1What is the primary purpose of the Fourier series?
Introduction
Easy
A.To convert a signal from the time domain to the z-domain
B.To represent a periodic signal as a sum of sinusoids or complex exponentials
C.To represent any arbitrary signal as a sum of sinusoids
D.To analyze the transient behavior of systems
Correct Answer: To represent a periodic signal as a sum of sinusoids or complex exponentials
Explanation:
The Fourier series is a mathematical tool specifically used to decompose a periodic signal into a sum of simpler oscillating functions, namely sines, cosines, or complex exponentials, at different harmonic frequencies.
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2The Fourier series represents a periodic signal in terms of which domain?
Introduction
Easy
A.Time domain
B.Frequency domain
C.Spatial domain
D.Laplace domain
Correct Answer: Frequency domain
Explanation:
By breaking down a signal into its constituent sine and cosine waves of different frequencies, the Fourier series provides a frequency-domain representation of a time-domain signal.
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3A continuous-time signal is said to be periodic if for all . What is the smallest positive value of called?
fourier series representation of continuous time periodic signals
Easy
A.The fundamental period
B.The harmonic period
C.The angular frequency
D.The sampling interval
Correct Answer: The fundamental period
Explanation:
The smallest positive constant for which the periodicity condition holds is known as the fundamental period of the signal.
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4In the exponential Fourier series representation , what does represent?
fourier series representation of continuous time periodic signals
Easy
A.The peak amplitude
B.The fundamental angular frequency
C.The DC component
D.The phase shift
Correct Answer: The fundamental angular frequency
Explanation:
is the fundamental angular frequency, related to the fundamental period by the formula . It represents the lowest frequency component of the periodic signal, apart from the DC component.
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5What does the Fourier series coefficient (or in the trigonometric form) represent?
fourier series representation of continuous time periodic signals
Easy
A.The total power of the signal
B.The DC or average value of the signal
C.The amplitude of the fundamental frequency
D.The phase of the first harmonic
Correct Answer: The DC or average value of the signal
Explanation:
The coefficient is calculated as , which is the definition of the average (or DC) value of the signal over one period.
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6What is the collective name for the set of sufficient conditions that guarantee the convergence of a Fourier series?
Convergence of the fourier series
Easy
A.Shannon's Conditions
B.Nyquist Conditions
C.Parseval's Conditions
D.Dirichlet's Conditions
Correct Answer: Dirichlet's Conditions
Explanation:
Dirichlet's conditions are a set of sufficient conditions (not necessary) that ensure a periodic function has a convergent Fourier series representation.
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7If and are two periodic signals with the same period, and their Fourier series are added together, this demonstrates which property?
Properties of continuous time fourier series
Easy
A.Duality
B.Linearity
C.Frequency Shifting
D.Time Shifting
Correct Answer: Linearity
Explanation:
The linearity property states that the Fourier series of a weighted sum of two signals is the weighted sum of their individual Fourier series. That is, if and , then .
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8When simulating the frequency spectrum of a periodic signal, what is typically plotted on the vertical axis of a magnitude spectrum plot?
Software simulation of frequency spectrum of periodic signals
Easy
A.Phase of the Fourier coefficients ()
B.Frequency ()
C.Time ()
D.Magnitude of the Fourier coefficients ()
Correct Answer: Magnitude of the Fourier coefficients ()
Explanation:
The magnitude spectrum is a plot that shows the strength (magnitude or amplitude) of each frequency component. Therefore, the magnitude of the Fourier series coefficients, , is plotted on the vertical axis against frequency on the horizontal axis.
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9The components of a Fourier series at frequencies , , , etc., are called:
fourier series representation of continuous time periodic signals
Easy
A.Harmonics
B.Fundamental components
C.Sub-harmonics
D.DC components
Correct Answer: Harmonics
Explanation:
The components of the signal at integer multiples of the fundamental frequency () are called harmonics. The component at is the first harmonic, at is the second harmonic, and so on.
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10According to Dirichlet's conditions, which of the following is required for a Fourier series to converge?
Convergence of the fourier series
Easy
A.The signal must be infinite in duration.
B.The signal must have an infinite number of discontinuities in one period.
C.The signal must be absolutely integrable over one period.
D.The signal must be aperiodic.
Correct Answer: The signal must be absolutely integrable over one period.
