1In terms of energy band theory, insulators are materials with a...
Insulators, Semiconductors and Metals
Easy
A.Overlapping valence and conduction bands
B.Completely empty valence band
C.Partially filled valence band
D.Completely filled valence band and a large energy gap
Correct Answer: Completely filled valence band and a large energy gap
Explanation:
Insulators have a large energy gap (typically > 3 eV) between the full valence band and the empty conduction band, making it very difficult for electrons to jump to the conduction band and conduct electricity.
Incorrect! Try again.
2How are metals characterized in terms of their energy bands?
Insulators, Semiconductors and Metals
Easy
A.There is a large energy gap between bands
B.The valence band is completely empty
C.The conduction band is completely full
D.The valence and conduction bands overlap
Correct Answer: The valence and conduction bands overlap
Explanation:
In metals, the valence and conduction bands overlap, meaning there is no energy gap. This allows electrons to move freely and conduct electricity with very little energy.
Incorrect! Try again.
3Which of the following is a common example of an elemental semiconductor?
Insulators, Semiconductors and Metals
Easy
A.Diamond
B.Silicon (Si)
C.Glass
D.Copper (Cu)
Correct Answer: Silicon (Si)
Explanation:
Silicon (Si) and Germanium (Ge) are the most common elemental semiconductors. Copper is a metal, while glass and diamond are insulators.
Incorrect! Try again.
4In an intrinsic (pure) semiconductor at room temperature, the number of free electrons () is...
Electrons and holes in an intrinsic semiconductor
Easy
A.Less than the number of holes ()
B.Always zero
C.Greater than the number of holes ()
D.Equal to the number of holes ()
Correct Answer: Equal to the number of holes ()
Explanation:
In an intrinsic semiconductor, electrons are excited from the valence band to the conduction band, leaving behind a hole. Thus, each free electron created corresponds to one hole, so .
Incorrect! Try again.
5The process by which thermal energy creates an electron-hole pair in a semiconductor is known as...
Electrons and holes in an intrinsic semiconductor
Easy
A.Generation
B.Drift
C.Doping
D.Recombination
Correct Answer: Generation
Explanation:
Generation is the process where thermal or optical energy gives an electron enough energy to jump from the valence band to the conduction band, creating an electron-hole pair.
Incorrect! Try again.
6At absolute zero temperature (0 K), an intrinsic semiconductor behaves like a(n)...
Electrons and holes in an intrinsic semiconductor
Easy
A.Superconductor
B.N-type semiconductor
C.Perfect insulator
D.Perfect conductor
Correct Answer: Perfect insulator
Explanation:
At 0 K, there is no thermal energy to excite electrons to the conduction band. The valence band is full and the conduction band is empty, so it cannot conduct electricity.
Incorrect! Try again.
7To create an N-type semiconductor, a pure semiconductor is doped with what kind of impurity?
Donor and Acceptor Impurities
Easy
A.Pentavalent
B.Monovalent
C.Trivalent
D.Divalent
Correct Answer: Pentavalent
Explanation:
Pentavalent impurities (like Phosphorus or Arsenic) have five valence electrons. When added to a semiconductor like Silicon (which has four), they donate an extra electron, making electrons the majority carriers and creating an N-type material.
Incorrect! Try again.
8Adding acceptor impurities to a semiconductor increases the concentration of...
Donor and Acceptor Impurities
Easy
A.Both electrons and holes equally
B.Free electrons
C.Holes
D.Ions
Correct Answer: Holes
Explanation:
Acceptor impurities (trivalent atoms like Boron) have three valence electrons. They create a "hole" or a vacancy for an electron in the crystal lattice, which acts as a positive charge carrier.
Incorrect! Try again.
9What is the process of deliberately adding impurities to a pure semiconductor to modify its electrical properties called?
Donor and Acceptor Impurities
Easy
A.Doping
B.Fabrication
C.Annealing
D.Diffusion
Correct Answer: Doping
Explanation:
Doping is the intentional introduction of impurities (dopants) into an intrinsic semiconductor for the purpose of modulating its electrical, optical, and structural properties.
Incorrect! Try again.
10In an N-type semiconductor, the Fermi level is located...
Fermi level in a semiconductor having impurities
Easy
A.Closer to the valence band
B.Exactly in the middle of the band gap
C.Closer to the conduction band
D.Inside the valence band
Correct Answer: Closer to the conduction band
Explanation:
In an N-type semiconductor, there are many electrons in the conduction band. The Fermi level, which represents the average energy of these carriers, therefore shifts upward from the center of the band gap toward the conduction band.
Incorrect! Try again.
11When a pure semiconductor is doped to become P-type, the Fermi level...
