1What is the fundamental physical principle behind the propagation of light in an optical fiber?
A.Refraction
B.Diffraction
C.Total Internal Reflection
D.Polarization
Correct Answer: Total Internal Reflection
Explanation:Light propagates through an optical fiber due to Total Internal Reflection (TIR) occurring at the core-cladding interface when the angle of incidence exceeds the critical angle.
Incorrect! Try again.
2In an optical fiber, what is the relationship between the refractive index of the core () and the refractive index of the cladding ()?
A.
B.
C.
D.
Correct Answer:
Explanation:For Total Internal Reflection to occur, light must travel from a denser medium to a rarer medium. Therefore, the core refractive index must be greater than that of the cladding.
Incorrect! Try again.
3Which component of the optical fiber provides mechanical strength and protects the core-cladding structure?
A.Core
B.Cladding
C.Buffer Coating / Jacket
D.Acceptance Cone
Correct Answer: Buffer Coating / Jacket
Explanation:The core carries light, the cladding confines it, and the buffer coating (or primary coating/jacket) provides mechanical protection against moisture and abrasion.
Incorrect! Try again.
4The critical angle at the core-cladding interface is given by which formula?
A.
B.
C.
D.
Correct Answer:
Explanation:From Snell's law, at the critical angle, the angle of refraction is . Therefore, , leading to .
Incorrect! Try again.
5What is the 'Acceptance Angle' of an optical fiber?
A.The angle at which light reflects inside the core
B.The maximum angle of incidence at the input end for which light is propagated
C.The critical angle of the core-cladding interface
D.The angle of refraction inside the cladding
Correct Answer: The maximum angle of incidence at the input end for which light is propagated
Explanation:The acceptance angle is the maximum semi-angle of the cone within which incident light is captured by the core and guided via total internal reflection.
Incorrect! Try again.
6The Numerical Aperture (NA) of a fiber is a measure of its:
A.Attenuation capability
B.Light gathering power
C.Dispersion limit
D.Core diameter
Correct Answer: Light gathering power
Explanation:Numerical Aperture represents the light-gathering ability of an optical fiber. A higher NA implies the fiber can accept light from a wider angle.
Incorrect! Try again.
7Which of the following is the correct formula for Numerical Aperture (NA) assuming air () is the launch medium?
A.
B.
C.
D.
Correct Answer:
Explanation:The Numerical Aperture is defined as the sine of the acceptance angle, which relates to the refractive indices as .
Incorrect! Try again.
8The Relative Refractive Index Difference () is defined as:
A.
B.
C.
D.
Correct Answer:
Explanation:The precise definition is . However, for small differences, it is often approximated as .
Incorrect! Try again.
9How is the Numerical Aperture (NA) related to the Relative Refractive Index Difference ()?
A.
B.
C.
D.
Correct Answer:
Explanation:Substituting into , we get .
Incorrect! Try again.
10If the refractive index of the core is 1.50 and the cladding is 1.48, what is the Numerical Aperture (approximate)?
Correct Answer: The number of modes the fiber can support
Explanation:The V-number is a dimensionless quantity that determines the number of guided modes in a step-index fiber.
Incorrect! Try again.
12What is the formula for the V-number?
A.
B.
C.
D.
Correct Answer:
Explanation:, where is the core radius and is the wavelength. Since , the correct option is .
Incorrect! Try again.
13What is the condition for a Step Index fiber to be Single Mode?
A.
B.
C.
D.
Correct Answer:
Explanation:A step-index fiber supports only a single mode (the fundamental mode) if the V-number is less than or equal to 2.405.
Incorrect! Try again.
14Approximately how many modes () travel in a Step Index Multimode fiber if is large?
A.
B.
C.
D.
Correct Answer:
Explanation:For a step-index fiber with a large V-number, the total number of guided modes is approximately .
Incorrect! Try again.
15Approximately how many modes () travel in a Graded Index (parabolic profile) Multimode fiber?
A.
B.
C.
D.
Correct Answer:
Explanation:For a parabolic graded-index fiber, the number of modes is approximately half that of a step-index fiber with the same parameters, so .
Incorrect! Try again.
