The ester bonds in PLA are readily cleaved by hydrolysis and microbial action, allowing the polymer to break down into environmentally benign products.
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30Which mechanism describes photodegradation of polymers?
biodegradable polymers: classifications, uses and methods of degradation
Medium
A.Breakdown by water absorption
B.Degradation due to applied stress
C.Chain scission by enzymes
D.Bond cleavage induced by UV light
Correct Answer: Bond cleavage induced by UV light
Explanation:
Photodegradation occurs when UV radiation supplies enough energy to break chemical bonds in the polymer backbone, initiating chain scission.
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31The main purpose of a lubricant between two moving surfaces is to:
lubricants: lubrication and its purpose
Medium
A.Raise the operating temperature
B.Increase the coefficient of friction
C.Increase surface adhesion
D.Reduce friction and wear
Correct Answer: Reduce friction and wear
Explanation:
A lubricant forms a film that separates surfaces, minimizing direct contact, thereby lowering friction, wear, and heat generation.
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32Pour point depressants are added to lubricating oils to:
additives for lubricants
Medium
A.Prevent oxidation of the oil
B.Improve the oil's flash point
C.Increase oil viscosity at high temperature
D.Keep the oil fluid at low temperatures
Correct Answer: Keep the oil fluid at low temperatures
Explanation:
Pour point depressants interfere with wax crystal formation, lowering the temperature at which the oil ceases to flow.
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33A high viscosity index (VI) lubricant is desirable because its viscosity:
chemical and physical properties of lubricant
Medium
A.Drops sharply as temperature rises
B.Depends only on pressure
C.Changes little with temperature
D.Increases rapidly with temperature
Correct Answer: Changes little with temperature
Explanation:
A high VI means the lubricant maintains a stable viscosity over a wide temperature range, ensuring reliable lubrication.
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34Nylon-6,6 is classified as which type of polymer based on its mode of synthesis?
Classification of polymers
Medium
A.Addition polymer
B.Condensation polymer
C.Coordination polymer
D.Free-radical polymer
Correct Answer: Condensation polymer
Explanation:
Nylon-6,6 forms by condensation of a diamine and a diacid with elimination of water, making it a step-growth condensation polymer.
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35In chain-growth (addition) polymerization, monomers must generally contain:
Basics of Polymer chemistry
Medium
A.Two different functional groups
B.A metal catalyst atom
C.An ester linkage
D.A reactive double bond or ring
Correct Answer: A reactive double bond or ring
Explanation:
Addition polymerization proceeds through unsaturation (C=C) or ring-opening, adding monomers one at a time without loss of small molecules.
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36Compared to an amorphous polymer, a highly crystalline polymer of the same type generally shows:
Structure-property relationship
Medium
A.Higher density and greater rigidity
B.Greater transparency and flexibility
C.Reduced tensile strength
D.Lower melting point
Correct Answer: Higher density and greater rigidity
Explanation:
Ordered chain packing in crystalline regions increases density, stiffness, and melting point, while typically reducing transparency.
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37Which application directly uses the electrical conductivity of conducting polymers?
conductivity and transport in conducting polymers with applications in electronics, energy, and sensors
Medium
Conducting polymers transport charge carriers, making them useful in OLEDs, solar cells, batteries, and sensors.
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38Cross-linking a polymer network typically affects by:
Basic factors affecting Tg (with examples, no details)
Medium
A.Leaving it completely unchanged
B.Eliminating it entirely
C.Lowering it due to increased free volume
D.Raising it due to restricted chain motion
Correct Answer: Raising it due to restricted chain motion
Explanation:
Cross-links tie chains together and restrict segmental mobility, so more energy is needed to reach the glassy-to-rubbery transition, raising .
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39An ideal elastomer must have chains that are:
structure, synthesis and applications of elastomers and common polymers
Medium
A.Fully cross-linked into a dense network
B.Flexible with occasional cross-links
C.Short and completely linear
D.Rigid and highly crystalline
Correct Answer: Flexible with occasional cross-links
Explanation:
Elastomers need flexible, coiled chains for reversible stretching, plus light cross-linking so the material recovers its original shape.
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40If the degree of polymerization of polystyrene (monomer mass ) is , its number-average molecular weight is approximately:
Degree of polymerization
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
.
