In the active region, the BJT acts as an amplifier. This requires the emitter-base junction to be forward-biased to allow current flow, and the collector-base junction to be reverse-biased to collect the charge carriers.
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4Which of the following equations correctly relates the Emitter (), Base (), and Collector () currents in a BJT?
Transistor current components
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
According to Kirchhoff's Current Law applied to the transistor, the emitter current () is the sum of the base current () and the collector current ().
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5In a Common Emitter (CE) configuration, which terminal is common to both the input and output circuits?
CE, CB and CC configurations of BJT
Easy
A.Collector
B.Base
C.None of the above
D.Emitter
Correct Answer: Emitter
Explanation:
In the Common Emitter (CE) configuration, the input signal is applied between the base and emitter, and the output is taken from between the collector and emitter. Thus, the emitter terminal is common.
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6In which region of operation is a BJT primarily used for amplification?
BJT as an amplifier
Easy
A.Cut-off Region
B.Saturation Region
C.Breakdown Region
D.Active Region
Correct Answer: Active Region
Explanation:
A BJT acts as a linear amplifier when it is biased to operate in the active region. The cut-off and saturation regions are used for switching applications.
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7When a transistor is used as a switch, it primarily operates in which two regions?
Transistor as a Switch
Easy
A.Active and Saturation
B.Active and Breakdown
C.Cut-off and Active
D.Cut-off and Saturation
Correct Answer: Cut-off and Saturation
Explanation:
As a switch, a transistor is either fully OFF (cut-off region, acting as an open switch) or fully ON (saturation region, acting as a closed switch).
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8The common-base DC current gain, alpha (), is defined as the ratio of:
Transistor current components
Easy
A.Collector Current to Emitter Current ()
B.Collector Current to Base Current ()
C.Emitter Current to Collector Current ()
D.Base Current to Emitter Current ()
Correct Answer: Collector Current to Emitter Current ()
Explanation:
Alpha () is the DC current gain for the common-base configuration. It is the ratio of the collector current () to the emitter current (). Its value is always slightly less than 1.
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9A PNP transistor consists of:
Junction transistor
Easy
A.Two layers of P-type material only
B.A layer of N-type material sandwiched between two layers of P-type material
C.Two layers of N-type material only
D.A layer of P-type material sandwiched between two layers of N-type material
Correct Answer: A layer of N-type material sandwiched between two layers of P-type material
Explanation:
A PNP transistor is formed by sandwiching a thin layer of N-type semiconductor (the base) between two thicker layers of P-type semiconductor (the emitter and collector).
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10The common-emitter DC current gain, beta (), is defined as the ratio of:
Transistor current components
Easy
A.Emitter Current to Base Current ()
B.Collector Current to Emitter Current ()
C.Collector Current to Base Current ()
D.Base Current to Collector Current ()
Correct Answer: Collector Current to Base Current ()
Explanation:
Beta () is the DC current gain for the common-emitter configuration. It is the ratio of the collector current () to the base current (). Its value is typically high, often between 50 and 400.
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11Which BJT amplifier configuration is known for having the highest current gain?
Comparisons of transistor amplifier configurations
Easy
A.Common Collector (CC)
B.Common Emitter (CE)
C.Common Base (CB)
D.All have the same current gain
Correct Answer: Common Emitter (CE)
Explanation:
The Common Emitter (CE) configuration provides the highest current gain, represented by beta (), which is typically much larger than 1. The CB configuration has a current gain slightly less than 1, and the CC configuration has a high current gain similar to CE.
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12Which BJT configuration is also known as an 'emitter follower'?
CE, CB and CC configurations of BJT
Easy
A.Common Gate (CG)
B.Common Emitter (CE)
C.Common Collector (CC)
D.Common Base (CB)
Correct Answer: Common Collector (CC)
Explanation:
The Common Collector (CC) configuration is called an emitter follower because the output voltage taken at the emitter closely follows the input voltage applied at the base. It has a voltage gain of approximately 1.
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13Which BJT configuration is characterized by a high input impedance and a low output impedance?
Comparisons of transistor amplifier configurations
Easy
A.Common Collector (CC)
B.None of the above
C.Common Base (CB)
D.Common Emitter (CE)
Correct Answer: Common Collector (CC)
Explanation:
The Common Collector (CC) or emitter follower configuration is widely used as a buffer because it has a high input impedance (doesn't load the previous stage) and a low output impedance (can drive low-impedance loads).
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14In a BJT, the emitter region is doped ____ compared to the base and collector regions.