Fermi level in a semiconductor having impurities
Easy
A.Moves closer to the conduction band
B.Moves into the conduction band
C.Moves closer to the valence band
D.Remains at the center of the band gap
Correct Answer: Moves closer to the valence band
Explanation:
In a P-type semiconductor, the majority carriers are holes, which exist in the valence band. The Fermi level, which indicates the energy level with a high probability of occupation by holes, shifts down closer to the valence band.
Incorrect! Try again.
12The law of mass action for a semiconductor is given by which equation, where is intrinsic concentration?
Charge densities in a semiconductor
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
The mass action law states that in thermal equilibrium, the product of the free electron concentration () and the free hole concentration () is constant and equal to the square of the intrinsic carrier concentration ().
Incorrect! Try again.
13In a P-type semiconductor, which charge carriers are considered the majority carriers?
Charge densities in a semiconductor
Easy
A.Electrons
B.Both electrons and holes
C.Holes
D.Protons
Correct Answer: Holes
Explanation:
P-type semiconductors are created by doping with acceptor impurities, which create an excess of holes. Therefore, holes are the majority charge carriers, and electrons are the minority carriers.
Incorrect! Try again.
14What is the definition of carrier mobility ()?
Mobility and Conductivity
Easy
A.Current per unit area
B.Resistance per unit length
C.Total carriers per unit volume
D.Drift velocity per unit electric field
Correct Answer: Drift velocity per unit electric field
Explanation:
Mobility () is a measure of how quickly a charge carrier moves in a material under an applied electric field (). It is defined by the equation , where is the drift velocity.
Incorrect! Try again.
15What is the standard SI unit for carrier mobility?
Mobility and Conductivity
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
Mobility () is drift velocity (, in m/s) divided by electric field (, in V/m). Therefore, the unit of mobility is .
Incorrect! Try again.
16The electrical conductivity of a semiconductor is the reciprocal of its...
Conductivity of a semiconductor
Easy
A.Resistivity
B.Resistance
C.Current
D.Mobility
Correct Answer: Resistivity
Explanation:
Conductivity () is an intrinsic property of a material that measures its ability to conduct electric current. It is defined as the reciprocal of resistivity (), i.e., .
Incorrect! Try again.
17How does the conductivity of a semiconductor generally change with an increase in temperature?
Conductivity of a semiconductor
Easy
A.It becomes zero
B.It remains constant
C.It increases
D.It decreases
Correct Answer: It increases
Explanation:
Unlike metals, semiconductors have a negative temperature coefficient of resistance. As temperature rises, more electron-hole pairs are generated, increasing the number of charge carriers and thus increasing conductivity.
Incorrect! Try again.
18The total conductivity () of a semiconductor is given by the expression: ( = elementary charge, = carrier densities, = carrier mobilities)
Conductivity of a semiconductor
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
Total conductivity is the sum of conductivity due to electrons () and conductivity due to holes (). Combining them gives the total conductivity .
Incorrect! Try again.
19Diffusion current in a semiconductor flows due to...
Diffusion and Life time
Easy
A.An externally applied electric field
B.An externally applied magnetic field
C.The non-uniform concentration of charge carriers
D.A uniform temperature
Correct Answer: The non-uniform concentration of charge carriers
Explanation:
Diffusion is the natural movement of particles from a region of higher concentration to a region of lower concentration. This movement of charge carriers without an external field constitutes the diffusion current.
Incorrect! Try again.
20The average time an excess minority carrier exists before it disappears is called...
Diffusion and Life time
Easy
A.Recombination time
B.Transit time
C.Diffusion time
D.Carrier lifetime
Correct Answer: Carrier lifetime
Explanation:
Carrier lifetime (or minority carrier lifetime) is the average time it takes for an excess minority carrier to recombine with a majority carrier and thus be eliminated.
Incorrect! Try again.
21As temperature increases from 0 K towards room temperature, how does the electrical conductivity of a pure semiconductor change compared to that of a metal?
Insulators, Semiconductors and Metals
Medium
A.Both increase at approximately the same rate.
B.Semiconductor conductivity decreases, while metal conductivity increases.
C.Semiconductor conductivity increases exponentially, while metal conductivity decreases linearly.
D.Both decrease due to increased atomic vibrations.
Correct Answer: Semiconductor conductivity increases exponentially, while metal conductivity decreases linearly.
Explanation:
In semiconductors, increasing temperature excites electrons from the valence to the conduction band, exponentially increasing the number of free charge carriers (). In metals, the number of carriers is constant, but higher temperature increases lattice vibrations (phonon scattering), which impedes electron flow and slightly decreases conductivity.
Incorrect! Try again.
22The intrinsic carrier concentration () of a semiconductor is given by the expression . If the energy bandgap () of semiconductor A is twice that of semiconductor B (), what is the approximate ratio of their intrinsic concentrations () at the same temperature?
Electrons and holes in an intrinsic semiconductor
Medium
A.
