1In an inverting summing amplifier with three input voltages applied through resistors respectively, and a feedback resistor , what is the output voltage ?
A.
B.
C.
D.
Correct Answer:
Explanation:The inverting summing amplifier sums the weighted inputs and inverts the phase. The weight is determined by the ratio of the feedback resistor to the respective input resistor.
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2To configure an inverting summing amplifier as an averaging amplifier for inputs, which of the following conditions must be met?
A.
B. where all input resistors are equal
C. where all input resistors are equal
D.
Correct Answer: where all input resistors are equal
Explanation:For an averaging amplifier, the gain for each input must be . Therefore, , which implies .
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3What is the primary advantage of an Instrumentation Amplifier over a basic differential amplifier?
A.Higher bandwidth
B.Lower power consumption
C.High CMRR and high input impedance
D.Simpler circuit design
Correct Answer: High CMRR and high input impedance
Explanation:Instrumentation amplifiers are designed for high Common Mode Rejection Ratio (CMRR) and very high input impedance, making them ideal for measuring small differential signals amidst noise.
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4In a standard three-op-amp instrumentation amplifier, how many resistors are typically varied to adjust the gain?
A.One ()
B.Two
C.Three
D.All resistors
Correct Answer: One ()
Explanation:The gain of a standard instrumentation amplifier is usually adjusted by varying a single external resistor, often denoted as or .
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5A voltage-to-current converter with a floating load is typically used in which application?
A.Driving a speaker
B.Low voltage signaling
C.Driving a grounded load
D.Testing diodes or driving panel meters
Correct Answer: Testing diodes or driving panel meters
Explanation:In floating load configurations, the load is placed in the feedback loop. This is common for moving-coil meters or testing components where the load does not need to be referenced to ground.
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6For a voltage-to-current converter with a floating load (load in feedback), the output current is given by:
A.
B.
C.
D.
Correct Answer:
Explanation:Since the op-amp maintains virtual ground (or virtual short), the current through the input resistor is , which flows directly through the floating load in the feedback path.
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7Which circuit configuration is commonly used for a Voltage-to-Current converter with a grounded load?
A.Basic Inverting Amplifier
B.Voltage Follower
C.Howland Current Pump
D.Differentiator
Correct Answer: Howland Current Pump
Explanation:The Howland Current Pump is a topology that allows a load to be connected to ground while maintaining a constant current proportional to the input voltage.
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8A current-to-voltage converter is also known as a:
A.Transconductance amplifier
B.Transimpedance amplifier
C.Voltage follower
D.Difference amplifier
Correct Answer: Transimpedance amplifier
Explanation:A current-to-voltage converter takes an input current and produces an output voltage, effectively acting as a transimpedance (Transfer Impedance) amplifier.
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9In an ideal basic integrator circuit using an op-amp, the feedback element is:
A.A Resistor
B.A Capacitor
C.An Inductor
D.A Diode
Correct Answer: A Capacitor
Explanation:An ideal integrator uses a capacitor in the feedback loop and a resistor at the input.
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10If a square wave is applied to the input of an ideal integrator, the output will be:
A.A Sine wave
B.A Triangular wave
C.A Square wave
D.A Spike
Correct Answer: A Triangular wave
Explanation:Integrating a constant voltage (the flat top/bottom of a square wave) results in a linear ramp. Alternating positive and negative constants produce a triangular wave.
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11What is the primary problem with a basic ideal differentiator at high frequencies?
A.It stops working
B.The gain decreases
C.It becomes unstable and amplifies high-frequency noise
D.It turns into an integrator
Correct Answer: It becomes unstable and amplifies high-frequency noise
Explanation:Since the reactance of the input capacitor () decreases as frequency increases, the gain () increases with frequency, causing high-frequency noise amplification and potential instability.
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12To convert an ideal differentiator into a practical differentiator, what component is added?
A.A capacitor in parallel with the input resistor
B.A resistor in series with the input capacitor
C.A resistor in series with the feedback capacitor
D.An inductor in the feedback loop
Correct Answer: A resistor in series with the input capacitor
Explanation:Adding a resistor in series with the input capacitor limits the gain at high frequencies, improving stability and reducing noise. Often a capacitor is also added in parallel with the feedback resistor.
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13A 'lossy integrator' or practical integrator includes a resistor in parallel with the feedback capacitor. What is the function of this resistor?
A.To increase the bandwidth
B.To limit the low-frequency gain and prevent saturation
C.To increase the slew rate
D.To convert it into a differentiator
Correct Answer: To limit the low-frequency gain and prevent saturation
Explanation:At DC (0 Hz), the capacitor acts as an open circuit. Without the feedback resistor , the op-amp would operate open-loop and saturate due to offset voltages. limits the DC gain.