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41A sample of poly(vinyl chloride) (repeat unit mass ) has a number-average molar mass of . What is its number-average degree of polymerization?
Degree of polymerization
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Degree of polymerization .
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42Which combination of structural changes would be expected to raise the glass transition temperature () of a polymer the most?
Basic factors affecting Tg (with examples, no details)
Hard
A.Adding plasticizer and increasing free volume
B.Introducing flexible ether linkages and lowering molar mass
C.Increasing chain stiffness and increasing crosslink density
D.Increasing side-chain length and reducing intermolecular forces
Correct Answer: Increasing chain stiffness and increasing crosslink density
Explanation:
Stiffer backbones and higher crosslink density both restrict segmental motion, requiring more thermal energy to reach the rubbery state, thus raising . Plasticizers, flexible linkages, and bulky flexible side chains generally lower .
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43In trans-polyacetylene, a neutral soliton is best described as which of the following?
conducting polymers: p-electron delocalization, doping mechanisms, and charge carriers (solitons, polarons, bipolarons)
Hard
A.A bond-alternation domain wall carrying spin but no charge
B.A pair of positive charges bound within a single benzenoid unit
C.A radical cation with both spin and charge localized on one site
D.A doubly charged spinless defect spanning several rings
Correct Answer: A bond-alternation domain wall carrying spin but no charge
Explanation:
In the degenerate ground state of trans-polyacetylene, a neutral soliton is a domain wall separating the two equivalent bond-alternation phases. It carries spin () but no charge, an unusual spin-charge separation characteristic of solitons.
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44In polymers with a non-degenerate ground state such as polypyrrole, increasing the doping level typically converts polarons into bipolarons. A bipolaron is:
conducting polymers: p-electron delocalization, doping mechanisms, and charge carriers (solitons, polarons, bipolarons)
Hard
A.Two independent free electrons in the conduction band
B.A neutral radical acting as a mobile domain wall
C.A spinless dication (or dianion) stabilized by lattice distortion
D.A singly charged species carrying spin
Correct Answer: A spinless dication (or dianion) stabilized by lattice distortion
Explanation:
A bipolaron is a doubly charged, spinless quasiparticle formed when two polarons combine at high doping. The associated lattice relaxation makes it energetically favorable in non-degenerate systems, and its spinless nature is confirmed by ESR/magnetic-susceptibility measurements.
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45Two polyethylene samples have identical molar mass. Sample X is high-density (HDPE) and Sample Y is low-density (LDPE). Which statement correctly relates their structure to density and crystallinity?
Molecular shape and Crystallinity
Hard
A.Both have identical crystallinity because molar mass is equal
B.X is highly branched, which increases crystallinity and density
C.Y is more linear and therefore more crystalline than X
D.X is more linear, packs more efficiently, and is more crystalline and denser than Y
Correct Answer: X is more linear, packs more efficiently, and is more crystalline and denser than Y
Explanation:
HDPE has minimal branching, allowing chains to pack tightly into ordered crystalline regions, giving higher crystallinity and density. LDPE's extensive branching hinders packing, lowering both.
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46Isotactic polypropylene is a hard, high-melting crystalline solid, whereas atactic polypropylene is a soft, amorphous, tacky material. The primary structural reason is:
Structure-property relationship
Hard
A.The atactic form has stronger hydrogen bonding between chains
B.The isotactic form contains extensive covalent crosslinks
C.Regular stereochemistry in the isotactic form permits ordered chain packing into crystallites
D.The atactic form has a much higher molar mass than the isotactic form
Correct Answer: Regular stereochemistry in the isotactic form permits ordered chain packing into crystallites
Explanation:
Isotactic chains have all methyl groups on the same side, giving stereoregularity that enables tight, ordered packing and crystallinity. Atactic chains have random methyl placement, preventing crystallization and giving an amorphous, soft material.
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47Poly(lactic acid) (PLA) and poly(glycolic acid) degrade primarily by which mechanism under physiological conditions?
biodegradable polymers: classifications, uses and methods of degradation
Hard
A.Photodegradation initiated by UV chromophores
B.Hydrolysis of ester linkages in the backbone
C.Enzymatic cleavage of amide bonds only
D.Oxidative cleavage of carbon-carbon bonds
Correct Answer: Hydrolysis of ester linkages in the backbone
Explanation:
PLA and PGA are aliphatic polyesters. Their ester bonds undergo hydrolytic cleavage (which may be enzyme-assisted) to yield lactic/glycolic acid, which are metabolized. This makes them useful for resorbable sutures and drug delivery.
