1What is the simplest camera model that describes the geometric mapping from 3D space to a 2D image without using lenses?
pinhole cameras
Easy
A.Pinhole camera
B.Orthographic camera
C.Spherical camera
D.Stereo camera
Correct Answer: Pinhole camera
Explanation:
The pinhole camera is the most basic camera model. It uses a small hole (pinhole) to let light through, forming an inverted image on the image plane without the need for a lens.
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2In the pinhole camera model, what is the distance between the pinhole (camera center) and the image plane called?
pinhole cameras
Easy
A.Aperture
B.Optical axis
C.Focal length
D.Principal point
Correct Answer: Focal length
Explanation:
The focal length is defined as the perpendicular distance from the camera center (the pinhole) to the image plane.
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3Why are lenses typically used in real cameras instead of simple pinholes?
cameras with lenses
Easy
A.To gather more light while maintaining focus
B.To increase the focal length
C.To completely eliminate all image distortions
D.To convert 3D coordinates to 1D
Correct Answer: To gather more light while maintaining focus
Explanation:
A simple pinhole lets in very little light, resulting in dark or noisy images. Lenses are used to gather a larger amount of light and focus it onto the image plane, allowing for faster exposure times.
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4What is a common optical distortion introduced by lenses where straight lines in the real world appear curved in the image?
cameras with lenses
Easy
A.Radial distortion
B.Chromatic aberration
C.Perspective distortion
D.Motion blur
Correct Answer: Radial distortion
Explanation:
Radial distortion, such as barrel or pincushion distortion, is an optical effect caused by the shape of the lens, which makes straight lines appear curved.
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5What does 'CCD' stand for in the context of digital cameras?
CCD cameras
Easy
A.Computer Centric Diode
B.Central Computation Display
C.Camera Control Device
D.Charge-Coupled Device
Correct Answer: Charge-Coupled Device
Explanation:
CCD stands for Charge-Coupled Device. It is an integrated circuit containing an array of linked capacitors, widely used as an image sensor in digital cameras to convert light into electronic signals.
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6In a CCD camera, the continuous image is sampled into a discrete grid of elements. What are these individual elements called?
CCD cameras
Easy
A.Homographies
B.Voxels
C.Pixels
D.Points at infinity
Correct Answer: Pixels
Explanation:
An image sensor divides the continuous light field into a 2D grid of discrete picture elements, commonly known as pixels.
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7A general projective camera maps 3D world points to 2D image points. What are the dimensions of the projection matrix used for this transformation?
general projective cameras
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
The camera projection matrix is a matrix that maps points from 3D projective space (represented as 4-vectors) to 2D projective space (represented as 3-vectors).
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8Which assumption characterizes an affine camera model (such as an orthographic camera)?
affine cameras
Easy
A.The depth of the object is large compared to its size
B.The camera has an infinite number of pinholes
C.The image plane is a sphere
D.The focal length is zero
Correct Answer: The depth of the object is large compared to its size
Explanation:
An affine camera model assumes that the depth variation of the object is small compared to its distance from the camera, allowing perspective effects to be approximated by parallel lines.
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9What is the primary goal of camera calibration?
camera calibration
Easy
A.To reduce the file size of an image
B.To determine the camera's intrinsic and extrinsic parameters
C.To physically clean the camera lens
D.To increase the resolution of the image
Correct Answer: To determine the camera's intrinsic and extrinsic parameters
Explanation:
Camera calibration is the process of estimating internal (intrinsic) parameters like focal length and optical center, and external (extrinsic) parameters like rotation and translation.
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10Which of the following is considered an INTRINSIC parameter of a camera?
camera calibration
Easy
A.The camera's 3D rotation in the world
B.The principal point (optical center)
C.The lighting of the scene
D.The camera's 3D translation in the world
Correct Answer: The principal point (optical center)
Explanation:
Intrinsic parameters describe the internal characteristics of the camera, such as focal length, principal point, and skew coefficient. Extrinsic parameters describe the camera's position and orientation in the world.
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11In 2-D planar geometry, what geometric entity is represented by the equation ?
planar geometry
Easy
A.A circle
B.A point at infinity
C.A parabola
D.A line
Correct Answer: A line
Explanation:
In 2D planar geometry, the equation represents a straight line.