B.2
C.
D.0.5
Correct Answer:
Explanation:
We have . The ratio is . Since , the ratio becomes . This shows that a smaller bandgap leads to a much higher intrinsic carrier concentration.
Incorrect! Try again.
23When a small amount of Boron (a Group III element) is added to a pure Silicon (a Group IV element) crystal, what is the primary effect on the material's properties at room temperature?
Donor and Acceptor Impurities
Medium
A.The material remains intrinsic but its resistivity increases.
B.The material becomes p-type, and the Fermi level moves closer to the valence band.
C.The energy bandgap of Silicon decreases significantly.
D.The material becomes n-type, and the Fermi level moves closer to the conduction band.
Correct Answer: The material becomes p-type, and the Fermi level moves closer to the valence band.
Explanation:
Boron is a trivalent acceptor impurity. It accepts an electron from the valence band, creating a mobile hole. This makes the material p-type. The increase in hole concentration causes the Fermi level to shift downwards from the intrinsic level, moving closer to the valence band.
Incorrect! Try again.
24In a semiconductor sample, an electric field of 20 V/cm is applied. If the electrons drift with an average velocity of 500 m/s, what is the electron mobility ()?
Mobility and Conductivity
Medium
A.0.04 cm/V-s
B.5000 cm/V-s
C.2500 cm/V-s
D.25 cm/V-s
Correct Answer: 2500 cm/V-s
Explanation:
Mobility is defined as . First, ensure consistent units. The drift velocity is . The electric field is . Therefore, .
Incorrect! Try again.
25Calculate the conductivity of an n-type Germanium sample at 300 K, doped with donors/cm. Assume complete ionization and an electron mobility cm/V-s. The contribution of holes can be neglected.
Conductivity of a semiconductor
Medium
A.6.24 (Ω-cm)
B.39.0 (Ω-cm)
C.62.4 (Ω-cm)
D.0.39 (Ω-cm)
Correct Answer: 62.4 (Ω-cm)
Explanation:
For an n-type semiconductor where donor concentration is much greater than the intrinsic concentration , the electron concentration cm. The conductivity is .
Incorrect! Try again.
26A p-type semiconductor is heated from room temperature (300 K) to a very high temperature (e.g., 600 K) where it begins to behave intrinsically. How does the position of its Fermi level () change?
Fermi level in a semiconductor having impurities
Medium
A.It moves further down, closer to the valence band.
B.It moves into the conduction band.
C.Its position remains fixed relative to the valence band.
D.It moves upwards, towards the center of the bandgap.
Correct Answer: It moves upwards, towards the center of the bandgap.
Explanation:
At room temperature, the Fermi level in a p-type material is near the valence band. As temperature increases, thermally generated electron-hole pairs become significant, and their concentration () eventually exceeds the acceptor concentration. The material's behavior approaches that of an intrinsic semiconductor, causing the Fermi level to move upwards towards the intrinsic Fermi level, which is near the middle of the bandgap.
Incorrect! Try again.
27A silicon sample is doped with donors/cm and acceptors/cm. Assuming complete ionization and thermal equilibrium, what is the type and approximate majority carrier concentration? (Given cm)
Charge densities in a semiconductor
Medium
A.n-type, cm
B.p-type, cm
C.n-type, cm
D.p-type, cm
Correct Answer: n-type, cm
Explanation:
This is a compensated semiconductor. Since the donor concentration is greater than the acceptor concentration , the material is n-type. The effective donor concentration is cm. Since , the majority carrier (electron) concentration is cm.
Incorrect! Try again.
28The diffusion current density for holes () is given by the equation . What does the negative sign signify in this context?
Diffusion and Life time
Medium
A.Holes diffuse from a region of higher concentration to lower concentration.
B.The current flows in the opposite direction of the electric field.
C.The diffusion constant is always negative.
D.Holes have a positive charge.
Correct Answer: Holes diffuse from a region of higher concentration to lower concentration.
Explanation:
If the hole concentration decreases as position increases, the concentration gradient is negative. The negative sign in the equation cancels this out, resulting in a positive current density , indicating current flow in the +x direction. This confirms that positively charged holes diffuse 'down' the concentration gradient.
Incorrect! Try again.
29In a semiconductor at room temperature, what is the primary reason for the decrease in carrier mobility as the doping concentration is significantly increased?
Mobility and Conductivity
Medium
A.A reduction in the energy bandgap.
B.Increased scattering from ionized impurity atoms.
C.A decrease in the effective mass of the carriers.
D.Increased scattering from lattice vibrations (phonons).
Correct Answer: Increased scattering from ionized impurity atoms.
Explanation:
At room temperature in doped semiconductors, a dominant scattering mechanism that limits mobility is impurity scattering. Each ionized donor or acceptor atom acts as a charged center that deflects moving charge carriers. Increasing their concentration increases the frequency of these scattering events, thus reducing mobility.