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48Charge transport in bulk conducting polymers is often limited not by intrachain motion but by:
conductivity and transport in conducting polymers with applications in electronics, energy, and sensors
Hard
A.The absence of any -conjugation along the backbone
B.Interchain hopping and transport across disordered/amorphous regions
C.The intrinsic band gap of a perfect single chain
D.Thermal expansion of the crystalline lattice at room temperature
Correct Answer: Interchain hopping and transport across disordered/amorphous regions
Explanation:
While delocalization along a conjugated chain is efficient, macroscopic conductivity requires charges to hop between chains and cross disordered domains. These interchain/inter-domain barriers usually dominate and limit overall conductivity.
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49A lubricant with a high viscosity index (VI) is preferred because it:
lubricants: lubrication and its purpose, additives for lubricants, chemical and physical properties of lubricant
Hard
A.Has very low viscosity at all temperatures
B.Becomes markedly thicker as temperature rises
C.Shows relatively small change in viscosity with temperature
D.Contains the highest possible sulfur content
Correct Answer: Shows relatively small change in viscosity with temperature
Explanation:
The viscosity index measures how much a lubricant's viscosity changes with temperature. A high VI means the viscosity stays relatively stable across a wide temperature range, which is desirable for consistent film thickness and protection.
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50Vulcanization of natural rubber with sulfur improves its elastic properties chiefly because sulfur:
structure, synthesis and applications of elastomers and common polymers
Hard
A.Increases the degree of unsaturation in each chain
B.Converts the cis configuration entirely into the trans form
C.Forms crosslinks between polyisoprene chains, restoring shape after deformation
D.Fully crystallizes the amorphous rubber into a rigid solid
Correct Answer: Forms crosslinks between polyisoprene chains, restoring shape after deformation
Explanation:
Sulfur creates covalent crosslinks (bridges) between polyisoprene chains. These crosslinks prevent permanent chain slippage, so the material recovers its shape after stretching, giving improved strength, elasticity, and reduced tackiness.
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51For a semicrystalline polymer, which statement about and is correct?
Glass transition temperature (Tg)
Hard
A. is a property of the amorphous regions while is that of the crystalline regions, and
B. always occurs below in semicrystalline polymers
C. and are identical for any semicrystalline polymer
D.Fully crystalline polymers show a sharp but no
Correct Answer: is a property of the amorphous regions while is that of the crystalline regions, and
Explanation:
arises from the onset of segmental motion in amorphous domains, whereas is the melting of ordered crystalline domains. In a given polymer lies below ; a perfectly crystalline polymer would show only .
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52Bakelite (phenol-formaldehyde resin) is classified as a thermosetting polymer because:
Classification of polymers
Hard
A.It forms an irreversible three-dimensional crosslinked network on curing
B.It consists of linear chains held only by weak van der Waals forces
C.It softens repeatedly on heating and hardens on cooling
D.It is a linear addition polymer with no crosslinking
Correct Answer: It forms an irreversible three-dimensional crosslinked network on curing
Explanation:
Thermosets like Bakelite form dense, covalently crosslinked 3D networks during curing. This network cannot be remelted or reshaped, distinguishing them from thermoplastics, which soften reversibly on heating.
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53Which of the following distinguishes a condensation (step-growth) polymerization from a chain-growth (addition) polymerization?
Basics of Polymer chemistry
Hard
A.In step-growth, high molar mass polymer forms almost instantly at low conversion
B.Chain-growth always releases a small molecule such as water
C.Chain-growth requires bifunctional monomers with -COOH and -OH groups
D.In step-growth, monomers react in stages and small molecules are often eliminated; high molar mass appears only at high conversion
Correct Answer: In step-growth, monomers react in stages and small molecules are often eliminated; high molar mass appears only at high conversion
Explanation:
Step-growth builds up gradually as any two species with reactive ends combine, often expelling a small molecule (e.g., water). High molar mass requires very high conversion. Chain-growth adds monomers rapidly to active chain ends, forming high polymer early without necessarily losing a byproduct.