Operation
Easy
A.heavily
B.equally
C.moderately
D.lightly
Correct Answer: heavily
Explanation:
The emitter is heavily doped to inject a large number of charge carriers into the base. The base is lightly doped and very thin, while the collector is moderately doped.
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15When a BJT switch is in the 'ON' state, it is operating in the ____ region.
Transistor as a Switch
Easy
A.Saturation
B.Breakdown
C.Active
D.Cut-off
Correct Answer: Saturation
Explanation:
The 'ON' state of a transistor switch corresponds to the saturation region, where the transistor acts like a closed switch with a small voltage drop across it, allowing maximum current to flow.
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16In a Common Base (CB) configuration, the input signal is applied to the ____ and the output is taken from the ____.
CE, CB and CC configurations of BJT
Easy
A.Collector; Emitter
B.Base; Collector
C.Emitter; Collector
D.Emitter; Base
Correct Answer: Emitter; Collector
Explanation:
In the Common Base (CB) configuration, the base terminal is common. The input signal is applied to the emitter, and the output signal is taken from the collector.
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17What is the primary purpose of using a BJT as an amplifier?
BJT as an amplifier
Easy
A.To act as a perfect conductor
B.To convert AC to DC
C.To increase the strength of a weak signal
D.To block current flow completely
Correct Answer: To increase the strength of a weak signal
Explanation:
An amplifier's main function is to take a weak input signal (voltage or current) and produce a stronger output signal that is a magnified replica of the input.
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18The time required for the collector current to rise from 10% to 90% of its final (saturation) value is called:
Transistor Switching Times
Easy
A.Rise Time ()
B.Storage Time ()
C.Delay Time ()
D.Fall Time ()
Correct Answer: Rise Time ()
Explanation:
Rise time () is a standard measure of a transistor's switching speed, specifically defining how quickly it transitions from the cut-off state to the saturation state once it begins to turn on.
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19Which amplifier configuration provides a voltage gain greater than one but a current gain of approximately one?
Comparisons of transistor amplifier configurations
Easy
A.Common Emitter (CE)
B.All configurations
C.Common Base (CB)
D.Common Collector (CC)
Correct Answer: Common Base (CB)
Explanation:
The Common Base (CB) configuration provides a high voltage gain but its current gain () is always slightly less than one. It is often used in high-frequency applications.
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20Which of the following represents the time it takes for a transistor to start conducting after the input pulse is applied?
Transistor Switching Times
Easy
A.Fall Time ()
B.Storage Time ()
C.Delay Time ()
D.Rise Time ()
Correct Answer: Delay Time ()
Explanation:
Delay time () is the time interval from the application of the input 'ON' pulse to the point where the collector current reaches 10% of its final value. It represents the initial delay before the transistor begins to turn on.
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21If the collector-base junction and the emitter-base junction of a BJT are both forward-biased, in which region of operation is the transistor?
Operation
Medium
A.Cutoff region
B.Saturation region
C.Active region
D.Reverse-active region
Correct Answer: Saturation region
Explanation:
In the saturation region, both the emitter-base junction and the collector-base junction are forward-biased. This allows maximum current to flow from collector to emitter, making the transistor act like a closed switch.
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22A transistor has a common-base current gain () of 0.99. If the emitter current () is 5 mA, what is the base current ()?
Transistor current components
Medium
A.0.99 mA
B.5.05 mA
C.4.95 mA
D.0.05 mA
Correct Answer: 0.05 mA
Explanation:
The correct option follows directly from the given concept and definitions.
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23In a Common Emitter (CE) configuration, if the common-emitter current gain () is 100, what is the corresponding common-base current gain ()?
CE, CB and CC configurations of BJT
Medium
A.100
B.0.99
C.1.01
D.0.9
Correct Answer: 0.99
Explanation:
The relationship between and is given by the formula . Substituting , we get .
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24Why is the Q-point (operating point) of a BJT amplifier typically set in the middle of the active region on the DC load line?
BJT as an amplifier
Medium
A.To ensure the transistor operates only in saturation.
B.To allow for maximum undistorted output signal swing.
C.To minimize the input impedance.
D.To maximize the power consumption.
Correct Answer: To allow for maximum undistorted output signal swing.
Explanation:
Placing the Q-point in the center of the active region provides the largest possible room for both the positive and negative swings of the AC output signal before it gets clipped by hitting the saturation or cutoff regions, thus avoiding distortion.
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25In a CE switching circuit, V, k, and . What minimum base current () is required to drive the transistor into saturation? (Assume V)
Transistor as a Switch
Medium
A.200 mA
B.0.196 mA
C.9.8 mA
D.0.2 mA
Correct Answer: 0.196 mA
Explanation:
The collector saturation current is . The minimum base current required for saturation is .
