1At absolute zero temperature (), an intrinsic semiconductor behaves as a/an:
A.Perfect conductor
B.Insulator
C.Superconductor
D.Variable resistor
Correct Answer: Insulator
Explanation:At absolute zero, all electrons are tightly bound to the atoms in the covalent bonds, leaving no free charge carriers in the conduction band. Hence, it behaves as a perfect insulator.
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2When a pure semiconductor is doped with a pentavalent impurity, it becomes a/an:
A.p-type semiconductor
B.n-type semiconductor
C.Intrinsic semiconductor
D.Insulator
Correct Answer: n-type semiconductor
Explanation:Pentavalent impurities (like Phosphorus or Arsenic) have five valence electrons. Four form covalent bonds, and the fifth becomes a free electron, creating an n-type (negative) semiconductor.
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3In a p-type semiconductor, the majority charge carriers are:
A.Electrons
B.Holes
C.Positive ions
D.Negative ions
Correct Answer: Holes
Explanation:p-type semiconductors are formed by doping with trivalent impurities, which create a deficiency of electrons called holes. Thus, holes are the majority carriers.
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4Which of the following equations correctly represents the Mass-Action Law for semiconductors under thermal equilibrium?
A.
B.
C.
D.
Correct Answer:
Explanation:The Mass-Action Law states that under thermal equilibrium, the product of electron concentration () and hole concentration () is a constant equal to the square of the intrinsic carrier concentration ().
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5In an n-type semiconductor, the Fermi energy level lies:
A.Exactly in the middle of the bandgap
B.Closer to the valence band
C.Closer to the conduction band
D.Inside the valence band
Correct Answer: Closer to the conduction band
Explanation:Due to the excess of electrons in the conduction band contributed by donor atoms, the probability of finding electrons is higher near the conduction band, shifting the Fermi level upwards.
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6An ideal diode in the forward-biased condition acts as a/an:
A.Open circuit
B.Short circuit
C.Current source
D.Voltage source
Correct Answer: Short circuit
Explanation:An ideal diode has zero resistance when forward-biased, allowing maximum current to flow, thus acting as a perfect short circuit or closed switch.
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7The depletion region of an unbiased p-n junction diode contains:
A.Free electrons and holes
B.Only free electrons
C.Only free holes
D.Immobile positive and negative ions
Correct Answer: Immobile positive and negative ions
Explanation:During the formation of a p-n junction, electrons and holes recombine near the junction, leaving behind immobile uncompensated ions (positive on n-side, negative on p-side) that form the depletion region.
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8What is the net current flowing through an unbiased p-n junction diode?
A.Maximum
B.Zero
C.Equal to the reverse saturation current
D.Equal to the forward current
Correct Answer: Zero
Explanation:In an unbiased diode, the diffusion current of majority carriers is exactly balanced by the drift current of minority carriers, resulting in a net macroscopic current of zero.
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9When a p-n junction diode is forward-biased, the width of the depletion region:
A.Increases
B.Decreases
C.Remains unchanged
D.Alternates periodically
Correct Answer: Decreases
Explanation:Forward biasing applies an external electric field that opposes the built-in potential, pushing majority carriers toward the junction and thereby narrowing the depletion region.
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10When a p-n junction diode is reverse-biased, it offers:
A.Low resistance
B.Zero resistance
C.High resistance
D.Negative resistance
Correct Answer: High resistance
Explanation:Reverse biasing widens the depletion region and increases the barrier potential, preventing majority carriers from crossing and offering a very high resistance to current flow.
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11The typical knee voltage (barrier potential) for a Silicon diode at room temperature is approximately:
A.
B.
C.
D.
Correct Answer:
Explanation:For Silicon, the built-in potential barrier is typically around . For Germanium, it is around .
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12Which of the following represents the correct Shockley diode equation?
A.
B.
C.
D.
Correct Answer:
Explanation:The Shockley ideal diode equation is , where is reverse saturation current, is diode voltage, is the ideality factor, and is the thermal voltage.
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13At room temperature (), the thermal voltage () is approximately:
A.
B.
C.
D.
Correct Answer:
Explanation:Thermal voltage is calculated as . At , it is approximately , which is commonly rounded to .
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14What is the formula for the dynamic resistance () of a forward-biased diode?
A.
B.
C.
D.
Correct Answer:
Explanation:Dynamic resistance is the derivative of voltage with respect to current. Differentiating the Shockley equation yields at a given operating direct current .
