1Which component of a data communication system sends the data?
Basics of Data Communications
Easy
A.Receiver
B.Protocol
C.Sender
D.Medium
Correct Answer: Sender
Explanation:
The sender is the device that originates and transmits the data.
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2What is a protocol in data communication?
Basics of Data Communications
Easy
A.A type of network cable
B.A device that stores messages
C.A set of communication rules
D.A signal that continuously changes its amplitude during transmission
Correct Answer: A set of communication rules
Explanation:
A protocol defines the rules that devices follow when exchanging data.
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3Which guided medium consists of pairs of insulated copper wires twisted together?
Guided Transmission Media
Easy
A.Microwave link
B.Coaxial cable
C.Optical fiber
D.Twisted-pair cable
Correct Answer: Twisted-pair cable
Explanation:
A twisted-pair cable uses twisted insulated copper wires to carry signals.
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4Which transmission medium carries data as pulses of light?
Guided Transmission Media
Easy
A.Twisted-pair cable
B.Coaxial cable
C.A copper conductor surrounded by insulation and metallic shielding
D.Optical fiber
Correct Answer: Optical fiber
Explanation:
Optical fiber transmits data using pulses of light through glass or plastic fibers.
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5Which unguided transmission medium commonly requires a line-of-sight path?
Unguided Transmission Media
Easy
A.Radio waves
B.Microwaves
C.Twisted-pair signals
D.Low-frequency signals that always follow the curvature of Earth
Correct Answer: Microwaves
Explanation:
Terrestrial microwave communication commonly requires an unobstructed line-of-sight path.
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6Which technology uses electromagnetic waves to transmit data without a physical cable?
Unguided Transmission Media
Easy
A.Twisted-pair communication
B.Coaxial communication
C.Optical fiber
D.Wireless communication
Correct Answer: Wireless communication
Explanation:
Wireless communication sends data through air or space using electromagnetic waves.
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7What is the gradual loss of signal strength during transmission called?
Transmission Impairments and Performance
Easy
A.Distortion
B.Attenuation
C.Propagation
D.Noise
Correct Answer: Attenuation
Explanation:
Attenuation is the reduction in signal strength as the signal travels through a medium.
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8What does bandwidth commonly describe in a communication channel?
Transmission Impairments and Performance
Easy
A.The channel's data-carrying capacity
B.The physical length of the channel
C.The number of connected computers
D.The complete procedure used to correct every damaged frame automatically
Correct Answer: The channel's data-carrying capacity
Explanation:
Bandwidth indicates how much data a channel can carry in a given time.
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9What is the basic unit of data handled by the data link layer?
Elementary Data Link Protocols
Easy
A.Segment
B.Bit
C.Packet
D.Frame
Correct Answer: Frame
Explanation:
The data link layer organizes transmitted data into units called frames.
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10What is the main purpose of flow control at the data link layer?
Elementary Data Link Protocols
Easy
A.To assign network addresses
B.To select a physical cable
C.To prevent receiver overload
D.To increase the transmitter's power whenever a frame crosses a router
Correct Answer: To prevent receiver overload
Explanation:
Flow control prevents a fast sender from overwhelming a slower receiver.
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11What is the purpose of error detection in data communication?
Error Detection and Correction
Easy
A.To increase cable length
B.To convert all analog signals into optical signals before transmission
C.To identify corrupted data
D.To assign device names
Correct Answer: To identify corrupted data
Explanation:
Error detection determines whether transmitted data was changed or damaged.
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12Which method asks the sender to transmit data again after an error is detected?
Error Detection and Correction
Easy
A.Automatic Repeat reQuest
B.Circuit switching
C.Frequency division
D.Signal modulation
Correct Answer: Automatic Repeat reQuest
Explanation:
Automatic Repeat reQuest (ARQ) uses acknowledgments and retransmissions to recover from errors.
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13What can a standard Hamming code do when a single-bit error occurs?
Hamming code
Easy
A.Delete the entire message
B.Locate and correct it
C.Only detect its presence
D.Correct every possible combination of multiple damaged bits in the codeword
Correct Answer: Locate and correct it
Explanation:
A standard Hamming code can identify the position of a single-bit error and correct it.