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26Which BJT amplifier configuration is most suitable for impedance matching, connecting a high-impedance source to a low-impedance load?
Comparisons of transistor amplifier configurations
Medium
A.Common Emitter (CE)
B.Common Collector (CC)
C.Common Base (CB)
D.Common Gate (CG)
Correct Answer: Common Collector (CC)
Explanation:
The Common Collector (CC) configuration, also known as an emitter follower, is characterized by a high input impedance and a low output impedance. This makes it ideal for use as a buffer or for impedance matching between stages.
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27What is the primary cause of 'storage time' () when a BJT is switched from saturation to cutoff?
Transistor Switching Times
Medium
A.The time needed to remove excess minority carriers stored in the base region.
B.The time required for the collector voltage to rise.
C.The time taken to charge the base-emitter junction capacitance.
D.The delay caused by parasitic inductance in the circuit.
Correct Answer: The time needed to remove excess minority carriers stored in the base region.
Explanation:
When a transistor is in saturation, the base is flooded with more charge carriers than needed. Storage time is the delay required for these excess minority carriers in the base to recombine or be swept out before the transistor can begin to turn off.
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28Why is the base region of a BJT made very thin and lightly doped?
Junction transistor
Medium
A.To ensure most charge carriers from the emitter pass to the collector without recombining.
B.To maximize the base-emitter voltage.
C.To increase the resistance of the base and reduce power consumption.
D.To increase the transit time of charge carriers.
Correct Answer: To ensure most charge carriers from the emitter pass to the collector without recombining.
Explanation:
A thin and lightly doped base minimizes the chance for charge carriers (electrons in NPN, holes in PNP) injected from the emitter to recombine with the majority carriers in the base. This allows almost all injected carriers to reach the collector, resulting in a high current gain ().
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29How is the collector leakage current in a common-emitter configuration () related to the leakage current in a common-base configuration ()?
Transistor current components
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
is the collector-emitter leakage current with the base open. This small leakage current acts as a base current and gets amplified by the transistor, resulting in a much larger collector current given by .
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30What is the phase relationship between the input voltage at the base and the output voltage at the collector for a Common Emitter (CE) amplifier?
BJT as an amplifier
Medium
A.90 degrees (leading)
B.0 degrees (in phase)
C.270 degrees (lagging)
D.180 degrees (out of phase)
Correct Answer: 180 degrees (out of phase)
Explanation:
In a CE amplifier, when the input voltage at the base increases, it increases the base current () and consequently the collector current (). The increased causes a larger voltage drop across the collector resistor (), which in turn decreases the output voltage (). This inverse relationship results in a 180-degree phase shift.
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31Which BJT configuration provides a high voltage gain, a high current gain, and a high power gain?
Comparisons of transistor amplifier configurations
Medium
A.All three configurations have similar power gain.
B.Common Emitter (CE)
C.Common Collector (CC)
D.Common Base (CB)
Correct Answer: Common Emitter (CE)
Explanation:
The Common Emitter (CE) configuration is the most widely used because it provides both significant voltage gain and significant current gain. The product of these two results in the highest power gain among the three configurations.
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32The input characteristics of a Common Base (CB) configuration are a plot of __.
CE, CB and CC configurations of BJT
Medium
A.Base Current () vs. Base-Emitter Voltage () for a constant Collector-Emitter Voltage ()
B.Emitter Current () vs. Emitter-Base Voltage () for a constant Collector-Base Voltage ()
C.Collector Current () vs. Base Current () for a constant Collector-Emitter Voltage ()
D.Collector Current () vs. Collector-Base Voltage () for a constant Emitter Current ()
Correct Answer: Emitter Current () vs. Emitter-Base Voltage () for a constant Collector-Base Voltage ()
Explanation:
Input characteristics show the relationship between the input current and input voltage. For a CB configuration, the input is at the emitter-base junction. Therefore, the plot is of input current () versus input voltage (), while keeping the output voltage () constant.
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33What is the 'Early Effect' or 'base-width modulation' in a BJT?
Operation
Medium
A.The increase in emitter current with temperature.
B.The reduction in current gain () at high collector currents.
C.The widening of the base-collector depletion region into the base as increases, which reduces the effective base width.
D.The effect of forward biasing the collector-base junction.
Correct Answer: The widening of the base-collector depletion region into the base as increases, which reduces the effective base width.