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15How does the reverse saturation current () of a diode behave with an increase in temperature?
A.It halves for every rise
B.It doubles for every rise
C.It remains constant
D.It decreases linearly
Correct Answer: It doubles for every rise
Explanation:A rule of thumb for semiconductor diodes is that the reverse saturation current approximately doubles for every rise in temperature due to increased thermal generation of minority carriers.
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16For a constant forward current, the barrier potential of a Silicon diode changes with temperature at a rate of approximately:
A.
B.
C.
D.
Correct Answer:
Explanation:The forward voltage drop decreases as temperature increases because intrinsic carrier concentration rises. The standard temperature coefficient is .
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17In the V-I characteristics of a p-n junction diode, the forward current rises exponentially after surpassing the:
A.Breakdown voltage
B.Peak inverse voltage
C.Knee voltage
D.Pinch-off voltage
Correct Answer: Knee voltage
Explanation:The knee voltage (or threshold voltage/cut-in voltage) is the point on the forward V-I curve where the current starts increasing rapidly and exponentially as it overcomes the barrier potential.
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18Zener breakdown occurs predominantly in diodes that are:
A.Lightly doped
B.Moderately doped
C.Heavily doped
D.Intrinsic
Correct Answer: Heavily doped
Explanation:Zener breakdown occurs in heavily doped diodes. The heavy doping creates a very narrow depletion region, resulting in a highly intense electric field that can pull electrons directly out of covalent bonds.
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19Avalanche breakdown in a reverse-biased diode is caused by:
A.Direct rupture of covalent bonds by an electric field
B.Impact ionization due to high-velocity minority carriers
C.Thermal runaway melting the junction
D.Spontaneous electron-hole recombination
Correct Answer: Impact ionization due to high-velocity minority carriers
Explanation:In lightly doped diodes, the depletion region is wide. High reverse voltage accelerates minority carriers, giving them enough kinetic energy to break covalent bonds upon collision, creating an avalanche of carriers.
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20The breakdown voltage of a typical Zener diode has a negative temperature coefficient, whereas Avalanche breakdown has a:
A.Negative temperature coefficient
B.Positive temperature coefficient
C.Zero temperature coefficient
D.Exponential temperature coefficient
Correct Answer: Positive temperature coefficient
Explanation:Zener breakdown voltage decreases with increased temperature (negative coefficient), while Avalanche breakdown voltage increases with temperature (positive coefficient) due to increased lattice vibrations hindering carrier acceleration.
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21To use a Zener diode as a voltage regulator, it must be operated in the:
A.Forward bias region
B.Unbiased condition
C.Reverse breakdown region
D.Reverse saturation region
Correct Answer: Reverse breakdown region
Explanation:A Zener diode regulates voltage by operating in its reverse breakdown region, where it maintains a nearly constant voltage across its terminals despite wide variations in reverse current.
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22In a Zener voltage regulator circuit, the Zener diode is connected in:
A.Series with the load and forward-biased
B.Series with the load and reverse-biased
C.Parallel with the load and forward-biased
D.Parallel with the load and reverse-biased
Correct Answer: Parallel with the load and reverse-biased
Explanation:The Zener diode is placed in parallel (shunt) with the load to ensure the load voltage equals the Zener voltage. It must be reverse-biased to operate in the breakdown region.
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23Line regulation in a power supply refers to the ability to maintain a constant output voltage despite changes in:
A.Load current
B.Ambient temperature
C.Input line voltage
D.Output load resistance
Correct Answer: Input line voltage
Explanation:Line regulation is the measure of an electronic regulator's ability to maintain a constant output voltage when the input (line) voltage fluctuates.
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24Load regulation describes the change in output voltage when there is a change in:
A.Input voltage
B.Load current (or load resistance)
C.Ripple frequency
D.Transformer turns ratio
Correct Answer: Load current (or load resistance)
Explanation:Load regulation specifies how well a power supply can maintain its output voltage as the load current varies from no-load to full-load conditions.
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25The maximum theoretical rectification efficiency of a Half-Wave Rectifier is:
A.
B.
C.
D.
Correct Answer:
Explanation:Efficiency is the ratio of DC output power to AC input power. For a half-wave rectifier, this ratio mathematically limits at because only one half-cycle is utilized.
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26The maximum theoretical rectification efficiency of a Full-Wave Rectifier is:
A.
B.
C.
D.