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14Where are parity bits commonly placed in a Hamming codeword?
Hamming code
Easy
A.Only at the end of the codeword
B.At positions that are powers of two
C.Only between two consecutive data bits
D.At positions that are multiples of three
Correct Answer: At positions that are powers of two
Explanation:
Hamming parity bits are placed at positions .
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15What does CRC stand for?
CRC
Easy
A.Central Routing Control
B.Cyclic Redundancy Check
C.Code Recovery Channel
D.Cyclic Routing Calculation
Correct Answer: Cyclic Redundancy Check
Explanation:
CRC stands for Cyclic Redundancy Check, an error-detection technique.
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16In CRC, what is appended to the original data before transmission?
CRC
Easy
A.A parity matrix
B.A calculated remainder
C.A receiver address
D.A complete duplicate of every data bit in the original message
Correct Answer: A calculated remainder
Explanation:
CRC appends the remainder from polynomial division to the data.
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17In even parity, what must the total number of bits be?
Parity
Easy
A.Zero
B.Prime
C.Even
D.Odd
Correct Answer: Even
Explanation:
Even parity sets the parity bit so that the total number of bits is even.
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18Which type of error can a single parity bit reliably detect?
Parity
Easy
A.Every burst error
B.Every two-bit error
C.A single-bit error
D.Any number of errors occurring anywhere in an unlimited data stream
Correct Answer: A single-bit error
Explanation:
A single changed bit always alters the expected parity, so it is detected.
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19How is a checksum generally used by a receiver?
Checksum
Easy
A.It permanently stores every received frame for later manual examination
B.It recalculates and compares the value
C.It changes the frame address
D.It increases the signal frequency
Correct Answer: It recalculates and compares the value
Explanation:
The receiver recalculates the checksum and compares it with the transmitted checksum.
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20What does a checksum mainly help detect?
Checksum
Easy
A.Errors in transmitted data
B.The physical cable type
C.The sender's location
D.The maximum number of devices that can be installed in a building
Correct Answer: Errors in transmitted data
Explanation:
A checksum helps determine whether data was altered during transmission.
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21A sender transmits an file over a link. Assuming bytes and ignoring all delays except transmission delay, how long does transmission take?
Basics of Data Communications
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The file contains bits. Thus, the transmission delay is s, or .
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22A full-duplex link is rated at . What transmission capability does this rating provide?
Basics of Data Communications
Medium
A. in each direction simultaneously
B. shared between both directions
C. in each direction simultaneously
D. in each direction simultaneously
Correct Answer: in each direction simultaneously
Explanation:
Full-duplex communication allows simultaneous transmission in both directions, with each direction operating at the stated rate.
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23Two buildings in an industrial area must be connected using a high-speed cable. The route passes close to heavy electrical machinery and the buildings have different ground potentials. Which medium is most suitable?
Guided Transmission Media
Medium
A.Unshielded twisted-pair cable
B.Multimode optical fiber
C.Baseband coaxial cable
D.Shielded twisted-pair cable
Correct Answer: Multimode optical fiber
Explanation:
Optical fiber is immune to electromagnetic interference and does not conduct electricity, so it also avoids problems caused by different ground potentials.
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24Which design feature of twisted-pair cable primarily reduces crosstalk and externally induced electromagnetic noise?
Guided Transmission Media
Medium
A.Adding more connectors
B.Using identical bit patterns
C.Twisting the wire pairs
D.Increasing conductor thickness
Correct Answer: Twisting the wire pairs
Explanation:
Twisting causes interference to affect both conductors similarly, allowing a differential receiver to cancel much of the induced noise.
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25A terrestrial microwave link must connect two stations separated by a long distance with a hill between them. Which change is most likely to make the link reliable?
Unguided Transmission Media
Medium
A.Increase the wavelength without changing the path
B.Reduce the antenna height
C.Install a repeater on the hill
D.Replace directional antennas with omnidirectional antennas
Correct Answer: Install a repeater on the hill
Explanation:
Terrestrial microwaves generally require a line-of-sight path. A repeater on the hill can receive and retransmit the signal across the obstruction.