Explanation:
The Early effect describes how the reverse bias voltage across the collector-base junction affects the transistor's behavior. An increase in this reverse bias widens the depletion region, reducing the effective width of the base. This leads to a slight increase in collector current, causing the output characteristic curves to have a non-zero slope.
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34When a BJT is used as a switch, what are the ideal values of the collector-emitter voltage () in the OFF and ON states, respectively?
Transistor as a Switch
Medium
A.0 V and
B.0.7 V and 0.2 V
C. and
D. and 0 V
Correct Answer: and 0 V
Explanation:
Ideally, in the OFF state (cutoff), the transistor acts as an open circuit, so no current flows and the output voltage is equal to the supply voltage . In the ON state (saturation), it acts as a perfect closed switch, so there is no voltage drop across it, making equal to 0 V.
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35The turn-on time () of a BJT switch is defined as the sum of which two time intervals?
Transistor Switching Times
Medium
A.Rise time () and fall time ()
B.Delay time () and rise time ()
C.Storage time () and fall time ()
D.Delay time () and storage time ()
Correct Answer: Delay time () and rise time ()
Explanation:
The turn-on time () is the total time it takes for the transistor to switch from the OFF state to the ON state. It is composed of the delay time (), which is the time before the collector current starts to rise, and the rise time (), which is the time it takes for the current to rise from 10% to 90% of its final value. So, .
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36What is the primary reason for doping the emitter region of a BJT much more heavily than the base region?
Junction transistor
Medium
A.To make the transistor physically smaller.
B.To ensure a high emitter injection efficiency.
C.To increase the breakdown voltage of the emitter-base junction.
D.To reduce the resistance of the emitter terminal.
Correct Answer: To ensure a high emitter injection efficiency.
Explanation:
Heavy doping of the emitter ensures that when the emitter-base junction is forward-biased, the current is dominated by charge carriers injected from the emitter into the base, rather than carriers injected from the base into the emitter. This high injection efficiency is crucial for achieving a high current gain.
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37A Common Base (CB) amplifier has its input applied to the emitter and its output taken from the collector. What is a key characteristic of its voltage gain and current gain?
CE, CB and CC configurations of BJT
Medium
A.Low voltage gain (approximately 1), low current gain (less than 1).
B.Low voltage gain (less than 1), high current gain.
C.High voltage gain, low current gain (less than 1).
D.High voltage gain, high current gain.
Correct Answer: High voltage gain, low current gain (less than 1).
Explanation:
The CB configuration has a current gain () that is always slightly less than 1. However, it can provide a very high voltage gain because its high output impedance allows a large output voltage swing for a small input voltage change. It is often used in high-frequency applications.
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38In a CE amplifier circuit, if the emitter bypass capacitor is removed, what is the most significant effect on the amplifier's performance?
BJT as an amplifier
Medium
A.The voltage gain will increase significantly.
B.The voltage gain will decrease significantly.
C.The output signal will no longer be inverted.
D.The DC Q-point will become unstable.
Correct Answer: The voltage gain will decrease significantly.
Explanation:
Removing the bypass capacitor introduces the emitter resistor () into the AC circuit. This creates negative feedback, also known as emitter degeneration. This feedback stabilizes the amplifier but drastically reduces the AC voltage gain. The gain becomes approximately .
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39If the terminals of an NPN transistor (designed as emitter, base, collector) are accidentally connected with the emitter and collector leads swapped, what is the likely outcome on its performance?
Operation
Medium
A.The transistor will only operate as a diode.
B.The transistor will function normally with no change.
C.The transistor will operate in the reverse-active mode with a very low current gain ().
D.The transistor will be permanently damaged.
Correct Answer: The transistor will operate in the reverse-active mode with a very low current gain ().
Explanation:
While both emitter and collector are N-type, their doping levels and physical sizes are very different. The emitter is heavily doped for high injection efficiency, and the collector is large to dissipate heat. Swapping them makes the new 'emitter' (the original collector) a poor injector of carriers, resulting in a very low reverse .
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40How does an increase in temperature typically affect the collector current () in a BJT?
Transistor current components
Medium
A.It has no significant effect on .
B.It causes to become unstable and oscillate.
C.It causes to decrease due to increased electron-hole recombination.
D.It causes to increase, mainly due to the increase in reverse saturation current ().
Correct Answer: It causes to increase, mainly due to the increase in reverse saturation current ().
Explanation:
The reverse saturation current () is highly dependent on temperature, approximately doubling for every 10°C rise. Since the total collector current in a CE configuration is , an increase in leads to a significant increase in the overall collector current, which can cause thermal runaway if not properly stabilized.