Correct Answer:
Explanation:Because a full-wave rectifier utilizes both half-cycles of the input AC signal, its maximum theoretical efficiency is exactly double that of a half-wave rectifier, i.e., .
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27What is the Ripple Factor () of a standard Half-Wave Rectifier?
A.$1.21$
B.$0.48$
C.$1.11$
D.$0.50$
Correct Answer: $1.21$
Explanation:The ripple factor for a half-wave rectifier is calculated as , which yields $1.21$. This means the AC ripple exceeds the DC component.
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28What is the Ripple Factor () of a Full-Wave Rectifier?
A.$1.21$
B.$0.48$
C.$1.11$
D.$0.50$
Correct Answer: $0.48$
Explanation:For a full-wave rectifier, the ripple factor is $0.48$, indicating that the AC ripple component is less than the DC component, resulting in a smoother output compared to a half-wave rectifier.
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29What is the Peak Inverse Voltage (PIV) rating required for a diode in a center-tapped Full-Wave Rectifier (where is the peak voltage of half the secondary winding)?
A.
B.
C.
D.
Correct Answer:
Explanation:In a center-tapped full-wave rectifier, when one diode is conducting, the other reverse-biased diode must block the sum of the voltages across both halves of the secondary, making the PIV equal to .
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30What is the Peak Inverse Voltage (PIV) of each diode in a Bridge Full-Wave Rectifier (where is the peak secondary voltage)?
A.
B.
C.
D.
Correct Answer:
Explanation:In a bridge rectifier, the reverse-biased diodes are connected directly across the secondary winding (minus the forward drop of conducting diodes), so the maximum reverse voltage they must withstand is .
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31How many diodes are required to construct a Bridge Full-Wave Rectifier?
A.1
B.2
C.3
D.4
Correct Answer: 4
Explanation:A bridge rectifier requires exactly 4 diodes arranged in a bridge topology to convert both half-cycles of the AC input into DC without needing a center-tapped transformer.
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32If the input AC supply frequency is , what is the fundamental frequency of the output ripple in a Full-Wave Rectifier?
A.
B.
C.
D.
Correct Answer:
Explanation:Because a full-wave rectifier inverts the negative half-cycle, the fundamental period of the output waveform is halved, effectively doubling the output frequency to .
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33A circuit designed to remove a specific portion of an input waveform without distorting the remaining part is called a:
A.Clamper
B.Clipper
C.Rectifier
D.Filter
Correct Answer: Clipper
Explanation:Clippers (or limiters) are used to 'clip off' or remove portions of alternating waveforms above or below a certain reference level.
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34A Series Positive Clipper circuit operates by:
A.Removing the negative half-cycle of the input signal
B.Removing the positive half-cycle of the input signal
C.Shifting the entire waveform upwards
D.Shifting the entire waveform downwards
Correct Answer: Removing the positive half-cycle of the input signal
Explanation:A positive clipper removes the positive part of the input signal. In a series configuration, the diode is reverse-biased during the positive half-cycle, preventing it from reaching the output.
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35What is the primary function of a biased clipper?
A.To amplify the input signal
B.To clip the waveform at a specific non-zero DC reference voltage
C.To convert an AC signal directly to pure DC
D.To shift the waveform to a new DC level
Correct Answer: To clip the waveform at a specific non-zero DC reference voltage
Explanation:By adding a DC voltage source (bias) in series with the diode in a clipper circuit, the clipping level can be shifted from to any desired positive or negative reference voltage.
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36A circuit that shifts an entire AC waveform to a different DC level without changing its shape is known as a:
A.Clipper
B.Clamper
C.Voltage Regulator
D.Inverter
Correct Answer: Clamper
Explanation:A clamper (or DC restorer) adds a positive or negative DC component to an AC signal, thereby shifting the entire waveform up or down without altering its peak-to-peak amplitude or shape.
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37Which of the following components is essential in a Clamper circuit but generally not required in a simple Clipper circuit?
A.Diode
B.Resistor
C.Capacitor
D.Inductor
Correct Answer: Capacitor
Explanation:A clamper relies on a capacitor to store charge and provide the DC offset voltage that shifts the waveform. Clippers use only diodes and resistors (and sometimes DC sources).
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38A Light Emitting Diode (LED) emits light when it is:
A.Reverse biased
B.Forward biased
C.Unbiased
D.In avalanche breakdown
Correct Answer: Forward biased
Explanation:When an LED is forward-biased, electrons from the n-region and holes from the p-region recombine near the junction, releasing energy in the form of photons (light).
