Unit 3: Differentiability of function
Differentiability studies the rate at which a function changes and the conditions under which that rate is well defined. The derivative of f at x = a is the limit of the average rate of change over a shrinking interval, and it exists only when the function is smooth enough at that point.
Governing definition: the derivative is
f'(a) = lim(h→0) [f(a+h) − f(a)] / h
provided the limit exists and is finite.
- Domain of the derivative:
f'(x)is itself a function, defined only where the limit exists. - Geometric meaning:
f'(a)is the slope of the tangent toy = f(x)atx = a. - Continuity is necessary: if
fis differentiable ata, it is continuous ata; the converse fails (e.g.|x|at0). - Notation:
f'(x),dy/dx, andD fall denote the same object; the operatord/dxacts on a function. - Standard forms carried throughout:
d/dx(x^n) = n·x^(n−1),d/dx(sin x) = cos x,d/dx(cos x) = −sin x,d/dx(constant) = 0.
II. Foundations of the Derivative
Definition, existence, and the arithmetic rules.
A. Derivatives by first principle
This is the direct evaluation of the defining limit, without shortcut rules.
- Method: form the difference quotient
[f(x+h) − f(x)] / h, simplify to cancel thehin the denominator, then leth → 0. - Purpose: it proves the standard formulae and handles functions with no ready rule.
- Worked example —
f(x) = x²:
TEXTf'(x) = lim(h→0) [(x+h)² − x²]/h = lim(h→0) [2xh + h²]/h = lim(h→0) (2x + h) = 2x - Trigonometric case: for
sin x, expandingsin(x+h)and usinglim(h→0)(sin h)/h = 1andlim(h→0)(1−cos h)/h = 0givescos x.
B. Algebra of derivative of functions
Derivatives distribute over the basic arithmetic operations by fixed rules.
- Sum/difference:
(u ± v)' = u' ± v'. - Constant multiple:
(k·u)' = k·u'for constantk. - Product rule:
(u·v)' = u'·v + u·v'. - Quotient rule:
(u/v)' = (u'·v − u·v') / v², valid wherev ≠ 0. - Anchor: for
y = x²·sin x,y' = 2x·sin x + x²·cos x.
C. Differentiability
A function is differentiable at a point when its left- and right-hand derivatives agree.
- Left derivative:
lim(h→0⁻) [f(a+h) − f(a)]/h. - Right derivative:
lim(h→0⁺) [f(a+h) − f(a)]/h. - Criterion: differentiable at
a⇔ both one-sided derivatives exist and are equal. - Failure modes: a corner (
|x|at0, slopes−1and+1), a cusp, a vertical tangent (x^(1/3)at0), or a discontinuity. - On an interval:
fis differentiable on(a,b)iff'(x)exists for every point of the interval.
III. Differentiating Combinations of Functions
Composition and relations that are not solved for y.
A. Derivatives of composite functions
A composite f(g(x)) is differentiated by peeling the outer function first while holding the inner intact.
- Structure: identify outer
fand innergso thaty = f(u),u = g(x). - Principle: differentiate the outer function at the inner value, then multiply by the derivative of the inner.
- Anchor: for
y = (3x + 1)⁵, treatu = 3x + 1, givingy' = 5(3x+1)⁴·3.
B. Chain rule
The chain rule is the formal statement that governs composite differentiation.
- Formula:
TEXTdy/dx = (dy/du) · (du/dx)
wherey = f(u)andu = g(x). - Extension: for triple composition
y = f(g(h(x))),
TEXTdy/dx = f'(g(h(x))) · g'(h(x)) · h'(x) - Worked example —
y = sin(x²): withu = x²,dy/du = cos u,du/dx = 2x, soy' = 2x·cos(x²).
C. Derivatives of implicit functions
When y is defined implicitly by an equation F(x, y) = 0, differentiate every term with respect to x, treating y as a function of x.
- Key step: each
y-term picks up a factordy/dxby the chain rule. - Then: collect all
dy/dxterms on one side and solve algebraically. - Worked example —
x² + y² = 25:
TEXT2x + 2y·(dy/dx) = 0 ⇒ dy/dx = −x/y - Use: essential for curves like
x²+y²=r²orxy = cthat cannot be written asy = f(x)globally.
