Unit 5: Integration II
Integration extends the anti-derivative of Unit I into two directions: a stronger technique for products of functions, and the definite integral that attaches a number to a curve over an interval. The definite integral is defined rigorously as a limit of sums and then linked to anti-derivatives by the Fundamental Theorem of Calculus.
- Indefinite integral: the family of anti-derivatives, written
∫f(x) dx = F(x) + C, whereF'(x) = f(x)andCis arbitrary. - Definite integral: a single real number
∫ₐᵇ f(x) dxfixed once the limitsa(lower) andb(upper) are chosen; no constantCsurvives. - Continuity assumption: every function integrated below is assumed continuous, or at worst bounded with finitely many jumps, on the closed interval
[a, b]. - Fundamental Theorem of Calculus (FTC): if
Fis an anti-derivative of continuousf, then∫ₐᵇ f(x) dx = F(b) − F(a), written[F(x)]ₐᵇ. - Sign convention: area above the x-axis counts positive, area below counts negative; the integral gives the net signed area.
II. Integration by Parts
Reversing the product rule to integrate a product of two functions.
A. Statement and principle
The method integrates ∫u·v dx when the integrand is a product whose two factors behave differently — one simplifies on differentiation, the other stays integrable.
- Formula: derived from
(uv)' = u'v + uv', rearranged and integrated:
TEXT∫ u · v dx = u ∫v dx − ∫ [ (du/dx) · ∫v dx ] dx - Symbols:
uis the factor chosen to be differentiated,vthe factor to be integrated;du/dxis the derivative ofu, and∫v dxthe anti-derivative ofv. - Core idea: the new integral
∫(du/dx)(∫v dx) dxmust be simpler than the original, otherwise the choice ofuandvwas wrong.
B. Choosing the first function (ILATE rule)
The order of preference for which factor becomes u follows the mnemonic ILATE.
- I — Inverse trig: e.g.
sin⁻¹x, chosen first because it differentiates to an algebraic form. - L — Logarithmic: e.g.
log x, which has no elementary anti-derivative but a simple derivative1/x. - A — Algebraic: e.g.
x², powers that reduce in degree on differentiation. - T — Trigonometric: e.g.
sin x,cos x. - E — Exponential: e.g.
eˣ, taken asvlast because it integrates cleanly.
C. Worked example and special cases
Take ∫ x·eˣ dx, an Algebraic × Exponential product.
- Assignment:
u = x(A before E),v = eˣ, sodu/dx = 1,∫v dx = eˣ. - Apply:
x·eˣ − ∫ eˣ·1 dx = x·eˣ − eˣ + C = eˣ(x − 1) + C. - Single-function trick:
∫ log x dxis treated as∫ (log x)·1 dxwithv = 1, givingx log x − x + C. - Standard result:
∫ eˣ[f(x) + f'(x)] dx = eˣ·f(x) + C, a direct consequence useful for integrands of that shape.
III. The Definite Integral
Attaching a fixed numerical value to the integral over a closed interval.
A. Definition via the Fundamental Theorem
The definite integral evaluates the anti-derivative at the two limits and subtracts.
- Rule:
∫ₐᵇ f(x) dx = [F(x)]ₐᵇ = F(b) − F(a), whereF'(x) = f(x). - Constant cancels: using
F(x) + C, the+Cat both ends subtracts away, so the answer is independent of the choice of anti-derivative. - Geometric meaning: for
f(x) ≥ 0, the value equals the area bounded by the curvey = f(x), the x-axis, and the linesx = aandx = b. - Example:
∫₀¹ x² dx = [x³/3]₀¹ = 1/3 − 0 = 1/3.
B. Evaluating with substitution
When a substitution changes the variable, the limits must change with it.
- Method: if
t = g(x), replacedxand rewrite the limits ast = g(a)andt = g(b); there is then no need to revert tox. - Example:
∫₀¹ 2x·e^{x²} dx. Putt = x², sodt = 2x dx; limits becomet = 0tot = 1, giving∫₀¹ eᵗ dt = [eᵗ]₀¹ = e − 1.
IV. Definite Integral as the Limit of a Sum
Defining the integral from first principles as an infinite sum of thin rectangles.
A. Construction of the sum
The interval is sliced into equal strips whose areas are added and refined to a limit.
