Op-Amp is short for Operational Amplifier, a high-gain direct-coupled amplifier originally used to perform mathematical operations.
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2An operational amplifier is basically a:
Introduction to Op-Amp
Easy
A.Low-gain single-ended amplifier
B.High-gain differential amplifier
C.Tuned RF amplifier
D.Power amplifier only
Correct Answer: High-gain differential amplifier
Explanation:
An op-amp is a high-gain, direct-coupled differential amplifier that amplifies the difference between its two input signals.
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3The IC 741 op-amp is typically available in an 8-pin package. How many pins does this standard package have?
Block Diagram and Pin Configuration of 741 Op-Amp
Easy
A.8
B.4
C.14
D.16
Correct Answer: 8
Explanation:
The popular 741 op-amp comes in a standard 8-pin DIP (or metal can) package.
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4In the internal block diagram of an op-amp, which stage is directly connected to the two input terminals?
Block Diagram and Pin Configuration of 741 Op-Amp
Easy
A.Output driver stage
B.Differential amplifier stage
C.Level shifter stage
D.Intermediate gain stage
Correct Answer: Differential amplifier stage
Explanation:
The input stage of an op-amp is a differential amplifier that receives the inverting and non-inverting input signals.
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5In the 741 op-amp, the offset null pins are used to:
Block Diagram and Pin Configuration of 741 Op-Amp
Easy
A.Set the supply voltage
B.Adjust the slew rate
C.Increase the open-loop gain
D.Cancel the output offset voltage
Correct Answer: Cancel the output offset voltage
Explanation:
The offset null pins allow an external potentiometer to nullify the small DC output offset voltage present with zero input.
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6What is the open-loop voltage gain of an ideal op-amp?
Characteristics of Ideal Op-Amp
Easy
A.Zero
B.Infinite
C.Unity
D.One hundred
Correct Answer: Infinite
Explanation:
An ideal op-amp has infinite open-loop gain, meaning even the smallest input difference produces a large output.
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7The input impedance of an ideal op-amp is:
Characteristics of Ideal Op-Amp
Easy
A.Around 50
B.Zero
C.Infinite
D.Equal to the load resistance
Correct Answer: Infinite
Explanation:
An ideal op-amp has infinite input impedance, so it draws no current from the source connected to its inputs.
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8What is the output impedance of an ideal op-amp?
Characteristics of Ideal Op-Amp
Easy
A.Very high
B.Equal to input impedance
C.Infinite
D.Zero
Correct Answer: Zero
Explanation:
An ideal op-amp has zero output impedance, allowing it to drive any load without loss of output voltage.
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9For an ideal op-amp, the bandwidth is considered to be:
Characteristics of Ideal Op-Amp
Easy
A.Equal to the slew rate
B.Infinite
C.Limited to 1 kHz
D.Zero
Correct Answer: Infinite
Explanation:
An ideal op-amp is assumed to have infinite bandwidth, amplifying all frequencies equally without any roll-off.
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10CMRR in an op-amp stands for:
CMRR
Easy
A.Common Mode Resistance Ratio
B.Combined Mode Response Ratio
C.Current Mode Rejection Ratio
D.Common Mode Rejection Ratio
Correct Answer: Common Mode Rejection Ratio
Explanation:
CMRR stands for Common Mode Rejection Ratio, which measures an op-amp's ability to reject signals common to both inputs.
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11For a good op-amp, the value of CMRR should be:
CMRR
Easy
A.Exactly zero
B.Exactly equal to unity
C.As high as possible
D.As low as possible
Correct Answer: As high as possible
Explanation:
A high CMRR indicates strong rejection of unwanted common-mode signals such as noise, which is desirable.
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12The slew rate of an op-amp is usually expressed in units of:
Slew Rate
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
Slew rate is the maximum rate of change of output voltage with time, commonly expressed in volts per microsecond ().
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13Slew rate is defined as the maximum rate of change of which quantity?
Slew Rate
Easy
A.Supply voltage
B.Output voltage
C.Feedback resistance
D.Input current
Correct Answer: Output voltage
Explanation:
Slew rate is the maximum rate at which the op-amp's output voltage can change per unit time, limiting high-frequency large-signal performance.
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14A differential amplifier amplifies the:
Differential Amplifier Configurations
Easy
A.Product of two input signals
B.Sum of two input signals
C.Ratio of two input signals
D.Difference between two input signals
Correct Answer: Difference between two input signals
Explanation:
A differential amplifier produces an output proportional to the difference between the voltages applied at its two inputs.