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12What conceptual geometric elements are added to Euclidean space to form a projective space?
projective spaces
Easy
A.Negative coordinates
B.Points at infinity
C.Multiple origins
D.Complex numbers
Correct Answer: Points at infinity
Explanation:
Projective space extends Euclidean space by adding 'points at infinity', allowing parallel lines to intersect at these points.
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13In a 2D projective space, where do two parallel lines intersect?
projective spaces
Easy
A.At the origin
B.They never intersect
C.At a point at infinity
D.At the principal point
Correct Answer: At a point at infinity
Explanation:
Unlike Euclidean geometry where parallel lines never intersect, in projective geometry, they are defined to intersect at a unique point at infinity (an ideal point).
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14What are the homogeneous (projective) coordinates for a 2D Euclidean point ?
Representation in projective coordinates
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
To convert a 2D Euclidean point to homogeneous coordinates, we simply append a 1 as the third coordinate, resulting in .
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15How do you convert the homogeneous point back to 2D Euclidean coordinates, assuming ?
Representation in projective coordinates
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
To recover Euclidean coordinates from homogeneous coordinates, divide the first two coordinates by the non-zero scale factor .
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16What is a homography?
Homography and its properties
Easy
A.A mapping that turns an image to grayscale
B.A method to calculate focal length without calibration
C.A linear transformation that maps lines to lines between two projective planes
D.A technique to remove noise from an image
Correct Answer: A linear transformation that maps lines to lines between two projective planes
Explanation:
A homography is an invertible transformation from a projective plane to a projective plane that maps straight lines to straight lines.
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17What is the size of a homography matrix used for 2D projective transformations?
Homography and its properties
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
A 2D homography operates on 2D projective points represented as 3-vectors. Therefore, the transformation matrix is a matrix.
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18Although a 2D homography matrix has 9 elements, how many degrees of freedom does it actually possess?
Homography and its properties
Easy
A.8
B.3
C.9
D.6
Correct Answer: 8
Explanation:
A homography matrix has 9 elements but is defined only up to a scale factor. Therefore, it has degrees of freedom.
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19Which geometric transformation is predominantly used to map and align overlapping images into a single panorama in image stitching?
Applications: image stitching
Easy
A.Translation
B.Homography
C.Scaling
D.Reflection
Correct Answer: Homography
Explanation:
Homography relates the pixel coordinates of two images taken from the same camera center (or of a planar scene). This property makes it the core tool for stitching images together.
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20What is the purpose of image rectification in computer vision?
Applications: perspective correction and rectification
Easy
A.To convert an image from color to black and white
B.To add artistic blurring to the background
C.To compress the image size for web transfer
D.To geometrically transform an image to simulate a front-on view and remove perspective distortion
Correct Answer: To geometrically transform an image to simulate a front-on view and remove perspective distortion
Explanation:
Image rectification uses projective transformations to correct perspective distortion, making the image appear as if the camera were facing the plane of interest completely head-on.
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21In a pinhole camera with focal length , a point in 3D space is projected onto the image plane at . If the object moves twice as far from the camera along the Z-axis, what happens to its projected image coordinates?
pinhole cameras
Medium
A.They double
B.They remain the same
C.They are quartered
D.They are halved
Correct Answer: They are halved
Explanation:
The standard projection equations are and . If the depth becomes , the new coordinates become and .
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22If a pinhole camera's principal point is offset by from the origin of the image coordinates, how is the projection of a 3D point modified?
pinhole cameras
Medium
A.,
B.,
C.,
D.,
Correct Answer: ,
Explanation:
The principal point offset shifts the origin of the 2D image plane itself. Thus, the translation is added directly to the projected image coordinates.
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23How does decreasing the aperture size (increasing the f-number) affect a camera with a lens?
cameras with lenses
Medium
A.It increases the depth of field but reduces the light reaching the sensor.
B.It changes the focal length of the lens.
C.It shifts the position of the principal point.
D.It decreases the depth of field and increases the light reaching the sensor.
Correct Answer: It increases the depth of field but reduces the light reaching the sensor.