- Partition: divide
[a, b]intonequal subintervals of widthh = (b − a)/n. - Sample points: heights are read at
a, a+h, a+2h, …, a+(n−1)h, one per strip. - Riemann sum: the total rectangle area is
TEXTSₙ = h [ f(a) + f(a+h) + f(a+2h) + … + f(a+(n−1)h) ] - Definition: the definite integral is the limit as strips become infinitely thin:
TEXT∫ₐᵇ f(x) dx = lim (n→∞) h · Σ (r=0 to n−1) f(a + r·h), h = (b−a)/n - Symbols:
nis the number of strips,htheir common width,rthe strip index; asn→∞,h→0.
B. Evaluation from the definition
The limit is computed using standard summation formulae rather than an anti-derivative.
- Needed sums:
Σr = n(n−1)/2,Σr² = (n−1)n(2n−1)/6, andΣ1 = noverr = 0ton−1. - Example: evaluate
∫₀¹ x dxfrom first principles. Herea = 0,b = 1,h = 1/n,f(x) = x:
TEXTSₙ = h · Σ (r=0 to n−1) (r·h) = h² · Σr = (1/n²)·[n(n−1)/2] = (n−1)/(2n) = 1/2 − 1/(2n) - Take the limit: as
n→∞,1/(2n)→0, so the integral is1/2, matching[x²/2]₀¹. - Purpose: this confirms that the FTC value and the geometric area agree, grounding the shortcut in a genuine definition.
V. Some Properties of Definite Integrals
Structural rules that simplify evaluation before any anti-derivative is found.
A. Limit and interval properties
These govern how the value responds to the limits of integration.
- Reversal:
∫ₐᵇ f(x) dx = − ∫ᵇₐ f(x) dx; swapping limits flips the sign. - Zero width:
∫ₐᵃ f(x) dx = 0, since there is no interval. - Additivity (splitting):
∫ₐᵇ f(x) dx = ∫ₐᶜ f(x) dx + ∫ᶜᵇ f(x) dxfor anyc, typicallya < c < b; useful for piecewise functions. - Variable is dummy:
∫ₐᵇ f(x) dx = ∫ₐᵇ f(t) dt; the name of the integration variable does not affect the value.
B. Reflection and symmetry properties
These exploit how the integrand behaves under a change of variable.
- King's rule:
∫ₐᵇ f(x) dx = ∫ₐᵇ f(a + b − x) dx, replacingxbya+b−x; it often turns an awkward integrand into a solvable one. - Zero-to-a form:
∫₀ᵃ f(x) dx = ∫₀ᵃ f(a − x) dx, the special case witha = 0as lower limit. - Symmetric interval: over
[−a, a],
TEXT∫₋ₐᵃ f(x) dx = 2 ∫₀ᵃ f(x) dx if f is even, f(−x) = f(x) ∫₋ₐᵃ f(x) dx = 0 if f is odd, f(−x) = −f(x) - Example:
∫₋₁¹ x³ dx = 0, sincex³is odd; no computation of the anti-derivative is needed.
C. Order and periodicity properties
These bound the value and handle repeating functions.
- Doubling over a period:
∫₀^{2a} f(x) dx = 2∫₀ᵃ f(x) dxwhenf(2a − x) = f(x), and equals0whenf(2a − x) = −f(x). - Periodic functions:
∫₀^{nT} f(x) dx = n ∫₀ᵀ f(x) dxwhenfhas periodT; each period contributes the same area. - Order preservation: if
f(x) ≤ g(x)on[a, b], then∫ₐᵇ f(x) dx ≤ ∫ₐᵇ g(x) dx; integration keeps inequalities. - Sign rule: if
f(x) ≥ 0throughout[a, b], then∫ₐᵇ f(x) dx ≥ 0; the signed area cannot be negative when the curve stays above the axis.
D. Application of King's rule
The reflection property collapses certain integrals by adding the integral to its mirror image.
- Standard result:
∫₀^{π/2} [sinⁿx / (sinⁿx + cosⁿx)] dx = π/4for anyn. - Reasoning: call the integral
I; applyingx → π/2 − xswapssinandcos, giving a second expressionI'. AddingI + I' = ∫₀^{π/2} 1 dx = π/2, and sinceI = I', each equalsπ/4. - Value: the technique returns a closed number without integrating the messy quotient at all.
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