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26What is the approximate wavelength of a radio signal with frequency , assuming a propagation speed of ?
Unguided Transmission Media
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Using , the wavelength is .
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27A signal passes through an amplifier with a gain of and then through two cable sections with losses of and . What is the net gain?
Transmission Impairments and Performance
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Decibel gains and losses are added algebraically. The net gain is .
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28A channel has bandwidth and a signal-to-noise ratio of . Using Shannon capacity, what is its approximate maximum data rate?
Transmission Impairments and Performance
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
corresponds to an SNR of . Therefore, .
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29A -byte packet is sent over a link spanning . If the propagation speed is , what is the total transmission-plus-propagation delay?
Transmission Impairments and Performance
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Transmission delay is , and propagation delay is . Their sum is .
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30A stop-and-wait protocol sends frames with a transmission time of . The one-way propagation delay is , and acknowledgment transmission time is negligible. What is the approximate link utilization?
Elementary Data Link Protocols
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
One cycle takes . The sender transmits useful data for , so utilization is .
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31In an alternating-bit stop-and-wait protocol, a receiver gets another frame with the same sequence number as the previously accepted frame. What should the receiver normally do?
Elementary Data Link Protocols
Medium
A.Discard it and resend the acknowledgment
B.Store it until a different frame arrives
C.Deliver it and increment the sequence number
D.Request retransmission of the previous frame
Correct Answer: Discard it and resend the acknowledgment
Explanation:
The repeated sequence number indicates a duplicate, usually caused by a lost acknowledgment. The receiver discards the duplicate but acknowledges it again.
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32A Go-Back-N protocol uses a -bit sequence number field. What is the largest sender window that avoids ambiguity after sequence numbers wrap around?
Elementary Data Link Protocols
Medium
A. frames
B. frames
C. frames
D. frames
Correct Answer: frames
Explanation:
With sequence bits, Go-Back-N permits a maximum sender window of . For , this is frames.
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33A codeword is protected by one even-parity bit. During transmission, exactly two bits of the complete codeword are inverted. What will the parity check indicate?
Parity
Medium
A.The error will always be corrected
B.The codeword will have odd parity
C.The error will always remain undetected
D.Only the first error will be detected
Correct Answer: The error will always remain undetected
Explanation:
Inverting two bits preserves the overall evenness or oddness of the number of s. A single parity bit therefore cannot detect any two-bit error.
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34A block code has a minimum Hamming distance of . Which capability does the code have?
Error Detection and Correction
Medium
A.Detect up to errors or correct errors
B.Detect up to error or correct errors
C.Detect up to errors or correct error
D.Detect up to errors or correct errors
Correct Answer: Detect up to errors or correct error
Explanation:
A code with minimum distance detects up to errors and corrects up to errors.
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35How many parity bits are required for a Hamming code containing data bits and capable of correcting one-bit errors?
Hamming code
Medium
A. parity bits
B. parity bits
C. parity bits
D. parity bits
Correct Answer: parity bits
Explanation:
The number of parity bits must satisfy . For , gives .
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36In a Hamming code using even parity, parity bits occupy positions , , and . If data bits are placed in positions , , , and , what is the resulting codeword from position to ?
Hamming code
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Even-parity checks give , , and . Positions through are therefore .
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37A sender uses the CRC generator for the dataword . What remainder is obtained after appending three zeros and performing modulo-2 division?
CRC
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
Dividing the augmented dataword by the generator using modulo-2 division produces the three-bit remainder .
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38A CRC generator polynomial has degree and includes both its highest-degree and constant terms. Which burst errors are guaranteed to be detected?
CRC
Medium
A.All burst errors of length at most
B.All burst errors of every possible length
C.All burst errors of length at most
D.All burst errors of length at most
Correct Answer: All burst errors of length at most
Explanation:
A CRC with a generator of degree detects every burst error whose length is at most . Here, .
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39Using an -bit one's-complement checksum, what checksum is produced for the two words and ?
Checksum
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The sum is . Taking the one's complement gives .
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40When verifying a one's-complement checksum, a receiver adds all received data words and the checksum using end-around carry. Which result indicates that no error was detected?