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41In a PNP BJT, the base current is primarily composed of two components: recombination current in the base () and electron current injected from the base into the emitter (). If the base doping is significantly increased while keeping emitter doping constant, how does this affect the current gain and the emitter injection efficiency ?
Transistor current components
Hard
A. increases and increases.
B. decreases and decreases.
C. decreases and increases.
D. increases and decreases.
Correct Answer: decreases and decreases.
Explanation:
Emitter injection efficiency for a PNP BJT is . Increasing base doping increases the back-injected electron current () from the base to the emitter, thus decreasing . The current gain depends directly on (since ). A decrease in leads to a decrease in and a significant decrease in . Additionally, higher base doping increases recombination, which also reduces gain.
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42A common-emitter (CE) amplifier exhibits a significant Miller effect, which multiplies the base-collector capacitance () by a factor of approximately . Why is this effect negligible in a common-base (CB) configuration?
CE, CB and CC configurations of BJT
Hard
A.The voltage gain of a CB amplifier is less than unity, preventing any multiplication.
B.In a CB amplifier, the base is at AC ground, so the collector-base capacitance () is connected from the output node (collector) to ground, not between the input and output nodes.
C.The collector-base junction capacitance is short-circuited to ground in the CB configuration.
D.The input impedance of a CB amplifier is extremely high, preventing any current from flowing through the feedback capacitance.
Correct Answer: In a CB amplifier, the base is at AC ground, so the collector-base capacitance () is connected from the output node (collector) to ground, not between the input and output nodes.
Explanation:
The Miller effect occurs when an impedance (like ) is connected between the input and output of an inverting amplifier. In a CB configuration, the input is the emitter and the output is the collector. The base is the common terminal (AC ground). Therefore, the capacitance is connected between the output (collector) and AC ground, not providing a feedback path from output to input. This eliminates the Miller multiplication effect, contributing to the CB amplifier's excellent high-frequency response.
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43To minimize the storage time () of a BJT switching from saturation to cutoff, which of the following design choices is most effective?
Transistor Switching Times
Hard
A.Using a transistor with a very wide base region to increase minority carrier lifetime.
B.Increasing the collector resistor () to ensure the transistor barely enters the saturation region.
C.Using a transistor with a very high and driving it deep into saturation with a large base current.
D.Connecting a 'speed-up' capacitor in parallel with the base resistor and using a Schottky diode clamp between the base and collector.
Correct Answer: Connecting a 'speed-up' capacitor in parallel with the base resistor and using a Schottky diode clamp between the base and collector.
Explanation:
Storage time () is caused by the excess minority carriers stored in the base during saturation. A Schottky diode clamp (Baker clamp) prevents the BJT from hard-saturating by diverting excess base current to the collector, thus preventing large excess charge storage. A 'speed-up' capacitor provides a large negative current pulse at the beginning of turn-off, which helps to quickly remove any stored charge. This combination is highly effective at minimizing .
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44An application requires a three-stage amplifier with very high input impedance, high overall voltage gain, and a low output impedance to drive a 50 load. Which cascade of BJT configurations is the most suitable design choice?
Comparisons of transistor amplifier configurations
Hard
A.CC - CE - CC
B.CE - CB - CC
C.CB - CE - CC
D.CC - CE - CB
Correct Answer: CC - CE - CC
Explanation:
The first stage needs high input impedance, for which the Common-Collector (CC) stage is ideal. The second stage requires high voltage gain, which is the primary strength of the Common-Emitter (CE) stage. The third (output) stage must provide a low output impedance to effectively drive the low-impedance load, a task for which the Common-Collector (CC) stage is perfectly suited. Therefore, the CC-CE-CC configuration meets all the specified requirements.
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45For a BJT operating in the active region, the Early voltage () is 80 V and the collector current () is 4 mA. If the collector-emitter voltage () is increased from 5 V to 15 V, what is the approximate change in collector current () due to base-width modulation?
BJT as an amplifier
Hard
A. mA
B. mA
C. mA
D. mA
Correct Answer: mA
Explanation:
The Early effect is modeled by the output resistance . First, calculate the output resistance at the initial operating point: k. The change in collector current due to a change in is given by Ohm's law for this resistance: mA.
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46The phenomenon of 'punch-through' in a BJT results in a sharp increase in collector current. This occurs when:
Operation
Hard
A.The transistor becomes so heavily saturated that the collector-emitter voltage drops to almost zero, causing a current spike.
B.Thermal runaway causes the collector current to increase uncontrollably, melting the junctions.