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14The output of an op-amp differentiator is proportional to:
A.The integral of the input voltage
B.The rate of change of the input voltage
C.The amplitude of the input voltage
D.The square of the input voltage
Correct Answer: The rate of change of the input voltage
Explanation:A differentiator produces an output voltage proportional to the time derivative (rate of change) of the input voltage: .
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15Which of the following is an advantage of active filters over passive filters?
A.They require no power supply
B.They can provide gain and buffer the signal
C.They work at very high frequencies (GHz range)
D.They use inductors
Correct Answer: They can provide gain and buffer the signal
Explanation:Active filters use op-amps, which provide high input impedance, low output impedance (buffering), and the ability to add gain. They also eliminate the need for bulky inductors.
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16What defines the 'order' of an active filter?
A.The number of op-amps used
B.The number of resistors used
C.The number of reactive elements (RC pairs) determining the roll-off
D.The value of the supply voltage
Correct Answer: The number of reactive elements (RC pairs) determining the roll-off
Explanation:The order of the filter corresponds to the number of poles, which is determined by the number of RC networks. Each order adds -20 dB/decade to the roll-off rate.
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17The roll-off rate of a first-order Butterworth filter is:
A.20 dB/decade
B.40 dB/decade
C.6 dB/octave
D.Both A and C
Correct Answer: Both A and C
Explanation:A first-order filter has a roll-off of 20 dB per decade, which is mathematically equivalent to 6 dB per octave.
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18In a First Order Low Pass Butterworth filter, the cut-off frequency is given by:
A.
B.
C.
D.
Correct Answer:
Explanation:The cut-off frequency (where gain drops by 3dB) for a first-order RC filter is .
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19Which component configuration characterizes a First Order Active High Pass Filter?
A.Capacitor in the feedback loop
B.Capacitor in series with the input resistor at the non-inverting terminal
C.Capacitor in parallel with the input
D.Inductor in series with the input
Correct Answer: Capacitor in series with the input resistor at the non-inverting terminal
Explanation:A high pass filter blocks DC. This is achieved by placing a capacitor in series with the input signal entering the non-inverting terminal.
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20What is the phase shift between input and output at the cut-off frequency for a first-order low-pass filter?
A.-90 degrees
B.-45 degrees
C.0 degrees
D.-180 degrees
Correct Answer: -45 degrees
Explanation:At the cut-off frequency , the real and imaginary parts of the transfer function denominator are equal, resulting in a phase shift of -45 degrees.
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21A Butterworth filter is characterized by:
A.Ripple in the passband
B.Ripple in the stopband
C.Maximally flat passband response
D.Fastest roll-off
Correct Answer: Maximally flat passband response
Explanation:The Butterworth filter is designed to have a frequency response that is as flat as possible in the passband (maximally flat magnitude).
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22A wide band-pass filter can be constructed by cascading:
A.A Low Pass Filter and a High Pass Filter where
B.A Low Pass Filter and a High Pass Filter where
C.Two Low Pass Filters
D.Two High Pass Filters
Correct Answer: A Low Pass Filter and a High Pass Filter where
Explanation:To create a passband, the cut-off of the High Pass () must be lower than the cut-off of the Low Pass (). The signal passes between these two frequencies.
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23A Band Reject Filter is also commonly known as a:
A.Notch Filter
B.All-pass Filter
C.Delay Filter
D.Smoothing Filter
Correct Answer: Notch Filter
Explanation:A band reject filter that attenuates a very narrow range of frequencies is typically called a Notch Filter.
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24What is the primary function of an All-Pass Filter?
A.To attenuate all frequencies equally
B.To pass all frequencies with unity gain but change the phase
C.To block all frequencies
D.To remove noise
Correct Answer: To pass all frequencies with unity gain but change the phase
Explanation:An all-pass filter allows all frequencies to pass without attenuation (magnitude gain = 1) but introduces a predictable phase shift. It is used for phase equalization or delay.
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25In a square wave generator using an op-amp (Astable Multivibrator), the feedback used is:
A.Only negative feedback
B.Only positive feedback
C.Both positive and negative feedback
D.No feedback
Correct Answer: Both positive and negative feedback
Explanation:Positive feedback (via a voltage divider) sets the hysteresis thresholds (Schmitt Trigger action), and negative feedback (via an RC circuit) charges/discharges the capacitor to generate the timing.