Checksum
Medium
A.A word containing all s
B.A word containing all s
C.A carry without a final sum
D.A sum equal to the checksum
Correct Answer: A word containing all s
Explanation:
For a valid one's-complement checksum, adding the data and checksum produces an all-s result. Its complement is therefore zero.
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41A node begins transmitting a -byte frame over a Mbps link of length km. The propagation speed is m/s, and processing and queuing delays are negligible. How long after transmission begins does the last bit arrive at the destination?
Basics of Data Communications
Hard
A. ms
B. ms
C. ms
D. ms
Correct Answer: ms
Explanation:
Transmission delay is ms, and propagation delay is ms. Their sum is ms.
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42A modem transmits -QAM symbols at kbaud. Exactly one of every transmitted symbols is a pilot symbol carrying no user data. Ignoring all other overhead, what is the net user bit rate?
Basics of Data Communications
Hard
A. kbps
B. kbps
C. kbps
D. kbps
Correct Answer: kbps
Explanation:
Each data symbol carries bits. The net rate is bps.
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43A lossless transmission line is terminated by a purely resistive load. What fraction of the incident power is delivered to the load?
Guided Transmission Media
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The reflection coefficient is . The reflected power fraction is , so the delivered fraction is .
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44A step-index optical fiber has core radius and numerical aperture . At wavelength , which conclusion follows from its normalized frequency ?
Guided Transmission Media
Hard
A., so the fiber is multimode
B., so the fiber is single-mode
C., so the fiber is multimode
D., so the fiber is single-mode
Correct Answer: , so the fiber is single-mode
Explanation:
The normalized frequency is . A step-index fiber is single-mode when .
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45A free-space radio link changes its carrier frequency from GHz to GHz while distance, transmit power, and dimensionless antenna gains remain unchanged. By approximately how much does the received power change?
Unguided Transmission Media
Hard
A.It decreases by dB
B.It decreases by dB
C.It increases by dB
D.It increases by dB
Correct Answer: It decreases by dB
Explanation:
Free-space path loss changes by dB. With fixed dimensionless antenna gains, received power therefore decreases by that amount.
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46Using the approximate line-of-sight formula , what is the maximum direct-path distance between antennas of heights m and m?
Unguided Transmission Media
Hard
A. km
B. km
C. km
D. km
Correct Answer: km
Explanation:
The distance is km, or approximately km.
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47A noiseless signaling scheme uses distinct signal levels over a kHz channel. The actual channel has an SNR of dB. Considering both Nyquist and Shannon limits, what is the highest theoretical data rate?
Transmission Impairments and Performance
Hard
A. kbps
B. kbps
C. kbps
D. kbps
Correct Answer: kbps
Explanation:
Nyquist gives kbps. Shannon gives kbps. The tighter limit is kbps.
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48A transmitter outputs dBm. The path includes a dB cable loss, an dBi transmitting antenna, an dB propagation loss, and an dBi receiving antenna. If receiver noise power is dBm, what is the received SNR?
Transmission Impairments and Performance
Hard
A. dB
B. dB
C. dB
D. dB
Correct Answer: dB
Explanation:
Received power is dBm. Thus, dB.
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49A stop-and-wait protocol sends -byte frames over a Mbps link with a one-way propagation delay of ms. ACK transmission time, processing time, and errors are negligible. What is the sender's link utilization?
Elementary Data Link Protocols
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Frame transmission takes ms. A cycle takes ms, so utilization is .
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50In an alternating-bit protocol, the receiver correctly accepts frame , but its ACK is lost. The sender times out and retransmits frame . What must the receiver do?
Elementary Data Link Protocols
Hard
A.Discard the duplicate and remain silent until frame arrives
B.Deliver the duplicate and transmit an ACK for frame
C.Discard the duplicate and retransmit the ACK for frame
D.Deliver the duplicate and retransmit the ACK for frame
Correct Answer: Discard the duplicate and retransmit the ACK for frame
Explanation:
The sequence bit identifies the retransmission as a duplicate. The receiver must not redeliver it, but it must repeat the ACK so the sender can advance.