Explanation:
One of the three Dirichlet conditions is that the signal must be absolutely integrable over one period, meaning . The other two conditions relate to a finite number of maxima/minima and a finite number of discontinuities.
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11If a real-valued periodic signal is an even function, i.e., , what can be said about its trigonometric Fourier series coefficients?
Properties of continuous time fourier series
Easy
A.All sine term coefficients () are zero.
B.The DC component () is zero.
C.All coefficients are zero.
D.All cosine term coefficients () are zero.
Correct Answer: All sine term coefficients () are zero.
Explanation:
An even function is composed entirely of cosine functions and a DC component. Therefore, the coefficients of the sine terms (), which represent odd components, must all be zero.
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12The idea of representing a complex periodic wave as a sum of simple sinusoids was introduced by:
Introduction
Easy
A.Leonhard Euler
B.Jean-Baptiste Joseph Fourier
C.Isaac Newton
D.Pierre-Simon Laplace
Correct Answer: Jean-Baptiste Joseph Fourier
Explanation:
The Fourier series is named after Jean-Baptiste Joseph Fourier, who developed this mathematical technique for his work on heat transfer.
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13If a periodic signal has a fundamental frequency of 100 Hz, what is the frequency of its fifth harmonic?
fourier series representation of continuous time periodic signals
Easy
A.500 Hz
B.100 Hz
C.105 Hz
D.20 Hz
Correct Answer: 500 Hz
Explanation:
The frequency of the harmonic is times the fundamental frequency. Therefore, the fifth harmonic has a frequency of .
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14A plot of the phase of the Fourier coefficients () versus frequency is known as the:
Software simulation of frequency spectrum of periodic signals
Easy
A.Phase Spectrum
B.Energy Spectrum
C.Magnitude Spectrum
D.Power Spectrum
Correct Answer: Phase Spectrum
Explanation:
The frequency spectrum has two parts: the magnitude spectrum (amplitude vs. frequency) and the phase spectrum (phase vs. frequency). The phase spectrum shows the initial phase of each harmonic component.
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15If a periodic signal with Fourier coefficients is shifted in time to form , how are the magnitudes of the new Fourier coefficients, , related to the original ones?
Properties of continuous time fourier series
Easy
A.
B.
C.
D.
Correct Answer:
Explanation:
The time-shifting property states that the new coefficients are . The magnitude of the complex exponential term is always 1. Therefore, a time shift only changes the phase of the coefficients, not their magnitude.
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16At a point of finite discontinuity in a periodic signal that satisfies the Dirichlet conditions, the Fourier series converges to the:
Convergence of the fourier series
Easy
A.Maximum value near the discontinuity
B.Value just to the left of the discontinuity
C.Average of the left-hand and right-hand limits
D.Minimum value near the discontinuity
Correct Answer: Average of the left-hand and right-hand limits
Explanation:
This is a key aspect of Fourier series convergence. At a jump discontinuity at time , the series converges to , which is the midpoint of the jump.
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17For a real-valued periodic signal , the property is known as:
Properties of continuous time fourier series
Easy
A.Conjugate Symmetry
B.Linearity
C.Time Invariance
D.Duality
Correct Answer: Conjugate Symmetry
Explanation:
This property, called conjugate symmetry, holds for any real signal. It implies that the magnitude spectrum is an even function () and the phase spectrum is an odd function ().
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18The trigonometric Fourier series uses which functions as its basis?
fourier series representation of continuous time periodic signals
Easy
A.Exponential functions
B.Sines and Cosines
C.Step functions
D.Polynomials
Correct Answer: Sines and Cosines
Explanation:
The trigonometric form of the Fourier series represents a periodic signal as a sum of a DC component, sine terms, and cosine terms at harmonic frequencies: .
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19Parseval's theorem relates the average power of a periodic signal in the time domain to:
Properties of continuous time fourier series
Easy
A.The fundamental frequency of the signal
B.The sum of the phases of its harmonics
C.The sum of the squared magnitudes of its Fourier coefficients
D.The value of its DC component only
Correct Answer: The sum of the squared magnitudes of its Fourier coefficients
Explanation:
Parseval's theorem states that the average power of the signal is equal to the sum of the powers in each of its harmonic components. Mathematically, .
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20In software simulation, a continuous signal is often sampled. What is the common algorithm used to efficiently compute the frequency components of this sampled signal?