Incorrect! Try again.
30A p-type silicon sample at 300 K is doped with acceptor atoms to a concentration of cm. If the intrinsic carrier concentration is cm, what is the approximate minority carrier (electron) concentration, ?
Charge densities in a semiconductor
Medium
A. cm
B. cm
C. cm
D. cm
Correct Answer: cm
Explanation:
In a p-type semiconductor, the majority carrier (hole) concentration is cm. Using the law of mass action, , we find the minority carrier (electron) concentration: cm.
Incorrect! Try again.
31An n-type silicon sample has a donor concentration of cm. If acceptor impurities are added to a concentration of cm, what will be the resulting material type and approximate majority carrier concentration?
Donor and Acceptor Impurities
Medium
A.p-type with cm
B.n-type with cm
C.Intrinsic, as the dopants cancel each other out.
D.p-type with cm
Correct Answer: p-type with cm
Explanation:
This process is called compensation. Since the acceptor concentration () is greater than the donor concentration (), the material will convert to p-type. The holes from the acceptors first recombine with the free electrons from the donors. The effective majority carrier (hole) concentration will be cm.
Incorrect! Try again.
32A p-type silicon wafer has a hole concentration of cm and a hole mobility of cm/V-s. Neglecting the electron contribution, what is the resistivity () of the wafer?
Conductivity of a semiconductor
Medium
A.28.8 Ω-cm
B.0.347 Ω-cm
C.0.0347 Ω-cm
D.2.88 Ω-cm
Correct Answer: 0.347 Ω-cm
Explanation:
The correct option follows directly from the given concept and definitions.
Incorrect! Try again.
33For a very heavily doped n-type semiconductor (a degenerate semiconductor), where is the Fermi level () located at low temperatures?
Fermi level in a semiconductor having impurities
Medium
A.Inside the conduction band.
B.Exactly at the donor energy level ().
C.Inside the valence band.
D.At the intrinsic Fermi level ().
Correct Answer: Inside the conduction band.
Explanation:
When an n-type semiconductor is doped so heavily that donor atoms are very close, their energy levels merge and overlap with the bottom of the conduction band. The large number of electrons fills the lowest available energy states in the conduction band, pushing the Fermi level up into the conduction band itself.
Incorrect! Try again.
34What is the diffusion constant () for holes in silicon at room temperature (300 K) if their mobility () is 480 cm/V-s? (The thermal voltage at 300 K is approximately 0.026 V).
Diffusion and Life time
Medium
A.26.0 cm/s
B.4.8 cm/s
C.12.5 cm/s
D.18.5 cm/s
Correct Answer: 12.5 cm/s
Explanation:
Einstein's relation states that the ratio of the diffusion constant to mobility is equal to the thermal voltage: . At 300 K, V. Therefore, the diffusion constant is .
Incorrect! Try again.
35Which statement accurately describes the energy band structure of an insulator at 0 K?
Insulators, Semiconductors and Metals
Medium
A.A small energy gap ( 1 eV) separates the filled valence band from the empty conduction band.
B.The valence band is only partially filled with electrons.
C.The valence band and conduction band overlap, allowing for free electron movement.
D.A large energy gap ( 5 eV) separates a completely filled valence band from an empty conduction band.
Correct Answer: A large energy gap ( 5 eV) separates a completely filled valence band from an empty conduction band.
Explanation:
Insulators have very low conductivity because their valence band is completely full of electrons and is separated from the empty conduction band by a large energy gap (typically > 5 eV). A very large amount of energy is required to excite an electron across this gap, so very few free carriers are available for conduction.
Incorrect! Try again.
36If an intrinsic semiconductor is illuminated with light, creating excess electron-hole pairs, how does the recombination rate change compared to its thermal equilibrium value?
Electrons and holes in an intrinsic semiconductor
Medium
A.The recombination rate remains exactly the same as the generation rate.
B.The recombination rate becomes zero.
C.The recombination rate decreases.
D.The recombination rate increases significantly.
Correct Answer: The recombination rate increases significantly.
Explanation:
The rate of recombination is proportional to the product of the electron and hole concentrations (). In thermal equilibrium, this rate is balanced by the thermal generation rate. When light creates excess carriers, both and increase above their equilibrium values (), causing a significant increase in the recombination rate as the system seeks to return to equilibrium.
Incorrect! Try again.
37A semiconductor has a conductivity of 2 (Ω-m). If an electric field of 50 V/m is applied across it, what is the resulting drift current density ()?
Mobility and Conductivity
Medium
A.0.04 A/m
B.250 A/m
C.100 A/m
D.25 A/m
Correct Answer: 100 A/m
Explanation:
The drift current density () is given by the point form of Ohm's law: . Given conductivity (Ω-m) and electric field V/m, the current density is A/m.