Explanation:
A smaller aperture restricts the incoming bundle of light rays. This sharpens out-of-focus areas (increasing depth of field) but lets less light through, requiring a longer exposure time.
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24In a CCD camera, if the sensor elements are not perfectly rectangular, which intrinsic parameter accounts for this geometric distortion?
CCD cameras
Medium
A.Focal length
B.Radial distortion coefficient
C.Skew parameter
D.Principal point offset
Correct Answer: Skew parameter
Explanation:
The skew parameter in the camera intrinsic matrix models the angle between the and sensor axes, compensating for pixels that are sheared (non-rectangular).
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25A general finite projective camera is represented by a matrix . How many degrees of freedom does this matrix have?
general projective cameras
Medium
A.11
B.12
C.15
D.9
Correct Answer: 11
Explanation:
The camera matrix contains 12 elements but is defined only up to an overall scale factor in projective geometry. Therefore, it has degrees of freedom.
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26The camera center (in homogeneous coordinates) of a general projective camera matrix can be found by solving which of the following equations?
general projective cameras
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The camera center is the 1D right null space of the camera matrix . All points on a ray passing through the camera center project to an undefined point in the image, yielding .
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27Which of the following is a defining characteristic of an affine camera model compared to a general projective camera?
affine cameras
Medium
A.It accounts for strong perspective foreshortening.
B.Lines are not preserved during projection.
C.The principal plane is situated at infinity.
D.The camera matrix has 11 degrees of freedom.
Correct Answer: The principal plane is situated at infinity.
Explanation:
In an affine camera, projection rays are parallel, meaning the camera center is at infinity. Mathematically, this corresponds to the principal plane (the last row of ) being at infinity, typically represented as .
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28An orthographic projection is a special case of an affine camera. What happens to the apparent size of an object as its depth (distance from the camera) increases in this model?
affine cameras
Medium
A.Its apparent size decreases linearly.
B.Its apparent size remains constant.
C.Its apparent size increases.
D.Its apparent size decreases exponentially.
Correct Answer: Its apparent size remains constant.
Explanation:
Because projection rays in an orthographic camera are perfectly parallel and orthogonal to the image plane, the distance of the object from the camera (depth) does not affect its projected scale.
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29When using the Direct Linear Transformation (DLT) algorithm for camera calibration, what is the minimum number of known 3D-2D point correspondences required to uniquely solve for the general projective camera matrix?
camera calibration
Medium
A.5
B.8
C.6
D.4
Correct Answer: 6
Explanation:
A general projective camera matrix has 11 degrees of freedom. Since each 3D-to-2D point correspondence provides 2 linearly independent equations, a minimum of $5.5$ (rounded up to $6$) points are needed.
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30Which of the following scene features is primarily used to estimate and correct radial distortion in a camera?
camera calibration
Medium
A.The color distribution of the image
B.The illumination intensity across the image
C.The scale of objects at known depths
D.Straight lines in the scene
Correct Answer: Straight lines in the scene
Explanation:
Radial distortion bends straight lines in the real world into curved lines in the image. Algorithms often calibrate radial distortion by finding parameters that force these curved lines to become perfectly straight again.
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31In 2D planar geometry, a line is defined by . In homogeneous coordinates, what is the intersection point of two distinct, non-parallel lines and ?
planar geometry
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
In 2D projective geometry, the intersection of two lines represented as homogeneous 3-vectors and is straightforwardly computed by their cross product: .
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32What does the homogeneous coordinate represent in 2D planar geometry?
planar geometry
Medium
A.A line at infinity.
B.The origin of the Euclidean plane.
C.A point at infinity (an ideal point).
D.A point on the x-axis.
Correct Answer: A point at infinity (an ideal point).
Explanation:
A point in with a zero as its last coordinate cannot be normalized to standard Euclidean coordinates (division by zero). It represents a direction or a point at infinity, known as an ideal point.
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33If a 3D Euclidean point is mapped into a projective space, what is the dimension of the resulting projective space , and how many coordinates are used to represent the point?
projective spaces
Medium
A. using 3 coordinates
B. using 4 coordinates
C. using 4 coordinates
D. using 3 coordinates
Correct Answer: using 4 coordinates
Explanation:
A 3D Euclidean space embeds into the 3-dimensional projective space . Points in are mathematically represented by 4-dimensional homogeneous coordinates, typically .