C.The collector-base depletion region, widened by a large , extends completely through the neutral base and merges with the emitter-base depletion region.
D.The emitter-base junction avalanches, causing a massive increase in base current.
Correct Answer: The collector-base depletion region, widened by a large , extends completely through the neutral base and merges with the emitter-base depletion region.
Explanation:
Punch-through (or reach-through) is a breakdown mechanism distinct from avalanche or thermal runaway. It is caused by the widening of the collector-base depletion region under high reverse bias. If the base is sufficiently narrow and the voltage is high enough, the depletion region can span the entire base. When this happens, the emitter and collector are effectively shorted, and the base loses control over the current, leading to a large, uncontrolled current flow.
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47Consider a BJT inverter with V and . The transistor has a minimum guaranteed current gain, , and V. To ensure the switch operates in hard saturation with an overdrive factor (ODF) of 2.5, what is the required input base current ?
Transistor as a Switch
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Calculate the collector saturation current: mA.
Find the minimum base current for saturation: A.
Apply the overdrive factor (ODF): A.
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48In the design of a BJT for high-frequency applications, a trade-off exists between low base resistance () and a short base transit time (). Why does this fundamental trade-off exist?
Junction transistor
Hard
A.Decreasing base width to reduce inevitably increases base doping, which increases .
B.Making the base wider to decrease also increases the path length for carriers, increasing .
C.A narrow base (low ) requires light doping to prevent punch-through, which results in a high .
D.To decrease , the base must be narrow. To decrease for a given width, the doping must be high. However, very high base doping degrades emitter injection efficiency.
Correct Answer: To decrease , the base must be narrow. To decrease for a given width, the doping must be high. However, very high base doping degrades emitter injection efficiency.
Explanation:
Base transit time is proportional to the square of the base width (), so a narrow base is critical for high speed. Base resistance is inversely proportional to base width and base doping concentration. One could try to compensate for a narrow base by heavily increasing the base doping to lower . However, if the base doping becomes comparable to the emitter doping, the emitter injection efficiency plummets, destroying the transistor's gain. This forces a compromise between a narrow, lightly-doped base (fast but high resistance) and a wider, more heavily-doped base (slower but lower resistance).
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49In the Ebers-Moll model, the parameter (reverse common-base current gain) is typically much smaller than (forward gain). This is a direct physical consequence of:
Transistor current components
Hard
A.The Early effect being more prominent in the reverse active mode.
B.The deliberate structural asymmetry, where the emitter is heavily doped and the collector is lightly doped.
C.The base region being much narrower than the collector region.
D.The higher recombination rate in the collector bulk material compared to the emitter.
Correct Answer: The deliberate structural asymmetry, where the emitter is heavily doped and the collector is lightly doped.
Explanation:
The current gain is a product of emitter injection efficiency () and base transport factor. In forward active mode, the heavily doped emitter injects carriers very efficiently into the less-doped base, making close to 1. In reverse active mode, the collector acts as the emitter. Since the collector is lightly doped compared to the base, its ability to inject carriers into the base is very poor, resulting in a low reverse injection efficiency . This poor injection efficiency is the primary reason why is much smaller than .
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50The transition frequency, , of a BJT is defined as the frequency at which the common-emitter short-circuit current gain drops to unity. If a BJT has GHz and a low-frequency current gain , what is its beta cutoff frequency ()?
CE, CB and CC configurations of BJT
Hard
A.1.2 GHz
B.15 MHz
C.8 MHz
D.180 MHz
Correct Answer: 8 MHz
Explanation:
The gain-bandwidth product for a BJT states that the transition frequency is approximately equal to the product of the low-frequency current gain and the beta cutoff frequency . The relationship is . Therefore, we can find by rearranging the formula: MHz.
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51In a CE amplifier with emitter degeneration (an unbypassed emitter resistor ), the voltage gain is approximately and the input resistance is . What is the primary reason for the significant increase in output resistance () when looking into the collector?
BJT as an amplifier
Hard
A.The output resistance is always infinite for an ideal BJT, and makes it closer to ideal.
B.The negative feedback forces the collector current to be more independent of the collector voltage, making it behave more like an ideal current source.
C.The base current is reduced due to the feedback, which in turn reduces the collector current and increases the impedance.
D.The resistor simply adds to the collector resistance in the output loop.
Correct Answer: The negative feedback forces the collector current to be more independent of the collector voltage, making it behave more like an ideal current source.