Incorrect! Try again.
38In an intrinsic semiconductor, conductivity increases with temperature primarily due to the increase in . In a moderately doped extrinsic semiconductor at temperatures below the intrinsic range, conductivity might decrease with temperature primarily due to the decrease in .
Conductivity of a semiconductor
Medium
A.carrier mobility (); carrier concentration ( or )
In intrinsic semiconductors, the carrier concentration () increases exponentially with temperature, which is a much stronger effect than the decrease in mobility. In extrinsic semiconductors in their operating range, the majority carrier concentration is relatively fixed by the doping level. However, increasing temperature enhances lattice scattering, which causes carrier mobility () to decrease, leading to a slight drop in conductivity.
Incorrect! Try again.
39The energy level introduced by an acceptor impurity (like Gallium in Germanium) is typically located where in the energy band diagram?
Donor and Acceptor Impurities
Medium
A.Within the valence band.
B.Just below the conduction band edge ().
C.Exactly in the middle of the bandgap.
D.Just above the valence band edge ().
Correct Answer: Just above the valence band edge ().
Explanation:
An acceptor impurity has one less valence electron than the host atom, creating a 'vacancy'. It can easily accept an electron from the nearby valence band, creating a mobile hole. This requires very little energy, so the acceptor energy level () is located very close to, and just above, the valence band edge ().
Incorrect! Try again.
40Consider an n-type semiconductor and a p-type semiconductor, both with the same doping concentration. How do their Fermi level positions relative to the intrinsic Fermi level () compare at room temperature?
Fermi level in a semiconductor having impurities
Medium
A.Both have their Fermi levels below the intrinsic level .
B.The n-type is above by roughly the same amount that the p-type is below .
C.The n-type is significantly farther from than the p-type .
D.Both have their Fermi levels at the intrinsic level .
Correct Answer: The n-type is above by roughly the same amount that the p-type is below .
Explanation:
The position of the Fermi level is a function of the doping concentration. For an n-type material, is above , and for a p-type material, it is below . The magnitude of the shift, , is determined by the ratio of the majority carrier concentration to the intrinsic concentration. For the same doping level (e.g., ), the shifts will be approximately symmetric around the intrinsic level.
Incorrect! Try again.
41A silicon sample at 300 K is doped with cm donors and cm acceptors. Under high illumination, the total hole concentration is measured to be cm. Assuming full ionization of dopants and that the intrinsic carrier concentration is negligible compared to the doping levels, what is the total electron concentration, ?
Charge densities in a semiconductor
Hard
A. cm
B. cm
C. cm
D. cm
Correct Answer: cm
Explanation:
The principle of charge neutrality must hold under any condition (equilibrium or illumination). The equation is . Assuming full ionization, and . We can solve for : . Substituting the given values: cm.
Incorrect! Try again.
42A semiconductor bar at thermal equilibrium has a non-uniform donor doping profile that results in a free electron concentration profile of . Assuming the hole concentration is negligible, what is the net space charge density, , within the bar?
Charge densities in a semiconductor
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
At thermal equilibrium, the total current is zero, so the drift current must exactly balance the diffusion current: . This implies a built-in electric field . For , . Using the Einstein relation (), the field is , which is constant. From Gauss's Law, . Since E is constant, , and therefore the net space charge density is zero. This implies that the donor concentration profile must be to maintain local charge neutrality.
Incorrect! Try again.
43A compensated silicon sample contains cm donors and cm acceptors. The donor energy level is meV. At a very low temperature (e.g., 20 K), where meV, which statement best describes the free electron concentration ?
Donor and Acceptor Impurities
Hard
A. is small and its behavior is governed by an effective donor density of .
B. cm.
C. is small and its behavior is governed by the total donor density .
D., the intrinsic carrier concentration.
Correct Answer: is small and its behavior is governed by an effective donor density of .
Explanation:
At very low temperatures, electrons seek the lowest available energy states. The acceptors will capture electrons from the donors, neutralizing themselves and leaving donors ionized. This leaves an effective number of neutral donors equal to cm. The free electron concentration is then determined by the small fraction of these remaining donors that are thermally ionized. Since , this fraction is very small (freeze-out regime), so .
Incorrect! Try again.
44In Gallium Arsenide (GaAs), Silicon (Si) is an amphoteric dopant. If Si is incorporated into a GaAs crystal grown under Gallium-rich (Ga-rich) conditions, what is the most likely outcome?
Donor and Acceptor Impurities
Hard
A.The crystal remains intrinsic, as Si acts as both donor and acceptor equally.
B.The crystal becomes n-type, with Si substituting for As.
C.The crystal becomes p-type, with Si substituting for As.
D.The crystal becomes n-type, with Si substituting for Ga.
Correct Answer: The crystal becomes p-type, with Si substituting for As.