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15For an inverting amplifier with input resistor and feedback resistor , the closed-loop gain is:
Op-Amp Applications Inverting and Non-Inverting amplifiers
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
The gain of an inverting amplifier is ; the negative sign indicates a phase inversion.
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16The closed-loop voltage gain of a non-inverting amplifier is given by:
Op-Amp Applications Inverting and Non-Inverting amplifiers
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
For a non-inverting amplifier, the gain is , and the output is always in phase with the input.
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17In an inverting amplifier, the inverting input terminal is said to be at:
Concept of Virtual Ground
Easy
A.Virtual ground
B.Positive supply voltage
C.Negative supply voltage
D.Twice the input voltage
Correct Answer: Virtual ground
Explanation:
Because the non-inverting input is grounded and the differential input voltage is nearly zero, the inverting input sits at virtual ground (approximately 0 V).
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18A summing amplifier is used to:
Summing and Difference Amplifiers
Easy
A.Subtract one voltage from another
B.Add several input voltages together
C.Divide input voltages
D.Multiply two voltages
Correct Answer: Add several input voltages together
Explanation:
A summing amplifier (adder) produces an output proportional to the weighted sum of multiple input voltages applied to its inverting input.
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19What is the voltage gain of an op-amp voltage follower?
Voltage Follower
Easy
A.Infinite
B.Unity (1)
C.Zero
D.Ten
Correct Answer: Unity (1)
Explanation:
A voltage follower has a gain of 1, so the output equals the input; it is used mainly for impedance buffering.
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20In an op-amp integrator, which component is placed in the feedback path?
Differentiator and Integrator
Easy
A.Resistor
B.Diode
C.Inductor
D.Capacitor
Correct Answer: Capacitor
Explanation:
An op-amp integrator uses a capacitor in the feedback path and a resistor at the input, producing an output proportional to the integral of the input.
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21An inverting amplifier uses and . If the input voltage is , what is the output voltage?
Op-Amp Applications Inverting and Non-Inverting amplifiers
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
For an inverting amplifier, . The negative sign indicates phase inversion.
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22A non-inverting amplifier has and . What is its closed-loop voltage gain?
Op-Amp Applications Inverting and Non-Inverting amplifiers
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Non-inverting gain is .
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23An op-amp has a differential gain of and a common-mode gain of . What is its CMRR in dB?
CMRR
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
.
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24An op-amp has a slew rate of . What is the maximum frequency at which it can produce an undistorted sine wave output of peak?
Slew Rate
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Full-power bandwidth: .
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25In an ideal inverting amplifier, why is the inverting input terminal called a virtual ground?
Concept of Virtual Ground
Medium
A.Because it is physically connected directly to the ground terminal of the power supply
B.Because the non-inverting terminal supplies a large current to keep it grounded
C.Because the output voltage at that node is always exactly zero regardless of input
D.Because it is held at approximately by feedback while no current flows into the op-amp input
Correct Answer: Because it is held at approximately by feedback while no current flows into the op-amp input
Explanation:
With the non-inverting input grounded and infinite open-loop gain, feedback forces . It is 'virtual' because it acts like ground without being physically connected to it.
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26Which set of parameters correctly describes an ideal op-amp?
Characteristics of Ideal Op-Amp
Medium
A.Infinite open-loop gain, infinite input impedance, zero output impedance
B.Zero open-loop gain, infinite input impedance, infinite output impedance
C.Finite open-loop gain, zero input impedance, infinite output impedance
D.Infinite open-loop gain, zero input impedance, zero output impedance
Correct Answer: Infinite open-loop gain, infinite input impedance, zero output impedance
Explanation:
An ideal op-amp has infinite open-loop gain, infinite input impedance (no input current), zero output impedance, infinite bandwidth, and infinite CMRR.
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27In a summing amplifier with and three input resistors each , inputs are , and . What is the output?
Summing and Difference Amplifiers
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
since all resistors are equal.
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28What is the primary purpose of using a voltage follower (unity-gain buffer) in a circuit?
Voltage Follower
Medium
A.Amplifying a small signal by a large voltage gain factor
B.Impedance matching by providing high input impedance and low output impedance
C.Inverting the phase of the input signal by
D.Converting an AC signal into a DC voltage level
Correct Answer: Impedance matching by providing high input impedance and low output impedance
Explanation:
A voltage follower has unity gain () but presents very high input impedance and very low output impedance, making it ideal for buffering and isolating stages.