Explanation:
The output resistance is the change in collector voltage divided by the resulting change in collector current (), with the input source set to zero. Emitter degeneration provides negative feedback. If a change in (e.g., due to the Early effect) causes to change, this also changes , which alters the voltage drop across . This change is fed back to the base-emitter loop, opposing the initial change in . This opposition makes much less sensitive to variations in , which by definition means the output resistance is higher.
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52The total charge stored in the base of a BJT in the forward-active region is , and the excess charge stored in saturation is . The turn-on base current is and the turn-off base current is . The rise time () and storage time () are primarily determined by:
Transistor Switching Times
Hard
A.Both and depend on supplying the total charge ().
B.Both and depend on charging parasitic capacitances and are independent of stored charge.
C. depends on removing , and depends on supplying .
D. depends on supplying , and depends on removing .
Correct Answer: depends on supplying , and depends on removing .
Explanation:
The switching times are directly related to the movement of charge. The rise time () is the time it takes for the collector current to rise from 10% to 90% of its final value, which corresponds to the time taken by the base current to supply the charge needed to support the active-region current. The storage time () is the delay before the transistor begins to turn off, which is the time required for the reverse base current to remove the excess saturation charge from the base.
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53A cascode amplifier (CE stage followed by a CB stage) is known for its wide bandwidth. This is primarily because the Miller effect is suppressed. How does the cascode configuration achieve this suppression?
Comparisons of transistor amplifier configurations
Hard
A.The overall current gain of the cascode is reduced to unity, eliminating the gain term in the Miller equation.
B.The CB stage has a voltage gain of -1, which cancels the Miller capacitance.
C.The load seen by the CE stage is the very low input impedance of the CB stage (), resulting in a very small voltage gain for the CE stage, which minimizes the Miller multiplication of .
D.The cascode topology uses positive feedback to resonate with and cancel the Miller capacitance at high frequencies.
Correct Answer: The load seen by the CE stage is the very low input impedance of the CB stage (), resulting in a very small voltage gain for the CE stage, which minimizes the Miller multiplication of .
Explanation:
The Miller input capacitance is given by , where is the voltage gain of the first stage. In a cascode amplifier, the first CE stage (Q1) is loaded by the second CB stage (Q2). The input impedance of a CB stage is its emitter resistance, , which is very small (e.g., a few ohms). Therefore, the voltage gain of the CE stage, . With a voltage gain close to -1, the Miller multiplication factor is only about 2, compared to potentially >100 in a normal CE stage. This drastic reduction in the effective input capacitance is what gives the cascode its superior high-frequency performance.
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54In a BJT switch with a resistive load, the peak instantaneous power dissipation occurs during the switching transition (rise/fall times). Assuming linear transitions for both and , at what point during the transition from OFF to ON does this peak power occur?
Transistor as a Switch
Hard
A.Exactly at the midpoint of the transition, when and .
B.At the very beginning of the transition, when is highest.
C.Peak power is constant throughout the entire transition period.
D.At the very end of the transition, when is highest.
Correct Answer: Exactly at the midpoint of the transition, when and .
Explanation:
Instantaneous power is . During the transition from OFF to ON, falls from to 0 (approx) and rises from 0 to . If we assume linear ramps, and , where T is the transition time. Then . This is a parabolic function of , which has its maximum at the midpoint, . At this point, and , and the peak power is .
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55The Gummel number () is the integral of the majority carrier concentration over the neutral base width. How does the Gummel number relate to a BJT's collector current () and current gain ()?
Operation
Hard
A. only affects the base current, so is independent of it, but is inversely proportional to .
B. and are both directly proportional to squared.
C. is inversely proportional to , and is also generally inversely related to .
D. is directly proportional to , leading to a higher .
Correct Answer: is inversely proportional to , and is also generally inversely related to .
Explanation:
The collector current in a BJT is determined by the diffusion of minority carriers across the base, and its magnitude is inversely proportional to the total number of majority carriers in the base, which is the Gummel Number. So, . The base current is primarily due to recombination, which is directly related to the amount of charge in the base, and thus also increases with . Since , and decreases while increases with , the current gain is strongly and inversely dependent on the Gummel number.
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56A SiGe Heterojunction Bipolar Transistor (HBT) can achieve much higher gain and frequency response than a standard silicon BJT. This is possible because the SiGe base:
Junction transistor
Hard
A.Greatly reduces the dielectric constant of the base region, which lowers the junction capacitances and .
B.Allows for very heavy base doping to reduce base resistance, without sacrificing injection efficiency due to the valence band energy barrier created by the heterojunction.
C.Has a wider bandgap than the Si emitter, which blocks reverse current flow.
D.Is an intrinsic semiconductor, which eliminates base recombination current entirely.