16In a Step Index fiber, the refractive index:
A.Decreases continuously from the axis to the cladding
B.Increases continuously from the axis to the cladding
C.Is constant in the core and changes abruptly at the cladding boundary
D.Is constant throughout the core and cladding
Correct Answer: Is constant in the core and changes abruptly at the cladding boundary
Explanation:Step Index fibers have a uniform refractive index throughout the core, which drops abruptly (like a step) at the interface with the cladding.
Incorrect! Try again.
17In a Graded Index (GRIN) fiber, the light rays travel in:
A.Straight lines zig-zagging
B.Sinusoidal or helical paths
C.Only along the axis
D.Square waves
Correct Answer: Sinusoidal or helical paths
Explanation:Due to the varying refractive index in the core of a GRIN fiber, light rays are continuously refracted, resulting in a curved (sinusoidal) path.
Incorrect! Try again.
18Why are Graded Index fibers preferred over Step Index Multimode fibers for higher bandwidth applications?
A.They have higher attenuation
B.They significantly reduce intermodal dispersion
C.They are cheaper to manufacture
D.They have a larger numerical aperture
Correct Answer: They significantly reduce intermodal dispersion
Explanation:In GRIN fibers, rays traveling further from the axis (higher modes) move faster due to lower refractive index, arriving at the same time as axial rays, thus minimizing pulse spreading (intermodal dispersion).
Incorrect! Try again.
19What is the typical core diameter of a Single Mode Fiber (SMF)?
A.50 m
B.8 - 10 m
C.200 m
D.1 mm
Correct Answer: 8 - 10 m
Explanation:SMF requires a very small core diameter (comparable to the wavelength of light) to allow only one mode to propagate, typically around 8 to 10 micrometers.
Incorrect! Try again.
20Attenuation in an optical fiber is usually expressed in:
A.Watts
B.Decibels (dB)
C.dB/km
D.Volts/m
Correct Answer: dB/km
Explanation:Attenuation describes signal loss per unit length, standardly measured in decibels per kilometer (dB/km).
Incorrect! Try again.
21If the input power is and output power is over a length , the attenuation (in dB/km) is calculated as:
A.
B.
C.
D.
Correct Answer:
Explanation:Attenuation is defined by the logarithmic ratio of input to output power, normalized by length. The factor is 10 because it is in decibels.
Incorrect! Try again.
22Rayleigh scattering loss is inversely proportional to:
A.
B.
C.
D.
Correct Answer:
Explanation:Rayleigh scattering is caused by density fluctuations smaller than the wavelength and scales as , meaning shorter wavelengths scatter much more.
Incorrect! Try again.
23Which of the following causes Intrinsic Absorption in optical fibers?
A.OH ions (water peaks)
B.Iron impurities
C.Electronic transitions in the UV region and atomic vibrations in the IR region
D.Microbending
Correct Answer: Electronic transitions in the UV region and atomic vibrations in the IR region
Explanation:Intrinsic absorption is fundamental to the glass material itself, occurring at UV (electronic) and IR (atomic vibration) ranges. Impurities like OH ions cause extrinsic absorption.
Incorrect! Try again.
24The peak absorption around 1.38 m in silica fibers is primarily caused by:
A.Rayleigh Scattering
B.OH (hydroxyl) ions
C.Transition metals
D.Macrobending
Correct Answer: OH (hydroxyl) ions
Explanation:Water vapor trapped during manufacturing creates hydroxyl (OH) ions, which absorb light strongly at specific wavelengths, notably around 1.38 m.
Incorrect! Try again.
25Microbending loss is caused by:
A.Large radius bends in the fiber cable installation
B.Microscopic irregularities in the fiber geometry or pressure from cabling
C.Scattering by atomic defects
D.Absorption by impurities
Correct Answer: Microscopic irregularities in the fiber geometry or pressure from cabling
Explanation:Microbending refers to small-scale distortions in the fiber's straightness, often caused by uneven coating or cabling pressure, which couples light out of the core.
Incorrect! Try again.
26Which type of dispersion is dominant in Single Mode Fibers?
A.Intermodal Dispersion
B.Intramodal (Chromatic) Dispersion
C.Modal Noise
D.Polarization Mode Dispersion only
Correct Answer: Intramodal (Chromatic) Dispersion
Explanation:Since SMF supports only one mode, intermodal dispersion is absent. The primary dispersion comes from Chromatic Dispersion (Material + Waveguide).