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26In an op-amp square wave generator, the frequency of oscillation depends on:
A.The supply voltage only
B.The RC time constant and the feedback fraction
C.The input offset voltage
D.The load resistor
Correct Answer: The RC time constant and the feedback fraction
Explanation:The frequency is determined by how fast the capacitor charges/discharges through R () between the threshold voltages set by the feedback fraction .
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27A triangular wave generator is typically formed by connecting:
A.A differentiator to a square wave input
B.An integrator to a square wave generator
C.Two high pass filters in series
D.A voltage follower to a sine wave
Correct Answer: An integrator to a square wave generator
Explanation:Integrating a square wave (constant positive and negative voltages) produces linear ramps up and down, resulting in a triangular wave.
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28In a triangular wave generator, what determines the slope of the ramp?
A.The amplitude of the square wave and the integrator RC time constant
B.The supply voltage of the integrator only
C.The feedback resistor of the comparator
D.The slew rate of the op-amp only
Correct Answer: The amplitude of the square wave and the integrator RC time constant
Explanation:The slope is . Since is the square wave amplitude, both that amplitude and the RC values determine the slope.
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29How is a sawtooth waveform different from a triangular waveform?
A.It has a constant frequency
B.It has equal rise and fall times
C.It has unequal rise and fall times
D.It is sinusoidal
Correct Answer: It has unequal rise and fall times
Explanation:A sawtooth wave has a slow linear rise (ramp) and a very fast fall (flyback), or vice-versa, making it asymmetric compared to a symmetrical triangular wave.
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30A Voltage Controlled Oscillator (VCO) produces an output signal whose frequency is proportional to:
A.The input current
B.The input voltage
C.The supply current
D.The ambient temperature
Correct Answer: The input voltage
Explanation:As the name suggests, a VCO's oscillation frequency is controlled directly by an external DC control voltage.
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31Which logic creates a sawtooth wave generator from a triangular wave generator circuit?
A.Adding a diode in parallel with the integrator resistor
B.Using a larger capacitor
C.Removing the comparator
D.Using a dual supply
Correct Answer: Adding a diode in parallel with the integrator resistor
Explanation:By placing a diode (often with a small resistor) in parallel with the charging resistor, the capacitor charges and discharges through different paths with drastically different time constants, creating the asymmetry.
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32The Quality Factor (Q) of a Band Pass Filter determines:
A.The gain of the filter
B.The selectivity or sharpness of the passband
C.The input impedance
D.The DC offset
Correct Answer: The selectivity or sharpness of the passband
Explanation:Q is defined as . A high Q indicates a narrow bandwidth and high selectivity.
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33What is the gain of a voltage follower?
A.Infinity
B.Zero
C.Unity (1)
D.-1
Correct Answer: Unity (1)
Explanation:A voltage follower (buffer) has a voltage gain of exactly 1. .
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34In a first-order high pass filter, as frequency approaches infinity, the gain approaches:
A.
B.The passband gain defined by resistors ()
C.Infinity
D.-1
Correct Answer: The passband gain defined by resistors ()
Explanation:At high frequencies, the capacitor acts as a short circuit, and the circuit behaves like a standard non-inverting amplifier with gain .
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35The phase shift of an All-Pass filter varies from:
A.0 to 180 degrees
B.-90 to +90 degrees
C.0 to 90 degrees
D.Fixed at 180 degrees
Correct Answer: 0 to 180 degrees
Explanation:Depending on the specific topology (lag or lead), the phase shift of a first-order all-pass filter typically spans from 0 to 180 degrees (or -180 to 0) as frequency sweeps from 0 to infinity.
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36A scaling amplifier is essentially:
A.A summing amplifier where inputs have different weighting resistors
B.A unity gain buffer
C.A comparator
D.A differentiator
Correct Answer: A summing amplifier where inputs have different weighting resistors
Explanation:If the input resistors in a summing amplifier are not equal, the inputs are amplified by different factors (scaled) before being summed.
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37In a transconductance amplifier (Voltage-to-Current), if the load is grounded, the circuit relies on:
A.Positive feedback only
B.Matched resistors to balance the bridge (e.g., Howland)
C.A capacitor in the input
D.Open loop operation
Correct Answer: Matched resistors to balance the bridge (e.g., Howland)
Explanation:The Howland Current Pump relies on precise resistor matching to ensure the output current depends only on the input voltage and not on the load voltage swing.