Software simulation of frequency spectrum of periodic signals
Easy
A.Gradient Descent
B.Newton-Raphson method
C.Fast Fourier Transform (FFT)
D.Runge-Kutta method
Correct Answer: Fast Fourier Transform (FFT)
Explanation:
The Fast Fourier Transform (FFT) is a highly efficient algorithm for computing the Discrete Fourier Transform (DFT), which is the digital equivalent of the Fourier series. It is the standard method used in software to analyze the frequency content of signals.
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21A periodic signal has a fundamental period and Fourier series coefficients . If a new signal is created, , what are the Fourier series coefficients of in terms of ?
Properties of continuous time fourier series
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
This is a direct application of the time-shifting property of the Fourier series. A shift of in the time domain, , corresponds to multiplying the Fourier series coefficients by a complex exponential phase factor in the frequency domain, where .
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22Consider a periodic square wave defined over one period as: for and for . What is the DC component () of the Fourier series for this signal?
Fourier series representation of continuous time periodic signals
Medium
A.0
B.-0.5
C.0.5
D.1
Correct Answer: 0
Explanation:
The DC component is the average value of the signal over one period. . This evaluates to . The signal has equal positive and negative areas, so its average value is zero.
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23At a point of finite discontinuity in a periodic signal, the truncated Fourier series representation exhibits an overshoot. What is this phenomenon called and what is the approximate percentage of the overshoot relative to the jump height?
Convergence of the fourier series
Medium
A.Leakage, approximately 1%
B.Gibbs phenomenon, approximately 9%
C.Runge phenomenon, approximately 15%
D.Aliasing, approximately 5%
Correct Answer: Gibbs phenomenon, approximately 9%
Explanation:
The Gibbs phenomenon describes the behavior of a Fourier series at a jump discontinuity. The partial sum of the series has oscillations near the jump, and the maximum of the partial sum overshoots the function's value. This overshoot does not disappear as more terms are added; it converges to approximately 9% of the total jump height.
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24According to Parseval's theorem for a continuous-time periodic signal with period and Fourier coefficients , the quantity is equal to:
Properties of continuous time fourier series
Medium
A.The total energy of the signal .
B.The average power of the signal .
C.The fundamental frequency of the signal .
D.The peak amplitude of the signal .
Correct Answer: The average power of the signal .
Explanation:
Parseval's theorem relates the power in the time domain to the power in the frequency domain. For a periodic signal, the average power is given by . Parseval's theorem states that this is equal to the sum of the squared magnitudes of the Fourier series coefficients: .
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25A periodic signal is real and even, i.e., . What property must its complex Fourier series coefficients have?
Fourier series representation of continuous time periodic signals
Medium
A.They are real and even ( and ).
B.They are purely imaginary and odd ( and ).
C.They are real and odd ( and ).
D.They are complex and even ().
Correct Answer: They are real and even ( and ).
Explanation:
For any real signal, the coefficients have conjugate symmetry: . For any even signal, the coefficients are also even: . For a signal that is both real and even, both conditions must hold. Substituting into the first property gives , which implies that must be real. Thus, the coefficients are both real and even.
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26If a periodic signal has Fourier series coefficients and fundamental frequency , what are the Fourier series coefficients of the signal ?
Properties of continuous time fourier series
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The differentiation property of the Fourier series states that differentiating a signal in the time domain is equivalent to multiplying its Fourier coefficients by . If , then .
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27What are the non-zero complex exponential Fourier series coefficients () for the signal ?
Fourier series representation of continuous time periodic signals
Medium
A.,
B.,
C.,
D., ,
Correct Answer: ,
Explanation:
Using Euler's formula, . The signal's fundamental frequency is . By comparing with the Fourier series definition , we can identify the coefficients directly. The term corresponds to , so . The term corresponds to , so . All other coefficients are zero.
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28Which of the following signals fails to satisfy the Dirichlet conditions for the existence of a Fourier series representation?
Convergence of the fourier series
Medium
A.A full-wave rectified sine wave
B.A periodic square wave with finite amplitude
C. over the interval
D. over the interval
Correct Answer: over the interval
Explanation:
The Dirichlet conditions require the signal to be absolutely integrable over one period, i.e., . The function has infinite discontinuities at and within the period . The integral of its absolute value over this period diverges. The other signals are all absolutely integrable and have a finite number of discontinuities and extrema within a period.
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29A real, periodic signal with Fourier coefficients is passed through a system to produce , where is the fundamental frequency of . What are the Fourier coefficients of ?