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54Treating polyacetylene with iodine () is an example of p-type doping. The role of iodine is to:
conducting polymers: p-electron delocalization, doping mechanisms, and charge carriers (solitons, polarons, bipolarons)
Hard
A.Donate electrons to the polymer backbone, forming negative carriers
B.Form covalent C-I bonds that saturate all double bonds
C.Accept electrons from the polymer, creating positive charge carriers on the chain
D.Break the conjugation to localize electrons on individual carbons
Correct Answer: Accept electrons from the polymer, creating positive charge carriers on the chain
Explanation:
Iodine is an oxidizing (electron-accepting) dopant. It removes electrons from the system, generating positive carriers (polarons/solitons) and counterions, which dramatically raises conductivity (p-type doping).
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55In a step-growth polymerization following Carothers' equation, the number-average degree of polymerization is . To achieve , the required extent of reaction is:
Degree of polymerization
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
From , gives , so . This illustrates why step-growth needs very high conversions to reach useful molar masses.
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56Kevlar (poly-p-phenylene terephthalamide) has exceptional tensile strength primarily due to:
Structure-property relationship
Hard
A.Rigid rod-like chains aligned and held by extensive interchain hydrogen bonding
B.Weak dispersion forces allowing chains to slide and self-heal
C.A highly branched network that resists any deformation
D.Random amorphous coils that dissipate stress uniformly
Correct Answer: Rigid rod-like chains aligned and held by extensive interchain hydrogen bonding
Explanation:
Kevlar's aromatic amide backbone is rigid and rod-like, and the amide groups form dense, regular hydrogen-bonded sheets between aligned chains. This ordered, strongly bonded structure gives its high strength-to-weight ratio.
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57Under extreme pressure (EP) conditions where metal surfaces nearly touch, boundary lubrication is maintained by EP additives that:
lubricants: lubrication and its purpose, additives for lubricants, chemical and physical properties of lubricant
Hard
A.Neutralize acids formed during oil oxidation
B.Lower the pour point so oil flows at low temperature
C.React chemically with the metal surface to form a low-shear protective film
D.Increase the bulk viscosity so a thick fluid film is always present
Correct Answer: React chemically with the metal surface to form a low-shear protective film
Explanation:
In boundary/EP lubrication a full fluid film cannot form. EP additives (often containing S, P, or Cl) react with the hot metal to create a sacrificial, easily sheared surface film that prevents welding and reduces wear. The other options describe VI improvers, pour-point depressants, and detergents.
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58Which classification best fits polyhydroxyalkanoates (PHAs) such as PHB?
biodegradable polymers: classifications, uses and methods of degradation
Hard
A.Crosslinked thermosets requiring incineration for disposal
PHAs are polyesters produced by microorganisms as intracellular carbon/energy storage. Being natural biopolyesters, they are readily biodegraded by microbial enzymes in soil and marine environments, making them attractive for compostable packaging.
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59Adding bulky, irregular side groups along a polymer backbone generally:
Molecular shape and Crystallinity
Hard
A.Has no effect on crystallinity, only on molar mass
B.Decreases crystallinity by hindering regular chain packing
C.Increases crystallinity by strengthening dipole interactions
D.Always converts the polymer into a perfect single crystal
Correct Answer: Decreases crystallinity by hindering regular chain packing
Explanation:
Crystallinity requires chains to pack into ordered arrays. Bulky, irregularly placed side groups introduce steric hindrance and disrupt this regular packing, reducing the fraction of crystalline material and favoring amorphous structure.
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60PEDOT:PSS is widely used in electronics. Which pairing of material role and application is correct?
conductivity and transport in conducting polymers with applications in electronics, energy, and sensors
Hard
A.Transparent conductive electrode / hole-injection layer in OLEDs and flexible displays
B.High-band-gap insulator / dielectric spacer in capacitors
C.Optical fiber cladding / long-distance signal transmission
D.Ferromagnetic core / data storage in hard drives
Correct Answer: Transparent conductive electrode / hole-injection layer in OLEDs and flexible displays
Explanation:
PEDOT:PSS is a doped conducting polymer that is transparent, solution-processable, and hole-conducting. It is used as a transparent electrode and hole-injection/transport layer in OLEDs, solar cells, and flexible electronics.
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