Unit 5: Multivariable integration and applications - Subjective Questions
MTH165 — Mathematics For Engineers • Practice Questions with Detailed Answers
20 questions
Define the double integral of a function over a bounded region using Riemann sums. State the conditions under which the integral exists.
Definition: Let be a bounded region divided into small subregions having areas . If is a sample point in , then
provided the limit exists and is independent of the subdivision and sample points.
- The largest diameter of the subregions must approach zero.
- If is continuous on a closed and bounded region , then it is integrable over .
- A bounded function with only finitely many discontinuities is also generally integrable when the boundary of is sufficiently regular.
- Geometrically, when , the integral represents the volume below and above .
Evaluate the double integral
First integrate with respect to :
Now integrate with respect to :
Therefore,
Evaluate , where is the triangular region bounded by , , and .
The triangular region can be described as
Thus,
Evaluating the inner integral,
Therefore,
Hence,
Change the order of integration in and use the result to find the area of the region.
The original inequalities are
The region lies between and . Solving for in terms of gives
Therefore, after changing the order,
For the area, set :
Thus,
Explain why a region may need to be split when setting up or changing the order of a double integral. Illustrate your answer for the triangle bounded by , , and .
A region must be split when a single pair of boundary functions cannot describe all slices taken in the selected direction.
For vertical slices, the upper boundary changes at the intersection of and :
Therefore, the integral must be split as
For horizontal slices, one description covers the complete region:
Hence, the reversed order is
This demonstrates that changing the order can replace a sum of integrals with a single integral.
Use a double integral to calculate the area enclosed by the curves and .
The curves intersect where
On , the upper curve is and the lower curve is . Therefore,
Evaluating,
Thus,
Use a double integral to find the volume below the paraboloid and above the -plane.
The surface meets the -plane when
Thus, the base is the disk . Using polar coordinates,
The volume is
The radial integral is
Therefore,
Derive the Jacobian for the polar-coordinate transformation , , and state the resulting formula for a double integral.
For the transformation
the Jacobian is
Substituting the derivatives,
Therefore,
Hence,
and the transformation formula is
Evaluate where is the disk .
Using polar coordinates,
The disk is described by
Therefore,
Evaluating,
Thus,
Using a suitable change of variables, derive the area of the ellipse
Use the transformation
The ellipse becomes the unit disk
The Jacobian is
Therefore,
The area of the unit disk is , so
Equivalently, polar coordinates and give
Define a triple integral and explain how Fubini's theorem is used to evaluate it.
Definition: If a solid region is divided into small elements of volume , then
provided the limit exists.
Fubini's theorem: If is continuous on a rectangular box
then the triple integral can be evaluated as an iterated integral, for example,
- The integrations may be performed in any of the six possible orders when the hypotheses are satisfied.
- For , the integral gives the volume of .
- For variable-bound regions, the limits must correctly describe each slice of the solid.
Evaluate where is the box , , and .
The integral is
Separate it into three terms:
and
Therefore,
Use a triple integral to derive the volume of the tetrahedron in the first octant bounded by the coordinate planes and
The tetrahedron is described by
and
Hence,
Alternatively, apply
The Jacobian is , and the transformed region is
Thus,
The integral over the unit tetrahedron equals . Therefore,
For the solid , write the volume integral in three different orders and evaluate it.
One order is
Two other valid orders are
and
Evaluating the first form,
The inner integral is
Therefore,
All six integration orders give the same result when their limits describe the same tetrahedron.
Describe cylindrical coordinates, derive their volume element, and use a triple integral to obtain the volume of a right circular cylinder of radius and height .
Cylindrical coordinates are defined by
The Jacobian of the transformation is , so
For a cylinder of radius and height ,
Therefore,
Evaluating,
Hence,
Use a triple integral in cylindrical coordinates to derive the volume of a right circular cone having base radius and height .
Place the vertex at and the base at . At height , the radius of the cone is
Thus, the cone is described by
Using ,
Integrating with respect to and gives
Since
the required volume is
Describe spherical coordinates and use them to evaluate the volume of a sphere of radius .
Spherical coordinates are defined by
Their volume element is
For a sphere of radius ,
Therefore,
The three factors are
and
Hence,
State and explain the change-of-variables theorem for double integrals. Why is the absolute value of the Jacobian required?
Let
be a continuously differentiable, one-to-one transformation from a region in the -plane to a region in the -plane. If the Jacobian is nonzero in the interior of , then
where
Explanation:
- The Jacobian measures the local area-scaling factor of the transformation.
- A small rectangle of area is transformed approximately into a parallelogram of area .
- A negative Jacobian indicates reversal of orientation, not negative area.
- Therefore, the absolute value is required to ensure that transformed area elements remain nonnegative.
Use the transformation , to find the area of the region defined by and .
Under the transformation,
the region becomes the square
Solving for and ,
The Jacobian is
Thus,
The required area is
Therefore,
Compare the double-integral and triple-integral methods for finding volume, and calculate the volume enclosed between the paraboloids and .
Comparison:
- A double integral computes volume by integrating the vertical height over the projection in the -plane.
- A triple integral computes volume directly by integrating throughout the solid.
The surfaces intersect when
so
The vertical height is
Using a double integral,
Thus,
The equivalent triple integral is
which gives the same result.
Define the double integral of a function over a bounded region using Riemann sums. State the conditions under which the integral exists.
Definition: Let be a bounded region divided into small subregions having areas . If is a sample point in , then
provided the limit exists and is independent of the subdivision and sample points.
- The largest diameter of the subregions must approach zero.
- If is continuous on a closed and bounded region , then it is integrable over .
- A bounded function with only finitely many discontinuities is also generally integrable when the boundary of is sufficiently regular.
- Geometrically, when , the integral represents the volume below and above .
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