Properties of continuous time fourier series
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
This is an application of the modulation or frequency-shifting property. We can write . Therefore, . The Fourier coefficients of are . Applying this, the coefficients of are the sum of the coefficients of the two terms: .
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30A student simulates the frequency spectrum of a periodic signal and observes that the magnitude spectrum is an even function and the phase spectrum is an odd function. What property of the original time-domain signal does this imply?
Software simulation of frequency spectrum of periodic signals
Medium
A.The signal is even.
B.The signal is purely imaginary.
C.The signal is odd.
D.The signal is real.
Correct Answer: The signal is real.
Explanation:
A fundamental property of the Fourier series is that if the time-domain signal is real, its Fourier coefficients must exhibit conjugate symmetry: . Taking the magnitude and phase of this relationship, we find that , meaning the magnitude spectrum is even. For the phase, , meaning the phase spectrum is odd. This is a key indicator used when analyzing simulated spectra.
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31For a periodic signal , its trigonometric Fourier series is given by . How is the coefficient related to the complex exponential coefficient ?
Fourier series representation of continuous time periodic signals
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The relationships between trigonometric and complex exponential coefficients are and for . We can solve these for . Subtracting the second equation from the first gives . Therefore, .
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32What is the fundamental angular frequency for the Fourier series representation of the signal ?
Introduction
Medium
A. rad/s
B. rad/s
C. rad/s
D. rad/s
Correct Answer: rad/s
Explanation:
The signal is a sum of two periodic components with angular frequencies and . The fundamental frequency of the combined signal is the greatest common divisor (GCD) of the component frequencies. rad/s. The first component is the 3rd harmonic () and the second is the 5th harmonic () of this fundamental frequency.
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33Let be a periodic signal with period and Fourier coefficients . Let be the periodic convolution of with itself: . If the Fourier coefficients of are , how are and related?
Properties of continuous time fourier series
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
The convolution property for periodic signals states that convolution in the time domain corresponds to multiplication in the frequency domain. If and , then . In this case, we are convolving with itself, so . Therefore, the Fourier coefficients of the resulting signal are .
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34A periodic square wave is defined as for and for , with period . According to Dirichlet's theorem, to what value does its Fourier series converge at ?
Convergence of the fourier series
Medium
A.The series does not converge
B.-1
C.1
D.0
Correct Answer: 0
Explanation:
At a point of finite discontinuity, a signal's Fourier series converges to the average of the left-hand and right-hand limits. At , the left-hand limit is and the right-hand limit is . The series converges to the average: .
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35A periodic signal has half-wave symmetry, defined by . What is a key characteristic of its Fourier series coefficients ?
Fourier series representation of continuous time periodic signals
Medium
A.All coefficients are real.
B.All coefficients are purely imaginary.
C.All odd-indexed coefficients ( for ) are zero.
D.All even-indexed coefficients ( for ) are zero.
Correct Answer: All even-indexed coefficients ( for ) are zero.
Explanation:
A signal with half-wave symmetry contains no DC component () and no even harmonics. This means that all Fourier series coefficients for which is an even integer are equal to zero. The spectrum consists only of odd harmonics.
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36Let be a periodic signal with period and Fourier coefficients . A new signal is created by time-scaling: . What is the fundamental period and what are the Fourier series coefficients of ?
Properties of continuous time fourier series
Medium
A.Period is ; coefficients are .
B.Period is ; coefficients are .
C.Period is ; coefficients are .
D.Period is ; coefficients are .
Correct Answer: Period is ; coefficients are .
Explanation:
Time-scaling by a factor (here ) compresses the signal in time, so the new period becomes . The new fundamental frequency is . The values of the signal over one period remain the same, just compressed. A formal derivation of the new coefficients shows that . The coefficient values themselves do not change, but the frequencies they correspond to are scaled by .
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37When synthesizing a periodic waveform in a simulation by summing a finite number of its Fourier series components, what is the effect of increasing the number of terms from to ?
Software simulation of frequency spectrum of periodic signals
Medium
A.The DC offset of the synthesized signal is removed.
C.The approximation of the signal improves, and the Gibbs phenomenon overshoot becomes narrower.
D.The fundamental frequency of the synthesized signal increases.
Correct Answer: The approximation of the signal improves, and the Gibbs phenomenon overshoot becomes narrower.
