Unit 3: Differentiability of function - Subjective Questions
MTH110 — Remedial Mathematics • Practice Questions with Detailed Answers
20 questions
Define the derivative of a function using the first principle. Using this definition, find the derivative of .
Derivative by First Principle:
The derivative of a function with respect to is defined as:
provided the limit exists.
Finding derivative of :
Substituting:
Therefore, .
Find the derivative of from first principles.
Using first principle:
Using the identity :
Rewriting:
Since and :
Therefore, .
State and explain the algebra of derivatives (sum, difference, product, and quotient rules) with their formulas.
Let and be two differentiable functions. Then:
1. Sum Rule:
2. Difference Rule:
3. Product Rule:
4. Quotient Rule:
5. Constant Multiple Rule:
These rules allow us to differentiate complex algebraic combinations of functions systematically.
Define differentiability of a function at a point. Explain the relationship between continuity and differentiability.
Differentiability at a point:
A function is said to be differentiable at if the following limit exists:
This means the left-hand derivative must equal the right-hand derivative:
Relationship between Continuity and Differentiability:
- If a function is differentiable at a point, then it is continuous at that point.
- However, the converse is not always true. A function can be continuous but not differentiable.
- Example: is continuous at but not differentiable there (the graph has a sharp corner).
Conclusion: Differentiability Continuity, but Continuity Differentiability.
Show that the function is continuous but not differentiable at .
Checking Continuity at :
Since the left limit = right limit = , the function is continuous at .
Checking Differentiability at :
Left-hand derivative (LHD):
Right-hand derivative (RHD):
Since LHD RHD , the derivative does not exist at .
Conclusion: is continuous but not differentiable at .
State the chain rule for derivatives. Using it, find the derivative of .
Chain Rule:
If and are both differentiable functions, then the derivative of the composite function is:
Applying to :
Let , so .
Therefore:
Explain the method of finding derivatives of composite functions. Find if .
Derivatives of Composite Functions:
A composite function is a function of a function, written as . To differentiate it, we use the chain rule, differentiating the outer function while keeping the inner function intact, then multiplying by the derivative of the inner function.
Solving :
Let , so .
Therefore:
Explain the method of implicit differentiation. Find if .
Implicit Differentiation:
When a relationship between and is given in the form and cannot be easily solved for explicitly, we differentiate both sides with respect to , treating as a function of . Wherever we differentiate a term in , we multiply by (chain rule).
Solving :
Differentiate both sides with respect to :
Solving for :
Derive the derivative of and hence find the derivative of .
Derivative of :
Let , so , where .
Differentiating both sides with respect to :
Since (positive in the given range):
Derivative of :
Since , differentiating both sides:
Derive the derivatives of and using implicit differentiation.
Derivative of :
Let , so .
Differentiating:
Therefore:
Derivative of :
Let , so .
Differentiating:
Since and :
Find the derivative of from first principles, and state the derivative of .
Derivative of from first principles:
Using the standard limit :
Therefore, .
Derivative of :
Using :
Find the derivative of (natural logarithm) and state the derivative of .
Derivative of :
Let , then .
Differentiating both sides with respect to :
Therefore:
Derivative of :
Using the change of base formula :
Explain logarithmic differentiation. Using it, find if .
Logarithmic Differentiation:
This technique is used to differentiate functions of the form (variable base and variable exponent) or products/quotients of many functions. We take the natural logarithm on both sides to simplify the expression before differentiating.
Steps:
- Take on both sides.
- Use log properties to simplify.
- Differentiate implicitly.
- Solve for .
Solving :
Taking on both sides:
Differentiating both sides with respect to :
Therefore:
Using logarithmic differentiation, find for .
Given:
Taking natural logarithm on both sides:
Differentiating both sides with respect to (using product rule on the right):
Therefore:
Explain how to find derivatives of functions in parametric form. If and , find .
Parametric Differentiation:
When both and are expressed in terms of a third variable (parameter), say or , i.e., and , then the derivative is found using:
Solving , :
Differentiating with respect to :
Therefore:
If and , find and the second order derivative .
Given: ,
First derivatives with respect to :
First derivative :
Second order derivative :
Therefore, .
Define second order derivatives. Find the second order derivative of .
Second Order Derivative:
The second order derivative of a function is the derivative of its first derivative. If , then:
- First derivative:
- Second derivative:
It represents the rate of change of the slope and is useful in determining concavity and points of inflection.
Solving :
First derivative:
Second derivative:
Distinguish between explicit and implicit functions with examples, and explain when implicit differentiation is preferred.
Explicit Function:
- A function where the dependent variable is expressed directly and solely in terms of the independent variable .
- Form:
- Example: ,
Implicit Function:
- A function where and are mixed together in an equation and is not isolated.
- Form:
- Example: ,
Comparison Table:
| Feature | Explicit | Implicit |
|---|---|---|
| Form | ||
| isolated | Yes | No |
| Differentiation | Direct | Requires chain rule on terms |
When Implicit Differentiation is Preferred:
Implicit differentiation is preferred when it is difficult or impossible to solve for explicitly (e.g., ), or when isolating makes differentiation more complex. It allows finding without solving for .
Find using the product and chain rules for .
Given: (product of three functions)
Using the extended product rule for three functions :
Let:
- (chain rule)
Substituting:
Factoring out :
If , prove that .
Given:
First derivative (product rule):
Note that , so .
Second derivative (differentiate equation (1)):
Since , we have and :
Rearranging:
Hence proved.
Define the derivative of a function using the first principle. Using this definition, find the derivative of .
Derivative by First Principle:
The derivative of a function with respect to is defined as:
provided the limit exists.
Finding derivative of :
Substituting:
Therefore, .
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