered diluent can neutralize acid carryover. Confirming the resulting pH distinguishes recovery inhibition from a genuinely low viable population.
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51After correcting for dilution and plated volume, a manure produces estimates of , , and from successive tenfold dilutions. What pattern is most strongly suggested?
Study of the microbial status (total viable count) of organic manures
Hard
A.The manure population followed exact Poisson variability
B.Residual inhibitors suppressed recovery at lower dilutions
C.Colony merging increased as the sample became more dilute
D.Microbial multiplication occurred in the most dilute tubes
Correct Answer: Residual inhibitors suppressed recovery at lower dilutions
Explanation:
Increasing dilution-corrected estimates with dilution commonly indicate dilution of antimicrobial compounds or other matrix-related inhibitors.
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52Duplicate plates from the same dilution contain 12 and 88 colonies, although plating and incubation conditions were nominally identical. What is the most appropriate response?
Study of the microbial status (total viable count) of organic manures
Hard
A.Use only 88 because higher counts have lower relative error
B.Repeat after remixing and investigate pipetting or sample clumping
C.Use only 12 because isolated colonies are easier to distinguish
D.Average the plates because duplicate results are always combinable
Correct Answer: Repeat after remixing and investigate pipetting or sample clumping
Explanation:
The discrepancy is far larger than expected from ordinary Poisson variation. Inadequate mixing, clumping, or a plating error should be investigated before reporting.
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53An aerobic plate count is used to assess manure rich in obligately anaerobic bacteria. Which statement best characterizes the result?
Study of the microbial status (total viable count) of organic manures
Hard
A.It estimates all viable bacteria because oxygen affects only growth rate
B.It measures anaerobes accurately if the incubation period is extended
C.It selectively estimates organisms able to form colonies aerobically
D.It estimates total cells because non-growing bacteria remain visible
Correct Answer: It selectively estimates organisms able to form colonies aerobically
Explanation:
Obligate anaerobes may not form colonies in aerobic incubation. The result is therefore an aerobic culturable count, not a universal viable count.
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54Two laboratories analyze identical manure. One incubates plates at for 48 hours, while the other uses for 24 hours. Their results differ by one log. What is the strongest conclusion?
Study of the microbial status (total viable count) of organic manures
Hard
A.The results are not directly comparable without method harmonization
B.The difference proves the manure changed during sample subdivision
C.The higher result necessarily represents the true viable population
D.The lower result identifies the laboratory with inaccurate pipettes
Correct Answer: The results are not directly comparable without method harmonization
Explanation:
Temperature and incubation duration determine which organisms form visible colonies. Counts obtained under different recovery conditions are operationally different measurements.
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55A non-heat-treated manure suspension yields , while an otherwise identical heat-shocked suspension yields . Assuming heat shock eliminates vegetative cells but allows equivalent recovery of resistant spores, what fraction of the original count is heat resistant?
Study of the microbial status (total viable count) of organic manures
Hard
A.7.5%
B.13.3%
C.0.75%
D.92.5%
Correct Answer: 7.5%
Explanation:
The heat-resistant fraction is , or 7.5%.
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56A spread plate contains 45 well-separated visible colonies, but microscopic inspection shows that many inoculum particles contained chains of viable cells. What does represent most accurately?
Study of the microbial status (total viable count) of organic manures
Hard
A.At most 45 metabolically active cells in the sample
B.Exactly 45 individual viable microbial cells
C.At least 45 colony-forming units in the plated aliquot
D.Exactly 45 microbial species in the plated aliquot
Correct Answer: At least 45 colony-forming units in the plated aliquot
Explanation:
A colony-forming unit may be a single cell or a viable aggregate. The number of individual viable cells can therefore exceed the colony count.
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57Equal wet masses of manure A and manure B are mixed. A contains 60% moisture and ; B contains 20% moisture and . Assuming no loss of viability, what is the count of the mixture on a dry-mass basis?
Study of the microbial status (total viable count) of organic manures
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
For 1 g of each manure, total CFUs are and total dry mass is . Thus, .
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58A manure plate is completely covered by confluent growth. Why is assigning a count based on the visible surface sectors generally invalid?
Study of the microbial status (total viable count) of organic manures
Hard
A.Confluent growth proves every organism in the manure was viable
B.Sector counting converts viable counts into direct microscopic counts
C.Dense plates contain fewer nutrients than sterile dilution blanks
D.Overlapping colonies violate the assumption that CFUs remain resolvable
Correct Answer: Overlapping colonies violate the assumption that CFUs remain resolvable
Explanation:
At excessive density, colonies merge and inhibit one another, so visible growth regions no longer correspond reliably to separate CFUs. A higher dilution should be plated.
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59A control manure and a treated manure are plated on different days using different batches of growth medium. The treated manure gives a lower count. Which design change best supports a causal treatment comparison?
Study of the microbial status (total viable count) of organic manures
Hard
A.Randomize and process both treatments with the same medium batch
B.Plate each treatment on separate days to avoid cross-contamination
C.Use a higher dilution only for the treatment expected to be effective
D.Incubate treated samples longer to compensate for treatment injury
Correct Answer: Randomize and process both treatments with the same medium batch
Explanation:
Randomized concurrent analysis controls day and medium-batch effects, preventing these methodological factors from being confounded with treatment.
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60A sanitizer-treated manure may contain sublethally injured bacteria. Which protocol is most likely to avoid underestimating its total viable count?
Study of the microbial status (total viable count) of organic manures
Hard
A.Plate immediately on a strongly selective medium at high temperature
B.Use a nonselective recovery medium before applying selective conditions
C.Acidify the diluent so only fully resistant organisms form colonies
D.Count colonies after the shortest incubation yielding visible growth
Correct Answer: Use a nonselective recovery medium before applying selective conditions
Explanation:
Sublethally injured cells may remain viable but fail under immediate selective stress. Nonselective resuscitation permits cellular repair and improves recovery.
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