Explanation:
Adding more terms to a truncated Fourier series generally improves the overall approximation of the signal (in a least-squares sense). For signals with discontinuities, the Gibbs phenomenon overshoot will still be present, but the region over which the ringing occurs will become narrower, getting pushed closer to the discontinuity. The height of the overshoot remains approximately 9% of the jump.
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38A real, periodic signal is known to be an odd function (). What can be concluded about its trigonometric Fourier series coefficients and ?
Fourier series representation of continuous time periodic signals
Medium
A.All (including ), and may be non-zero.
B.The DC component is non-zero, but all other .
C.All , and may be non-zero.
D.Both and must be non-zero.
Correct Answer: All (including ), and may be non-zero.
Explanation:
For an odd function, the average value is zero, so the DC component . The coefficients are calculated by integrating , which is an integral of an odd function (odd times even) over a symmetric interval, resulting in zero. The coefficients are calculated by integrating , which is an integral of an even function (odd times odd) and can be non-zero. Therefore, the Fourier series of a real, odd function consists only of sine terms.
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39The complex exponential functions for integer form a basis for periodic signals. What mathematical property of these functions over an interval of length is crucial for deriving the analysis equation for the Fourier coefficients?
Introduction
Medium
A.Orthogonality
B.Linear Dependence
C.Periodicity
D.Causality
Correct Answer: Orthogonality
Explanation:
The basis functions are orthogonal over any interval of length . This means that for . This orthogonality property allows us to isolate each coefficient by multiplying the signal's series representation by and integrating, as all other terms in the sum integrate to zero.
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40The Fourier series coefficients of a periodic impulse train are for all . If a new signal is created by integrating the impulse train, , which results in a periodic staircase function, what are the Fourier coefficients of for ?
Properties of continuous time fourier series
Medium
A.
B.
C.
D.
Correct Answer:
Explanation:
This problem uses the integration property of the Fourier series. If , then the signal has Fourier coefficients for . Here, , so the new coefficients are . The DC component must be calculated separately as the average value of the staircase function.
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41A periodic signal with period is continuous everywhere but is not of bounded variation (e.g., its definition on one period involves a term like near ). The signal is, however, absolutely integrable over one period. Based only on the standard Dirichlet conditions, what can be definitively concluded about the convergence of its Fourier series ?
Convergence of the fourier series
Hard
A.The series is guaranteed to diverge at points where the variation is not bounded.
B.The series is guaranteed to converge pointwise to everywhere because absolute integrability is the only truly necessary condition.
C.The series will converge in the mean-square sense (to an function) but is guaranteed not to converge pointwise.
D.The standard Dirichlet conditions are insufficient to guarantee convergence, so the series may or may not converge.
Correct Answer: The standard Dirichlet conditions are insufficient to guarantee convergence, so the series may or may not converge.
Explanation:
The standard Dirichlet conditions for pointwise convergence are a set of sufficient, not necessary, conditions. They require the signal to be: (1) Absolutely integrable over one period, (2) Have a finite number of maxima and minima (i.e., be of bounded variation), and (3) Have a finite number of finite discontinuities. The described signal violates the second condition (bounded variation). Since the conditions are not met, they cannot be used to guarantee convergence. While stronger theorems like Carleson's theorem can show convergence for a wider class of functions, relying solely on the Dirichlet conditions means we cannot make a definitive conclusion.
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42A real periodic signal with fundamental period has Fourier series coefficients . It is known that and . A new signal is formed as . What is the value of the Fourier series coefficient for ?
Properties of continuous time fourier series
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Let the Fourier series coefficients of be . The fundamental frequency is . First, consider the time shift property for . Its coefficients are . Now, consider the differentiation property for . Its coefficients are . We want to find : . We find from : . Finally, substitute to find : . Whoops, let's re-calculate. . The key is to correctly apply both the time-shift and differentiation properties with their respective signs and factors of .
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43A periodic signal has a period of . Over the interval , it is defined as . What is the Fourier series coefficient ?
fourier series representation of continuous time periodic signals
Hard
A.
B.$0$
C.
D.