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38The 'virtual ground' concept is most applicable to:
A.The non-inverting terminal in a non-inverting amplifier
B.The inverting terminal in an inverting amplifier with the non-inverting terminal grounded
C.The output terminal
D.The power supply pins
Correct Answer: The inverting terminal in an inverting amplifier with the non-inverting terminal grounded
Explanation:Because the non-inverting terminal is grounded and the potential difference between inputs is effectively zero due to high gain, the inverting terminal is at 'virtual ground'.
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39For a first-order low pass filter, if and , the cut-off frequency is approximately:
A.159 Hz
B.1.59 kHz
C.15.9 kHz
D.159 kHz
Correct Answer: 1.59 kHz
Explanation:.
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40What happens to the output of an ideal integrator if the input is a constant positive DC voltage?
A.The output remains constant
B.The output ramps down linearly towards negative saturation
C.The output ramps up linearly towards positive saturation
D.The output oscillates
Correct Answer: The output ramps down linearly towards negative saturation
Explanation:For an inverting integrator, . If is positive constant, the integral grows positively, and the negative sign causes the output to ramp down negatively.
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41Which filter is used to remove mains hum (50Hz or 60Hz) from a signal?
A.Low Pass Filter
B.High Pass Filter
C.Narrow Band Reject (Notch) Filter
D.All-Pass Filter
Correct Answer: Narrow Band Reject (Notch) Filter
Explanation:A notch filter is designed to reject a specific frequency (like 50/60Hz noise) while passing all other frequencies.
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42In a Schmitt trigger (used in square wave generators), the hysteresis voltage is defined as:
A.The difference between the Upper Threshold Voltage () and Lower Threshold Voltage ()
B.The sum of the threshold voltages
C.The supply voltage
D.The offset voltage
Correct Answer: The difference between the Upper Threshold Voltage () and Lower Threshold Voltage ()
Explanation:Hysteresis width = . This prevents noise from causing false triggering.
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43To increase the period of oscillation in an op-amp square wave generator, one should:
A.Decrease the value of the capacitor C
B.Increase the value of the capacitor C
C.Remove the feedback resistor
D.Increase the supply voltage
Correct Answer: Increase the value of the capacitor C
Explanation:The period is proportional to . Increasing C increases the time constant, slowing down the charging/discharging, thus increasing the period (lowering frequency).
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44The input impedance of an inverting summing amplifier is:
A.Infinite
B.Zero
C.Approximately equal to the corresponding input resistor for that channel
D.Equal to the feedback resistor
Correct Answer: Approximately equal to the corresponding input resistor for that channel
Explanation:Because of the virtual ground at the inverting input, the input impedance seen by source is simply .
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45What is the effect of changing the duty cycle in a pulse generator?
A.It changes the frequency significantly
B.It changes the ratio of the ON time to the total period
C.It changes the amplitude
D.It converts the wave to a sine wave
Correct Answer: It changes the ratio of the ON time to the total period
Explanation:Duty cycle is defined as . Varying it changes the pulse width without necessarily changing the frequency.
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46Active filters are generally not suitable for:
A.Audio frequencies
B.Instrumentation signals
C.Very high voltage and high current applications
D.Biomedical signals
Correct Answer: Very high voltage and high current applications
Explanation:Op-amps are typically low-power devices. Active filters are used for signal processing, not for handling high power (voltage/current) directly.
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47In a wide band-reject filter constructed by summing outputs, how are the filters arranged?
A.A Low Pass () and High Pass () in parallel, summed at output, with
B.Cascaded Low Pass and High Pass
C.Two All-Pass filters
D.Two Low Pass filters
Correct Answer: A Low Pass () and High Pass () in parallel, summed at output, with
Explanation:To reject the middle band, you pass low frequencies (LPF) and high frequencies (HPF) separately and sum them. The gap between the LPF cut-off and HPF cut-off becomes the reject band.
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48Why is the Butterworth response often preferred for audio applications?
A.It has the steepest roll-off
B.It introduces the least phase distortion
C.It has no ripple in the passband (flat response)
D.It is the cheapest to build
Correct Answer: It has no ripple in the passband (flat response)
Explanation:The maximally flat magnitude response ensures that frequencies within the passband are amplified equally, preserving the fidelity of the audio signal.
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49The output of a differentiator for a sine wave input is:
A.
B.
C.
D.
Correct Answer:
Explanation:Differentiation of is . The inverting op-amp adds a negative sign and the gain factor . Output is .
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50A typical VCO IC used in analog electronics is:
A.IC 741
B.IC 555
C.IC 566
D.IC 7805
Correct Answer: IC 566
Explanation:The NE/SE566 is a classic Voltage Controlled Oscillator IC. (Note: 555 can be configured as VCO, but 566 is a dedicated VCO chip).
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