IV. Derivatives of Special Functions
Inverse trigonometric, exponential, logarithmic, and the logarithmic technique.
A. Derivatives of inverse trigonometric functions
These follow from the chain rule applied to the defining relation (e.g. y = sin⁻¹x ⇔ sin y = x).
- Standard results:
TEXTd/dx(sin⁻¹x) = 1/√(1−x²) |x| < 1 d/dx(cos⁻¹x) = −1/√(1−x²) |x| < 1 d/dx(tan⁻¹x) = 1/(1+x²) d/dx(cot⁻¹x) = −1/(1+x²) d/dx(sec⁻¹x) = 1/(|x|√(x²−1)) |x| > 1 d/dx(csc⁻¹x) = −1/(|x|√(x²−1)) |x| > 1 - Derivation sketch: differentiate
sin y = ximplicitly:cos y·(dy/dx) = 1, sody/dx = 1/cos y = 1/√(1−x²). - Anchor: paired functions differ only in sign;
sin⁻¹andcos⁻¹derivatives sum to zero.
B. Derivatives of exponential and logarithmic functions
The exponential base e is the fixed point of differentiation, and the logarithm is its inverse.
- Core results:
TEXTd/dx(e^x) = e^x d/dx(a^x) = a^x·ln a a > 0 d/dx(ln x) = 1/x x > 0 d/dx(log_a x) = 1/(x·ln a) - With chain rule:
d/dx(e^(g(x))) = e^(g(x))·g'(x); e.g.d/dx(e^(2x)) = 2e^(2x). - Anchor:
a^x = e^(x ln a), so its derivative inherits the factorln a.
C. Logarithmic differentiation
This technique takes the natural log of both sides before differentiating, simplifying products, quotients, and variable exponents.
- When to use: functions of the form
y = [f(x)]^(g(x)), or long products/quotients. - Procedure: take
lnof both sides, use log laws to split, differentiate implicitly, then multiply through byy. - Worked example —
y = x^x:
TEXTln y = x·ln x (1/y)·(dy/dx) = ln x + 1 dy/dx = x^x (ln x + 1) - Anchor: neither the power rule nor the exponential rule alone handles a variable base with a variable exponent.
V. Parametric and Higher-Order Derivatives
Curves given through a parameter, and repeated differentiation.
A. Derivatives of functions in parametric forms
When x and y are each given as functions of a parameter t, the derivative is a ratio of parameter derivatives.
- Formula:
TEXTdy/dx = (dy/dt) / (dx/dt), provided dx/dt ≠ 0 - Reason: by the chain rule,
dy/dt = (dy/dx)·(dx/dt), then rearrange. - Worked example —
x = a cos t,y = a sin t:
TEXTdx/dt = −a sin t, dy/dt = a cos t dy/dx = (a cos t)/(−a sin t) = −cot t - Anchor: the result is expressed in terms of
t, notx.
B. Second order derivatives
The second derivative is the derivative of the first derivative and measures how the slope itself changes.
- Notation:
f''(x),d²y/dx², orD²y. - Meaning: it gives concavity —
f'' > 0means the curve bends upward (convex),f'' < 0means it bends downward. - Direct case: for
y = x⁴,y' = 4x³,y'' = 12x². - Parametric case (needs care): differentiate
dy/dx(a function oft) with respect tot, then divide again bydx/dt:
TEXTd²y/dx² = d/dt(dy/dx) · (1/(dx/dt))
It is not(d²y/dt²)/(d²x/dt²). - Implicit case: differentiate
dy/dxagain with respect tox, substituting the knowndy/dxwhere it reappears. - Anchor: for
x²+y²=25, fromdy/dx = −x/y,
TEXTd²y/dx² = −(y − x·(dy/dx))/y² = −(y + x²/y)/y² = −25/y³
The derivative, built from the first-principle limit and extended by the algebra, chain, implicit, and logarithmic techniques, reduces almost every differentiation problem to a small set of standard forms combined by fixed rules; the second derivative then reapplies the same machinery to describe curvature.
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