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39The physical phenomenon responsible for light emission in an LED is called:
A.Thermionic emission
B.Electroluminescence
C.Photoluminescence
D.Photoelectric effect
Correct Answer: Electroluminescence
Explanation:Electroluminescence is the phenomenon where a material emits light in response to the passage of an electric current or a strong electric field, which is exactly how an LED operates via carrier recombination.
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40Which of the following semiconductor materials is commonly used to manufacture visible Light Emitting Diodes?
Explanation:Visible LEDs require direct bandgap materials with an appropriate energy gap to emit visible photons. GaAsP is commonly used. Silicon and Germanium are indirect bandgap materials and primarily emit heat.
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41Why are standard Silicon and Germanium diodes not used to make LEDs?
A.They are too expensive
B.They have a direct bandgap
C.They have an indirect bandgap
D.Their breakdown voltage is too low
Correct Answer: They have an indirect bandgap
Explanation:In indirect bandgap semiconductors like Si and Ge, electron-hole recombination requires a momentum change, causing the released energy to be mostly dissipated as heat (phonons) rather than light (photons).
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42The wavelength () of the light emitted by an LED is related to the bandgap energy () of the semiconductor by which equation?
A.
B.
C.
D.
Correct Answer:
Explanation:The energy of a photon is . Since the emitted photon energy corresponds to the bandgap , the wavelength is .
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43Which of the following represents the correct sequential block diagram of a regulated linear DC power supply?
Explanation:The AC mains is stepped down by the transformer, converted to pulsating DC by the rectifier, smoothed by the filter, and finally stabilized by the voltage regulator.
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44The primary purpose of the filter circuit in a DC power supply is to:
A.Step down the AC input voltage
B.Convert AC to pulsating DC
C.Remove AC ripples from the pulsating DC output
D.Regulate the output voltage against load variations
Correct Answer: Remove AC ripples from the pulsating DC output
Explanation:A filter (typically a capacitor or an LC circuit) smoothens the pulsating DC generated by the rectifier, reducing the AC ripple component and providing a steadier DC voltage.
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45In a simple capacitor filter power supply, the capacitor is connected:
A.In series with the load
B.In parallel with the load
C.In series with the transformer primary
D.In parallel with the AC mains
Correct Answer: In parallel with the load
Explanation:The smoothing capacitor is placed in parallel with the load resistor. It charges to the peak voltage during the conduction half-cycle and slowly discharges through the load during the non-conduction period.
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46The purpose of a voltage regulator in a power supply design is to:
A.Increase the ripple factor
B.Maintain a constant output voltage despite line and load variations
C.Convert DC voltage back to AC voltage
D.Step up the output DC voltage
Correct Answer: Maintain a constant output voltage despite line and load variations
Explanation:A voltage regulator ensures that the output DC voltage remains stable and constant even if the input AC mains voltage fluctuates (line) or the load current demand changes (load).
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47In a diode datasheet, what does the parameter denote?
A.Peak inverse current
B.Maximum average forward current
C.Surge current
D.Reverse leakage current
Correct Answer: Maximum average forward current
Explanation:The parameter stands for Average Forward Current. It represents the maximum allowable average current that can flow through the diode in the forward direction safely.
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48In a diode datasheet, the Reverse Recovery Time () is a critical parameter that determines the diode's:
A.Maximum power dissipation
B.Maximum operating frequency (switching speed)
C.Forward voltage drop
D.Thermal resistance
Correct Answer: Maximum operating frequency (switching speed)
Explanation:Reverse recovery time () is the time taken by a diode to completely turn off (stop reverse current) when switching from forward to reverse bias. A smaller allows for higher frequency switching operations.
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49According to a standard diode datasheet, the parameter represents the:
A.Maximum repetitive peak reverse voltage
B.RMS working reverse voltage
C.Minimum forward breakdown voltage
D.Maximum reverse recovery voltage
Correct Answer: Maximum repetitive peak reverse voltage
Explanation: (Voltage, Repetitive Reverse Maximum) is the maximum peak reverse voltage that the diode can withstand continuously or repetitively without breaking down.
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50What is indicated by the parameter in a semiconductor diode datasheet?
A.Maximum Peak Diode Current
B.Maximum Power Dissipation
C.Phase Delay maximum
D.Potential Difference maximum
Correct Answer: Maximum Power Dissipation
Explanation: specifies the maximum power that the device can safely dissipate as heat into its surroundings without sustaining damage.