Incorrect! Try again.
27Material dispersion arises because:
A.The core diameter varies along the length
B.The refractive index of the glass varies with wavelength
C.Light rays take different paths
D.The cladding index is higher than the core index
Correct Answer: The refractive index of the glass varies with wavelength
Explanation:Material dispersion occurs because the refractive index is a function of wavelength (), causing different spectral components of a pulse to travel at different speeds.
Incorrect! Try again.
28What is the primary advantage of operating at the 1550 nm wavelength window?
A.Zero dispersion
B.Minimum attenuation
C.Maximum scattering
D.Highest V-number
Correct Answer: Minimum attenuation
Explanation:Silica fibers exhibit their lowest attenuation (lowest loss) typically around 1550 nm, making it the standard for long-haul communications.
Incorrect! Try again.
29Intermodal dispersion leads to:
A.Signal strengthening
B.Pulse broadening
C.Wavelength shifting
D.Increased NA
Correct Answer: Pulse broadening
Explanation:Intermodal dispersion causes different modes to arrive at different times, spreading out the optical pulse and limiting the bandwidth.
Incorrect! Try again.
30Which rays propagate through the fiber axis without reflecting?
A.Meridional rays
B.Skew rays
C.Axial rays
D.Evanescent waves
Correct Answer: Axial rays
Explanation:Axial rays travel straight down the center of the fiber. Meridional rays pass through the axis, while Skew rays do not intersect the axis.
Incorrect! Try again.
31Skew rays are rays that:
A.Intersect the fiber axis
B.Travel only in the cladding
C.Follow a helical path and never intersect the fiber axis
D.Are reflected back to the source
Correct Answer: Follow a helical path and never intersect the fiber axis
Explanation:Skew rays follow a spiral or helical path down the fiber and do not cross the optical axis, unlike meridional rays.
Incorrect! Try again.
32Why is an optical fiber considered a 'Dielectric Waveguide'?
A.It conducts electricity
B.It is made of non-conducting (insulating) materials like glass/plastic
C.It requires a dielectric coating to function
D.It uses magnetic fields to guide light
Correct Answer: It is made of non-conducting (insulating) materials like glass/plastic
Explanation:Dielectric means electrically insulating. Optical fibers guide electromagnetic waves (light) using non-conducting materials like silica, hence 'dielectric waveguide'.
Incorrect! Try again.
33If the fractional refractive index change and , what is ?
A.1.485
B.1.515
C.1.490
D.1.0
Correct Answer: 1.485
Explanation:Using : .
Incorrect! Try again.
34Macrobending loss can be reduced by:
A.Increasing the core radius
B.Decreasing the refractive index difference
C.Increasing the Numerical Aperture (NA)
D.Using a lower frequency light
Correct Answer: Increasing the Numerical Aperture (NA)
Explanation:A higher NA means stronger confinement of light (tighter acceptance cone relative to the core). This makes the fiber less sensitive to bending losses.
Incorrect! Try again.
35What is the unit of the V-number?
A.Hertz
B.Meters
C.Dimensionless
D.Degrees
Correct Answer: Dimensionless
Explanation:The V-number is a normalized frequency parameter derived from ratios of physical dimensions and indices, making it a dimensionless quantity.
Incorrect! Try again.
36Waveguide dispersion depends primarily on:
A.The material composition only
B.The fiber diameter and refractive index profile relative to wavelength
C.The purity of the silica
D.The cable jacket material
Correct Answer: The fiber diameter and refractive index profile relative to wavelength
Explanation:Waveguide dispersion arises because a portion of the light travels in the cladding (which travels faster). The amount depends on the ratio of core radius to wavelength.
Incorrect! Try again.
37Which window of optical communication is typically around 850 nm?
A.First window
B.Second window
C.Third window
D.Fourth window
Correct Answer: First window
Explanation:The first optical window (used in early systems) is around 800-900 nm (typically 850 nm), compatible with GaAs sources.
Incorrect! Try again.
38What is the phenomenon responsible for the 'Zero Dispersion Wavelength'?
A.Material dispersion and Waveguide dispersion cancel each other out
B.Attenuation is zero
C.Refractive index becomes 1
D.TIR stops occurring
Correct Answer: Material dispersion and Waveguide dispersion cancel each other out
Explanation:At a specific wavelength (typically near 1310 nm for standard silica), positive waveguide dispersion cancels out negative material dispersion, resulting in zero total chromatic dispersion.