Explanation:
Si is a Group IV element in a III-V semiconductor (Ga-As). If Si substitutes for Ga (Group III), it acts as a donor. If it substitutes for As (Group V), it acts as an acceptor. Growth under Ga-rich conditions implies a relative scarcity of As sites (or an abundance of As vacancies). Therefore, Si atoms are more likely to incorporate onto the As sublattice. When Si occupies an As site, it has one less valence electron than As, so it acts as an acceptor, making the crystal p-type.
Incorrect! Try again.
45If the effective mass of electrons () and holes () in a semiconductor were both hypothetically doubled, while the bandgap () and temperature () remained constant, how would the new intrinsic carrier concentration () relate to the original ()?
Electrons and holes in an intrinsic semiconductor
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The correct option follows directly from the given concept and definitions.
Incorrect! Try again.
46According to the Shockley-Read-Hall (SRH) model for recombination via a single-level trap, the net recombination rate is maximized when the trap energy level is located where?
Electrons and holes in an intrinsic semiconductor
Hard
A.Near the Fermi level of the doped semiconductor.
B.Near the intrinsic Fermi level, .
C.Exactly at the conduction band edge, .
D.Exactly at the valence band edge, .
Correct Answer: Near the intrinsic Fermi level, .
Explanation:
The SRH recombination rate is given by , where and . The rate is maximized when the denominator is minimized. The denominator is smallest when and are small, which occurs when is close to the midgap, i.e., close to the intrinsic Fermi level . Such midgap traps are the most effective recombination centers.
Incorrect! Try again.
47A silicon sample is doped with both donors () and acceptors () such that cm. This creates a perfectly compensated semiconductor. Assuming the temperature is high enough for full dopant ionization but low enough to be in the extrinsic range for a non-compensated sample, where will the Fermi level () be located?
Fermi level in a semiconductor having impurities
Hard
A.Very near the intrinsic Fermi level, .
B.Halfway between the donor level and the conduction band .
C.The position is undefined due to perfect compensation.
D.Halfway between the acceptor level and the valence band .
Correct Answer: Very near the intrinsic Fermi level, .
Explanation:
In thermal equilibrium, the charge neutrality condition is . With full ionization, and . Since the problem states , the neutrality equation simplifies to . This is the definition of an intrinsic semiconductor. Therefore, the Fermi level must be at the intrinsic level, , regardless of the doping concentration, as long as the compensation is perfect and dopants are ionized.
Incorrect! Try again.
48Consider a moderately doped n-type silicon sample. How does the Fermi level move as the temperature T varies from near absolute zero (0 K) to very high temperatures (e.g., 1000 K)?
Fermi level in a semiconductor having impurities
Hard
A.Starts at midgap, moves up towards the donor level , and stays there.
B.Starts halfway between the donor level and the conduction band , then moves down towards the intrinsic level as T increases.
C.Starts near the conduction band , and moves progressively further into the conduction band.
D.Starts halfway between and , moves up towards , then moves down towards midgap.
Correct Answer: Starts halfway between the donor level and the conduction band , then moves down towards the intrinsic level as T increases.
Explanation:
At T approaching 0 K, the Fermi level is located halfway between the donor energy level () and the conduction band edge (). As temperature increases into the freeze-out region, moves down. In the extrinsic (saturation) region, is below and continues to move down slowly. At very high temperatures, the semiconductor starts to behave intrinsically ( becomes comparable to ), and the Fermi level approaches the intrinsic level () near the center of the bandgap.
Incorrect! Try again.
49The total mobility in a semiconductor is limited by lattice scattering () and impurity scattering (). Given that and , at what temperature will the total mobility be maximum?
Mobility and Conductivity
Hard
A.At a very high temperature where lattice scattering dominates completely.
B.At the lowest possible temperature (T -> 0 K).
C.At the temperature where .
D.Mobility always decreases with temperature.
Correct Answer: At the temperature where .
Explanation:
According to Mathiessen's rule, the total scattering rate is the sum of individual scattering rates: . To find the maximum mobility, we need to find the minimum of . We take the derivative with respect to temperature T and set it to zero: . Since is a decreasing function of T and is an increasing function of T, the derivative of is positive and the derivative of is negative. The minimum of their sum (and thus maximum of ) occurs when the magnitudes of their rates of change are equal, which happens near the temperature where the mobilities themselves are equal, i.e., .
Incorrect! Try again.
50The Hall mobility () and drift mobility () are related by the Hall scattering factor . For electrons in n-type silicon, where the conduction band consists of multiple anisotropic valleys, what is the typical value of ?
Mobility and Conductivity
Hard
A.
B.