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34Given a 3D point in homogeneous coordinates , what is its equivalent representation in standard 3D Euclidean coordinates?
Representation in projective coordinates
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
To convert from homogeneous coordinates to Euclidean coordinates, divide the first three components by the final scale component (). Thus, .
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35In 2D projective coordinates, what is the mathematical formulation for the line passing through two points and ?
Representation in projective coordinates
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Due to the principle of duality in 2D projective geometry, just as the intersection of two lines is their cross product, the line connecting two points is found by the cross product of the two point vectors.
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36A 2D homography is a projective transformation mapping points from one plane to another. How many degrees of freedom does a general 2D homography matrix have?
Homography and its properties
Medium
A.9
B.4
C.6
D.8
Correct Answer: 8
Explanation:
A 2D homography is represented by a matrix with 9 elements. Since it operates in projective space, it is defined up to a non-zero scale factor, resulting in degrees of freedom.
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37Which geometric property is strictly preserved under a general homography (projective) transformation?
Homography and its properties
Medium
A.Angles between lines
B.Ratios of distances
C.Collinearity of points
D.Parallelism of lines
Correct Answer: Collinearity of points
Explanation:
A general projective transformation preserves collinearity, meaning straight lines map to straight lines. However, it does not generally preserve parallelism, angles, or distance ratios (except for the cross-ratio).
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38Under which specific condition can a 2D homography perfectly relate two overlapping images of a general, non-planar 3D scene taken by a camera?
Applications: image stitching
Medium
A.The camera has a very wide field of view.
B.The camera undergoes pure rotation around its optical center.
C.The camera moves freely but the scene contains high depth variation.
D.The camera undergoes a pure translation.
Correct Answer: The camera undergoes pure rotation around its optical center.
Explanation:
Two images of a 3D scene can be perfectly mapped to one another via a 2D homography if the camera only rotates around its optical center (no translation), because parallax effects are avoided.
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39In perspective correction, to remove projective distortion and map an image back to an affine frame, where must the image of the line at infinity be mapped?
Applications: perspective correction and rectification
Medium
A.To the principal point
B.To its canonical position
C.To the origin
D.To the x-axis
Correct Answer: To its canonical position
Explanation:
Projective distortion occurs because the line at infinity is mapped to a finite, visible line in the image. Affine rectification requires applying a homography that maps this finite line back to .
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40How can vanishing points be practically used to rectify a perspective image of a building facade?
Applications: perspective correction and rectification
Medium
A.By rotating the image until the vanishing points align with the x and y axes.
B.By calculating the cross product of two vanishing points to find the image of the line at infinity, then transforming it to .
C.By mapping the vanishing points to the center of the camera matrix.
D.By translating the image such that the vanishing points are moved to the principal point.
Correct Answer: By calculating the cross product of two vanishing points to find the image of the line at infinity, then transforming it to .
Explanation:
Sets of parallel lines on a plane intersect at vanishing points in the image. The cross product of two such points defines the vanishing line. Mapping this line to infinity performs an affine rectification.
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41A projective camera matrix is given by , where is a non-singular matrix and is a 3-vector. What is the geometrical interpretation of the 1D right null-space of ?
pinhole cameras
Hard
A.It corresponds to the image of the absolute conic on the focal plane.
B.It represents the 3D coordinates of the camera center in homogeneous coordinates.
C.It represents the principal point on the image plane in homogeneous coordinates.
D.It defines the direction of the optical axis in the world coordinate system.
Correct Answer: It represents the 3D coordinates of the camera center in homogeneous coordinates.
Explanation:
The right null-space of is a 4-vector such that . For a finite camera , the homogeneous vector satisfies this condition. This point is the camera center, which cannot be projected onto the image plane because a ray from the center to itself is undefined.
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42Suppose a pinhole camera is modified such that the pinhole is shifted by a vector parallel to the image plane, while the image plane itself remains fixed. How does the new camera calibration matrix relate to the original matrix ?
pinhole cameras
Hard
A.The principal point is shifted to , altering the third column of .