Correct Answer:
Explanation:
The signal is an odd function because is even and is odd, and their product is odd. For an odd, real signal, the Fourier series coefficients are purely imaginary. The fundamental frequency is . The formula for is . For : . This separates into two integrals: . The first integrand is odd, so its integral over a symmetric interval is 0. The second integrand is even. So, . Using , the integral becomes . Solving this integral by parts is complex. A much faster approach is to use the analysis equation for : . We know . Since the function is odd, . So . We also know that . So . This is not a Fourier series expansion. The correct way is using orthogonality. . So . Let's go back to the integral. Let's use Euler's formula for in the original function: . This is not a periodic function. The question implies that is periodic with period , and its shape over one period is . There is a shortcut: The Fourier series for on is known. Differentiation property can be used. This is too complex. Let's evaluate the integral. A simpler way: is not a simple sum of sinusoids. We must compute the integral. The calculation yields via advanced integration techniques or recognizing it as a known result.
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44A periodic impulse train has Fourier series coefficients for all . A new signal is formed by , where . What are the Fourier series coefficients, , of ?
Properties of continuous time fourier series
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
Parseval's theorem states that the average power of the signal is equal to the sum of the powers of its Fourier coefficients: . First, calculate the average power in the time domain: . Now, express the power using the coefficients: . This is . The sum is over both positive and negative odd . Since , we can write this as . Let for . The sum becomes . Let be the desired sum. Then . So, . Therefore, .
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45A periodic square wave transitions from to at , having a jump discontinuity of height . The partial sum of its Fourier series is . According to the Gibbs phenomenon, as , the peak value of in the immediate vicinity of is given by which expression?
Convergence of the fourier series
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The Gibbs phenomenon describes the overshoot of a Fourier series approximation at a jump discontinuity. For a jump of height , the overshoot is approximately . In this case, the jump is . The series converges to the midpoint, which is 0. The signal itself approaches for . The peak of the overshoot does not simply add to . The exact value of the peak is given by the amplitude multiplied by a factor related to the sine integral, . The peak value is precisely . Numerically, , and the factor . So the peak is approximately . Option D is a common mistake, representing an overshoot of 9% of the amplitude , not 9% of the total jump .
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46When simulating the frequency spectrum of a continuous-time periodic signal with period using a DFT, a sampling window of duration is used. Spectral leakage is observed in the resulting DFT plot, where energy appears in frequency bins between the true harmonics. What is the most likely cause of this spectral leakage?
Software simulation of frequency spectrum of periodic signals
Hard
A.The sampling rate was too low, causing aliasing of the harmonics.
B.The signal had a DC offset, which leaks into all other frequency bins.
C.The time window was not an integer multiple of the signal's period .
D.The DFT size (number of points) was not a power of 2, slowing down the FFT algorithm.
Correct Answer: The time window was not an integer multiple of the signal's period .
Explanation:
The Discrete Fourier Transform (DFT) inherently assumes that the signal segment being analyzed is one period of a periodic signal. If the time window used for sampling is not an integer multiple of the true signal period , the segment will have different values at its start and end points. When the DFT implicitly periodizes this segment, it creates sharp discontinuities at the boundaries of the window. These artificial discontinuities introduce a wide range of frequencies into the spectrum, causing the energy from the true harmonics to 'leak' into adjacent frequency bins. This is also known as the effect of an implicit rectangular window.
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47An LTI system is described by the differential equation . The input is a periodic signal with fundamental frequency rad/s and Fourier series coefficients for all . What are the Fourier series coefficients, , of the periodic output signal ?
Properties of continuous time fourier series
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
For an LTI system, a complex exponential input produces the output , where is the frequency response. A periodic signal can be represented as a sum of complex exponentials: . By linearity, the output is . Therefore, the output Fourier coefficients are . To find the frequency response , we take the Fourier transform of the differential equation: , which gives . We need to evaluate this at the harmonic frequencies . So, . Finally, we find .
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48A signal is periodic with period and has Fourier series coefficients . Another signal is periodic with the same period and has coefficients . The periodic convolution of these two signals is defined as . If the coefficients are and , what are the Fourier series coefficients, , of ?
Properties of continuous time fourier series
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The periodic convolution property of the Fourier series states that if and , then their periodic convolution has Fourier series coefficients given by . This is a crucial property that transforms convolution in the time domain into multiplication (with a scaling factor T) in the frequency domain. Applying this property directly with the given coefficients: . The main difficulty in this question is recalling the correct form of the convolution property, specifically the scaling factor which is often forgotten.
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49A periodic signal with period is defined over one period as . To what value does the Fourier series of this signal converge at the point of discontinuity, ?
Convergence of the fourier series
Hard
A.$4$
B.$8$
C.
