1The depletion region in a PN junction is a region that is depleted of:
Depletion region
Easy
A.Covalent bonds
B.Mobile charge carriers
C.Fixed negative ions
D.Fixed positive ions
Correct Answer: Mobile charge carriers
Explanation:
The depletion region contains only immobile (fixed) ions and is depleted of free mobile charge carriers such as electrons and holes.
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2The width of the depletion region in a PN junction increases when the junction is:
Depletion region
Easy
A.Left unbiased and heated
B.Reverse biased
C.Doped more heavily
D.Forward biased
Correct Answer: Reverse biased
Explanation:
Reverse bias pulls carriers away from the junction, widening the depletion region. Forward bias narrows it.
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3The junction capacitance that dominates when a diode is reverse biased is called:
Junction capacitance
Easy
A.Coupling capacitance
B.Transition capacitance
C.Storage capacitance
D.Diffusion capacitance
Correct Answer: Transition capacitance
Explanation:
Under reverse bias, the transition (depletion) capacitance dominates due to the widened depletion region acting like a parallel-plate capacitor.
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4The diffusion capacitance of a PN junction is significant when the diode is:
Junction capacitance
Easy
A.Forward biased
B.Reverse biased
C.In breakdown region
D.At zero bias only
Correct Answer: Forward biased
Explanation:
Diffusion capacitance arises from stored minority charge carriers during forward bias and becomes significant only in the forward-biased condition.
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5In the diode equation , the term represents the:
Diode equation
Easy
A.Peak forward current
B.Junction leakage voltage
C.Reverse saturation current
D.Breakdown current
Correct Answer: Reverse saturation current
Explanation:
is the reverse saturation current, the small current flowing when the diode is reverse biased.
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6In the diode equation, the thermal voltage at room temperature is approximately:
Diode equation
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
The thermal voltage at room temperature (about 300 K).
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7The reverse saturation current of a diode approximately:
Effect of temperature on reverse saturation current
Easy
A.Doubles for every rise in temperature
B.Falls to zero at high temperature
C.Remains constant with temperature
D.Halves for every rise
Correct Answer: Doubles for every rise in temperature
Explanation:
The reverse saturation current roughly doubles for every increase in temperature due to increased thermal generation of carriers.
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8The reverse saturation current increases with temperature mainly because of increased:
Effect of temperature on reverse saturation current
Easy
A.Barrier potential
B.Generation of minority carriers
C.Doping concentration
D.Width of the depletion region
Correct Answer: Generation of minority carriers
Explanation:
Higher temperature generates more thermally excited minority carriers, which increases the reverse saturation current.
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9A PN junction diode is formed by joining:
Construction and Working
Easy
A.Two P-type semiconductors
B.A P-type and an N-type semiconductor
C.A metal and an insulator
D.Two N-type semiconductors
Correct Answer: A P-type and an N-type semiconductor
Explanation:
A PN junction diode is created at the boundary where a P-type and an N-type semiconductor material meet.
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10A silicon PN junction diode starts conducting appreciably in forward bias at about:
Construction and Working
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
A silicon diode has a knee (cut-in) voltage of about , whereas germanium is about .
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11In the forward V-I characteristic of a diode, the current:
V-I characteristics
Easy
A.Decreases as voltage increases
B.Remains zero at all voltages
C.Is constant at all voltages
D.Rises rapidly after the knee voltage
Correct Answer: Rises rapidly after the knee voltage
Explanation:
Once the applied forward voltage exceeds the knee voltage, the diode current increases sharply with a small increase in voltage.
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12In the reverse bias region of a diode's V-I characteristic, the current is:
V-I characteristics
Easy
A.Exactly zero always
B.Very large and increasing
C.Very small and nearly constant
D.Equal to the forward current
Correct Answer: Very small and nearly constant
Explanation:
In reverse bias, only a tiny reverse saturation current flows and it stays nearly constant until breakdown.
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13The main function of a rectifier is to convert:
Junction diode rectifiers
Easy
A.DC into AC
B.Low voltage into high voltage
C.AC into DC
D.AC into higher-frequency AC
Correct Answer: AC into DC
Explanation:
A rectifier uses diodes to convert alternating current (AC) into direct current (DC).
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14A rectifier circuit works by exploiting the diode's property of:
Junction diode rectifiers
Easy
A.Conducting in only one direction
B.Amplifying signals
C.Generating AC voltage
D.Storing charge indefinitely
Correct Answer: Conducting in only one direction
Explanation:
A diode conducts only when forward biased, allowing current in one direction, which is the basis of rectification.