B.The skew parameter becomes non-zero, proportional to .
C.The focal lengths are scaled by , altering the diagonal of .
D.The principal point is shifted to , altering the third column of .
Correct Answer: The principal point is shifted to , altering the third column of .
Explanation:
Moving the pinhole by while keeping the image sensor fixed effectively moves the orthogonal projection of the pinhole onto the image sensor in the opposite relative direction from the perspective of the sensor's coordinate system, thus shifting the principal point by .
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43In the presence of radial distortion modeled by , straight lines in the 3D world that do not pass through the optical axis project to curves. If a camera exhibits severe barrel distortion (), what happens to the curvature of the projected line as its shortest distance from the principal point increases?
cameras with lenses
Hard
A.The projected curve remains a straight line but experiences non-uniform scaling.
B.The projected curve bows outwards away from the principal point, and its maximum curvature decreases.
C.The projected curve bows inwards towards the principal point, and its maximum curvature increases.
D.The projected curve bows outwards away from the principal point, and its maximum curvature increases.
Correct Answer: The projected curve bows outwards away from the principal point, and its maximum curvature increases.
Explanation:
Barrel distortion () causes points to be displaced towards the principal point. For a straight line not passing through the center, the points furthest from the center are displaced inward more than points closest to the center. This causes the line to bow outwards, and this effect (curvature) worsens as the line is located further from the principal point.
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44For a CCD camera, the skew parameter in the intrinsic matrix is non-zero. If the angle between the and pixel axes on the sensor array is , what is the exact expression for ?
CCD cameras
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
When the sensor grid axes are not exactly orthogonal (skewed by an angle ), the and coordinates become coupled. The standard derivation maps the skewed axes to an orthogonal coordinate system, introducing a skew factor in the intrinsic matrix , where is the focal length in terms of -pixels.
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45Let be a projection matrix of a general projective camera. To determine the intrinsic parameters and rotation , we decompose the left submatrix . Which decomposition is strictly required, and what constraint must be enforced on ?
general projective cameras
Hard
A.QR decomposition; must be an orthogonal matrix with determinant .
B.RQ decomposition; must be upper triangular with strictly positive diagonal elements.
C.Singular Value Decomposition (SVD); the singular values forming must be sorted in descending order.
D.Cholesky decomposition; must be a symmetric positive-definite matrix.
Correct Answer: RQ decomposition; must be upper triangular with strictly positive diagonal elements.
Explanation:
The matrix is formed by . Since is an upper triangular matrix representing intrinsic parameters (where diagonal elements like focal length must be positive to fix the ambiguity) and is an orthogonal rotation matrix, an RQ decomposition (not QR) is uniquely suited to factor into an upper triangular matrix and an orthogonal matrix.
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46Given two distinct pixels and on the image plane of a calibrated camera with intrinsic matrix , the angle between their corresponding back-projected 3D rays is given by . What does the matrix represent?
general projective cameras
Hard
A.The Essential matrix, capturing relative rotation and translation.
B.The Image of the Absolute Conic (IAC), given by .
C.The dual Absolute Quadric, given by .
D.The Fundamental matrix, mapping points to epipolar lines.
Correct Answer: The Image of the Absolute Conic (IAC), given by .
Explanation:
Angles between rays in 3D can be measured using the Absolute Conic. The projection of the Absolute Conic onto the image plane is the Image of the Absolute Conic (IAC), denoted by . It acts as a metric on the projective plane to measure angles between incident rays.
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47Consider an affine camera matrix . Which of the following mathematical properties strictly differentiates an affine camera from a general projective camera regarding the camera center?
affine cameras
Hard
A.The rank of is strictly 2, preventing depth recovery from any single image.
B.The left submatrix of is exactly the identity matrix, restricting the camera to parallel projection.
C.The right null-space of is a 4-vector of the form , meaning the camera center lies on the plane at infinity.
D.The camera center resides at the world origin , forcing the translation vector to be zero.
Correct Answer: The right null-space of is a 4-vector of the form , meaning the camera center lies on the plane at infinity.
Explanation:
An affine camera performs parallel projection. Geometrically, parallel rays intersect at infinity. Thus, the camera center of an affine camera is an ideal point (a point on the plane at infinity), represented in homogeneous coordinates with the fourth coordinate being zero.