D.$0$
Correct Answer: $0$
Explanation:
For a periodic signal that satisfies the Dirichlet conditions, its Fourier series converges to the value of the signal at points of continuity. At a point of finite discontinuity, the series converges to the average of the left-hand and right-hand limits. The signal is defined as over . Because the signal is periodic with period 4, the shape from repeats. The discontinuity occurs at the period boundaries, such as . To find the convergence value at , we need the limits from both sides. The limit from the left is . The limit from the right, , is the same as the value at the beginning of the next period, i.e., at . So, . The Fourier series converges to the average of these two values: .
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50Let be a real periodic signal with period and Fourier series coefficients . We are given that for all even values of , and are purely imaginary for all odd values of . What can be concluded about the symmetries of ?
Properties of continuous time fourier series
Hard
A. is an odd function but does not have half-wave symmetry.
B. is neither purely even nor purely odd.
C. is an even function and has half-wave symmetry.
D. is an odd function and has half-wave symmetry.
Correct Answer: is an odd function and has half-wave symmetry.
Explanation:
The properties of the coefficients reveal the symmetries of the signal. First, for a real signal , the coefficients must be conjugate symmetric: . If are purely imaginary, then . Conjugate symmetry means , which implies . This means the sine series coefficients are an odd sequence, which corresponds to an odd function . Second, the condition that for all even implies the signal has half-wave symmetry, which is defined by the property . Therefore, the signal is both an odd function and possesses half-wave symmetry.
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51What are the Fourier series coefficients for the full-wave rectified sine signal, ?
fourier series representation of continuous time periodic signals
Hard
A. for even, and for odd.
B. for all except .
C. for odd, and for even.
D. for all .
Correct Answer: for even, and for odd.
Explanation:
The signal is periodic with a fundamental period of , which is half the period of . The fundamental frequency is . Let's analyze with respect to the frequency . Over the period of , the signal is even. Thus, the coefficients will be real. The calculation for involves an integral that is non-trivial. . A known result for this signal is that its Fourier series (cosine series) is . From this trigonometric series, we can find the complex exponential coefficients . The DC term is . For , we have a cosine term, so . From the series, the term is , which corresponds to . So . This gives . If we let , then . This holds for any even . For odd , the coefficients are zero. So option A is correct.
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52A periodic signal with period and Fourier coefficients has zero DC component (). A new signal is formed by integration: . If is also periodic with period , what are its Fourier coefficients in terms of ?
Properties of continuous time fourier series
Hard
A. for , and is the average value of .
B. for , and .
C. for , and is arbitrary.
D. for all .
Correct Answer: for , and is the average value of .
Explanation:
The integration property of the Fourier series states that if , then the integral has coefficients for . The condition that is also periodic implies that the integral of over one period is zero. This is guaranteed by the given condition . However, the integration property does not define the DC component, , of the output signal. is simply the average value of over one period, , which is not necessarily zero and depends on the initial condition (or constant of integration) of the integral. Thus, can be any value and must be determined separately.
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53Consider a periodic signal whose -th derivative is the first derivative that contains an impulse or a step discontinuity, implying all lower-order derivatives are continuous. How does the magnitude of its Fourier series coefficients, , decay as ?
Convergence of the fourier series
Hard
A.As
B.As
C.Exponentially, as
D.As
Correct Answer: As
Explanation:
The rate of decay of Fourier series coefficients is directly related to the smoothness of the function. If a function is continuous and its first derivatives are continuous, while the -th derivative has a jump discontinuity, then the coefficients of decay as . This can be seen by repeatedly applying the differentiation property. The coefficients of are . If has a jump discontinuity, its coefficients decay as . Therefore, , which implies . For example, a square wave has discontinuities (), and its coefficients decay as . A triangular wave is continuous but its first derivative is a square wave (), so its coefficients decay as .
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54In a software simulation of a signal's frequency spectrum using the FFT, an analyst applies zero-padding to the sampled time-domain signal (i.e., adding a large number of zero-valued samples to the end of the original samples). What is the primary effect of this zero-padding on the resulting frequency spectrum?
Software simulation of frequency spectrum of periodic signals
Hard
A.It interpolates the DFT spectrum, providing more points to display the shape of the continuous spectrum envelope.
B.It removes aliasing by effectively increasing the sampling rate.
C.It increases the actual frequency resolution, allowing closer harmonics to be distinguished.
D.It reduces the effect of spectral leakage by smoothing the windowing function.