Correct Answer: Allows for very heavy base doping to reduce base resistance, without sacrificing injection efficiency due to the valence band energy barrier created by the heterojunction.
Explanation:
In an HBT, the base (SiGe) has a smaller bandgap than the emitter (Si). This creates an energy barrier in the valence band that blocks the back-injection of holes from the base into the emitter. This unwanted current is a major component of the base current in normal BJTs and is what limits the maximum useful base doping. Since this current is suppressed in an HBT, the base can be doped very heavily. This drastically reduces the base resistance () without compromising the high emitter injection efficiency, leading to simultaneously high gain and high maximum frequency of oscillation ().
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57Which statement most accurately describes the primary feedback mechanism responsible for thermal runaway in a BJT amplifier with a fixed base voltage bias (e.g., from a voltage divider)?
BJT as an amplifier
Hard
A.An increase in temperature causes the base-emitter voltage to decrease (at ~ -2.1 mV/°C). With a fixed base voltage, this increases the effective forward bias, causing an exponential increase in and a runaway power-temperature loop.
B.An increase in temperature causes the reverse saturation current to double for every 10°C rise, which significantly increases , power dissipation, and temperature.
C.An increase in temperature lowers the transistor's thermal resistance, causing heat to be generated faster than it can be dissipated.
D.An increase in temperature causes to increase, which increases , leading to more power dissipation and a further temperature rise.
Correct Answer: An increase in temperature causes the base-emitter voltage to decrease (at ~ -2.1 mV/°C). With a fixed base voltage, this increases the effective forward bias, causing an exponential increase in and a runaway power-temperature loop.
Explanation:
While changes in and contribute, the dominant effect is the temperature dependence of . The collector current is exponentially dependent on (). For a fixed base voltage , as temperature rises, required for a certain current drops. This means the forward bias voltage () across the junction increases, causing to rise exponentially. This increases power dissipation (), which raises the temperature further, creating a strong positive feedback loop that can destroy the device.
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58In a common-collector (emitter-follower) amplifier, the output resistance looking into the emitter is approximately given by , where is the source resistance. Why does the source resistance (), which is in the input circuit, have a significant impact on the output resistance?
CE, CB and CC configurations of BJT
Hard
A.The dependent current source creates a feedback path where any voltage change at the output (emitter) affects , which in turn is affected by the voltage drop across , thus linking to the output impedance.
B.The Early effect links the input and output circuits through base-width modulation.
C.This formula is incorrect; output resistance is independent of the source.
D.The source resistance adds directly in series with the emitter resistance when viewed from the output.
Correct Answer: The dependent current source creates a feedback path where any voltage change at the output (emitter) affects , which in turn is affected by the voltage drop across , thus linking to the output impedance.
Explanation:
To find the output resistance, we apply a test voltage at the output (emitter) and find the current , with the input voltage source set to zero. The test voltage at the emitter creates a base current that flows back through the input loop. With the input source shorted, this flows through the source resistance , creating a base voltage . The base-emitter voltage is then . The entire behavior of the transistor is coupled through . Because influences , which is itself dependent on , the relationship between and the resulting output current (which is a function of ) is fundamentally tied to the value of .
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59At high collector current densities, the transition frequency of a BJT begins to fall off sharply. This degradation is caused by the Kirk effect (base pushout), which is best described as:
Transistor current components
Hard
A.The transistor entering deep saturation, causing a significant increase in charge storage time.
B.An avalanche breakdown in the collector region, leading to a sudden increase in collector current.
C.A sharp decrease in due to increased recombination at high current levels.
D.The charge of mobile carriers (electrons in an NPN) in the collector-base depletion region becoming comparable to the fixed donor ion charge, effectively widening the neutral base into the collector.
Correct Answer: The charge of mobile carriers (electrons in an NPN) in the collector-base depletion region becoming comparable to the fixed donor ion charge, effectively widening the neutral base into the collector.
Explanation:
The Kirk effect occurs when the injected minority carrier density in the collector becomes comparable to the collector's doping density. This mobile charge effectively cancels out the fixed charge from the ionized dopant atoms, collapsing the electric field in the collector-base depletion region. This causes the effective (neutral) base to expand into the physical collector region. This increase in the effective base width () dramatically increases the base transit time (), which directly causes the transition frequency () to decrease.
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60The storage time of a BJT switch is given by . Given a turn-on current , a minimum saturation current , and a turn-off current . If we want to reduce the storage time by a factor of 2, what new turn-off current is required, assuming is constant?
Transistor Switching Times
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The correct option follows directly from the given concept and definitions.