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48A generic affine camera maps 3D points to 2D image points using a matrix. How many degrees of freedom does a general affine camera matrix have?
affine cameras
Hard
A.8 degrees of freedom
B.15 degrees of freedom
C.11 degrees of freedom
D.12 degrees of freedom
Correct Answer: 8 degrees of freedom
Explanation:
A general projective camera has 11 degrees of freedom (a matrix up to scale). An affine camera restricts the last row to be . The remaining elements consist of the top two rows (8 elements). Since scale is fixed by the 1 in the last row, the matrix has exactly 8 degrees of freedom.
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49When calibrating a camera using the Direct Linear Transformation (DLT) algorithm, we stack point correspondence equations to form . If all 3D calibration points happen to lie on a single 3D plane, what is the rank of the matrix (assuming noise-free correspondences), and what consequence does this have?
camera calibration
Hard
A.Rank 8; the null space is 4-dimensional, making the full camera matrix unrecoverable without additional non-coplanar points.
B.Rank 9; the focal length and principal point cannot be distinguished, leading to ambiguity in the intrinsic matrix .
C.Rank 10; the camera center is constrained to a line, allowing only a 1-parameter family of solutions for .
D.Rank 11; the camera matrix is uniquely recoverable up to scale because planar points impose stricter homographic constraints.
Correct Answer: Rank 8; the null space is 4-dimensional, making the full camera matrix unrecoverable without additional non-coplanar points.
Explanation:
If all calibration points are coplanar, there is a projective transformation mapping the 3D plane directly to the 2D image. This mapping is a homography (8 DOF). Consequently, the matrix in DLT only achieves a rank of 8, leaving a 4-dimensional null space. Thus, the full 11-DOF camera matrix cannot be uniquely determined (up to scale) from a single plane.
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50In Zhang's camera calibration method, each image of a planar checkerboard pattern provides constraints on the Image of the Absolute Conic (IAC) denoted by . If and are the first two columns of the homography mapping the pattern to the image, which of the following equations correctly expresses the orthogonal constraints of the checkerboard axes?
camera calibration
Hard
A. and
B. and
C. and
D. and
Correct Answer: and
Explanation:
In Zhang's method, the columns and of the homography are the projections of the orthogonal and equal-length unit vectors of the model plane. Using the absolute conic to evaluate angles and lengths in the image plane, orthogonality implies , and equal scale implies .
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51Four distinct collinear points have a cross-ratio . If a projective transformation permutes these points such that their new cross ratio is equal to , which permutation of the points occurred?
planar geometry
Hard
A.Swapping and , while keeping and fixed.
B.Swapping and , or swapping and .
C.A cyclic permutation of all four points .
D.Swapping and , while keeping and fixed.
Correct Answer: Swapping and , while keeping and fixed.
Explanation:
The cross-ratio is given by . Permuting the points generates up to six distinct cross-ratios. Swapping the middle two points, yielding , changes the cross-ratio to . Swapping and would yield .
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52A non-degenerate conic is transformed under a 2D projective transformation represented by an invertible matrix . If a point maps to , how does the dual conic , which represents the envelope of tangent lines to , transform?
planar geometry
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
A point transforms as . A line transforms as . The dual conic consists of lines such that . Substituting gives . Thus, the transformed dual conic is .
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53In , the line at infinity is . What is the geometric locus of points defined by the intersection of an arbitrary circle with in this projective space?
projective spaces
Hard
A.The circular points (ideal points) and .
B.The origin of the affine plane .
C.The real points and , representing orthogonal directions.
D.A set of continuously varying points on depending on the circle's radius.
Correct Answer: The circular points (ideal points) and .
Explanation:
In , any circle defined by translates in homogeneous coordinates to a conic. Intersecting this conic with the line at infinity yields , which factors into . This gives the imaginary circular points and .
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54Consider a 3D projective space . Which of the following best describes the properties of the Absolute Dual Quadric ?
projective spaces
Hard
A.It is a rank 4 quadric, invariant to all projective transformations, consisting of the locus of all camera centers.