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15A half-wave rectifier conducts during:
Half wave rectifiers
Easy
A.Only the negative half cycle continuously
B.Both half cycles of the AC input
C.Only one half cycle of the AC input
D.None of the AC cycle
Correct Answer: Only one half cycle of the AC input
Explanation:
A half-wave rectifier uses a single diode that conducts during only one half cycle of the input AC waveform.
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16The ripple frequency at the output of a half-wave rectifier fed by a supply is:
Half wave rectifiers
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
A half-wave rectifier produces one output pulse per input cycle, so the ripple frequency equals the supply frequency, .
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17The minimum number of diodes required in a bridge full-wave rectifier is:
Full wave rectifiers
Easy
A.Three
B.One
C.Two
D.Four
Correct Answer: Four
Explanation:
A bridge full-wave rectifier uses four diodes arranged in a bridge configuration.
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18The ripple frequency at the output of a full-wave rectifier fed by a supply is:
Full wave rectifiers
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
A full-wave rectifier produces two output pulses per input cycle, so the ripple frequency is twice the supply frequency, i.e. .
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19The maximum theoretical efficiency of a half-wave rectifier is approximately:
Efficiency
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
The maximum rectifier efficiency of an ideal half-wave rectifier is about .
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20A Zener diode is normally operated in the:
Zener diode
Easy
A.Cut-off region
B.Reverse breakdown region
C.Saturation region
D.Forward conduction region
Correct Answer: Reverse breakdown region
Explanation:
A Zener diode is designed to operate in the reverse breakdown region, where it maintains a nearly constant voltage, making it useful for voltage regulation.
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21In an unbiased PN junction, the width of the depletion region on the lightly doped side compared to the heavily doped side is:
Depletion region
Medium
A.Larger on the heavily doped side
B.Equal on both sides
C.Zero on the lightly doped side
D.Larger on the lightly doped side
Correct Answer: Larger on the lightly doped side
Explanation:
To maintain equal charge on both sides (), the depletion region extends more into the lightly doped region, where fewer dopant atoms are available.
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22When forward bias is applied to a PN junction, the depletion region width:
Depletion region
Medium
A.Remains constant
B.Becomes infinite
C.Decreases
D.Increases
Correct Answer: Decreases
Explanation:
Forward bias reduces the barrier potential, allowing majority carriers to recombine near the junction, thereby narrowing the depletion region.
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23The transition (depletion) capacitance of a reverse-biased PN junction varies with reverse voltage approximately as:
Junction capacitance
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
For an abrupt junction, depletion width increases with , and since , the capacitance decreases as .
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24Diffusion capacitance in a PN junction becomes dominant under which condition?
Junction capacitance
Medium
A.Breakdown region
B.Reverse bias
C.Zero bias only
D.Forward bias
Correct Answer: Forward bias
Explanation:
Diffusion capacitance arises from stored minority charge injected during forward bias, and it dominates over transition capacitance in the forward-biased region.
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25According to the Shockley diode equation , for a large reverse voltage the current approaches:
Diode equation
Medium
A.Zero
B.
C.Infinity
D.
Correct Answer:
Explanation:
For large negative , the exponential term , so , the reverse saturation current.
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26At room temperature (300 K), the thermal voltage is approximately:
Diode equation
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Thermal voltage at 300 K.
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27The reverse saturation current of a silicon diode approximately doubles for every temperature rise of:
Effect of temperature on reverse saturation current
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
As a rule of thumb, the reverse saturation current of a diode roughly doubles for every increase in temperature due to increased thermal generation of carriers.
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28If the reverse saturation current of a diode is at , its approximate value at is:
Effect of temperature on reverse saturation current
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
A rise means three doublings: .
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29In a PN junction diode, the barrier potential exists because of:
Construction and Working
Medium
A.Applied external voltage
B.Diffusion of majority carriers across the junction
C.Recombination in the neutral regions
D.Thermal generation in the bulk
Correct Answer: Diffusion of majority carriers across the junction
Explanation:
Diffusion of electrons and holes across the junction leaves behind immobile ions, creating a built-in electric field and barrier potential even without external bias.
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30The cut-in (knee) voltage of a silicon diode and a germanium diode respectively are approximately:
V-I characteristics
Medium
A. and
B. and
C. and
D. and
Correct Answer: and
Explanation:
Silicon diodes have a cut-in voltage of about , while germanium diodes conduct at about due to their smaller bandgap.