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51Frames use a -bit sequence number field. To avoid ambiguity after sequence-number wraparound, what are the maximum sender-window sizes for Go-Back-N and Selective Repeat, respectively?
Elementary Data Link Protocols
Hard
A. for Go-Back-N and for Selective Repeat
B. for Go-Back-N and for Selective Repeat
C. for Go-Back-N and for Selective Repeat
D. for Go-Back-N and for Selective Repeat
Correct Answer: for Go-Back-N and for Selective Repeat
Explanation:
With bits, Go-Back-N permits at most outstanding frames, while Selective Repeat permits at most . For , these are and .
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52A block code has minimum Hamming distance . If a received word may contain two unknown bit errors plus erasures whose positions are known, what is the largest for which correction is guaranteed?
Error Detection and Correction
Hard
A. erasure
B. erasures
C. erasures
D. erasures
Correct Answer: erasures
Explanation:
Correction is guaranteed when . With , , so the largest possible value is .
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53Using a Hamming code with even parity, parity bits at positions , , and , and data bits placed in positions , , , and , what codeword is produced?
Hamming code
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The parity bits are , , and . Positions through therefore contain .
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54In a SECDED Hamming code, a received word has a nonzero Hamming syndrome, but the overall parity check indicates even parity. Assuming at most two bits were altered, how should the decoder classify the result?
Hamming code
Hard
A.A single-bit error occurred at the syndrome position
B.The overall parity bit alone is erroneous and should be flipped
C.No error occurred, so the word should be accepted
D.A double-bit error occurred and is not safely correctable
Correct Answer: A double-bit error occurred and is not safely correctable
Explanation:
A nonzero syndrome indicates an error in the Hamming-protected positions. Even overall parity means an even number of bits changed; under the two-error assumption, this is a detected double-bit error.
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55A message has data bits. What is the minimum number of check bits required to construct a SECDED code using Hamming parity bits plus one overall parity bit?
Hamming code
Hard
A. check bits, giving a -bit codeword
B. check bits, giving a -bit codeword
C. check bits, giving a -bit codeword
D. check bits, giving a -bit codeword
Correct Answer: check bits, giving a -bit codeword
Explanation:
Seven Hamming bits suffice because . SECDED requires one additional overall parity bit, giving check bits and total bits.
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56The dataword is protected by the CRC generator . What remainder is appended to the dataword?
CRC
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Dividing followed by four zeros by generator using modulo- division produces the four-bit remainder .
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57A CRC uses generator polynomial . Which error-detection guarantee is valid for every protected frame?
CRC
Hard
A.Every two-bit error at any separation is detected
B.Every error containing an odd number of flipped bits is detected
C.Every burst error of length at most is detected
D.Every burst error of length at most is detected
Correct Answer: Every burst error of length at most is detected
Explanation:
A generator of degree detects every burst error of length at most . Here . The polynomial lacks the factors needed to guarantee the other listed cases.
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58A block uses even two-dimensional parity with one parity bit per row and one per column. Which data-bit error pattern can pass both sets of parity checks undetected?
Parity
Hard
A.Three flipped bits forming three corners of a rectangle
B.Four flipped bits distributed across four rows and one column
C.Four flipped bits located at all corners of a rectangle
D.Two flipped bits in one row but different columns
Correct Answer: Four flipped bits located at all corners of a rectangle
Explanation:
At the four corners of a rectangle, each affected row and each affected column contains exactly two flipped bits. All row and column parities therefore remain even.
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59Using an -bit one's-complement checksum with end-around carry, what checksum is generated for the words , , and ?
Checksum
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
, which wraps to . Adding gives , whose one's complement is .
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60A checksum is computed solely as the one's-complement sum of fixed-size data words, with no position-dependent fields. Which corruption is guaranteed to preserve the checksum?
Checksum
Hard
A.Incrementing one data word without changing the others
B.Rotating every data word left by one bit position
C.Complementing one data word without changing the others
D.Reordering the data words without changing their values
Correct Answer: Reordering the data words without changing their values
Explanation:
One's-complement addition is commutative and associative, so changing only the order of the words leaves their sum and checksum unchanged.
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