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29For an ideal op-amp integrator with input resistor and feedback capacitor , the output voltage is proportional to:
Differentiator and Integrator
Medium
A.The logarithm of the input voltage
B.The derivative of the input voltage
C.The square of the input voltage
D.The integral of the input voltage
Correct Answer: The integral of the input voltage
Explanation:
An integrator output is , so the output is proportional to the time integral of the input signal.
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30In an op-amp differentiator with and , if the input rises linearly at , what is the output voltage?
Differentiator and Integrator
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
.
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31In the standard 8-pin DIP package of the 741 op-amp, which pins are used for offset null adjustment?
Block Diagram and Pin Configuration of 741 Op-Amp
Medium
A.Pins 1 and 5
B.Pins 4 and 7
C.Pins 6 and 8
D.Pins 2 and 3
Correct Answer: Pins 1 and 5
Explanation:
In the 741 8-pin DIP, pins 1 and 5 are the offset null pins, pins 2 and 3 are inputs, pin 6 is output, and pins 4 and 7 are power supplies.
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32When an op-amp is used as a comparator with the reference at the inverting input, what happens when (at non-inverting input) exceeds the reference?
Comparators
Medium
A.Output saturates to negative supply rail
B.Output oscillates continuously
C.Output saturates to positive supply rail
D.Output remains at
Correct Answer: Output saturates to positive supply rail
Explanation:
When , the huge open-loop gain drives the output to positive saturation (). Open-loop operation forces the output to a rail.
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33A difference amplifier has all four resistors equal (). If (non-inverting side) and (inverting side), what is the output?
Summing and Difference Amplifiers
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
With equal resistors, . The circuit performs a simple subtraction with unity gain.
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34An op-amp is fundamentally a:
Introduction to Op-Amp
Medium
A.Fixed-gain current amplifier with capacitive coupling
B.Single-ended AC-coupled voltage amplifier
C.Low-gain power amplifier with transformer coupling
Replacing the emitter resistor with a constant-current source presents a very high effective emitter resistance, which maximizes CMRR by strongly suppressing common-mode signals.
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36In a datasheet, the parameter 'Input Offset Voltage' () refers to:
understanding datasheets of op-amps
Medium
A.The difference between the two supply rail voltages
B.The differential input voltage needed to make the output zero
C.The output voltage present when both inputs are grounded and no correction applied
D.The maximum voltage the input pins can tolerate safely
Correct Answer: The differential input voltage needed to make the output zero
Explanation:
Input offset voltage is the small DC differential voltage that must be applied between the inputs to force the output to zero, arising from internal mismatches.
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37An inverting amplifier is required to have a gain of . If , what value of is needed?
Op-Amp Applications Inverting and Non-Inverting amplifiers
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
For inverting gain, , so .
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38Slew rate limiting in an op-amp primarily causes which type of distortion for large-amplitude high-frequency sine waves?
Slew Rate
Medium
A.The output becomes triangular rather than sinusoidal
B.The output phase leads the input by
C.The output amplitude doubles unexpectedly
D.The output DC offset drifts to the positive rail
Correct Answer: The output becomes triangular rather than sinusoidal
Explanation:
When the required rate of change exceeds the slew rate, the output cannot follow the sine wave and rises/falls at a fixed maximum slope, producing a triangular waveform.
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39In a voltage follower, how is the feedback arranged?
Voltage Follower
Medium
A.Output connected to both inputs through equal resistors
B.Output left open with feedback taken from the supply
C.Output connected directly to the inverting input (100% negative feedback)
D.Output connected through a large resistor to the non-inverting input
Correct Answer: Output connected directly to the inverting input (100% negative feedback)
Explanation:
A voltage follower connects the output directly back to the inverting input, giving 100% negative feedback and unity gain with .
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40The concept of a 'virtual short' between the two input terminals of an op-amp with negative feedback is valid because:
Characteristics of Ideal Op-Amp
Medium
A.The two input terminals are physically wired together internally
B.The output impedance is infinite, isolating the inputs from the load
C.The input impedance is zero so both terminals share the same current
D.Infinite open-loop gain forces the differential input voltage toward zero
Correct Answer: Infinite open-loop gain forces the differential input voltage toward zero
Explanation:
Since with for a finite output, , so the two inputs are at nearly the same potential (virtual short).