Incorrect! Try again.
39In the context of fiber optics, what does 'Modes' refer to?
A.Different colors of light
B.Allowed paths for light propagation solving the wave equation
C.The number of fibers in a cable
D.The speed settings of the laser
Correct Answer: Allowed paths for light propagation solving the wave equation
Explanation:Modes are specific electromagnetic field patterns (solutions to Maxwell's equations) that satisfy the boundary conditions of the waveguide and can propagate through it.
Incorrect! Try again.
40If a fiber has an acceptance angle of , light entering at will:
A.Be guided efficiently
B.Refract into the cladding and be lost
C.Undergo total internal reflection
D.Travel faster than the other rays
Correct Answer: Refract into the cladding and be lost
Explanation:Light must enter within the acceptance cone () to satisfy the condition for TIR inside. At , the internal angle will not exceed the critical angle.
Incorrect! Try again.
41For a Multimode Step Index fiber, if the core radius is doubled, the number of modes increases by a factor of:
A.2
B.4
C.8
D.It remains the same
Correct Answer: 4
Explanation:The number of modes . Since (radius), . Doubling results in times the modes.
Incorrect! Try again.
42The refractive index profile of a Graded Index fiber is typically:
A.Parabolic
B.Hyperbolic
C.Linear
D.Exponential
Correct Answer: Parabolic
Explanation:A parabolic profile (where decreases with the square of the distance from the axis) is optimal for focusing rays and minimizing intermodal dispersion.
Incorrect! Try again.
43Which of the following is NOT a source of loss in optical fibers?
A.Rayleigh Scattering
B.Absorption
C.Bending
D.Total Internal Reflection
Correct Answer: Total Internal Reflection
Explanation:Total Internal Reflection is the mechanism of propagation, not a loss mechanism. Theoretically, TIR is 100% efficient.
Incorrect! Try again.
44Which fiber type has the largest information-carrying capacity (Bandwidth)?
A.Multimode Step Index
B.Multimode Graded Index
C.Single Mode Step Index
D.Plastic Optical Fiber
Correct Answer: Single Mode Step Index
Explanation:Single Mode fibers eliminate intermodal dispersion, allowing for extremely high bandwidths and long-distance transmission.
Incorrect! Try again.
45The cone of acceptance is the solid angle formed by rotating the:
A.Critical angle
B.Acceptance angle
C.Refraction angle
D.Brewster angle
Correct Answer: Acceptance angle
Explanation:Rotating the acceptance angle around the fiber axis creates the cone of acceptance, within which light is gathered.
Incorrect! Try again.
46If light travels from air () into a fiber core (), the maximum value of NA is theoretically:
A.0.5
B.1.0
C.1.5
D.Infinity
Correct Answer: 1.0
Explanation:. The maximum value of is 1. Since , the maximum theoretical NA for light entering from air is 1.
Incorrect! Try again.
47Why are optical fibers immune to Electromagnetic Interference (EMI)?
A.They are shielded by copper
B.Light photons are electrically neutral
C.The frequency is too low
D.The cladding reflects the EMI
Correct Answer: Light photons are electrically neutral
Explanation:Optical fibers transmit signals as light (photons), which carry no charge and are not affected by electromagnetic fields, unlike electric currents in copper wires.
Incorrect! Try again.
48Calculate the acceptance angle if the Numerical Aperture is 0.5 and the medium is air.
A.
B.
C.
D.
Correct Answer:
Explanation:. Therefore, .
Incorrect! Try again.
49As the wavelength of light increases, the V-number of the fiber:
A.Increases
B.Decreases
C.Remains constant
D.Becomes zero
Correct Answer: Decreases
Explanation:. Since is inversely proportional to , increasing the wavelength decreases the V-number.
Incorrect! Try again.
50Dispersion is usually measured in units of:
A.dB/km
B.ps/(nmkm)
C.nm/km
D.Hz
Correct Answer: ps/(nmkm)
Explanation:Dispersion represents time spreading per unit spectral width per unit length. The standard unit is picoseconds per nanometer per kilometer.
Incorrect! Try again.
Give Feedback
Help us improve by sharing your thoughts or reporting issues.