C. exactly
D. (typically ~1.18 for lattice scattering)
Correct Answer:
Explanation:
The Hall scattering factor depends on the band structure and the dominant scattering mechanism. For a simple spherical energy band, is slightly greater than 1. However, the conduction band of silicon has 6 equivalent ellipsoidal (anisotropic) valleys. The transport properties involve averaging over these valleys. This complex band structure and the nature of intervalley scattering lead to a Hall scattering factor that is less than 1 for electrons in silicon, typically around 0.7-0.9.
Incorrect! Try again.
51A silicon wafer has a measured conductivity of (-cm) at 300K. A Hall measurement indicates it is n-type. If it is a compensated semiconductor, and the total dopant concentration is cm, what are the approximate values of and ? (Use cm/V-s, is negligible, C).
Conductivity of a semiconductor
Hard
A. cm, cm
B. cm,
C. cm, cm
D. cm, cm
Correct Answer: cm, cm
Explanation:
For an n-type semiconductor, conductivity is . The net electron concentration is . From the given conductivity, we find cm. So, we have a system of two linear equations: (1) and (2) . Adding the two equations gives , so cm. Substituting this back into the second equation gives cm.
Incorrect! Try again.
52The conductivity of a doped semiconductor is measured as a function of temperature. In which temperature range is the conductivity most likely to decrease as temperature increases?
Conductivity of a semiconductor
Hard
A.The freeze-out region
B.The intrinsic region
C.Conductivity of a semiconductor never decreases with increasing temperature
D.The extrinsic (saturation) region
Correct Answer: The extrinsic (saturation) region
Explanation:
Conductivity is given by . In the extrinsic (or saturation) region of a doped semiconductor, the majority carrier concentration (e.g., for n-type) is nearly constant, as all dopants are ionized. However, in this temperature range, carrier mobility () is limited by lattice scattering (phonons), which increases with temperature. This causes mobility to decrease with temperature, typically as . Since is constant and decreases, the conductivity decreases with increasing temperature.
Incorrect! Try again.
53The classical Einstein relation is a cornerstone of semiconductor physics. How must this relation be modified for electrons in a heavily doped n-type (degenerate) semiconductor where the Fermi level is located within the conduction band?
Diffusion and Life time
Hard
A.The ratio becomes larger than the classical value and depends on the Fermi energy.
B.The classical relation remains perfectly valid even under degenerate conditions.
C.The ratio becomes smaller than the classical value.
D.The diffusion coefficient D becomes zero, so the ratio is zero.
Correct Answer: The ratio becomes larger than the classical value and depends on the Fermi energy.
Explanation:
The Einstein relation is derived assuming a non-degenerate semiconductor obeying Maxwell-Boltzmann statistics. In a degenerate semiconductor, Fermi-Dirac statistics must be used. The generalized Einstein relation shows that the ratio is proportional to how rapidly the carrier concentration changes with the Fermi level. For a degenerate n-type material, this leads to a value greater than . A common approximation is , where is the energy difference between the Fermi level and the conduction band edge, which is significantly larger than in the degenerate case.
Incorrect! Try again.
54In a Haynes-Shockley experiment, a pulse of minority carriers is observed to drift and spread. If the experiment is repeated at a higher temperature, how will the measured drift mobility () and diffusion coefficient () most likely change?
Diffusion and Life time
Hard
A.From the decay in the total area under the pulse as the drift distance is varied.
B.It cannot be determined from this experiment.
C.From the drift time only.
D.From the pulse width only.
Correct Answer: From the decay in the total area under the pulse as the drift distance is varied.
Explanation:
The Haynes-Shockley experiment measures drift mobility () from the pulse arrival time () and diffusion coefficient () from the pulse spreading (width ). The minority carrier lifetime () is determined by observing how many carriers are lost to recombination as they drift. The total number of carriers in the pulse is proportional to the area under the measured voltage curve. By measuring this area for two different drift distances ( and ) and corresponding drift times ( and ), the lifetime can be calculated from the exponential decay relationship: .
Incorrect! Try again.
55A thin filament of n-type silicon of length has a bulk minority carrier (hole) lifetime of . Recombination also occurs at the two end surfaces, characterized by a surface recombination velocity . What is the effective lifetime, , of holes in this filament under the condition of very high surface recombination velocity ()?
Diffusion and Life time
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The total recombination rate is the sum of the bulk and surface recombination rates: . For a 1D filament of length L, the surface lifetime depends on the geometry and the surface recombination velocity S. In the limit of infinite surface recombination (), the excess carrier concentration is forced to zero at the surfaces (x=0, x=L). Solving the continuity equation with these boundary conditions yields a decay dominated by the lowest-order spatial mode, which has an effective lifetime related to diffusion. This diffusion-limited lifetime is given by . Since is infinite, this surface term will dominate the bulk lifetime, making .
Incorrect! Try again.