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41An op-amp has a slew rate of . For an output sine wave of peak amplitude , what is the maximum frequency (full-power bandwidth) before slew-rate distortion occurs?
Slew Rate
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The full-power bandwidth is .
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42A differential amplifier has a differential gain of and a common-mode gain of . If both inputs receive a common-mode signal of plus a differential signal of , what is the ratio of the wanted output to the unwanted output?
CMRR
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Wanted output ; unwanted output . Ratio .
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43An op-amp datasheet lists and open-loop differential gain . What is the approximate common-mode gain ?
CMRR
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
, so . Thus .
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44In an inverting amplifier with and , why does the summing junction remain at approximately despite carrying signal current?
Concept of Virtual Ground
Hard
A.Negative feedback forces the inverting input to track the grounded non-inverting input due to near-infinite open-loop gain
B.The input resistor drops the entire input voltage to zero regardless of feedback
C.The feedback resistor shorts the node directly to ground through a low impedance path
D.The op-amp output actively drives the node to ground potential using its internal reference
Correct Answer: Negative feedback forces the inverting input to track the grounded non-inverting input due to near-infinite open-loop gain
Explanation:
With very high open-loop gain and negative feedback, the differential input voltage is nearly zero, so the inverting input sits at the same potential as the grounded non-inverting input—a virtual ground.
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45An ideal integrator has and . A step input of is applied at . What is the output voltage at (assuming initially discharged capacitor)?
Differentiator and Integrator
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
.
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46Why is a resistor often added in series with the input capacitor of a practical differentiator?
Differentiator and Integrator
Hard
A.To limit high-frequency gain and improve stability against high-frequency noise
B.To provide a DC path that eliminates the differentiating action entirely
C.To increase the differentiation constant at all frequencies uniformly
D.To convert the differentiator into an integrator above the corner frequency
Correct Answer: To limit high-frequency gain and improve stability against high-frequency noise
Explanation:
An ideal differentiator's gain rises with frequency, amplifying noise and risking instability. Adding sets a corner frequency beyond which gain flattens, stabilizing the circuit.
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47A summing amplifier has inputs , , through resistors , , and respectively, with . What is the output voltage?
Summing and Difference Amplifiers
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
... recompute: . Correct value is .
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48A non-inverting amplifier is designed for a gain of . If the op-amp has a finite open-loop gain of , what is the actual closed-loop gain (accounting for gain error)?
Op-Amp Applications Inverting and Non-Inverting amplifiers
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Feedback factor . Actual gain .
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49A Schmitt trigger (inverting) uses saturation and feedback resistors (to non-inverting input) and (to output). What is the total hysteresis width (difference between upper and lower thresholds)?
Comparators
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Thresholds are . Hysteresis width .
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50Which combination of parameters correctly describes an ideal op-amp?
Characteristics of Ideal Op-Amp
Hard
A.Infinite input impedance, infinite output impedance, finite gain, infinite bandwidth
B.Infinite input impedance, zero output impedance, infinite gain, infinite bandwidth
C.Zero input impedance, infinite output impedance, infinite gain, zero bandwidth
D.Zero input impedance, zero output impedance, infinite gain, finite bandwidth
Correct Answer: Infinite input impedance, zero output impedance, infinite gain, infinite bandwidth
Explanation:
An ideal op-amp draws no input current (infinite ), delivers unlimited current (zero ), has infinite open-loop gain, and infinite bandwidth with zero offset and infinite CMRR.
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51Two op-amps A and B have identical unity-gain bandwidths but A has twice the slew rate of B. For a small-amplitude, high-frequency sine wave well within both bandwidths, which statement is true?
Slew Rate
Hard
A.Neither can reproduce the signal because slew rate governs small-signal response
B.Op-amp A always produces a cleaner output regardless of amplitude
C.Op-amp B distorts because lower slew rate limits all frequencies
D.Both reproduce the signal similarly since slew rate limiting does not dominate for small signals
Correct Answer: Both reproduce the signal similarly since slew rate limiting does not dominate for small signals
Explanation:
Slew rate limits large-signal high-frequency response. For small amplitudes, the required is low, so both op-amps (with equal bandwidth) reproduce the signal comparably.
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52In the 741 op-amp's internal block diagram, which stage is primarily responsible for providing high voltage gain?