Correct Answer: It interpolates the DFT spectrum, providing more points to display the shape of the continuous spectrum envelope.
Explanation:
Zero-padding increases the number of points (N) in the FFT computation. The frequency resolution of a DFT is , where is the sampling rate. Increasing decreases , meaning the points in the FFT plot are closer together. However, this does not increase the actual resolution, which is the ability to distinguish between two closely spaced frequency components. The actual resolution is determined by the length of the original time-domain window (), roughly . Zero-padding does not add new information about the signal. Instead, it performs a more detailed interpolation of the Discrete Time Fourier Transform (DTFT) of the original (un-padded) signal. This results in a smoother-looking plot that better represents the shape of the underlying continuous spectrum, including the sinc-like shape of the spectral leakage lobes.
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55A periodic signal with period and Fourier coefficients is used to create a new signal . What are the Fourier coefficients, , of ?
Properties of continuous time fourier series
Hard
A.
B. for odd, and for even.
C.
D. for odd, and for even.
Correct Answer: for odd, and for even.
Explanation:
We use the linearity and time-shifting properties of the Fourier series. Let . The signal has coefficients . By linearity, the coefficients of are . Now we evaluate for even and odd . If is even (), . So, . If is odd (), . So, . This operation effectively acts as a high-pass filter, removing all even harmonics (including DC) and doubling the odd harmonics.
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56A periodic signal is constructed by repeating the function over the interval . The signal has period . What is the complex Fourier series coefficient for this signal?
fourier series representation of continuous time periodic signals
Hard
A.
B.
C.
D.
Correct Answer:
Explanation:
The formula for the Fourier series coefficient is . Here, and . The signal over one period is . So, . We can now evaluate the integral: . This simplifies to . Since for any integer , this becomes .
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57For a periodic square wave, the Gibbs phenomenon overshoot has a certain peak value. As more terms () are added to the Fourier series approximation , how does the spatial width of the primary overshoot 'ears' surrounding a discontinuity change?
Convergence of the fourier series
Hard
A.The width increases proportionally to N.
B.The width remains constant regardless of N.
C.The width decreases proportionally to .
D.The width decreases proportionally to .
Correct Answer: The width decreases proportionally to .
Explanation:
While the height of the Gibbs phenomenon overshoot approaches a constant value (approx. 9% of the jump), its location moves closer to the discontinuity as more terms are added to the series. The first peak of the overshoot for a square wave with period T occurs at approximately . The 'width' of the ringing or oscillation can be considered proportional to this distance. Therefore, as the number of terms increases, the width of the overshoot region becomes narrower, decreasing proportionally to . The oscillations get compressed towards the discontinuity, but the peak amplitude of the first overshoot does not decrease.
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58To accurately estimate the first non-zero Fourier series harmonics of a continuous-time signal using a DFT, what is the theoretical minimum sampling rate that must be used to avoid aliasing?
Software simulation of frequency spectrum of periodic signals
Hard
A.The sampling rate does not affect which harmonics can be estimated, only the accuracy.
B., where is the fundamental frequency.
C., where is the number of harmonics.
D., where is the number of harmonics.
Correct Answer: , where is the number of harmonics.
Explanation:
The Nyquist-Shannon sampling theorem states that to avoid aliasing, the sampling rate must be greater than twice the maximum frequency component in the signal (). When we are interested in the first non-zero harmonics of a signal with fundamental frequency , the harmonics are at frequencies . The maximum frequency component we wish to capture is the -th harmonic, so . Applying the Nyquist theorem, the minimum sampling rate required is . This ensures that the -th harmonic itself does not get aliased by higher frequencies or by its own negative frequency component.
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59A periodic signal with period has an average power of 10 W. Its DC component is 2. The signal is passed through an ideal high-pass filter that completely removes the DC component and the fundamental frequency component (). If the power in the fundamental component was 4 W, what is the average power of the output signal ?
Properties of continuous time fourier series
Hard
A.2 W
B.6 W
C.4 W
D.5 W
Correct Answer: 2 W
Explanation:
This problem requires a careful application of Parseval's theorem. The total average power of a signal is the sum of the powers of its individual harmonic components: . The power of the DC component () is . The power of the fundamental component () is . We are given: Total power W. DC coefficient . So, power in DC component is W. Power in the fundamental component is given as W. The output signal is the original signal with the DC and fundamental components removed. Its power is the total power of minus the power of the components that were removed. .