B.It is a rank 2 quadric, uniquely defining the plane at infinity, and is invariant only under Euclidean transformations.
C.It is a rank 3 point quadric that defines the absolute conic and is invariant under affine transformations.
D.It is a rank 3 quadric envelope, consisting of planes tangent to the absolute conic, and it is invariant strictly under 3D similarity transformations.
Correct Answer: It is a rank 3 quadric envelope, consisting of planes tangent to the absolute conic, and it is invariant strictly under 3D similarity transformations.
Explanation:
In , the Absolute Dual Quadric is a dual quadric (representing an envelope of planes) of rank 3. It geometrically encapsulates both the absolute conic and the plane at infinity. A fundamental property is that is invariant if and only if the transformation is a similarity (rotation, translation, and isotropic scaling).
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55Two parallel lines on the Euclidean plane are given by and . When represented in homogeneous coordinates in , what is the exact homogeneous coordinate of their intersection point?
Representation in projective coordinates
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
In homogeneous coordinates, the lines are represented by vectors and . Their intersection is the cross product . Computing this gives . Normalizing this vector by dividing by 7 yields . This point lies on the line at infinity.
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56In , a line can be represented by a Plücker matrix , which is a skew-symmetric matrix. If two 3D points in homogeneous coordinates are and , how is constructed from and , and what is its rank?
Representation in projective coordinates
Hard
A., and it has rank 4.
B. (generalized cross product), and it has rank 3.
C., and it has rank 2.
D., and it has rank 2.
Correct Answer: , and it has rank 2.
Explanation:
A line in passing through two points and can be defined by the Plücker matrix . This matrix is skew-symmetric by definition. Because it is formed by the outer product of two distinct points, its non-zero eigenspace is spanned by and , resulting in exactly rank 2.
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57Suppose a camera captures a planar scene , meaning points on the plane satisfy . If the camera moves by a rotation and translation , with an intrinsic matrix , the transformation between the old image coordinates and new image coordinates is given by a homography . What is the closed-form expression for ?
Homography and its properties
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
For a plane equation , we have . The new 3D point is . Projecting into the camera with intrinsics , the relation between image points and becomes , which is the homography induced by the plane.
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58A projective homography matrix is estimated between two images taken by the same camera undergoing purely rotational motion around its camera center. Let the rotation angle be . If the intrinsic matrix is known, what are the eigenvalues of the conjugate matrix up to a common non-zero scale factor?
Homography and its properties
Hard
A., ,
B., ,
C., ,
D., ,
Correct Answer: , ,
Explanation:
For pure rotation, the homography is . Therefore, . The matrix is a 3D rotation matrix (an orthogonal matrix with determinant 1). The eigenvalues of any rotation matrix corresponding to an angle are exactly and .
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59When performing image stitching on a sequence of overlapping images taken by a freely translating and rotating camera, a single 2D projective homography generally fails to perfectly align an image pair. However, perfect alignment via homography is theoretically guaranteed regardless of scene depth variations under which specific condition?
Applications: image stitching
Hard
A.The intrinsic matrix of the camera remains strictly constant.
B.The camera optical centers for both views are perfectly coincident.
C.The scene is strictly constrained to an affine space.
D.The baseline between the two views is exactly orthogonal to the optical axis.
Correct Answer: The camera optical centers for both views are perfectly coincident.
Explanation:
Parallax (depth-dependent displacement of features) only occurs when the camera center translates between views. If the camera purely rotates (translation ), the optical center remains stationary. The mapping between two such views is governed entirely by a homography , which is entirely independent of the 3D depth of the scene points, allowing flawless stitching.
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60In stereo vision, image rectification applies 2D projective homographies and to a pair of images to make corresponding epipolar lines collinear and horizontal. If is the epipole in the first unrectified image, what is the strict algebraic constraint on to achieve standard horizontal epipolar lines?
Applications: perspective correction and rectification
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Rectification ensures that epipolar lines become horizontal scanlines. For a horizontal epipolar line, all epipolar lines intersect at horizontal infinity. Therefore, the rectifying homography must map the original epipole (the intersection of all epipolar lines in the unrectified image) to the ideal point on the -axis, which in homogeneous coordinates is .