Block Diagram and Pin Configuration of 741 Op-Amp
Hard
A.The input differential amplifier stage
B.The output push-pull class-AB stage
C.The level-shifting and biasing network
D.The intermediate common-emitter stage with an active current-source load
Correct Answer: The intermediate common-emitter stage with an active current-source load
Explanation:
The input stage provides moderate gain and high CMRR, but the intermediate common-emitter gain stage (with an active load) contributes most of the 741's overall high open-loop voltage gain.
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53A voltage follower is used to buffer a sensor with source resistance driving a load. What is the primary benefit compared to direct connection?
Voltage Follower
Hard
A.It increases the source resistance seen by the load to reduce current
B.It provides voltage gain while inverting the polarity of the signal
C.It prevents loading of the sensor, delivering nearly the full source voltage to the load
D.It amplifies the sensor signal by the ratio of load to source resistance
Correct Answer: It prevents loading of the sensor, delivering nearly the full source voltage to the load
Explanation:
Direct connection forms a voltage divider losing signal. The follower's high input impedance draws negligible current from the source and its low output impedance drives the load, transferring the full voltage.
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54In a BJT differential amplifier, replacing the emitter resistor with a constant-current source improves which parameter most significantly?
Differential Amplifier Configurations
Hard
A.Slew rate, by increasing the tail current abruptly
B.CMRR, by increasing the effective common-mode emitter impedance
C.Differential gain, by lowering the emitter degeneration
D.Input offset voltage, by matching the transistors better
Correct Answer: CMRR, by increasing the effective common-mode emitter impedance
Explanation:
A current source presents very high AC impedance at the common emitter node, strongly suppressing common-mode signals while leaving differential gain unaffected—dramatically improving CMRR.
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55A difference amplifier uses and . If a common-mode signal appears at both inputs but is mistakenly , what happens?
Summing and Difference Amplifiers
Hard
A.The differential gain drops to zero while common-mode gain becomes maximum
B.The output remains exactly zero because ideal op-amps reject common-mode
C.A small common-mode error appears at the output due to resistor mismatch
D.The common-mode signal is amplified by the full differential gain of
Correct Answer: A small common-mode error appears at the output due to resistor mismatch
Explanation:
Common-mode rejection in a difference amplifier depends on precise resistor ratio matching. A mismatch () breaks the balance, producing a nonzero common-mode output error.
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56A datasheet specifies input bias current and input offset current . In an inverting amplifier with , what compensation resistor value at the non-inverting input minimizes output error due to bias current, given ?
understanding datasheets of op-amps
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The compensating resistor equals the parallel combination of and : , balancing the bias-current-induced voltage drops.
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57Why does an op-amp require negative feedback for most linear applications despite having very high open-loop gain?
Introduction to Op-Amp
Hard
A.To increase the open-loop gain further beyond its intrinsic value
B.To convert the op-amp into a comparator with defined thresholds
C.To eliminate the need for a dual power supply in operation
D.To set a precise, stable closed-loop gain that is largely independent of the variable open-loop gain
Correct Answer: To set a precise, stable closed-loop gain that is largely independent of the variable open-loop gain
Explanation:
Open-loop gain is huge but poorly controlled and temperature/device dependent. Negative feedback trades excess gain for a predictable, stable closed-loop gain set by external resistors.
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58An inverting amplifier has and . What is its input resistance seen by the source, and its gain?
Op-Amp Applications Inverting and Non-Inverting amplifiers
Hard
A.Input resistance , gain
B.Input resistance , gain
C.Input resistance , gain
D.Input resistance , gain
Correct Answer: Input resistance , gain
Explanation:
Due to the virtual ground, the source sees . The gain is .
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59What is the key advantage of a comparator with hysteresis (Schmitt trigger) over a simple comparator when processing a slowly varying noisy input?
Comparators
Hard
A.It prevents multiple false transitions by requiring the input to cross separated thresholds
B.It provides a linear output proportional to the input near the threshold
C.It amplifies the noise so the true signal becomes clearer at the output
D.It increases output switching speed by boosting the slew rate
Correct Answer: It prevents multiple false transitions by requiring the input to cross separated thresholds
Explanation:
Hysteresis creates two distinct thresholds. Once switched, the input must move past the opposite threshold to switch back, so noise near a single level cannot cause repeated false toggling.
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60Applying the two 'golden rules' (virtual short and no input current) to a non-inverting amplifier with (to ground) and (feedback), what is the closed-loop gain?
Characteristics of Ideal Op-Amp
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The virtual short forces . With no input current, and form a divider: , giving gain .
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