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31In the forward region of a diode's V-I characteristic, the dynamic resistance at a forward current is given by:
V-I characteristics
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Differentiating the diode equation gives , so dynamic resistance decreases as forward current increases.
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32The main function of a rectifier circuit is to:
Junction diode rectifiers
Medium
A.Convert DC into AC
B.Convert AC into pulsating DC
C.Regulate output voltage
D.Amplify an AC signal
Correct Answer: Convert AC into pulsating DC
Explanation:
A rectifier uses the unidirectional conduction of diodes to convert alternating current into a pulsating unidirectional (DC) output.
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33For a half-wave rectifier with peak output voltage , the DC (average) output voltage is:
Half wave rectifiers
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
For a half-wave rectifier the diode conducts only half the cycle, giving .
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34The ripple factor of an ideal half-wave rectifier is approximately:
Half wave rectifiers
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The ripple factor of a half-wave rectifier is , indicating high ripple content.
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35For a full-wave rectifier with peak voltage , the DC output voltage is:
Full wave rectifiers
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
A full-wave rectifier produces output over both half-cycles, giving , twice that of a half-wave rectifier.
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36In a center-tapped full-wave rectifier, the Peak Inverse Voltage (PIV) across each diode is:
Full wave rectifiers
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
In a center-tapped rectifier the non-conducting diode experiences the full secondary voltage plus from the conducting half, giving PIV .
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37The maximum theoretical rectification efficiency of a full-wave rectifier is approximately:
Efficiency
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The maximum efficiency of a full-wave rectifier is , double that of a half-wave rectifier ().
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38Compared to a half-wave rectifier, a full-wave rectifier has a ripple factor that is:
Efficiency
Medium
A.The same
B.Higher (about )
C.Lower (about )
D.Exactly zero
Correct Answer: Lower (about )
Explanation:
The full-wave rectifier has a ripple factor of about , much lower than the half-wave value of , giving smoother DC output.
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39A Zener diode used as a voltage regulator is always operated in which region?
Zener diode
Medium
A.Reverse breakdown region
B.Forward conduction region
C.Saturation region
D.Cut-off region
Correct Answer: Reverse breakdown region
Explanation:
A Zener diode maintains a nearly constant voltage across it when operated in the reverse breakdown region, which is exploited for voltage regulation.
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40The Zener breakdown mechanism (as opposed to avalanche) dominates in diodes that are:
Zener diode
Medium
A.Lightly doped with a wide depletion region
B.Heavily doped with a thin depletion region
C.Forward biased strongly
D.Undoped intrinsic semiconductors
Correct Answer: Heavily doped with a thin depletion region
Explanation:
Zener breakdown occurs in heavily doped junctions where the thin depletion region produces a high electric field that directly pulls electrons from covalent bonds; avalanche dominates in lightly doped, wider junctions.
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41A silicon diode has a reverse saturation current at . Assuming ideality factor and , what forward voltage is required to produce a forward current of ?
Diode equation
Hard
A.Approximately
B.Approximately
C.Approximately
D.Approximately
Correct Answer: Approximately
Explanation:
Using , so .
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42The reverse saturation current of a diode doubles for every rise in temperature. If at , what is its approximate value at ?
Effect of temperature on reverse saturation current
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The temperature rise is , which is 5 doubling intervals. Thus .
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43For an abrupt PN junction, the transition (depletion) capacitance varies with reverse bias voltage as:
Junction capacitance
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
For a step (abrupt) junction, depletion width and , so . This is the basis of the varactor diode.
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44A full-wave bridge rectifier feeds a purely resistive load with a peak secondary voltage of . Neglecting diode drops, what is the DC (average) output voltage?
Full wave rectifiers
Hard
A.Approximately
B.Approximately
C.Approximately
D.Approximately
Correct Answer: Approximately
Explanation:
Peak voltage . For a full-wave rectifier .
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45A half-wave rectifier delivers an RMS load current of . What is the DC component of the load current?
Half wave rectifiers
Hard
A.Approximately
B.Approximately
C.Approximately
D.Approximately
Correct Answer: Approximately
Explanation:
For a half-wave rectifier , so . The DC value .
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46The maximum theoretical rectification efficiency of an ideal half-wave rectifier and a full-wave rectifier are respectively:
Efficiency
Hard
A. and
B. and
C. and
D. and
Correct Answer: and
Explanation:
Rectification efficiency . For half-wave it is and for full-wave it is (neglecting resistances).