56The optical absorption coefficient () near the band edge for a direct bandgap semiconductor follows the relation , while for an indirect bandgap semiconductor, it follows , where is a phonon energy. Why is the functional form so different?
Insulators, Semiconductors and Metals
Hard
A.An indirect transition requires a third particle (a phonon) to conserve momentum, making it a less probable, second-order process.
B.Indirect transitions are forbidden by quantum mechanical selection rules, while direct transitions are always allowed.
C.Direct bandgap materials have a much larger bandgap, which changes the physics of absorption.
D.The effective mass of carriers in indirect semiconductors is significantly higher, restricting absorption.
Correct Answer: An indirect transition requires a third particle (a phonon) to conserve momentum, making it a less probable, second-order process.
Explanation:
In a direct bandgap material, the conduction band minimum and valence band maximum occur at the same crystal momentum (k-vector). A photon () can directly excite an electron, conserving both energy and momentum (since the photon's momentum is negligible). This is a high-probability, first-order process, leading to a sharp onset of absorption proportional to the density of states, giving the dependence. In an indirect material, the band extrema are at different k-vectors. To conserve momentum, the transition must also involve the absorption or emission of a lattice phonon, which has the required momentum. This is a three-body interaction (electron, photon, phonon), which is a much less probable, second-order quantum mechanical process, resulting in a weaker and more gradual absorption onset described by the squared dependence.
Incorrect! Try again.
57According to simple band theory, a material with an odd number of electrons per unit cell should be a metal because it will have a partially filled energy band. However, some materials like NiO are insulators. What is the primary reason for this discrepancy?
Insulators, Semiconductors and Metals
Hard
A.Strong electron-electron correlation effects (Coulomb repulsion) are not considered in simple band theory.
B.The presence of a large number of crystal defects creates trap states that prevent conduction.
C.The bandgap in these materials is simply too large for conduction.
D.These materials are always amorphous, so band theory does not apply.
Correct Answer: Strong electron-electron correlation effects (Coulomb repulsion) are not considered in simple band theory.
Explanation:
Simple band theory is a one-electron approximation that ignores the interactions between electrons. In some materials, particularly those with transition metal or rare earth elements (like NiO), the electrons in the d or f orbitals are highly localized. The strong on-site Coulomb repulsion energy () required to put a second electron on the same atom is much larger than the band width (). This large energy cost effectively splits the partially filled band into two separate bands (a lower and upper Hubbard band), creating a bandgap and making the material an insulator. These materials are known as Mott insulators.
Incorrect! Try again.
58An n-type silicon sample is doped so heavily that it becomes degenerate, with the Fermi level located 0.1 eV above the conduction band edge at 300K ( eV). How does the electron concentration in this sample change as the temperature is increased slightly from 300K?
Fermi level in a semiconductor having impurities
Hard
A. remains almost constant.
B. doubles for every 10K increase.
C. decreases significantly.
D. increases exponentially.
Correct Answer: remains almost constant.
Explanation:
In a degenerate semiconductor, the Fermi level is inside the conduction (or valence) band. This means the electron concentration is extremely high and is primarily determined by the doping density, not thermal excitation. The states well below the Fermi level are almost entirely filled. A slight increase in temperature will only cause a minor 'smearing' of the Fermi-Dirac distribution around , promoting a very small number of electrons to even higher energy states. The total number of electrons in the band remains essentially unchanged, much like the number of electrons in a metal. Significant changes would only occur at very high temperatures where thermal energy becomes comparable to the Fermi energy.
Incorrect! Try again.
59In an ideal one-sided abrupt p-n junction at thermal equilibrium, how does the magnitude of the electric field, , vary with position within the depletion region on the lightly doped n-side? (Let the metallurgical junction be at and the depletion edge be at ).
Charge densities in a semiconductor
Hard
A.It decreases linearly from a maximum at to zero at .
B.It is constant throughout the n-side depletion region.
C.It follows a parabolic decrease from a maximum at .
D.It increases linearly from zero at to a maximum at .
Correct Answer: It decreases linearly from a maximum at to zero at .
Explanation:
Within the depletion region on the n-side, the space charge density is constant and positive, given by , where is the donor concentration. The electric field can be found by integrating the charge density using Gauss's Law: . Integrating from a point to the edge of the depletion region (where ), we get . The magnitude . This is a linear function of , which is maximum at the junction () and decreases to zero at the depletion edge ().
Incorrect! Try again.
60A piece of intrinsic silicon at 300 K has a conductivity of (-cm). An identical piece is doped with cm of Boron atoms (acceptors). What is the ratio of the conductivity of the doped sample to the intrinsic sample, ? (Use , cm/V-s, C).
Conductivity of a semiconductor
Hard
A.Approximately
B.Approximately
C.Approximately $1.00$
D.Approximately
Correct Answer: Approximately
Explanation:
The correct option follows directly from the given concept and definitions.