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47In a PN junction, the P-side doping is 10 times greater than the N-side doping (). How does the depletion width on each side compare?
Depletion region
Hard
A.P-side depletion width is times the N-side width
B.Both sides have equal depletion widths
C.P-side depletion width is 10 times the N-side width
D.N-side depletion width is 10 times the P-side width
Correct Answer: N-side depletion width is 10 times the P-side width
Explanation:
Charge neutrality requires . Since , we get . The depletion region penetrates deeper into the lightly-doped (N) side.
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48A Zener regulator uses a Zener with from a supply. If the load draws , what current flows through the Zener?
Zener diode
Hard
A.Approximately
B.Approximately
C.Approximately
D.Approximately
Correct Answer: Approximately
Explanation:
Series current . By KCL, .
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49The dynamic (AC) resistance of a diode at a forward operating current of , assuming and , is:
V-I characteristics
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The dynamic resistance , obtained by differentiating the diode equation.
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50In a center-tapped full-wave rectifier with peak load voltage , the Peak Inverse Voltage (PIV) across each diode is:
Full wave rectifiers
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
In a center-tapped rectifier, when one diode conducts, the non-conducting diode experiences the sum of the load voltage and the reverse-biased half-secondary voltage, giving .
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51A full-wave rectifier output has a ripple factor of (unfiltered). If a capacitor filter reduces the ripple to , the improvement factor in ripple is approximately:
Junction diode rectifiers
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The improvement factor is the ratio of original to final ripple: . This shows the capacitor filter reduces ripple by roughly 24 times.
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52A diode carries at forward voltage and at . For and , the voltage change is approximately:
Diode equation
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
. This is the classic 60 mV/decade rule.
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53For a silicon diode, the forward voltage drop at constant current changes with temperature at approximately:
Effect of temperature on reverse saturation current
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
At constant forward current, the diode voltage decreases by about per rise because increased carrier generation requires less applied voltage. This negative temperature coefficient is well known for silicon.
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54For a one-sided abrupt (p+ n) junction, the depletion width is essentially determined by:
Depletion region
Hard
A.The heavily-doped P-side doping concentration
B.The geometric mean of both doping levels
C.Neither doping level, only the junction area
D.The lightly-doped N-side doping concentration
Correct Answer: The lightly-doped N-side doping concentration
Explanation:
In a p+ n junction, almost all the depletion region extends into the lightly-doped N-side. Thus and is governed primarily by , the lower doping concentration.
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55A Zener diode has a breakdown voltage of and a dynamic resistance of . If the Zener current changes by , the change in the regulated output voltage is:
Zener diode
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The output change due to finite Zener resistance is . Lower gives better regulation.
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56Two identical silicon diodes are connected in series and forward-biased by a source through a resistor. Compared to a single diode at the same current, the total voltage drop across the pair is:
V-I characteristics
Hard
A.Twice the single-diode drop
B.Half the single-diode drop
C. times the single-diode drop
D.Equal to the single-diode drop
Correct Answer: Twice the single-diode drop
Explanation:
Since the same current flows through both series diodes, each develops the same voltage drop as a single diode at that current. The drops add, giving twice the single-diode voltage.
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57The diffusion capacitance of a forward-biased diode is primarily associated with:
Junction capacitance
Hard
A.The parasitic lead inductance
B.The reverse leakage current
C.The immobile ions in the depletion layer
D.Storage of minority charge carriers in the neutral regions
Correct Answer: Storage of minority charge carriers in the neutral regions
Explanation:
Diffusion (storage) capacitance dominates under forward bias and arises from injected minority carriers stored near the junction. It is proportional to forward current and limits high-frequency switching.
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58A half-wave rectifier has a load resistance of and diode forward resistance of , with . The DC output power delivered to the load is approximately:
Half wave rectifiers
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
. . .
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59During the manufacture of a PN junction, the built-in potential barrier increases when:
Construction and Working
Hard
A.The junction cross-sectional area is increased
B.Temperature is raised significantly
C.Doping concentrations on both sides are increased
D.The reverse bias is removed
Correct Answer: Doping concentrations on both sides are increased
Explanation:
The built-in potential rises with higher doping. It is independent of junction area and actually decreases with temperature due to the rapid rise of .
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60A full-wave rectifier and a half-wave rectifier deliver the same peak current . The ratio of the DC output current of the full-wave to that of the half-wave rectifier is:
Full wave rectifiers
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
For full-wave and for half-wave . The ratio is .
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